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Bézout's identity: Revision history


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  • curprev 06:3906:39, 28 July 2022 LightbulbMEOW talk contribs 11,317 bytes +36 Bezout's identity always doesn't hold for polynomials (for example, 2x and x^2 when working in Z[x]). The polynomial case isn't cited anywhere else in the article except in the "Generalizations" section, which describes it more accurately anyways. undo

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