Ponderomotive energy: Difference between revisions
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==Equation == |
==Equation == |
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The ponderomotive energy is given by |
The ponderomotive energy is given by |
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:<math>U_p = {e^2 |
:<math>U_p = {e^2 E^2 \over 4m \omega_0^2}</math>, |
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where <math>e</math> is the [[electron charge]], <math> |
where <math>e</math> is the [[electron charge]], <math>E</math> is the linearly [[Polarization (waves)|polarised]] electric field amplitude, <math>\omega_0</math> is the laser [[carrier frequency]] and <math>m</math> is the [[electron mass]]. |
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In terms of the laser [[Intensity (physics)|intensity]] <math>I</math>, using <math>I=c\epsilon_0 |
In terms of the laser [[Intensity (physics)|intensity]] <math>I</math>, using <math>I=c\epsilon_0 E^2/2</math>, it reads less simply: |
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:<math>U_p={e^2 I \over 2 c \epsilon_0 m \omega_0^2}={2e^2 \over c \epsilon_0 m} \cdot {I \over 4\omega_0^2}</math>, |
:<math>U_p={e^2 I \over 2 c \epsilon_0 m \omega_0^2}={2e^2 \over c \epsilon_0 m} \cdot {I \over 4\omega_0^2}</math>, |
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For typical orders of magnitudes involved in laser physics, this becomes: |
For typical orders of magnitudes involved in laser physics, this becomes: |
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:<math> U_p (\mathrm{eV}) = 9.33 \cdot I(10^{14} \mathrm{W/cm}^2) \cdot \lambda(\mathrm{\mu m} |
:<math> U_p (\mathrm{eV}) = 9.33 \cdot I(10^{14}\ \mathrm{W/cm}^2) \cdot \lambda^2(\mathrm{\mu m}^2) </math>,<ref>https://www.phys.ksu.edu/personal/cdlin/class/class11a-amo2/atomic_units.pdf {{Bare URL PDF|date=March 2022}}</ref> |
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where the laser wavelength is <math>\lambda= |
where the laser wavelength is <math>\lambda= 2\pi c/\omega_0</math>, and <math>c</math> is the speed of light. The units are electronvolts (eV), watts (W), centimeters (cm) and micrometers (μm). |
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===Atomic units=== |
===Atomic units=== |
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In [[atomic units]], <math>e=m=1</math>, <math>\epsilon_0=1/4\pi</math>, <math>\alpha c=1</math> where <math>\alpha \approx 1/137</math>. If one uses the [[Atomic units|atomic unit of electric field]],<ref>CODATA Value: [http://physics.nist.gov/cgi-bin/cuu/Value?auefld atomic unit of electric field]</ref> then the ponderomotive energy is just |
In [[atomic units]], <math>e=m=1</math>, <math>\epsilon_0=1/4\pi</math>, <math>\alpha c=1</math> where <math>\alpha \approx 1/137</math>. If one uses the [[Atomic units|atomic unit of electric field]],<ref>CODATA Value: [http://physics.nist.gov/cgi-bin/cuu/Value?auefld atomic unit of electric field]</ref> then the ponderomotive energy is just |
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:<math>U_p = \frac{ |
:<math>U_p = \frac{E^2}{4\omega_0^2}.</math> |
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==Derivation== |
==Derivation== |
Latest revision as of 21:30, 20 July 2024
In strong-field laser physics, ponderomotive energy is the cycle-averaged quiver energy of a free electron in an electromagnetic field.[1]
Equation
[edit]The ponderomotive energy is given by
- ,
where is the electron charge, is the linearly polarised electric field amplitude, is the laser carrier frequency and is the electron mass.
In terms of the laser intensity , using , it reads less simply:
- ,
where is the vacuum permittivity.
For typical orders of magnitudes involved in laser physics, this becomes:
- ,[2]
where the laser wavelength is , and is the speed of light. The units are electronvolts (eV), watts (W), centimeters (cm) and micrometers (μm).
Atomic units
[edit]In atomic units, , , where . If one uses the atomic unit of electric field,[3] then the ponderomotive energy is just
Derivation
[edit]The formula for the ponderomotive energy can be easily derived. A free particle of charge interacts with an electric field . The force on the charged particle is
- .
The acceleration of the particle is
- .
Because the electron executes harmonic motion, the particle's position is
- .
For a particle experiencing harmonic motion, the time-averaged energy is
- .
In laser physics, this is called the ponderomotive energy .
See also
[edit]References and notes
[edit]- ^ Highly Excited Atoms. By J. P. Connerade. p. 339
- ^ https://www.phys.ksu.edu/personal/cdlin/class/class11a-amo2/atomic_units.pdf [bare URL PDF]
- ^ CODATA Value: atomic unit of electric field