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{{Wikipedia:Reference_desk/Archives/Science/2009 May 31}}


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= December 18 =
{{Wikipedia:Reference_desk/Archives/Science/2009 June 2}}


== Why don't all mast radiators have top hats? ==
= June 3 =


[[Image:Hamersley radio mast closeup 2.jpg|thumb|right]]Our [[mast radiator]] article describes a device called a "top hat" which increases the range for mast radiators that can't be built tall enough.
== Earth is seriously moving away from sun? ==


So, why would you bother building a mast radiator without a top hat? Couldn't you just build it shorter with the top hat, and save steel? [[User:Marnanel|Marnanel]] ([[User talk:Marnanel|talk]]) 15:00, 18 December 2024 (UTC)
Is earth seriously moving away from sun? [http://www.supermemo.com/articles/users/earth_files/5.htm I saw it] was update like last night earth moving 20 centimeters apart each year they said because sun is losing solar winds and masses. Is it just earth or this is also happening to venus, mars, and others? If sun is losing mass now, then sun will just lose more and more, I don't think sun will gain mass back again.--[[Special:Contributions/69.229.240.187|69.229.240.187]] ([[User talk:69.229.240.187|talk]]) 00:25, 3 June 2009 (UTC)


:The main source cited in our article states, "{{tq|Top loading is less desirable than increased tower height but is useful where towers must be electrically short due to either extremely low carrier frequencies or to aeronautical limitations. Top loading increases the base resistance and lowers the capacitive base reactance, thus reducing the ''Q'' and improving the bandwidth of towers less than 90° high.}}"<sup>[https://books.google.com/books?id=V8Lk2ghPl7IC&pg=PA717&dq=%22Top+loading+is+less+desirable+than+increased+tower+height%22&hl=en]</sup> If "reducing the {{serif|''Q''}}" is an undesirable effect, this is a trade-off design issue in which height seems to be favoured if circumstances permit. &nbsp;--[[User talk:Lambiam#top|Lambiam]] 21:41, 18 December 2024 (UTC)
:Yes. Tidal forces and loss of solar mass both result in the Earth receding slightly from the Sun. Without checking numbers, I'd expect tidal forces to be the dominant mechanism. The same effect occurs at varying rates on all other bodies orbiting the Sun. The Sun can gain mass (any time a long-period comet crashes into it, for instance) but is a net loser of mass. &mdash; [[User talk:Lomn|Lomn]] 00:46, 3 June 2009 (UTC)
:It is true, but it is a negligible amount. Our measurements of the distance from the Earth to the Sun are only accurate to a few metres (according to [[Astronomical unit]]), so a change of 20 centimetres isn't even measurable. It is happening to all planets, though. When the sun nears the end of its life it will throw off its outer layers, dramatically reducing its mass, and then the Earth will move significantly further away, but that won't happen for billions of years. --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 00:49, 3 June 2009 (UTC)


== Name of our solar system ==
*Does all planets including Mercury and Venus? Venus have backwar orbit, so I always thought Venus will just end up like Triton vs.Neptune or Phobos vs. Mars. But how is Mercury moving farther when it is so close to sun?--[[Special:Contributions/69.229.240.187|69.229.240.187]] ([[User talk:69.229.240.187|talk]]) 00:58, 3 June 2009 (UTC)


*I honestly can't dig anymore. I couldn't find the source said all the planets is now moving out. [[Formation and evolution of the solar system]] don't give us enough informations though.--[[Special:Contributions/69.229.240.187|69.229.240.187]] ([[User talk:69.229.240.187|talk]]) 02:31, 3 June 2009 (UTC)
Is our star system officially called "Sol", or is that just something that came from science fiction and then became ubiquitous? [[Special:Contributions/146.90.140.99|146.90.140.99]] ([[User talk:146.90.140.99|talk]]) 22:06, 18 December 2024 (UTC)
:It's called the [[Solar System]], and its star is called Sol, from Latin via French. Hence terms like "solstice", which means "sun stands still" in its apparent annual "sine wave" shaped path through the sky. ←[[User:Baseball Bugs|Baseball Bugs]] <sup>''[[User talk:Baseball Bugs|What's up, Doc?]]''</sup> [[Special:Contributions/Baseball_Bugs|carrots]]→ 23:31, 18 December 2024 (UTC)
:::Via French? According to the OED, it came direct from Latin.<sup>[https://archive.org/details/in.ernet.dli.2015.271834/page/n1182/mode/1up]</sup> &nbsp;--[[User talk:Lambiam#top|Lambiam]] 11:45, 19 December 2024 (UTC)}}
::::Old French plus Latin.[https://www.etymonline.com/search?q=sol] ←[[User:Baseball Bugs|Baseball Bugs]] <sup>''[[User talk:Baseball Bugs|What's up, Doc?]]''</sup> [[Special:Contributions/Baseball_Bugs|carrots]]→ 14:25, 19 December 2024 (UTC)
:::::Also in Old French, the word meaning "sun" was ''[[wikt:soleil#Old French|soleil]]''. &nbsp;--[[User talk:Lambiam#top|Lambiam]] 23:42, 19 December 2024 (UTC)
::Let's say {{fact}} to that claim. The star is indeed called Sol if you're speaking Latin, but in English it's the Sun (or sun). Of course words like "solar" and "solstice" derive from the Latin name, but using "Sol" to mean "the Sun" does seem to be something from science fiction. --[[Special:Contributions/142.112.149.206|142.112.149.206]] ([[User talk:142.112.149.206|talk]]) 06:04, 19 December 2024 (UTC)
:::"Sol" is occasionally used to mean the Sun by astronomers. I feel like it is used in contexts where it is necessary to distinguish our experience with the Sun here on Earth, such as sunsets, from more "sterile" aspects of the Sun one might experience off the Earth. <span style="font-family: Cambria;"> [[User:Abductive|<span style="color: teal;">'''Abductive'''</span>]] ([[User talk:Abductive|reasoning]])</span> 08:56, 19 December 2024 (UTC)
::::Being an astronomer myself, I don't think I've ever heard anyone use "Sol" outside of a science fiction context. --[[User:Wrongfilter|Wrongfilter]] ([[User talk:Wrongfilter|talk]]) 09:06, 19 December 2024 (UTC)
::::::Scientific articles that use the term Sol; [https://www.sciencedirect.com/science/article/pii/S0094576522005598 Development of the HeliosX mission analysis code for advanced ICF space propulsion] and [https://arxiv.org/pdf/2309.07061 Swarming Proxima Centauri: Optical Communication Over Interstellar Distances]. These are rather speculative but as I mentioned, the usage is for off-planet situations. <span style="font-family: Cambria;"> [[User:Abductive|<span style="color: teal;">'''Abductive'''</span>]] ([[User talk:Abductive|reasoning]])</span> 13:05, 19 December 2024 (UTC)
:::::Using Sol, Terra and Luna to refer to the Sun, Earth and Moon only happens if you write your entire article in Latin and in science fiction, not in regular science articles. They are capitalised though. Just as people write about a galaxy (one of many) or the Galaxy (the Milky Way Galaxy, that's our galaxy). The Solar System is also capitalised. [[User:PiusImpavidus|PiusImpavidus]] ([[User talk:PiusImpavidus|talk]]) 10:38, 19 December 2024 (UTC)
::::::The article says "Sol" is the "personification" of the sun. Google Image the term "old Sol" and you'll see plenty of images of the sun with a face, not just Sci-Fi stuff. And "Luna" is obviously the basis for a number of words not connected with Sci-Fi. Lunar orbit, lunar module, etc. And the term "terra firma" has often been used in everyday usage. ←[[User:Baseball Bugs|Baseball Bugs]] <sup>''[[User talk:Baseball Bugs|What's up, Doc?]]''</sup> [[Special:Contributions/Baseball_Bugs|carrots]]→ 11:34, 19 December 2024 (UTC)
::::::: And yet, if you ask 1,000 people "What's that big yellow thing up in the sky called?", you'll get 1,000 "the Sun"s and zero "Sol"s. Yes, in specialised contexts, Sol is used; but that doesn't justify saying our solar system's star "is called Sol" without any qualification, as if that were the normal, default term. It's not. -- [[User:JackofOz|<span style="font-family: Papyrus;">Jack of Oz</span>]] [[User talk:JackofOz#top|<span style="font-size:85%; font-family: Verdana;"><sup>[pleasantries]</sup></span>]] 12:16, 19 December 2024 (UTC)
:::::::::And after you've gotten that response, ask them why it isn't the "Sunner System". And why a sun room attached to a house isn't called a "sunarium". And why those energy-gathering plates on some roofs are not called "sunner panels". ←[[User:Baseball Bugs|Baseball Bugs]] <sup>''[[User talk:Baseball Bugs|What's up, Doc?]]''</sup> [[Special:Contributions/Baseball_Bugs|carrots]]→ 14:22, 19 December 2024 (UTC)
::::::::::What does that have to do with anything? The question was 'Is our star system ''officially'' called "Sol"?' (my emphasis). The answer is it is not. And that does not preclude other terms being derived from Latin ''sol'' (or, often enough, from Greek ''helios''), nobody denies that, it is irrelevant to the question. --[[User:Wrongfilter|Wrongfilter]] ([[User talk:Wrongfilter|talk]]) 14:52, 19 December 2024 (UTC)
:::::::::::The problem is that the OP's question contains false premises. One is the question of what the "official" name is. There is no "official" name. It's the "conventional" name. And the second part, claiming that "Sol" comes from Sci-fi, is demonstrably false. ←[[User:Baseball Bugs|Baseball Bugs]] <sup>''[[User talk:Baseball Bugs|What's up, Doc?]]''</sup> [[Special:Contributions/Baseball_Bugs|carrots]]→ 15:05, 19 December 2024 (UTC)
::::::::::::Then demonstrate (that the usage of "Sol" as a name for the Sun, in English, not its use to derive adjectives, originated outside of SF), with references. The original question does not even include any premises, with maybe the exception of "ubiquitous". --[[User:Wrongfilter|Wrongfilter]] ([[User talk:Wrongfilter|talk]]) 15:18, 19 December 2024 (UTC)
:::::::::::::"Is our star system officially called "Sol" [answer: NO], or is that just something that came from science fiction [answer: NO] and then became ubiquitous? [whatever that means]". And the wording of your own question, just above, does not make sense. ←[[User:Baseball Bugs|Baseball Bugs]] <sup>''[[User talk:Baseball Bugs|What's up, Doc?]]''</sup> [[Special:Contributions/Baseball_Bugs|carrots]]→ 15:24, 19 December 2024 (UTC)
::::::::::::::Looking at Newspapers.com (pay site), I'm seeing colloquial references to "old Sol" (meaning the sun) as far back as the 1820s. No hint of sci-fi derivation. ←[[User:Baseball Bugs|Baseball Bugs]] <sup>''[[User talk:Baseball Bugs|What's up, Doc?]]''</sup> [[Special:Contributions/Baseball_Bugs|carrots]]→ 15:32, 19 December 2024 (UTC)
:::::::::::::::Great! Well done. --[[User:Wrongfilter|Wrongfilter]] ([[User talk:Wrongfilter|talk]]) 15:41, 19 December 2024 (UTC)
::::::::::::::::Feel free to box up this section. ←[[User:Baseball Bugs|Baseball Bugs]] <sup>''[[User talk:Baseball Bugs|What's up, Doc?]]''</sup> [[Special:Contributions/Baseball_Bugs|carrots]]→ 15:52, 19 December 2024 (UTC)
:::::::::::::The 1933 OED entry for ''Sol'', linked to above, gives several pre-SF uses, the earliest from 1450. &nbsp;--[[User talk:Lambiam#top|Lambiam]] 23:48, 19 December 2024 (UTC)
::::::::::::::Yes, of course, but that's not surprising, is it? 15th century humanists, astrologers and pre-Victorian poets liked to sprinkle their texts with Latin words. But I don't think this is what the question is about. It's a matter of context, but it should be up to OP to clarify that. --[[User:Wrongfilter|Wrongfilter]] ([[User talk:Wrongfilter|talk]]) 08:48, 20 December 2024 (UTC)
:::::::::::::::It's not surprising, but the discussion was not whether the use of ''Sol'' in English texts is surprising, but whether it originated outside of SF. &nbsp;--[[User talk:Lambiam#top|Lambiam]] 10:52, 20 December 2024 (UTC)
::::::::::::::::In my view, the question has a clear scifi bent, and that particular usage ("Where shall we go for our vacation? Alpha Centauri or Sol?") does not originate in the 15th century. The word is much older, of course it is, but the usage is not. In the 15th century people didn't even know that the Sun is just an ordinary star and could do with a particular name to distinguish it from the others. The connotations of ''sol'' were vastly different from what they are today and from what is implied in OP's question. Incidentally, the [[International Astronomical Union|IAU]] doesn't even define a name [https://www.iau.org/public/themes/naming/], although they recommend using capitalised "Sun". Certainly no "Sol" anywhere. --[[User:Wrongfilter|Wrongfilter]] ([[User talk:Wrongfilter|talk]]) 12:04, 20 December 2024 (UTC)
::::::::{{small|Does that make it a Sol-ecism? [[User:Clarityfiend|Clarityfiend]] ([[User talk:Clarityfiend|talk]]) 12:19, 19 December 2024 (UTC)}}
:::::::::<small>More like a [[solipsism|Sol-ips-ism]]. Meaning a factory where suns are made. From Sol = sun, and ipso = facto. Thus endeth the entymogology lesson for today. Go in peace to love and serve whomsoever. -- [[User:JackofOz|<span style="font-family: Papyrus;">Jack of Oz</span>]] [[User talk:JackofOz#top|<span style="font-size:85%; font-family: Verdana;"><sup>[pleasantries]</sup></span>]] 19:37, 19 December 2024 (UTC) </small>


== Mountains ==
**Venus does NOT have a backwards orbit. It has a backwards ''rotation'', which means that it turns through a day in the opposite direction as the other planets do (or if you prefer, it is upside-down. Same difference). It turns so slowly, however, that a venusian "day" is longer than a venusian "year". And it orbits in the same direction as all of the other planets. However, as noted, the sun is losing mass via [[nuclear fusion|mass-energy conversion]], which means that as the mass decreases, its gravity decreases over time. Since the force of gravity is decreasing, ALL objects gravitationally bound to the sun will drift farther away. It doesn't matter if we are talking about [[Mercury]] or the [[Oort cloud]]. Less mass = less gravity. Less gravity = larger orbits. Its that simple. --[[User:Jayron32|Jayron32]].[[User talk:Jayron32|<small>talk</small>]].[[Special:Contributions/Jayron32|<small>contribs</small>]] 03:02, 3 June 2009 (UTC)
::Even if it was a retrograde orbit (which is not the case), it would still move out to a larger radius if the sun's mass decreased. [[User:Nimur|Nimur]] ([[User talk:Nimur|talk]]) 03:55, 3 June 2009 (UTC)


Why there are no mountains on Earth with a height above 10,000 m? As the death zone is about at 8,000 m, and above 19,000 m, there is an Armstrong limit, where water boils at normal human body temperature, it is good that there are no more mountains higher than 8,000 km than just 14, but if there were hundreds of mountains above 9,000 m, then these were bad to climb. If there were different limits for death zone and Armstrong limit, would then there be possible to have higher mountains? I have just thought that, it is not a homework? --[[User:40bus|40bus]] ([[User talk:40bus|talk]]) 22:29, 18 December 2024 (UTC)
For perspective, at a rate of 20 cm / yr, the Earth's orbit would take 7.5 billion years to change 1% in radius. In other words, the current rate of expansion is utterly negligible for any practical purpose. [[User:Dragons flight|Dragons flight]] ([[User talk:Dragons flight|talk]]) 03:58, 3 June 2009 (UTC)


:There are [[List of tallest mountains in the Solar System|mountains elsewhere in the solar system]] that are over 20km high. Given that some of those are on airless worlds, I don't think the air pressure has any bearing on it. [[Special:Contributions/146.90.140.99|146.90.140.99]] ([[User talk:146.90.140.99|talk]]) 22:57, 18 December 2024 (UTC)
*If Dragon Flights is talking about in 7.5 billion years. It is still the same game as usual. Nothing have changed. Earth survival or not is still an even money (50/50). Mercury is going to go definitely. Venus' odd to doom is obviously better than a 50/50, Mars could be a doom one but highly unlikely. When sun expands, then it's surface area will increase drastically, then sun's mass and gravity will probably climb. This is possibly another story.--[[Special:Contributions/69.229.240.187|69.229.240.187]] ([[User talk:69.229.240.187|talk]]) 04:26, 3 June 2009 (UTC)
:: Surface area expands OK, but why would mass/gravity climb? It will only decrease. - [[User:Ranemanoj|manya]] ([[User talk:Ranemanoj|talk]]) 04:54, 3 June 2009 (UTC)


:Multiple sources from web searching suggest the ''theoretical'' maximum height for mountains on Earth is around 15,000 m – the limiting factor is [[Isostasy]]; the higher (therefore more voluminous) a mountain is, the more its weight causes the crust beneath it to sink. The actual heights of mountains are a trade-off between how fast tectonic movements can raise them versus isostatic sinking ''and'' how quickly they are eroded, and tectonic movements do not last for ever. See also [[Orogeny]]. {The poster formerly known as 87.81.230.195} [[Special:Contributions/94.1.223.204|94.1.223.204]] ([[User talk:94.1.223.204|talk]]) 00:25, 19 December 2024 (UTC)
::We don't even know if earth will still exist at that time or not. It got to be some theory to make earth getting engulf, it's still a 50/50 odds.--[[Special:Contributions/69.229.240.187|69.229.240.187]] ([[User talk:69.229.240.187|talk]]) 05:00, 3 June 2009 (UTC)
::And erosion goes faster as the mountain gets higher, in particular when it's high enough to support glaciers – one reason why mountains can get higher on an airless world. Now it gets interesting for a mountain high enough to reach into the stratosphere, as it would be too dry to have anything but bare rock. I suppose it would locally raise the tropopause, preventing that. [[User:PiusImpavidus|PiusImpavidus]] ([[User talk:PiusImpavidus|talk]]) 11:13, 19 December 2024 (UTC)


= December 19 =
::: 69': You have the ending of the sun all wrong. When it runs out of hydrogen and starts running on helium, it suddenly starts generating a LOT more energy (but not for very long) it blows off an immense amount of material - which is certainly enough to kill everything on earth, blow away it's atmosphere and oceans and generally trash the place. Once that's happened, both the mass and gravity of the sun are a lot less and the gravity can no longer stop the sun from expanding due to photon pressure from all the energy it's putting out - THAT'S why it expands. It doesn't gain mass or gravity - quite the opposite in fact!


== Does human DNA become weaker with each generation? ==
::: You have to think of stars as fighting a continual battle between their immense gravity trying to collapse them into something much smaller and more exotic (like a black hole or a neutron star) and the photon pressure from the energy they put out that's trying to inflate them. If the gravity loses the battle, the star grows to a larger, dimmer red giant - if gravity wins, it shrinks to a white dwarf, a neutron star or a black hole depending on how much gravity there is. Ironically - the bigger the star is, the smaller it ends up being! The Sun - being relatively tiny gets bigger - but NOT heavier. [[User:SteveBaker|SteveBaker]] ([[User talk:SteveBaker|talk]]) 12:47, 3 June 2009 (UTC)


As with photocopying something over and over, the text becomes less clear each time.
::::As the core fills up with heavier and heavier atoms it becomes denser and so so the pressure at the core increases (due to the stronger gravity) and the fusion rate increases. The sun expands because it is producing so much more energy. the expansion reduces the pressure in the core and slows down the rate of fusion. its a feedback process. (disclamer:I am not an expert) [[User:Em3ryguy|just-emery]] ([[User talk:Em3ryguy|talk]]) 20:04, 3 June 2009 (UTC)


Does human DNA become weaker with each generation? [[User:HarryOrange|HarryOrange]] ([[User talk:HarryOrange|talk]]) 21:22, 19 December 2024 (UTC)
:::I'm not getting the whole thing wrong just mass and gravity. I didn't know that in past, but I got it now. Yes, when sun gets bigger, it's mass and gravity plummets quickly, mass and gravity just dives way down. I got weight-size thing upside down. Yes I know neutron star and black hole comes from high mass star not sun since our sun is average mass star. yes, I know once sun runs out of hydrogen, earth ocean and life will run out first, earth will become a hell instantly until earth atmosphere runs out earth is a char garbage. But have you seen [[Formation and evolution of the Solar System#Future]] yet. They siad because of tidal interaction, earth will get destroy at end of sun's peak size, when mass and gravity drops suddenly. Studys 6 month ago hadn't change yet. Yes, if earth survives, then earth is a trash hell black-out scorchland with nothing on it. Maybe earth will be gone, destroy by sun. With [[tidal interaction]] between sun and earth I don't know what it is about.--[[Special:Contributions/69.229.240.187|69.229.240.187]] ([[User talk:69.229.240.187|talk]]) 22:37, 3 June 2009 (UTC)
:Sure, DNA replication is not perfect, although [[Proofreading (Biology)|proofreading]] reduces the error rate to about 1 mistake per 10<sup>9</sup> nucleotides (see our article on [[DNA Replication#DNA Polymerase|DNA Replication]]). But that is per generation of cells, not of the whole organisms. Many mutations will be neutral in effect (because much of our DNA is redundant), some will be deleterious, and a few might be advantageous. It is the process of natural selection that hinders the spread of deleterious mutations: sometimes this aspect is called [[Negative selection (natural selection)|purifying selection]]. One thus usually expects a stable [[mutation–selection balance]] over time rather than that "DNA becomes weaker with each generation". Medical science is reducing the selection pressure against some mutations, which consequently may become more common. One of the problems for asexual organisms is referred to as [[Muller's ratchet]]; assuming that reverse mutations are rare, each generation has at least the mutational load of its predecessor. In contrast, in sexual organisms [[genetic recombination]] generates the variation that, combined with selection, can repair the situation. Sexual organisms consequently have a lighter genetic load. [[User:Jmchutchinson|JMCHutchinson]] ([[User talk:Jmchutchinson|talk]]) 22:42, 19 December 2024 (UTC)
::So [[Negative selection (natural selection)|purifying selection]] won't work properly in case of [[Inbreeding]] ? [[User:HarryOrange|HarryOrange]] ([[User talk:HarryOrange|talk]]) 23:16, 19 December 2024 (UTC)
:::The larger the degree of inbreeding, the larger the chance that deleterious traits are expressed. But this very expression of traits leading to decreased biological fitness of their bearers is what actually enables purifying selection in the longer term. &nbsp;--[[User talk:Lambiam#top|Lambiam]] 23:36, 19 December 2024 (UTC)
::::@[[User:Lambiam|Lambiam]] so [[DNA repair]] won't stop these deleterious traits to get expressed? [[User:HarryOrange|HarryOrange]] ([[User talk:HarryOrange|talk]]) 14:11, 20 December 2024 (UTC)
:::::No, this is not an issue of [[DNA damage|damage to the DNA]]. The genes involved are faithfully reproduced and passed on from generation to generation. &nbsp;--[[User talk:Lambiam#top|Lambiam]] 15:53, 20 December 2024 (UTC)
:Or stronger e.g. "[https://www.biorxiv.org/content/10.1101/2024.09.09.611499v1.full.pdf ...we found that genes specifically duplicated in the Greenland shark form a functionally connected network enriched for DNA repair function]", and those guys live for centuries and have much more DNA than us. [[User:Sean.hoyland|Sean.hoyland]] ([[User talk:Sean.hoyland|talk]]) 15:21, 20 December 2024 (UTC)
::@[[User:Lambiam|Lambiam]] If not due to DNA damage, why do babies from inbreeding appear like DNA-damaged species? [[User:HarryOrange|HarryOrange]] ([[User talk:HarryOrange|talk]]) 17:29, 20 December 2024 (UTC)
:::Inbred offspring of species that normally outcross may show abnormalities because they are more likely than outcrossed offspring to be [[Zygosity|homozygous]] for [[Dominance (genetics)|recessive alleles]] that are deleterious. In individuals that are heterozygous at these loci, the recessive alleles will not be expressed (because the other wild-type dominant allele is sufficient to do their job adequately). See our article on [[inbreeding depression]]. [[User:Jmchutchinson|JMCHutchinson]] ([[User talk:Jmchutchinson|talk]]) 19:26, 20 December 2024 (UTC)


== Larvae going south ==
::Actually what is a [[tidal force]] thing when sun gets to peak of it's diameter about? how can tidal force happen when gravity and mass drops.--[[Special:Contributions/69.229.240.187|69.229.240.187]] ([[User talk:69.229.240.187|talk]]) 00:32, 4 June 2009 (UTC)


In a novel I've just finished (''[[The Chemistry of Death]]'' by [[Simon Beckett]]) he writes:
:All the informations is on [http://adsabs.harvard.edu/abs/2008MNRAS.386..155S this site] and source on [[Formation and evolution of the Solar System#Notes and references]] numbers 86-89, if my questions is clear fully.--[[Special:Contributions/69.229.240.187|69.229.240.187]] ([[User talk:69.229.240.187|talk]]) 02:24, 4 June 2009 (UTC)
* ''[The larvae] leave the body in an orderly fashion, following each other in a neat procession that always heads south. South-east or south-west sometimes, but never north. No-one knows why''.


The author has done considerable international research on the science of forensic identification of decayed bodies and I assume his details can be trusted.


I've looked online for any verification of this surprising statement, but found only [https://www.quora.com/Why-do-maggots-all-go-the-same-direction this], which seems to debunk it.
:I haven't read all those posts yet, but the Earth really is moving away from the Sun, and it's not due to nuclear fusion: http://www.skyandtelescope.com/news/46618862.html. That article suggests tidal interactions between Earth and the Sun. Sky and Telescope is a reputable amateur astronomy magazine, but I don't know how scientifically reliable that specific article is. --[[User:Bowlhover|Bowlhover]] ([[User talk:Bowlhover|talk]]) 10:54, 4 June 2009 (UTC)


Is there any truth to this? -- [[User:JackofOz|<span style="font-family: Papyrus;">Jack of Oz</span>]] [[User talk:JackofOz#top|<span style="font-size:85%; font-family: Verdana;"><sup>[pleasantries]</sup></span>]] 23:38, 19 December 2024 (UTC)
:Main factor of earth moving away from sun is lost of mass.It is not only earth but all planets maybe moons vs. planets (Titan and Saturn) is also moving away so is [[Galilean moons]] vs Jupiter. Fron [[Talk:Formation and evolution of the Solar System/Archive 2|Section 15]] they said because of tidal bulge. Earth is '''both''' moving '''farther''' and '''closer''' to sun. Is tidal bulge. Net solution is when sun gets old, hydrogen starts to deplete, then with less gravitational pull, then all planets and moons moves farther out. Tidal bulge is probably a friction, slows down earth's orbit, but I don't know how drag of sun and earth shrinking orbit works is my question.--[[Special:Contributions/69.229.240.187|69.229.240.187]] ([[User talk:69.229.240.187|talk]]) 22:32, 4 June 2009 (UTC)


:Can't speak to its truth, but . . .
== MM Experiment ==
:* Does Beckett state this in his own auctorial voice (i.e. as an [[Narration|omniscient narrator]])? If so, he might be genuinely mistaken.
:* The book was published nearly 20 years ago, what was the accepted wisdom ''then''?
:* What specific species (if any) is the book describing? – your linked Quora discussion refers only to "maggots" (which can be of numerous species and are a kind of larva, but there are many others, including for example [[Thaumetopoeinae|Processionary caterpillars]]).
:*Alternatively, if the statement is made by a character in the book, is that character meant to be infallible, or is he portrayed as less than omniscient, or an '[[unreliable narrator]]'?
:Regarding the statement, in the Northern hemisphere the arc of South-east to South-west is predominently where the Sun is found well above the horizon, the North never, so the larvae involved might simply be seeking maximum warmth or light. {The poster formerly known as 87.81.230.195} [[Special:Contributions/94.1.223.204|94.1.223.204]] ([[User talk:94.1.223.204|talk]]) 02:18, 20 December 2024 (UTC)


:: This appears in the very first paragraph of Chapter I, which starts out:
When Michelson and Morley did their experiment they were looking for variations in the brightness of the light right? I was under the impresssions that the split beams were recombined into a eyepiece. As they rotated the apparatus they were looking for variations in the brightness of the light right? Because they knew they couldn't make the arms exactly the same length apart. They weren't looking for actual fringe shift, just the effect. <span style="font-size: smaller;" class="autosigned">—Preceding [[Wikipedia:Signatures|unsigned]] comment added by [[Special:Contributions/24.171.145.63|24.171.145.63]] ([[User talk:24.171.145.63|talk]]) 00:53, 3 June 2009 (UTC)</span><!-- Template:UnsignedIP --> <!--Autosigned by SineBot-->
::* ''A human body starts to decompose four minutes after death. Once the encapsulation of life, it now undergoes its final metamorphoses. It begins to digest itself. Cells dissolve from the inside out. Tissue turns to liquid, then to gas. No longer animate, the body becomes an immovable feast for other organisms. Bacteria first, then insects. Flies. Eggs are laid, then hatched. The larvae feed on the nutrient-rich broth, and then migrate. They leave the body in an orderly fashion ...'' (then the quote above completes the paragraph).
:Basically you are correct. They could not measure the exact length of each arm with sufficient accuracy with any instrument at their disposal, but by looking at the interference pattern, you can obseerve changes in the difference between the lengths. Whe I set up an interformeter I used a laser, so I had a nice long coherence length to work with. With a laser, you start with two paths that ate roughly the same length. as you vary one length by one wavelength, you cah observe the pattern shift through an entire cycle. I used a mirror mounted to a piezoleletric actuator to vary the length through several wavelengths and observed the repeating cyclic pattern. When using a white light as Michelson did, you need to get the paths a lot closer to the same length to start with. -[[User:Arch dude|Arch dude]] ([[User talk:Arch dude|talk]]) 01:28, 3 June 2009 (UTC)
:: It's not until para 2 that he starts talking about any human characters, and not until para 4 that he invokes the first person.
:: That's as much as I know. But I find it hard to believe he'd just make up a detail and put it in such a prominent place if it could so easily be debunked if it were not true. -- [[User:JackofOz|<span style="font-family: Papyrus;">Jack of Oz</span>]] [[User talk:JackofOz#top|<span style="font-size:85%; font-family: Verdana;"><sup>[pleasantries]</sup></span>]] 02:39, 20 December 2024 (UTC)
:::I wonder how they would measure the migratory path of maggots within a sealed coffin. ←[[User:Baseball Bugs|Baseball Bugs]] <sup>''[[User talk:Baseball Bugs|What's up, Doc?]]''</sup> [[Special:Contributions/Baseball_Bugs|carrots]]→ 02:51, 20 December 2024 (UTC)
:::: The context of the novel is about finding decaying corpses that have been dumped in a forest. No coffins involved. -- [[User:JackofOz|<span style="font-family: Papyrus;">Jack of Oz</span>]] [[User talk:JackofOz#top|<span style="font-size:85%; font-family: Verdana;"><sup>[pleasantries]</sup></span>]] 06:08, 20 December 2024 (UTC)
::::::[[User:Baseball Bugs|Baseball Bugs]], see also [[body farm]] research facilities. [[User:Alansplodge|Alansplodge]] ([[User talk:Alansplodge|talk]]) 13:44, 20 December 2024 (UTC)
:::::Could it be that the larvae are setting off in search of another corpse? The prevailing wind in the UK is from the south-west, so by heading into the wind they won't be distracted by the frangrance of the one they've just left. [[User:Shantavira|Shantavira]]|[[User talk:Shantavira|<sup>feed me</sup>]] 09:30, 20 December 2024 (UTC)


If you can, have a look at 'Heinrich, Bernd. “Coordinated Mass Movements of Blow Fly Larvae (Diptera: Calliphoridae).” Northeastern Naturalist, vol. 20, no. 4, 2013, pp. N23–27. JSTOR, http://www.jstor.org/stable/43288173.' Here are some extracts
:::Just one more quick question:
* On the fourth day, after a cooling night with dew on the grass, a stream of tens of thousands of larvae exited from beneath the carcass within 1 h after sunrise, and proceeded in a single 1-2-cm-wide column directly toward the rising sun...
http://spiff.rit.edu/classes/phys314/images/mm/mm3_rot.jpg
* However, in this case, the larvae left at night, within 1 h after a cloudburst (at 21 :00 hours). But, unlike before, this nocturnal larval exodus in the rain was diffuse; thousands of larvae spread out in virtually all directions over an 8 m2area. Apparently, the sudden moisture had cued and facilitated the mass exodus, but the absence of sun had prevented a unidirectional, en masse movement.
On pg. 336 it says (little below the middle), that if the whole apparatus is turned through 90 degrees the fringe shift would double. Why? <span style="font-size: smaller;" class="autosigned">—Preceding [[Wikipedia:Signatures|unsigned]] comment added by [[Special:Contributions/24.171.145.63|24.171.145.63]] ([[User talk:24.171.145.63|talk]]) 04:34, 3 June 2009 (UTC)</span><!-- Template:UnsignedIP --> <!--Autosigned by SineBot-->
* However, on the following morning as the sun was starting to illuminate the carcass on the dewy grass, masses of larvae gathered at the east end of the carcass at 07:00 hours. In one half hour later, they started streaming in a column directly (within one degree) toward the rising sun, and the carcass was then nearly vacated.
::::That's what would happen if the speed of light *did* depend on motion through the "[[luminiferous aether]]". In actual fact, it doesn't, so there is no change. --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 14:56, 3 June 2009 (UTC)
It goes on. Maggot migration appears to be a bit more complicated than the novel suggests. [[User:Sean.hoyland|Sean.hoyland]] ([[User talk:Sean.hoyland|talk]]) 09:39, 20 December 2024 (UTC)
I suppose you could try to address it from the other direction and look at the technology your average maggot has access to in terms of light detection, heat detection, olfactory systems, orientation in magnetic fields (like many arthropods) etc. They presumably have quite a lot of tools. [[User:Sean.hoyland|Sean.hoyland]] ([[User talk:Sean.hoyland|talk]]) 10:13, 20 December 2024 (UTC)


:If orderly migrating maggots tend to move towards the sun, they should display a northward tendency in Oztralia. &nbsp;--[[User talk:Lambiam#top|Lambiam]] 10:31, 20 December 2024 (UTC)
== Smallest number of neutrons ==
:: Maybe, but the novel is set in England.
:: I must say, as soon as I read the quoted para for the first time, my immediate thought was that it might have something to do with the magnetic field of the earth. -- [[User:JackofOz|<span style="font-family: Papyrus;">Jack of Oz</span>]] [[User talk:JackofOz#top|<span style="font-size:85%; font-family: Verdana;"><sup>[pleasantries]</sup></span>]] 10:42, 20 December 2024 (UTC)
:::Prime suspect might be the Bolwig organ, the photoreceptor cluster many fly larvae have. [[User:Sean.hoyland|Sean.hoyland]] ([[User talk:Sean.hoyland|talk]]) 10:49, 20 December 2024 (UTC)
:::Obviously, Jack, you need to create a corpse, place it in a nearby forest, and carefully observe which way the maggots go. For Science! And Literary Criticism! {The poster formerly known as 87.81.230.195} [[Special:Contributions/94.1.223.204|94.1.223.204]] ([[User talk:94.1.223.204|talk]]) 21:01, 20 December 2024 (UTC)


= December 20 =
What is the smallest number of neutrons to start the formation of a Black Hole?


== Winter solstice and time of sunrise? ==
--<small>--<font face="rage italic" size="4.5" color="LightSteelBlue"> [[User:taxa|Taxa]]</font> ([[User talk:taxa|talk]])</small> 01:04, 3 June 2009 (UTC)


How is it that despite December 21st supposedly being the shortest day of the year, sunrise here happens later and later until December 26 and only on January 05 starts to turn around to occur earlier and earlier. On December 25 it takes place at about 08:44, between December 26 and January 04 it takes place at about 08:45, and on January 05 it takes place again at about 08:44. (Google rounds out the seconds). Is it Google's fault? Is it everywhere the same? Confused in Brussels, Belgium. [[Special:Contributions/178.51.16.158|178.51.16.158]] ([[User talk:178.51.16.158|talk]]) 12:06, 20 December 2024 (UTC)
:Neutrons do not form black holes. Generally, they are formed by collapsed stars, as such they are called [[Stellar black hole]]s (there are other types of [[black hole]]s, but when most people talk about black holes, they mean stellar black holes). According to our article, which I link, there are several factors besides the mass of a star which will lead to it forming a black hole, but the threshold limit seems to be roughly 20 solar masses. That is, stars which are larger than 20x the size of our sun will generally form black holes upon their death, while stars smaller than that will not. --[[User:Jayron32|Jayron32]].[[User talk:Jayron32|<small>talk</small>]].[[Special:Contributions/Jayron32|<small>contribs</small>]] 02:57, 3 June 2009 (UTC)
:The pertinent article is [[Analemma]], start with the section [[Analemma#Earliest_and_latest_sunrise_and_sunset|Earliest and latest sunrise and sunset]]. The details are not that simple to understand, but it's basically due to the ellipticity of Earth's orbit and its axial tilt. --[[User:Wrongfilter|Wrongfilter]] ([[User talk:Wrongfilter|talk]]) 12:22, 20 December 2024 (UTC)
::Also note that sunset begins to be later on 22 December so that the time between sunrise and sunset is a few seconds longer than on 21 December (3 seconds longer on 22/12/24 in Brussels according to [https://www.timeanddate.com/sun/belgium/brussels this]). [[User:Alansplodge|Alansplodge]] ([[User talk:Alansplodge|talk]]) 13:33, 20 December 2024 (UTC)
::Also see [[Equation of time#Major components]]. The obliquity of the ecliptic (that is, the Earth's axial tilt) is the main component and hardest to understand. But the idea is that the time when the Sun is exactly south (that is, the true noon) moves some minutes back and forth throughout the year and it moves quite rapidly to later times in late December. [[User:PiusImpavidus|PiusImpavidus]] ([[User talk:PiusImpavidus|talk]]) 19:05, 20 December 2024 (UTC)
:By the way is there a chart somewhere of the date of earliest/latest sunrise/sunset by latitude? [[User:Tamfang|—Tamfang]] ([[User talk:Tamfang|talk]]) 21:45, 29 December 2024 (UTC)
::Discussed at [[Wikipedia:Reference desk/Archives/Science/2024 August 9#Total daytime per latitude]]. [[Special:Contributions/2A02:C7C:F33B:4100:909B:C596:FD17:F530|2A02:C7C:F33B:4100:909B:C596:FD17:F530]] ([[User talk:2A02:C7C:F33B:4100:909B:C596:FD17:F530|talk]]) 13:42, 30 December 2024 (UTC)


== Three unit questions ==
::Neutrons typically form [[neutron star]]s, which can not collapse to small enough size to form a black hole. This is because the Pauli Exclusion Principle forbids two neutrons from occupying the same spatial location with the same quantum state. This quantum-mechanical explanation can be "summarized": even though they have no ''electric charge'', neutrons will repel each other if they get squished close enough together via a repulsive nuclear "force" (in truth, this is not a repulsive force because it can't be written as the gradient of an energy potential, which is why the quantum mechanical explanation is "better", but you can sort of conceptualize the idea). <strike>Neutrons</strike>Pure neutrons can't get close enough together for gravity to dominate (which is required for black hole formation) - they must start off with other particle types present, or accrete extra mass in order to form a black hole. [[User:Nimur|Nimur]] ([[User talk:Nimur|talk]]) 04:02, 3 June 2009 (UTC)


# Why territorial waters are defined by nautical miles instead of kilometers?
:::Actually the [[degeneracy pressure]] can be expressed as a gradient of a potential in the mesoscopic limit. It's still not a force in the everyday understanding of the word as applied to isolated nucleons, but the potential formulation is plenty useful. For example, the [[Tolman–Oppenheimer–Volkoff limit]] describes the point at which degeneracy pressure is no longer able to counter gravity and a neutron star would inevitably become a black hole. According to the article it is between 1.5 and 3 solar masses (with uncertainties due to limited understanding of the behavior of nuclear matter at extreme density). So a neutron star can have at most something less than 3 solar masses, which translates to ~4{{e|57}} neutrons. [[User:Dragons flight|Dragons flight]] ([[User talk:Dragons flight|talk]]) 04:30, 3 June 2009 (UTC)
# Why GDP is usually measured in US dollars rather than euros? Euro would be better because it is not tied into any country.
# Are there any laws in United States that are defined by metric units?
--[[User:40bus|40bus]] ([[User talk:40bus|talk]]) 23:30, 20 December 2024 (UTC)
:#There were nautical miles in use before there were kilometers.
:#There were US dollars in use before there were Euros.
:#Yes.
:The questions all reduce to Why can't millions of people make a change of historically widely accepted units that continue to serve their purpose, and convert to different units that would have no substantive difference, because someone has an opinion. [[User:Philvoids|Philvoids]] ([[User talk:Philvoids|talk]]) 00:52, 21 December 2024 (UTC)
::Do any people use metric units in marine and air navigation like "The ship is 10 kilometers from the port", "The plane is 10 kilometers from the destination? And is there any European country with metric flight levels? --[[User:40bus|40bus]] ([[User talk:40bus|talk]]) 07:22, 21 December 2024 (UTC)
:::Inland shipping (rivers, canals and lakes) in Europe (except the UK) is fully metric. Ships going for example [[Tilbury]] – [[Duisburg]] may have to switch units along the way. Gliders and ultralight aircraft in Europe often use metric instruments and airport dimensions are also metric (including runway length). Countries are free to define their territorial waters in whatever way they deem fit, so with nautical miles having no legal status in a fully metric country, they may define their territorial waters as extending 22224 metres. [[User:PiusImpavidus|PiusImpavidus]] ([[User talk:PiusImpavidus|talk]]) 11:23, 21 December 2024 (UTC)
::::Our [[nautical mile]] article says: {{xt|"In 1929 the international nautical mile was defined by the First International Extraordinary Hydrographic Conference in Monaco as exactly 1,852 metres (which is 6,076.12 ft). The United States did not adopt the international nautical mile until 1954. Britain adopted it in 1970..."}}
::As the US customary units are actually defined in terms that relate them to metric units, any US law based on measurements is technically defined by metric units.--[[User:Khajidha]] ([[User talk:Khajidha|talk]]) ([[Special:Contributions/Khajidha|contributions]]) 01:55, 21 December 2024 (UTC)
:::The US dollar has been the world's dominant [[reserve currency]] for about 75 years. As for the metric system in the US, it is standard in scientific, medical, electronics, auto manufacturing and other highly technical industries. By law, all packaged foods and beverages have metric quantities as well as customary quantities. See [[Metrication in the United States]]. [[User:Cullen328|Cullen328]] ([[User talk:Cullen328|talk]]) 02:28, 21 December 2024 (UTC)
The Wikipaedia article on the Nautical Mile talks about how the term originated, it was originally defined in terms of latitude not as a number of meters [[Special:Contributions/114.75.48.128|114.75.48.128]] ([[User talk:114.75.48.128|talk]]) 10:03, 24 December 2024 (UTC)


The euro is tied to multiple specific countries is it not? If you use euros you're just changing from one "dependency" to a "dependency" on the [[eurozone]] countries. A statement of the problem or problems intended to be addressed would be useful. Currency values are interconvertible in any case. Economics does sometimes use the "[[international dollar]]" for certain things, which is intended to adjust for differences in [[purchasing power]] between countries and over time. But since it's not an actual "real" currency it's not something one can easily "visualize" in their heads, which is likely why it's not used more. --[[User:Slowking Man|Slowking Man]] ([[User talk:Slowking Man|talk]]) 05:41, 26 December 2024 (UTC)
::::Of course all this applies for a neutron star under only gravitational contraction. If some other force compresses it, it should be able to go black earlier. Romulan force fields come to mind, but more realistically: What if two minimum mass neutron star smash into each other? [[Gamma ray burst]]? --[[User:Stephan Schulz|Stephan Schulz]] ([[User talk:Stephan Schulz|talk]]) 13:19, 3 June 2009 (UTC)
[[Eurostat]], the official source of European Union data, uses euros, not dollars, to measure the economy. See [[https://ec.europa.eu/eurostat/cache/metadata/en/na10_esms.htm]]?[[User:DOR (HK)|DOR (ex-HK)]] ([[User talk:DOR (HK)|talk]]) 01:27, 1 January 2025 (UTC)


[[Eurostat]], the official source of European Union data, uses euros, not dollars, to measure the economy. See [[https://ec.europa.eu/eurostat/cache/metadata/en/na10_esms.htm]]?[[User:DOR (HK)|DOR (ex-HK)]] ([[User talk:DOR (HK)|talk]]) 01:27, 1 January 2025 (UTC)
:If you're asking how big a neutron star has to be before its gravitational force is too large for it to keep form collapsing into a black hole, I have no idea. If you're asking for the smallest number required for a black hole to be physically possible, regardless of what forces them together, the answer is a [[Planck mass]] divided by the mass of a [[proton]] which is 2.1764411×10<sup>-8</sup> kg / 1.672621637×10<sup>−27</sup> kg = 3.6403606×10<sup>19</sup> neutrons. I think it's actually somewhat less than that, as the energy required to force the neutrons together would raise the mass. Also, the black hole would evaporate almost instantly. — [[User:DanielLC|DanielLC]] 21:45, 3 June 2009 (UTC)
::{{small|The user doubled-down on the response. ←[[User:Baseball Bugs|Baseball Bugs]] <sup>''[[User talk:Baseball Bugs|What's up, Doc?]]''</sup> [[Special:Contributions/Baseball_Bugs|carrots]]→ 01:32, 1 January 2025 (UTC)}}
::Why does a black hole need to be at least the Planck mass? I believe a smaller black hole would have a Schwarschild radius of less than the Planck length, which is a somewhat meaningless concept, but does that mean the black hole can't exist, rather than just that our theory of black holes breaks down? --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 22:03, 3 June 2009 (UTC)


= December 24 =
:::The latter. We don't have an accepted theory that can understand gravity at such small scales, so whether a black hole could have less than a Planck mass of material or be less than a Planck length in size is unknown. General relativity would no longer be an adequate theory to describe such objects. [[User:Dragons flight|Dragons flight]] ([[User talk:Dragons flight|talk]]) 08:28, 4 June 2009 (UTC)


== Unknown species of insect ==
::::But could you (hypothetically) take a single neutron and accelerate it until its mass exceeded the Planck mass, thus creating a black hole from one neutron (plus a lot of energy) ? [[User:Gandalf61|Gandalf61]] ([[User talk:Gandalf61|talk]]) 15:59, 4 June 2009 (UTC)


Am I correct in inferring that [[File:Anomala orientalis on window screen.jpg|150px]] this guy is an [[oriental beetle]]? I was off-put by the green head at first, but the antennae seem to match. '''[[User:JayCubby|<span style="background:#0a0e33;color:white;padding:2px;">Jay</span>]][[User talk:JayCubby|<span style="background:#1a237e;color:white;padding:2px;">Cubby</span>]]''' 03:00, 24 December 2024 (UTC)
::::: The energy used to accelerate a particle does not help creating a black whole, after all there will always be a coordinate system in which the particle is at rest. [[User:Dauto|Dauto]] ([[User talk:Dauto|talk]]) 18:18, 4 June 2009 (UTC)


(reference: https://www.genesdigest.com/macro/image.php?imageid=168&apage=0&ipage=1)
::::::Okay, how about colliding two neutrons travelling in opposite directions at near light speed - maybe in a galaxy-sized [[Large Hadron Collider|LHC]] ? Could that (hypothetically) generate a high enough energy density to create a quantum black hole ? [[User:Gandalf61|Gandalf61]] ([[User talk:Gandalf61|talk]]) 12:45, 5 June 2009 (UTC)


:<s>It looks like one of the invasive [[Japanese beetle]]s that happens to like my blackberries in the summer.</s> [[User:Modocc|Modocc]] ([[User talk:Modocc|talk]]) 13:11, 24 December 2024 (UTC)
:I think the problem lies in the definition of what a "black hole" is. A single point-sized particle (a neutron, for example) is a black hole according to some definitions. (Mathematically, there is some distance that lies outside the (zero) size of the particle at which it's gravity becomes so strong that light cannot escape.) Does that make it a black hole? Well, maybe, maybe not. You certainly can't get close enough to a neutron to be 'sucked in' as you would with a black hole created by a collapsing star. I think the problem here is not what nature does or does not do - but merely that we've decided to attach a name to a somewhat flawed definition. [[User:SteveBaker|SteveBaker]] ([[User talk:SteveBaker|talk]]) 17:26, 4 June 2009 (UTC)


::I would say not necessarily a Japanese beetle, but almost certainly one of the other [[Scarabaeidae|Scarab]] beetles, though with 35,000 species that doesn't help a lot. Looking at the infobox illustration in that article, 16. & 17., "[[Anisoplia segetum]]" looks very similar, but evidently we either don't have an article or (if our [[Anisoplia]] article is a complete list) it's been renamed. {The poster formerly known as 87.81.230.195} [[Special:Contributions/94.1.223.204|94.1.223.204]] ([[User talk:94.1.223.204|talk]]) 14:18, 24 December 2024 (UTC)
:: If a neutron is a black whole, than the [[no hair theorem]] is not valid. [[User:Dauto|Dauto]] ([[User talk:Dauto|talk]]) 18:18, 4 June 2009 (UTC)


:::Yes, it's not the Japanese beetle for this beetle appears to lack its white-dotted fringe although its condition is deteriorated. Its shape is also more or less more slender; and not as round. [[User:Modocc|Modocc]] ([[User talk:Modocc|talk]]) 15:02, 24 December 2024 (UTC)
== How to cure fungal plant pathogens ==
[[Image:Mango Tree with Leaf Spots.jpg|right|thumb|My Mango tree with leaf spots.]]
My Mango tree has some kind of fungus which is causing it's leafs to produce spots. I think it might be [[Cercospora capsici]] but I am not sure since there are many different kinds of plant fungus that might have similar outcomes.


:Perhaps it is the [[shining leaf chafer]] [[Strigoderma pimalis]]. Shown [https://bugguide.net/node/view/224249 here]. [[User:Modocc|Modocc]] ([[User talk:Modocc|talk]]) 16:09, 24 December 2024 (UTC)
I would like to know what I can do to get rid of the infestation and also how I can prevent it in the future. I have added a photo of the actual plant in question to better illustrate the problem. [[User:Zoohouse|Joel M.]] ([[User talk:Zoohouse|talk]]) 02:46, 3 June 2009 (UTC)
::That looks like easily the best match I've seen so far, and likely correct. {The poster formerly known as 87.81.230.195} [[Special:Contributions/94.1.223.204|94.1.223.204]] ([[User talk:94.1.223.204|talk]]) 17:09, 24 December 2024 (UTC)


= December 25 =
:Sorry for the lack of responses - have you tried contacting a "master gardener"? Where I live, the local university seems to loan them out to public places like shopping malls and tree nurseries, where they run a (physical) reference desk of their own for a few hours a weekend. (Photo moved) [[User:Tempshill|Tempshill]] ([[User talk:Tempshill|talk]]) 20:30, 3 June 2009 (UTC)


== Mass of oscillating neutrino ==
::[[Fungicide]] has a couple of natural things you can try that aren't that difficult to find. (If you can't find them at your local grocery store, health food store, drug store or pharmacy, try ordering online) I'm not sure how specific you'll have to target your fungus. Most fungicides seem to be pretty broad spectrum.[[Special:Contributions/71.236.26.74|71.236.26.74]] ([[User talk:71.236.26.74|talk]]) 15:22, 4 June 2009 (UTC)


From the [[Mass in special relativity|conservation of energy and momentum]] it follows that a particle that is not subject to external forces must have constancy of mass.
== Understanding another part of the MM experiment ==


If I am right, this means that the mass of the neutrino cannot change during the [[neutrino oscillation]], although its flavoring may. Is this written down somewhere? Thank you. [[User:Hevesli|Hevesli]] ([[User talk:Hevesli|talk]]) 19:24, 25 December 2024 (UTC)
:Any (flavored) neutrino that is really observed is a superposition of two or three mass eigenstates. This is actually the cause of [[neutrino oscillations]]. So, the answer to your question is complicated. [[User:Ruslik0|Ruslik]]_[[User Talk:Ruslik0|<span style="color:red">Zero</span>]] 19:40, 25 December 2024 (UTC)
:Important note: particle physicists today generally only ever use "mass" to mean "[[invariant mass]]" and never anything else: [https://profmattstrassler.com/articles-and-posts/particle-physics-basics/mass-energy-matter-etc/more-on-mass/the-two-definitions-of-mass-and-why-i-use-only-one/]. Like the term says, invariant mass is well, invariant, it never changes ever, no matter what "external forces" may or may not be involved. Being proper particle-icans and following the standard practice in the field, then, the three neutrino masses are constant values. ..."Wait, three?" Yeah sure, turns out [[neutrino flavor|neutrinos come in three "flavors" but each flavor is a mixture of the three possible mass "states"]]. As mentioned, due to Quantum Weirdness we aren't able to get these different states "alone by themselves" to measure each by itself, so we only know the differences of the squares of the masses. Yeah welcome to quantum mechanics.
:[[Richard Feynman]]: "Quantum mechanics describes nature as absurd from the point of view of common sense. And yet it fully agrees with experiment. So I hope you can accept nature as She is {{snd}} absurd." --[[User:Slowking Man|Slowking Man]] ([[User talk:Slowking Man|talk]]) 06:06, 26 December 2024 (UTC)
::The equation <math>E^2 = (p c)^2 + \left(m_0 c^2\right)^2</math> uses invariant mass {{math|''m''<sub>0</sub>}} which is constant if {{math|''E''}} and {{math|''p''}} are constant. The traveling neutrino has a varying mass mixture of different flavors with different masses. If a mixture of different masses changes, you would expect the resulting mass to change with it. But somehow this does not happen as the neutrino mass mixture changes. These mixture changes cannot be any changes. The changes must be such that the resulting mass of the traveling neutrino remains constant. My question is whether this is described somewhere. [[User:Hevesli|Hevesli]] ([[User talk:Hevesli|talk]]) 11:16, 26 December 2024 (UTC)
:::I freely confess I'm uncertain exactly what's being "asked for" or "gotten at" here. Have you looked at the [[neutrino oscillation]] article? From it: {{tpq|That is, the three neutrino states that interact with the charged leptons in [[weak interaction]]s are each a different [[superposition]] of the three (propagating) neutrino states of definite mass. Neutrinos are emitted and absorbed in weak processes in flavor [[eigenstate]]s[a] '''but travel as mass eigenstates.'''[18]}}
:::What is it that we're "doing" with the [[energy–momentum relation]] here? For the neutrino, we don't have a single value of "mass" to plug in for <math>m_0</math>, because we can't "see" the individual mass eigenstates, only some [[linear combination]] of them. What you want for describing neutrino interactions is [[quantum field theory]], which is special relativity + QM. (Remember, relativity is a "classical" theory, which presumes everything always has single well-defined values of everything. Which isn't true in quantum-world.) --[[User:Slowking Man|Slowking Man]] ([[User talk:Slowking Man|talk]]) 18:41, 26 December 2024 (UTC)
::::Not all potential evolutions of a linear combination of unequal values produce constant results. Constancy can only be guaranteed by a constraint on the evolutions. Does the fact that this constraint is satisfied in the case of neutrino oscillation follow from the [[mathematical formulation of the Standard Model]], or does this formulation allow evolutions of the mass mixture for which the combination is not constant? If the unequal values are unknown, I have no idea of how such a constraint might be formulated. I think the OP is asking whether this constraint is described somewhere. &nbsp;--[[User talk:Lambiam#top|Lambiam]] 00:51, 27 December 2024 (UTC)


Scrap my old questions; I get them now. Anyway- I hope this doesn't go against your reference desk policy since this isn't homework that I'm not trying on. [http://spiff.rit.edu/classes/phys314/refs/mm.html here] on page 340, first line, it says something along the lines of the width of the fringes varied from 40-60 divisions (im interpreting it to mean there were between 40 and 60 fringes). It than says the average is 50 and says one division means.02 wavelength. Where did this last statement come from?


= December 27 =
: One divided by 50 is 0.02. They are taking the reciprocal. The "divisions" are not number of fringes - it's the width of each fringe, measured in "Divisions of the screw head" instead of "millimeters" or "centimeters". I don't know why they use such arbitrary units - it's just like the number of marks on a ruler or optical viewer or other measurement device, and needs some conversion to standard units. [[User:Nimur|Nimur]] ([[User talk:Nimur|talk]]) 15:55, 3 June 2009 (UTC)


== Low-intensity exercise ==
== Lens and mirror placed in water ==


If you exercise at a low intensity for an extended period of time, does the [[runner's high]] still occur if you do it for long enough? Or does it only occur above a certain threshold intensity of exercise? [[Special:Contributions/2601:646:8082:BA0:CDFF:17F5:371:402F|2601:646:8082:BA0:CDFF:17F5:371:402F]] ([[User talk:2601:646:8082:BA0:CDFF:17F5:371:402F|talk]]) 20:13, 27 December 2024 (UTC)
We have been given following question in summer assignment:-<br />
:Hows about you try it and report back? :) ←[[User:Baseball Bugs|Baseball Bugs]] <sup>''[[User talk:Baseball Bugs|What's up, Doc?]]''</sup> [[Special:Contributions/Baseball_Bugs|carrots]]→ 21:31, 27 December 2024 (UTC)
"A concave mirror and a convex lens are placed in water. What change, if any, do you expect in their focal length"<br />Since f = 1/R and curvature of lens and mirror won't change if placed in water, am I correct in assuming that focal length won't change? --shanu 05:36, 3 June 2009 (UTC)
::I wanted to try it just today, but I had to exchange the under-desk [[elliptical trainer]] I got for Christmas for a different model with more inclined treadles because with the one I got, my knees would hit the desk at the top of every cycle. Anyway, I was hoping someone else tried it first (preferably as part of a formal scientific study) so I would know if I could control whether I got a runner's high from exercise or not? [[Special:Contributions/2601:646:8082:BA0:9052:E6AF:23C7:7CAF|2601:646:8082:BA0:9052:E6AF:23C7:7CAF]] ([[User talk:2601:646:8082:BA0:9052:E6AF:23C7:7CAF|talk]]) 03:09, 28 December 2024 (UTC)
:For a reflective system, the main concern is the geometry of the surface; but for a refractive system, I think you need to consider the [[refractive index]] when calculating the [[focal length]]. [[User:DMacks|DMacks]] ([[User talk:DMacks|talk]]) 05:51, 3 June 2009 (UTC)
Also, sorry for adding to my own question, but here's a related one: is it known whether the length of a person's [[dopamine receptor D4]] (which is inversely correlated with its sensitivity) influences whether said person gets a runner's high from exercise (and especially from low-intensity exercise)? [[Special:Contributions/2601:646:8082:BA0:9052:E6AF:23C7:7CAF|2601:646:8082:BA0:9052:E6AF:23C7:7CAF]] ([[User talk:2601:646:8082:BA0:9052:E6AF:23C7:7CAF|talk]]) 03:14, 28 December 2024 (UTC)


== [[fastidious organism]] vs [[auxotroph]] ==
::Take a look art the articles on [[mirror]] and [[refraction]]. A key point in the mirror article is that "a beam of light reflects off a mirror at an angle of reflection that is equal to its angle of incidence." A key point in the refraction article is "refraction occurs when light waves travel from a medium with a given [[refractive index]] to a medium with another." You may need to read more of the refraction article to better understand what this saying. Once you have a better understanding of the two principles, you can revisit the question of what effect water immersion has. A couple of related questions that may test your understanding: (1) When swimming, if you open your eyes underwater, can you see as well as above water? Why? (2) If you wear goggles or a face mask, does this change your vision? Why? (Hint: What shape is the outer surface of the face mask?). Feel free to ask follow-up questions after you've had a look. -- [[User:Tcncv|Tcncv]] ([[User talk:Tcncv|talk]]) 06:00, 3 June 2009 (UTC)
:::The question is discussed [http://www.physicsforums.com/showthread.php?t=56042 here]. [[User:Cuddlyable3|Cuddlyable3]] ([[User talk:Cuddlyable3|talk]]) 09:14, 3 June 2009 (UTC)
::::The key here is in the precise definition of ''refractive index''. Since this is borderline homework - I'll point you to the "Definition" section of [[Refractive index]] - read it carefully. [[User:SteveBaker|SteveBaker]] ([[User talk:SteveBaker|talk]]) 12:35, 3 June 2009 (UTC)
Thanks for your help. By the way does it also mean that R = 2f won't work for lens in water? And also since thin lens formula will change, microscopes will be affected when placed in water.--shanu 05:21, 4 June 2009 (UTC) <small><span class="autosigned">—Preceding [[Wikipedia:Signatures|unsigned]] comment added by [[User:Rohit..god does not exist|Rohit..god does not exist]] ([[User talk:Rohit..god does not exist|talk]] • [[Special:Contributions/Rohit..god does not exist|contribs]]) </span></small><!-- Template:Unsigned --> <!--Autosigned by SineBot-->

:[[Lens (optics)#Lensmaker's equation|That]] should also help. [[User:Dauto|Dauto]] ([[User talk:Dauto|talk]]) 15:36, 3 June 2009 (UTC)
::Thanks for your help. By the way does it also mean that R = 2f won't work for lens in water? And also since thin lens formula will change, microscopes will be affected when placed in water.--shanu 05:23, 4 June 2009 (UTC) <small><span class="autosigned">—Preceding [[Wikipedia:Signatures|unsigned]] comment added by [[User:Rohit..god does not exist|Rohit..god does not exist]] ([[User talk:Rohit..god does not exist|talk]] • [[Special:Contributions/Rohit..god does not exist|contribs]]) </span></small><!-- Template:Unsigned --> <!--Autosigned by SineBot-->
:For an importatn application, see [[Immersion lithography]].-[[User:Arch dude|Arch dude]] ([[User talk:Arch dude|talk]]) 08:11, 4 June 2009 (UTC)

== Sperm Count ==

Good day,

I was wondering - what is the time frame for the sperm count to reach its maximum ounce the person has ejaculated ? ( how long will it take from a count of 0 to reach 20 000 000)

Thank you

Marcello <small><span class="autosigned">—Preceding [[Wikipedia:Signatures|unsigned]] comment added by [[User:Saladza|Saladza]] ([[User talk:Saladza|talk]] • [[Special:Contributions/Saladza|contribs]]) 07:21, 3 June 2009 (UTC)</span></small><!-- Template:Unsigned --> <!--Autosigned by SineBot-->
:If I understand your question correctly, I do not believe it's normal for the sperm count to reach zero even after multiple ejaculations in a short space of time. If a sperm count is zero, that would likely indicate fertility problems like [[azoospermia]] or perhaps that the person has had a vasectomy. In fact according to our article "How long the man has abstained prior to providing the sample for analysis affects the results. Longer periods of abstinence correlate with poorer results - one study found that men with repeated normal results produced abnormal samples if they abstained for more than 10 days. It is recommended not to abstain for more than one or two days before providing the semen sample for analysis" although it's not clear if this includes sperm count or other factors like motility and morphology. Note that [[sperm count]]s are only really meaningful in when measuring them from [[ejaculation]]s. [[User:Nil Einne|Nil Einne]] ([[User talk:Nil Einne|talk]]) 07:45, 3 June 2009 (UTC)

== Three Step Process Of Lethal Injection ==

Why is it that we have a three step process for lethal injection, while pets only have one simple injection when they are getting put down? Wouldn't it be better just to use the one? It'd be cheaper and wouldn't last as long, and there have been no known accounts of pets still being alive and conscious yet paralysed when the final injection stops the heart and collapses the lungs (obviously because there is only one injection that kills them outright). Why not just do it like that? --[[User:KageTora|KageTora - (영호 (影虎))]] ([[User talk:KageTora|talk]]) 10:52, 3 June 2009 (UTC)

: You are evidently talking about the US procedure. There has been much debate about this - our article [[Lethal injection]] covers this in some detail. The idea is to use the first shot to briefly aneasthetise the victim - the second to relax the muscles so there is no embarrassing thrashing around - and the third to stop the heart. There is much controversy over this because there is a belief that the first injection might not work - or might not work for more than a couple of seconds - resulting in the victim being conscious but unable to move or speak (because of the muscle relaxant) while a painful heart attack ensues from the third injection...also the possibility of surviving the heart attack and then slowly suffocating while the muscle relaxant prevents breathing. For smaller animals (cats, dogs, etc) a single massive shot of barbiturates causes unconsciousness and then both heart stopping and a cessation of breathing in about 30 seconds. The problem is (as our [[Animal euthanasia]] article indicates), this doesn't work well on large animals because the barbiturate dose required is too high. I can only presume that humans fall into the "large animals" category...hence the controversial three-step process. [[User:SteveBaker|SteveBaker]] ([[User talk:SteveBaker|talk]]) 12:29, 3 June 2009 (UTC)
:::*Please avoid attempting a debate here by using loaded words like "victim". --Anonymous, 03:45 UTC, June 4, 2009.
:::::Please avoid being uneducated in the use of the English language...pick up a dictionary sometime. From Wiktionary, meaning (2) for the word "victim" is: "Anyone who is physically harmed by another."...being killed by the state executioner certainly counts as being "physically harmed". I chose that word with great care. I you choose to pick a different, and perhaps more 'loaded' meaning - that's a debate of your own making! [[User:SteveBaker|SteveBaker]] ([[User talk:SteveBaker|talk]]) 15:39, 4 June 2009 (UTC)
::::::[[Wikipedia talk:Reference desk#"Using loaded words"|To the talk page, please]]. --Anon, 08:00 UTC, June 5, 2009.
::Also, a different ethical standard is clearly being applied to animal euthanasia than to human euthanasia (which is used more sparingly). It seems to follow that the procedures would reflect that difference in ethical concerns. [[User:Nimur|Nimur]] ([[User talk:Nimur|talk]]) 16:00, 3 June 2009 (UTC)

:::Having used barbiturates to anesthetize animals for surgery, I can tell you that they are pretty tricky. Even huge doses with small animals don't lead to quick death with 100% reliability -- once in a hundred times the animal continues to breathe at a very slow rate for quite a while. Barbiturates don't actually stop the heart, by the way -- so suppression of breathing is the way they kill. [[User:Looie496|Looie496]] ([[User talk:Looie496|talk]]) 18:45, 3 June 2009 (UTC)
::::[[Animal euthanasia]] says there is cardiac arrest - is it incorrect? [[User:SteveBaker|SteveBaker]] ([[User talk:SteveBaker|talk]]) 20:03, 3 June 2009 (UTC)

== Pushing a helicopter ==

Suppose there's a helicopter (something small like a [[Bell 206]], not a [[CH-47 Chinook|Chinook]]) hovering a few feet off the ground. Would it be possible for a human standing on the ground to push/pull the helicopter enough to move it, in any direction, without the aid of any other equipment? — [[User:Bewildebeast|Matt Eason]] <sup>([[User talk:Bewildebeast|Talk]] &#149; [[Special:Contributions/Bewildebeast|Contribs]])</sup> 11:06, 3 June 2009 (UTC)

: Well, there is no friction and very little air resistance involved - so all you've got to do is overcome the inertia - which is considerable. The classic [[Bell 212]] helicopter weighs in at 3000 to 5000kg depending on fuel and passenger load (actually, technically, what we care about here is the ''mass'' not the weight - but it's still 3000 to 5000kg) so it would take quite a bit of effort to get it moving at any kind of speed - and quite a bit more to stop it: Force = Mass x Acceleration - so with a normal kind of force and a big mass, you don't get much acceleration. However even the smallest push would impart some acceleration and if you continue to push, the speed will gradually get faster and faster until you couldn't keep up with it anymore - so technically, in the purest theoretical sense - yes, you could push the helicopter around with no particular problem.

: However, a helicopter doesn't just hover in one place passively. If the ground beneath has even a slight slope or unevenness - or there is any kind of wind - or a vertical surface is within maybe 50' in any direction - or if the helicopter isn't set up just perfectly - then without the pilot actively working to keep the helicopter still - it would drift off and spin all over the place at accelerations much greater than you could overcome with your puny muscles! So realistically, the pilot (or perhaps some autopilot hovering aid) is actively and continually making tiny adjustments to keep the helicopter still - and those adjustments would easily counter your puny efforts to move it. If he stops making the adjustments - then the helicopter is going to drift and you're not going to be able to stop it or make a significant difference.

: So I'm pretty sure that the theoretical answer is "Yes" and the practical answer is at best "No" and at worst "Not a sufficiently precise question to yield a meaningful response"! [[User:SteveBaker|SteveBaker]] ([[User talk:SteveBaker|talk]]) 12:19, 3 June 2009 (UTC)

::Very interesting - thanks Steve — [[User:Bewildebeast|Matt Eason]] <sup>([[User talk:Bewildebeast|Talk]] &#149; [[Special:Contributions/Bewildebeast|Contribs]])</sup> 12:30, 3 June 2009 (UTC)

:[http://chinadaily.com.cn/world/2007-08/30/content_6069291.htm Here] is a guy doing the fairly common stunt of pulling a train with his teeth. They claim 300 [[tonne]]s in this case, and the situation seems analogous to Steve's theoretical perfectly tuned helicopter, with far greater mass. --[[User:TotoBaggins|Sean]] 13:10, 3 June 2009 (UTC)

:The practicality of this can be changed to a similar problem: Can the kick of shooting a gun move a helicopter? Humans are capable of countering the kick of large rifles. However, it was noted during Vietnam that firing rifles that were bolted down to the helicopter would cause it to rock enough to notice. So, humans can push with more force than the kick of the rifle and the kick of the rifle is enough force to cause the helicopter to rock. So, it is feasible that a human would have enough pushing force to cause a helicopter to noticeably move. -- [[User:Kainaw|<font color='#ff0000'>k</font><font color='#cc0033'>a</font><font color='#990066'>i</font><font color='#660099'>n</font><font color='#3300cc'>a</font><font color='#0000ff'>w</font>]][[User talk:Kainaw|&trade;]] 13:54, 3 June 2009 (UTC)
::::''"Humans are capable of countering the kick of large rifles."'' But a human probably cannot counter the kick of a .50 caliber machine gun fired rapidly - it's sort of a totally different animal. Even small machine gun like a [[Squad automatic weapon]] requires a bipod or a tripod to keep it from blowing back out of control. A large gun such as a [[GAU-19]] (standard fare on a Black Hawk) is going to impart tens or hundreds of kilogram-meters per second of momentum (according to our article, 500 pounds force sustained). I doubt any human sustain such a push. [[User:Nimur|Nimur]] ([[User talk:Nimur|talk]]) 16:06, 3 June 2009 (UTC)
::There is no doubt about that. As TotoBaggins points out, humans can move trains that are far heavier than a helicopter. The only problem is the one Steve points out about the natural movement of the helicopter due to the difficulties of keeping it steady are going to be greater than the movement a human could produce. --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 15:37, 3 June 2009 (UTC)

:You would probably be pushing below the center of mass, causing the helicopter to pitch or roll a little depending on where you push. I'm not sure which net effect this would have without corrections by the helicopter. [[User:PrimeHunter|PrimeHunter]] ([[User talk:PrimeHunter|talk]]) 16:04, 3 June 2009 (UTC)
::OK - I'm going to have to explain helicopter aerodynamics...bear with me! A civilian helicopter - or a heavy-lift military one - would have rotors that bend upwards a little (it's called the "coneing angle"). If you think about the helicoptors rotors - instead of being a couple of separate blades that are sweeping around really fast - imagine them as if they made a solid disk...that's kinda what it looks like. So that when the weight of the helicopter's body is supported by the rotors - the rotor disk is pulled down into a cone (with the point of the cone pointing downwards). Now, when the helicopter rolls (or pitches) that tilts that cone - right? So one side of the rotor disk/cone is now more horizontal and the other side is more steeply tilted upwards. As the rotors travel around the surface of the cone - the one that's moving more horizontally to the ground pushes down the air directly towards the ground - getting the maximum possible upward push - but the rotor that's on the opposite side is nowhere near horizontal - its at some angle to the ground - so the air it pushes goes out at an angle. This does two things. Firstly, it means that when you push on the skids at the bottom of the helicopter - the steeper blade (which is on the far side of the helicopter) pushes the air slightly away from you - which makes the helicopter try to push back against you. But because that air isn't being pushed as hard against the ground as on the blade that's nearest to you - the far side of the helicopter loses a bit of lift - and the side that's nearest to you gains a bit...for as long as you push. This tends to make the helicopter level back out again. So the effect of this coning angle thing - is to give the aircraft some inherent stability...if you make it roll - it tries to roll back to the level position again. That's actually the only thing that makes the helicopter flyable...it would be impossible to have good enough reaction time if it didn't do that. So the fact that you are pushing below the center of gravity turns out not to matter very much! The other thing that helps with stability is that the center of gravity is about halfway up the helicopter - where the engine, gearbox and fueltank probably are. However, the lift from the rotors pulls upwards from the top of the 'mast' - so (in physics 101 terms) you have a 'moment' - you have gravity acting on the center of gravity and the lift acting on the top of the mast. So long as those two forces are in a straight line - nothing much happens. But if the helicopter rolls (or pitches) the two forces are no longer in a straight line - which imparts a rotation - which in turn tries to keep the helicopter level. It's as if the body of the chopper was a plumb-bob hanging under the rotor disk. Anyway - I didn't want to complicate the earlier discussion with all of this complicated stuff. Suffice to say - this ISN'T the reason you couldn't (in theory) push a hovering helicopter. [[User:SteveBaker|SteveBaker]] ([[User talk:SteveBaker|talk]]) 19:58, 3 June 2009 (UTC)
:::Is it possible that the "pushing back against you" bit you mention would be strong enough to actually result in the helicopter moving towards you when you pushed it away from you? That would be a rather interesting bit of trivia. --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 22:00, 3 June 2009 (UTC)
::::I don't see how. But helicopters are complicated machines - all sorts of bizarre gyroscopic effects - and the way the tail-rotor figures into things...it's tough to reason all of the forces out. [[User:SteveBaker|SteveBaker]] ([[User talk:SteveBaker|talk]]) 22:50, 3 June 2009 (UTC)

::It's irrelevant to the original question, but it might be worth noting that the effect Steve describes in relation to coning has an analog on some airplanes. Rather than both wings being in a single plane, they may be tilted slightly to form a gentle V-shape, called "dihedral", and this contributes to the airplane's stability in the same way that Steve describes. On the other hand, on fighter aircraft where a bit of instability is desired so the plane is more maneuverable, the tilt may be reversed, which is called "anhedral". See [[dihedral (aircraft)]].
::One other point. Steve mentioned the helicopter pushing the air "against the ground". Either an airplane or a helicopter makes its lift by pushing air ''toward'' the ground, i.e. down. [[Newton's third law#Newton's third law: law of reciprocal actions|Newton's third law]] and all that. However, if the vehicle is near enough the ground that the air is pushed substantially against the ground, it gets ''more'' lift, as the ground bounces it back up: see [[ground effect in aircraft]].
::--Anonymous, 04:02 UTC, June 4, 2009.

:::[[Lift_(force)#Newton.27s_laws:_Lift_and_the_deflection_of_the_flow|"… the wing keeps the airplane up by pushing the air down"]] eh? True but useless. An [[aerodynamic force]] on a body moving through a fluid is accompanied by an equal and opposite force on the fluid, but one does not "make" the other. A body which pushes air down generates lift&mdash;a body which generates lift pushes air down.&mdash;[[User:EricR|eric]] 06:43, 4 June 2009 (UTC)
:::(Actually - I said it pushes the air "towards" the ground - not "against" it - I picked my words carefully.) I assume that if you're pushing against a helicopter - that it's close enough to the ground for "ground effect" to matter. That greatly increases the amount of lift the helicopter has - but it doesn't change the 'coning angle' effect - which is indeed similar to the effect of dihedral on a fixed-wing aircraft - except that in the case of the helicopter it helps pitch stability as well as roll.
::: Eric's criticism is technically valid but I can't agree that the original statement was useless - it enabled both he and I (and hopefully, the OP) to perfectly well understand what was being described...and I think it's a clearer statement to the layman. We have to tailor our ref desk responses to a typical layperson - because we can't make assumptions about their scientific background. Saying that pushing the air down keeps the plane up is a perfectly valid statement - it merely fails to explain the REASON why pushing air down keeps the plane up. But then we also say that gasoline propels your car along the road without going into the details of the fluid dynamics, chemistry, thermodynamics and mechanics that makes that happen. Nit picking is unnecessary here - so long as the meaning is clear. 15:32, 4 June 2009 (UTC)
::::The lice were in Anonymous' hair, not yours. You were explaining dihedral, he was directly discussing lift, and based on his response i suspected did not fully understand your shorthand. Apologies if this was an incorrect assumption.&mdash;[[User:EricR|eric]] 16:23, 4 June 2009 (UTC)
:::::I think there's been some misreading here. I was the one that mentioned dihedral (for airplanes); Steve was talking about coning (of a helicopter rotor) and I pointed out, as a point of interest, that the principle can extend to airplanes. As to the other point about "against the ground", if Steve would kindly reexamine his carefully worded posting, he will find the phrase in it. --Anon, 17:17 UTC, June 4, 2009.

== Monitoring blood glucose levels ==

A friend of mine is diabetic and she usually tests herself once before a meal and two hours afterwards. I was curious why she has to wait two hours. After a meal, does blood sugar slowly climb to its maximum point after two hours? Or does it quickly surge high and then comes back to a "normal" level over a two hour period. Why not test one hour after eating? or three? --[[Special:Contributions/68.92.139.62|68.92.139.62]] ([[User talk:68.92.139.62|talk]]) 12:38, 3 June 2009 (UTC)

:It depends to some extent on what she's eating. If it is high in sugar then it will increase her blood sugar level pretty quickly. If it more complex carbohydrates, or mostly protein, say, then it takes longer to digest. You may find [[glycemic index]] interesting. --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 12:51, 3 June 2009 (UTC)

:The timing of glucose testing in [[diabetes management]] mostly has to do with the medication regimen the patient is taking. In patients who take [[insulin]], there are different formulations that have short-term (i.e. within a couple hours) and long-term (i.e. over the course of 24 hours) effects. See [[insulin therapy]] for details. Every patient will have a different regimen, depending on their own situation. One typical regimen is to take long-term insulin to maintain blood sugar throughout the day, coupled with short-term insulin doses corresponding to each meal to cope with the influx of glucose that happens after eating. The "fasting" blood test (before the meal) is meant to verify that the long-term insulin dose is correct. The 2-hour "post-prandial" blood test checks that the insulin that was taken with the meal was appropriate. You can see from the [[glycemic index]] article that in normal individuals, the blood glucose should be about back to normal by 120 minutes = 2 hours. This is the result of the [[pancreas]] releasing a burst of insulin, which is what is being simulated by the dose of insulin at mealtime. This, along with the usual time of action of the short-term insulin, is why 2 hours is a good time for a post-prandial check. Often, the patient will be given instructions about what to do if the post-prandial glucose level is too high (take some more insulin) or too low (eat something). The doctor managing the diabetes treatment will look at the test records to make sure that the dosage regimen is appropriate. --- [[User:Medical geneticist|Medical geneticist]] ([[User talk:Medical geneticist|talk]]) 13:33, 3 June 2009 (UTC)

::Very interesting. Now my friend doesn't take insulin. It's all diet controlled. --[[Special:Contributions/70.167.58.6|70.167.58.6]] ([[User talk:70.167.58.6|talk]]) 23:17, 4 June 2009 (UTC)

== Energy of a point charge ==

I have read that that the self energy of a point charge, that is, the energy required to assemble a point charge, is infinite, and i am still struggling to come to terms with it. Does it mean that there cannot exist any point charges in the universe, or does it mean that it is just an embarrassing result of classical electrodynamics? I mean, you can say even the fundamental units of charge, the electron and the proton, are not point charges, but i am asking ''in principle''. Also, we have found that even these fundamental entities are made of quarks, and quarks are made up of what not i don't know, but is there a limit? Say we somehow find the structure of a quark, and find its made up of little xions, and now we start to analyze these xions-its back to square one... is there a limit to exploring the structure of matter? And going by this notion that there can be no point charges, will we ever be able to find an end to this non stop search inside an atom ? [[User:Rkr1991|Rkr1991]] ([[User talk:Rkr1991|talk]]) 12:52, 3 June 2009 (UTC)

:The energy required to reduce the separation between two like charges increases as they get closer together. Roughly speaking, the energy for the last bit involves dividing by zero, which gives you infinity (the more precise answer involves [[improper integral]]s). We often think about fundamental particles as being point particles, but that's really just because we don't really know what they are, talking about sizes at that scale is largely meaningless because of quantum mechanical effects. So we have to make exceptions for fundamental particles, but any charge made up of more than one such particle can't have zero size. --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 14:39, 3 June 2009 (UTC)
::You can't get around this problem by supposing that point charges exist a priori, because even an always-present point charge has an electric field, and the energy in the field (½ ∫ E²) equals the energy required to assemble the point charge from infinity. The field energy shows up as inertial and gravitational mass of the particle. This is a classical result, but in quantum field theory the problem gets worse, not better. The workaround is [[renormalization]], which amounts to treating the particles as though they had a small but nonzero size, or introducing some other small-scale cutoff with a similar effect. Fortunately the predictions of the Standard Model are independent of the cutoff scale as long as it's small enough (the Standard Model is renormalizable). This is understood to mean that the Standard Model is just a large-scale approximation to the real physics, which presumably avoids the infinity in some unknown way, possibly by being discrete or (as in string theory) by distributing the charge over a 1-D structure instead of concentrating it in a point. This is a lot like the use of calculus to model systems that we know are discrete, like fluids or biological populations. -- [[User:BenRG|BenRG]] ([[User talk:BenRG|talk]]) 16:00, 3 June 2009 (UTC)
:::A finite amount of charge in a one dimensional string would also have infinite amount of energy in its field unless it was infinitely long. the idea that the mass of an electron comes from its electric field through self induction has long be abandoned. [[User:Em3ryguy|just-emery]] ([[User talk:Em3ryguy|talk]]) 20:12, 3 June 2009 (UTC)
:::BenRG, sure you must be aware that what you described (the introduction of a small arbitrary size) is not the renormalization itself but an essential housekeeping step - the [[Regularization (physics)|regularization]] - that must be taken before the renormalization proper can be performed. There are several different ways to regularize the formally divergent integrals that show up in the solutions. Not all of those regularization schemes are based in the introduction of a cutoff. The renormalization itself is done by carefully subtracting the ''physically unorbservable'' (and often formally divergent) part of those integrals and keeping only the physically relevant terms. All point particles self energies gets taken care of that way. [[User:Dauto|Dauto]] ([[User talk:Dauto|talk]]) 21:25, 3 June 2009 (UTC)<br /><br />

Well i am able to understand and few points but unable to certain others (having had no formal education in QM), so i can only ask where this leaves us. Does it mean we shouldn't ask questions like what is the energy of a point charge, or that QM has somehow overcome this problem and say this much Joules is the energy of the point charge, or that we are still in the dark and don't know what to make of things ? Can there exeist any point charges in the universe, or is that forbidden ?[[User:Rkr1991|Rkr1991]] ([[User talk:Rkr1991|talk]]) 05:00, 4 June 2009 (UTC)

:A little bit of each. Firt: yes, you probabily shouldn't be asking that question because a point particle is a theoretical construct any ways which may not be a valid description of nature, second: yes, QFT solves the problem but it does so by sweeping it under the rug, and third: yes, we are somewhat still in the dark since we don't have a final theory yet. [[User:Dauto|Dauto]] ([[User talk:Dauto|talk]]) 17:52, 4 June 2009 (UTC)

== Is it possible to set your own innards on fire? ==

Is it really possible to set your own innards on fire if you're chainsmoking while drinking your [[Neutral grain spirit]] (Everclear and similar) straight? --[[Special:Contributions/90.240.197.75|90.240.197.75]] ([[User talk:90.240.197.75|talk]]) 14:46, 3 June 2009 (UTC)
:The [[autoignition temperature]] of [[ethanol]] is 425°C ([http://www.distill.com/materialsafety/msds-eu.html]). I doubt the smoke from a cigarette could get it up to that temperature, although I can't find a source for the temperature of cigarette smoke... --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 15:34, 3 June 2009 (UTC)

:: I'm trying to imagine where the oxygen to maintain the combustion would come from. I guess you'd have to keep taking deep breaths, but then ... [[User:Richard Avery|Richard Avery]] ([[User talk:Richard Avery|talk]]) 15:56, 3 June 2009 (UTC)

:::Did you swallow the booze and then swallow the cig, otherwise I can't imagine smoking gets temps that high inside a person. I am skeptical. [[Special:Contributions/65.121.141.34|65.121.141.34]] ([[User talk:65.121.141.34|talk]]) 16:04, 3 June 2009 (UTC)

::::It may be feasible to, with a combination of a lit cigarette and alcohol vapors, set your face and/or inside of your mouth on fire. But there is no way I could imagine that any such combination could burn your internal organs like lungs or GI-tract. --[[User:Jayron32|Jayron32]].[[User talk:Jayron32|<small>talk</small>]].[[Special:Contributions/Jayron32|<small>contribs</small>]] 18:13, 3 June 2009 (UTC)

: I could sorta kinda imagine your breath catching fire (although it seems unlikely) - but not your throat or stomach - there is just not enough oxygen down there to sustain anything like that. [[User:SteveBaker|SteveBaker]] ([[User talk:SteveBaker|talk]]) 19:40, 3 June 2009 (UTC)

:Sure, an accelerant and central nervous system depressant (Everclear), ignition source (cigarette), make it an [[Wick effect|obese person who maybe does not wash their clothes very often]], and you've all the makings of a case of [[spontaneous human combustion]].&mdash;[[User:EricR|eric]] 23:30, 3 June 2009 (UTC)

: Was anyone else reminded of [[Helpless (Buffy the Vampire Slayer)]]? —[[User:Tamfang|Tamfang]] ([[User talk:Tamfang|talk]]) 18:49, 4 June 2009 (UTC)

== What is VCR doing to my TV signal? ==

I have a coaxial cable from the aerial going into the VCR input socket, and another short coaxial cable connecting from the VCR output socket to the TV. I've noticed that when the VCR is completely unplugged from the power, rather than being just on standby, then the TV signal almost disapears with a very bad very noisy picture quality. So my question, please, is what is the VCR doing to my TV signal? I thought the input and output sockets on the VCR were just passively connected, but apparantly not. [[Special:Contributions/89.243.113.64|89.243.113.64]] ([[User talk:89.243.113.64|talk]]) 20:36, 3 June 2009 (UTC)
:Almost exactly the same question was asked further up: [[Wikipedia:Reference_desk/Science#Poor_TV_picture_improves_a_lot_when_VCR_on]]. See if that answer is any help. --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 20:51, 3 June 2009 (UTC)

I've already seen that thanks. This is a different question about the same items. [[Special:Contributions/89.243.74.161|89.243.74.161]] ([[User talk:89.243.74.161|talk]]) 08:53, 4 June 2009 (UTC)
:If the only connection between the VCR and the TV is a coaxial cable, that single cable carries either the off-air signal from the aerial '''OR''' the video from the VCR in the form of a modulated r.f. signal. The choice is made by an active switch circuit in the VCR. Without power the switch circuit can't pass either signal. [[User:Cuddlyable3|Cuddlyable3]] ([[User talk:Cuddlyable3|talk]]) 10:13, 4 June 2009 (UTC)

::The VCRs I've owned have passed the input coaxial signal to the output coax when powered off. -- [[User:Coneslayer|Coneslayer]] ([[User talk:Coneslayer|talk]]) 17:16, 4 June 2009 (UTC)

:You're right the question is largely unrelated but as mentioned in the above question, VCRs do amplify the antenna signal. This is done I believe because otherwise the VCR would antenuate the signal, as it is using it. This amplification is active as long as the VCR is on, regardless of whether it is in standby or fully on. As mentioned above, most VCRs are also capable of adding a additional signal on a selectable channel to the feed so that you can receive the VCR on your TV if your TV has no other inputs. [[User:Nil Einne|Nil Einne]] ([[User talk:Nil Einne|talk]]) 00:03, 5 June 2009 (UTC)

:I would expect the input to output of a VCR to include a powered buffer amplifier. (The phrase "common collector" comes to mind, or some reason). [[User:Edison|Edison]] ([[User talk:Edison|talk]]) 04:57, 5 June 2009 (UTC)

== Is there any connection? ==

Is there any correlation between people who have [[Irritable Bowel Syndrome]] and [[Panic Attacks]]? <span style="font-size: smaller;" class="autosigned">—Preceding [[Wikipedia:Signatures|unsigned]] comment added by [[Special:Contributions/86.167.247.150|86.167.247.150]] ([[User talk:86.167.247.150|talk]]) 21:23, 3 June 2009 (UTC)</span><!-- Template:UnsignedIP --> <!--Autosigned by SineBot-->

:I am not a medical practitioner and this is merely an observation from articles I read on Wikipedia. I seems that selective serotonin re-uptake inhibitors are listed as possible treatments for both conditions. I can imagine how frequent panic attacks could result from low serotonin levels and the same could possibly be true for IBS. If you added obsessive compulsive disorder to that list then it would definitely have my vote. But again, I'm not an expert or a professional and you should probably ignore me.

:It's unlikely that you'd get an official answer here as that would violate the terms of this page. [[Special:Contributions/196.210.200.167|196.210.200.167]] ([[User talk:196.210.200.167|talk]]) 16:32, 4 June 2009 (UTC) Eon

== Space inside a Black Hole ==

It appears then there are other requirements to form a Black Hole besides minimum number of neutrons<ref>http://en.wikipedia.org/wiki/Wikipedia:Reference_desk/Science#Smallest_number_of_neutrons</ref>. Is there a complete and ordered list of requirements, in addition to minimum number of neutrons, necessary to form a Black Hole?
Also can a Black Hole be described (or defined) as matter in space which contains no space?
--<small>--<font face="rage italic" size="4.5" color="LightSteelBlue"> [[User:taxa|Taxa]]</font> ([[User talk:taxa|talk]])</small> 21:57, 3 June 2009 (UTC)

:There is only one requirement for a black hole - that the matter in question be contained within a ball of radius smaller than the [[Schwarzschild radius]] corresponding to the mass of the matter. (Actually, that's for a non-charged, non-rotating black hole. Without those assumptions you need a slightly more complicated formula, but the principle is the same.) --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 23:19, 3 June 2009 (UTC)

== Applications of invisible light frequencies ==

I need a summer project for school. I have understood that variable lighting is a problem in computer vision, my just physics is not quite strong enough to tell if there are light frequecies that are not so dependent on sun's position on the sky or nearby lamps as visible light and cheap to generate/capture in good quality. I have feeling the answer is no, but it would be better to know for sure. Anyone have any idea? --[[Special:Contributions/194.197.235.28|194.197.235.28]] ([[User talk:194.197.235.28|talk]]) 23:02, 3 June 2009 (UTC)

:Actually this is quite commonly used in image processing. For example, a lot of toll-booths have a camera to catch the license plate of anyone who does not pay the toll. To cope with varying light conditions, the cameras are often sensitive only to infrared light, and the area is illuminated by an infrared bulb. This reduces interference from other sources of light and provides a controlled, constant illumination for the [[Optical Character Recognition]] program which will identify the vehicle. One reason this method is easy is because a lot of digital [[CCD camera]]s are already sensitive to infrared, so visible light can be filtered out (or left in as supplemental illumination). You might find [[Infrared photography]] interesting as well. We also have [[Thermographic camera]], which describes ''passive'' infrared photography (using infrared cameras without an illuminating infrared lightbulb). These are commonly used as a type of [[night vision]] (not to be confused with low-light amplification). Thermographic infrared images make it very easy to spot vehicles, trucks, humans, and other hot objects, and are also often used in automatic image-processing (for example, automatic aim correction on a combat helicopter). [[User:Nimur|Nimur]] ([[User talk:Nimur|talk]]) 02:41, 4 June 2009 (UTC)
::It's important to note that, while both called "infra-red", the light used by thermographic cameras and the light used by standard IR night vision cameras is very different. The latter uses "near infra-red", that is, light with wavelengths just slightly longer than that of visible red light. Thermal cameras use more distant infra-red. IR spans about 3 orders of magnitude compared to less than one spanned by visible light. There is a far greater difference between near and far IR than between violet and red visible light. If it were up to me, I would give near and far infra-red different names (with the boundary corresponding to 100°C). --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 02:21, 5 June 2009 (UTC)

:It's not the frequency of the light - after all, the computer's camera only really sees red, green and blue - and some computer vision is done in black and white just because it's easier and the color doesn't really help much. No - the problem is uneven lighting - where some things in the scene are lit by brighter light than others - or when the lights flicker or change brightness while the computer is gathering imagery - or when the light is strongly directional producing super-bright highlights and deep shadows. You really start to appreciate how amazingly adaptable human vision is. [[User:SteveBaker|SteveBaker]] ([[User talk:SteveBaker|talk]]) 02:43, 4 June 2009 (UTC)
::Right - the point of using active infrared illumination is to control the illumination environment. We could probably also control the visible-light environment too - but in the case of covert military or traffic cameras, flashing visible light around the imaging target is not an option. Using "invisible" infrared allows the operator to produce [[:File:Extreme-CCTV-Active-Infrared-Night-Vision.jpg|uniform illumination]] for the computer-vision system, without directly affecting the human-perceptible parts of the environment. Also, sometimes infrared just has better signal-to-noise qualities - I used a (mostly) [https://nimur-enterprises.stanford.edu/wiki/images/e/e0/Vision_acquired.jpg infrared beacon for my robotic target-tracker project] last year. [[User:Nimur|Nimur]] ([[User talk:Nimur|talk]]) 02:49, 4 June 2009 (UTC)

:::That answered my question perfectly. Thank you. --[[Special:Contributions/194.197.235.28|194.197.235.28]] ([[User talk:194.197.235.28|talk]]) 15:17, 4 June 2009 (UTC)

= June 4 =

== NDE recovery, fiction vs real life ==

I've seen it a hundred times on the tube: someone is found completely inert, often in water, and there's a moment of suspense – is the character pining for the fiords? – while CPR is attempted; then the rescuee noisily resumes breathing, and immediately is fully awake (though disoriented).

Does that really happen? —[[User:Tamfang|Tamfang]] ([[User talk:Tamfang|talk]]) 00:20, 4 June 2009 (UTC)

::While it's possible for a victim to regain consciousness, any good CPR will break ribs. Going from unresponsive to verbal (making sounds without any meaning) is probably the best you can hope for. Certainly most CPR will not result in a save, and you can ask anyone in the field. [[User:Mattman723|<font color="#000000">M@$+</font>]][[<font color="green">@</font>]] [[User:Mattman723|<font color="#000000">Ju</font>]] ~ [[User_talk:Mattman723|<font color="#000000">♠</font>]] 00:33, 4 June 2009 (UTC)
:::In that situation, would the heart necessarily have stopped? If all that is required is mouth-to-mouth then I think full conciousness can return pretty quickly. CPR is normally just to keep the person alive until someone with a defibrillator gets there (and even then, your chances aren't anywhere near as good as TV hospital dramas would have you believe). --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 01:39, 4 June 2009 (UTC)

::::Isn't it the case that in Real Life, the vast majority of 'flatlines' still result in death, despite the best efforts of everyone? EDIT: Also, that a defibrillator is useless in this situation, despite what TV tells us? --[[User:Kurt Shaped Box|Kurt Shaped Box]] ([[User talk:Kurt Shaped Box|talk]]) 02:45, 4 June 2009 (UTC)

:::::Properly done CPR need not break ribs. [[User:Edison|Edison]] ([[User talk:Edison|talk]]) 02:58, 4 June 2009 (UTC)

::::::I have no idea if this is actually true but I remember reading one of those 'true medical confessions!' books ages ago in which an anonymous MD stated that it was not unknown for doctors to deliberately break the patients ribs by performing rough CPR on a patient that they already knew was toast - if the relatives were watching. The thinking being that they'd see that and be assured that absolutely everything that could've be done had been done in an attempt to save the patient... --[[User:Kurt Shaped Box|Kurt Shaped Box]] ([[User talk:Kurt Shaped Box|talk]]) 03:06, 4 June 2009 (UTC)

:::::That is correct; the ever-popular 'flatline' (''beeeeeeeeeeeeeeeeeep'') in televised medical dramas is not a shockable rhythm. (See [[asystole]]). [[Cardiac arrest]]s can be divided into two broad groups: those which still include some mechanical action by the heart ([[ventricular tachycardia]], [[atrial fibrillation]]), and those which don't ([[asystole]], [[pulseless electrical activity]]). The former are susceptible to defibrillation and have a much higher survival rate. The latter aren't shockable, and have a very poor prognosis.
:::::Our article on cardiac arrest notes an overall survival rate of [[cardiac arrest#Prognosis|about 15%]] for in-hospital arrests. (Out of hospital rates are lower.) Patients with shockable rhythms fare about ''ten times'' better than those with asystole. [[User:TenOfAllTrades|TenOfAllTrades]]([[User_talk:TenOfAllTrades|talk]]) 13:48, 4 June 2009 (UTC)

:There are many studies of near drowning events, unfortunately i don't have access to any that would answer your question. 100% of victims will survive in the short term (otherwise it's a drowning and not a near drowning). Approximately 80% will survive beyond 24 hours, perhaps with some degree of neurological deficit. Many children with cyanosis or hypoxia following recovery resume breathing after clearing the airway and one or two rescue breaths, and are conscious and alert immediately thereafter.

:If the victim is in arrest the prognosis is much poorer, hypoxia has been prolonged and the brain is now [[ischemia|ischemic]]. CPR alone will probably not result in a return of spontaneous circulation, let alone regaining consciousness, defibrillation and/or drugs are required. One thing to note tho is that even professional healthcare providers have a poor success rate at finding a carotid pulse during a suspected arrest event. The following scenario most likely could happen: an apneic victim is removed from the water, rescuers begin CPR but fail to note the presence of a pulse. The victim resumes breathing and shortly regains consciousness. Chest compressions were performed but were not required.&mdash;[[User:EricR|eric]] 15:37, 4 June 2009 (UTC)

To clarify, my question is not about the odds of survival after (near)drowning or heart attack or whatever, but about the [[TV Tropes|TV cliché]] of ''sudden'' recovery of full consciousness. —[[User:Tamfang|Tamfang]] ([[User talk:Tamfang|talk]]) 19:02, 4 June 2009 (UTC)

== Penile's Erectiom Angel ==

plz answeer, how can i measure my Penile's Erection angle ? <small><span class="autosigned">—Preceding [[Wikipedia:Signatures|unsigned]] comment added by [[User:Greatfencer|Greatfencer]] ([[User talk:Greatfencer|talk]] • [[Special:Contributions/Greatfencer|contribs]]) 01:11, 4 June 2009 (UTC)</span></small><!-- Template:Unsigned --> <!--Autosigned by SineBot-->

: I suppose a mirror might help. —[[User:Tamfang|Tamfang]] ([[User talk:Tamfang|talk]]) 02:33, 4 June 2009 (UTC)

:[[Protractor]]? --[[User:Kurt Shaped Box|Kurt Shaped Box]] ([[User talk:Kurt Shaped Box|talk]]) 02:43, 4 June 2009 (UTC)

:Of course, [[Beavis and Butthead|the angle of the dangle is inversely proportional to the heat of the beat]]... --[[User:Jayron32|Jayron32]].[[User talk:Jayron32|<small>talk</small>]].[[Special:Contributions/Jayron32|<small>contribs</small>]] 02:50, 4 June 2009 (UTC)

:(EC)Use your [[Goniometer|goniometer]]. If you do not have one handy, the angle of the dangle has been said to be [http://books.google.com/books?id=1ALhLiy-hmoC&pg=PA180&dq=angle+dangle+heat+meat&lr=&as_drrb_is=q&as_minm_is=0&as_miny_is=&as_maxm_is=0&as_maxy_is=&as_brr=0 inversely proportionate to the heat of the meat], so a [[Meat thermometer]] might allow an accurate indirect measurement. Other anatomical surrogate measurements are mentioned in the work cited. [[User:Edison|Edison]] ([[User talk:Edison|talk]]) 02:54, 4 June 2009 (UTC)
::The word "goniometer" does not mean "a thing to measure gonads," just as "episcotister" is not a device to test episcopals. [[User:Edison|Edison]] ([[User talk:Edison|talk]]) 04:54, 5 June 2009 (UTC)
:(EC)How's about making an appointment for a visit to your local hospital's [[Penile tumescence lab]]? For some reason, the hospital seen on [[House M.D.]] would appear to have more than one. --[[User:Kurt Shaped Box|Kurt Shaped Box]] ([[User talk:Kurt Shaped Box|talk]]) 03:00, 4 June 2009 (UTC)

:Employ the service of a [[fluffer]] who charges by the degree and read the invoice. [[User:Cuddlyable3|Cuddlyable3]] ([[User talk:Cuddlyable3|talk]]) 09:53, 4 June 2009 (UTC)

:: &lt;applause&gt; —[[User:Tamfang|Tamfang]] ([[User talk:Tamfang|talk]]) 19:14, 4 June 2009 (UTC)

:[http://www.snopes.com/college/exam/barometer.asp Drop a barometer] from the top to determine the height, and use trigonometry. I am assuming that you know, or can measure, the length. -- [[User:Coneslayer|Coneslayer]] ([[User talk:Coneslayer|talk]]) 13:08, 4 June 2009 (UTC)

:: &lt;applause&gt; —[[User:Tamfang|Tamfang]] ([[User talk:Tamfang|talk]]) 19:14, 4 June 2009 (UTC)

:Take the barometer to a fluffer and say "I'll give you this really nice barometer if you'll measure the angle". [[User:SteveBaker|SteveBaker]] ([[User talk:SteveBaker|talk]]) 23:45, 4 June 2009 (UTC)

: I think that when dealing with an erection angel I wouldn't worry about her measurements. [[User:APL|APL]] ([[User talk:APL|talk]]) 03:49, 5 June 2009 (UTC)

:Does an erection angel work for a [[Venus|sex goddess]]? --[[User:Jayron32|Jayron32]].[[User talk:Jayron32|<small>talk</small>]].[[Special:Contributions/Jayron32|<small>contribs</small>]] 04:21, 5 June 2009 (UTC)

<sigh> Okay. What you need is a [[protractor]]. That's a half-circle (usually plastic) with marks or scratches indicating the various angles. Stand upright (yeah, ''erect'') and place the center of the flat edge of the protractor against the side of your erect penis, so that the protractor is straight up and down. It will probably be easier to take a measurement from your belly downwards rather than from your balls upwards. HTH. [[User:Matt Deres|Matt Deres]] ([[User talk:Matt Deres|talk]]) 23:58, 5 June 2009 (UTC)

:Hmmm - perhaps an [[inclinometer]] - it measures your inclination. [[User:SteveBaker|SteveBaker]] ([[User talk:SteveBaker|talk]]) 03:19, 6 June 2009 (UTC)

== global warming and human water retention ==

06:34, 4 June 2009 (UTC)[[User:Paul fitts|Paul fitts]] ([[User talk:Paul fitts|talk]])What year did the true science of global warming start? what was the Earth's population at that time? What is the percentage of the human body that is made of water? If you had a 3ft cube of ice, and you melted it...how much water would that be in gallons??

the main reason for my questions.....it doesn't really apprear that sea levels are rising, so if ice caps and glaciers are "melting", and the water levels aren't really rising.....wouldn't it stand to reason that, that the "melted" water has to go somewhere, why not human water retention to make up 3+ billion more we've created over ther last 30 years???


Paul Fitts

:The [[Tuvalu]]ans beg to differ. According to [http://uk.reuters.com/article/environmentNews/idUKSEO11194920070913 this Reuters article], their whole country could disappear under the waves in 30-50 years. Another factor (which I was reminded of by ''[[An Inconvenient Truth]]'') is that if the glaciers are in the water, their melting won't raise the water level. It's when the land-based ice melts that we have to worry. [[User:Clarityfiend|Clarityfiend]] ([[User talk:Clarityfiend|talk]]) 07:29, 4 June 2009 (UTC)

::We have, of course, and article at [[Current sea level rise]]. Sea level is rising several mm per year. I'm too lazy to work in feet and gallons (which gallons, anyways?), but one cubic meter of ice has 1000 l and will melt into very roughly 900 l of water. --[[User:Stephan Schulz|Stephan Schulz]] ([[User talk:Stephan Schulz|talk]]) 07:36, 4 June 2009 (UTC)

::Google can convert between units, put in something like "3 cubic feet in gallons". After that go outside and watch some grass carefully for a few hours. Did you see it grow? [[User:Dmcq|Dmcq]] ([[User talk:Dmcq|talk]]) 08:00, 4 June 2009 (UTC)

:To put this in context - sea levels are rising a few millimeters each year - but each millimeter of rise represents 360,000,000,000 cubic meters of water. There are about 7 billion people - even if each of us was retaining a cubic meter of water (not even close!) we'd represent only about 0.02 millimeters of ocean depth. No - the reason the rate seems low is that 360,000,000,000 cubic meters means that it takes an awful lot of water to raise all of the oceans in the world by one millimeter. But while a few millimeters may not sound much - over 100 years, that's enough to drown quite a few coastal cities. Sadly, the evidence is that the rate of increase is going up year on year - so we could easily have a dozen or more meters of ocean level rise during the lifetimes of our children - of the younger Ref.Desk denizens. [[User:SteveBaker|SteveBaker]] ([[User talk:SteveBaker|talk]]) 15:00, 4 June 2009 (UTC)

== Why are washers so called? ==

It was one of those idle, late night conversations in the tour van on the way home from a gig ... which led precisely nowhere.
My theory is that the bigger examples are called penny washers because they are the size of pre-decimal pennies, but what about smaller varieties, and where does 'washer' come from?
Any ideas please? [[User:Turbotechie|Turbotechie]] ([[User talk:Turbotechie|talk]]) 07:58, 4 June 2009 (UTC)

:According to [http://www.straightdope.com/columns/read/1713/whats-the-purpose-of-washers-the-round-metal-things] (80% down the page) the origin of the term "washer" for that piece of metal is unknown, though it has had that meaning for at least 400 years and perhaps as many as 650 years. [[User:Dragons flight|Dragons flight]] ([[User talk:Dragons flight|talk]]) 08:23, 4 June 2009 (UTC)

::<small>Outside a hardware store hung the alarming sign "''Nut screws washer and bolts''". [[User:Cuddlyable3|Cuddlyable3]] ([[User talk:Cuddlyable3|talk]]) 09:42, 4 June 2009 (UTC)</small>
:::<small>Not forgetting there was a launderette next door [[User:Mikenorton|Mikenorton]] ([[User talk:Mikenorton|talk]]) 10:01, 4 June 2009 (UTC)</small>

:You are right that penny washers are named for the old pennies, and often they are a similar size, but the term can actually be applied to any size washer. It is a washer with a disproportionately small centre-hole. [[User:Spinningspark|<font style="background:#FFF090;color:#00C000">'''Sp<font style="background:#FFF0A0;color:#80C000">in<font style="color:#C08000">ni</font></font><font style="color:#C00000">ng</font></font><font style="color:#2820F0">Spark'''</font>]] 16:34, 4 June 2009 (UTC)
::Just for my own education, do you have a source I can read up on SSpark? I would frame it the other way, since washers are designed for the inserted item, so rather than "disproportionately small centre-hole", I would say "disproportionately large outside-diameter". In my very limited engineering experience in a very specialized field, we termed these "standard" and "frictional" washers, where "frictional" were the big ones, designed to offer a larger weight-bearing surface, as opposed to the I/D / O/D sizes needed to transfer load from a bolt head to a typical clearance hole. [[User:Franamax|Franamax]] ([[User talk:Franamax|talk]]) 23:42, 4 June 2009 (UTC)

== Do facial products work? ==

Is there any scientific evidence that any face creams, anti wrinkle creams, eye treatments etc are any better than just splashing water on your face or is it really just hype? Kirk Uk <span style="font-size: smaller;" class="autosigned">—Preceding [[Wikipedia:Signatures|unsigned]] comment added by [[Special:Contributions/87.82.79.175|87.82.79.175]] ([[User talk:87.82.79.175|talk]]) 09:26, 4 June 2009 (UTC)</span><!-- Template:UnsignedIP --> <!--Autosigned by SineBot-->
:All 3 are better than water at generating profit for someone. Medical eye treatments have to be certified as safe. [[User:Cuddlyable3|Cuddlyable3]] ([[User talk:Cuddlyable3|talk]]) 09:46, 4 June 2009 (UTC)

Many of the anti-wrinkle creams are proven to give a temporary lift and do so by using proven science, similarly darkness-removal creams can be proven to remove the appearance of darkness by masking/covering it. You may notice that in adverts of these types the claims are always quite vague (to paraphrase [[Charlie Brooker]])...terms such as "98% of respondents agree", "help reduce appearance of", "helps fight" are all very 'vague' and undetailed - throw in a few random science-sounding (merged with natural-sounding) words and you've got something that says nothing when reviewed by a legal team but can suggest 'proof' to the average consumer. [[Special:Contributions/194.221.133.226|194.221.133.226]] ([[User talk:194.221.133.226|talk]]) 10:22, 4 June 2009 (UTC)

:In the UK, they have to say "improves the appearance of wrinkles" rather than "removes wrinkles" on the ads now. There was one company a couple of years back that got absolutely castigated for making completely false claims about the abilities of their product (Google for 'Boxwellox'). Not quite as bad as the toothpaste that claimed to be able to split water molecules, producing free oxygen for a deeper clean - but still... --[[User:Kurt Shaped Box|Kurt Shaped Box]] ([[User talk:Kurt Shaped Box|talk]]) 10:47, 4 June 2009 (UTC)

Sunscreen definitely helps us against wrinkles. It can be scientifically tested that protecting your face against UV rays will make you look younger than you are. For example, faces of truck drivers that have been laterally exposed to sun light have been analyzed, and the half exposed to sun light looked older than the other half.--[[User:Mr.K.|Mr.K.]] [[User_talk:Mr.K.|(talk)]] 10:57, 4 June 2009 (UTC)
:It helps preventively against wrinkles, by the way. --[[User:Mr.K.|Mr.K.]] [[User_talk:Mr.K.|(talk)]] 12:01, 4 June 2009 (UTC)

:The big hype of these things in the UK ended quite a few years ago when the manufacturers were faced with either having to downsize their claims - or be treated as medical/pharmacuticals. The fair trade people argued that if they ACTUALLY reduced wrinkles, then these creams must be penetrating the skin and acting on the tissues beneath - which would require them to be classified as drugs. If all they do is fill in the wrinkles - or change their color/reflectivity to make them temporarily less noticable - then that's OK, it's just a cosmetic effect. I don't understand why that's not also the case in the USA. Certainly the claims they make are ridiculously impossible - and if they were possible, these cosmetics would certainly have to be seriously tested because they could have any number of dangerous side-effects. To the extent that they block sunlight, they might work...but their effects are essentially just changes in appearance. [[User:SteveBaker|SteveBaker]] ([[User talk:SteveBaker|talk]]) 14:52, 4 June 2009 (UTC)

::Well, they also work as well as any other [[Moisturizer]]; that is by providing a barrier against evaporation, they cause the underlying skin to retain more moisture. Higher moisture content equals plumper epithelial cells, and plumper cells equals less wrinkles. Of course, a $5.00 bottle of any decent mositurizing lotion will do that; dropping $40.00 on a small 4 ounce tub of the same stuff mixed with a little make-up to cover over dark patches seems excessive to me... But then again, I'm not an aging woman trying to recapture my lost youth, what do I know. --[[User:Jayron32|Jayron32]].[[User talk:Jayron32|<small>talk</small>]].[[Special:Contributions/Jayron32|<small>contribs</small>]] 17:34, 4 June 2009 (UTC)

::: Hey, wait, here's [http://www.guardian.co.uk/science/2009/apr/28/boots-protect-perfect-anti-wrinkle-cream] a SCIENTIFIC assessment of a particular facial product sold by that 'well known high street chemist'. Whether you are impressed by the fact that 43% of the meagre sample thought their skin had improved is up to you. 23% of the placebo sample thought their skin had improved. [[User:Richard Avery|Richard Avery]] ([[User talk:Richard Avery|talk]]) 17:38, 4 June 2009 (UTC)

:::: A study involving 50 people; I assume half received the placebo and half the cream? That means of 25 receiving the placebo, 6 liked it, and of 25 receiving the cream, 12 liked it? I wouldn't call such small sample size "statistically significant". The error bars on a sample size of 25 would probably be bigger than the difference between the samples. Heck, I could flip a coin 25 times and get the same results. Additionally, as the sample did not compare the expensive treatment to a cheap one, only to a placebo, it only addresses the possibility that the expensive cream is better than ''nothing'' but not neccessarily better than ''cheaper alternatives''. What you have here is a clear example of [[How to Lie with Statistics]]. --[[User:Jayron32|Jayron32]].[[User talk:Jayron32|<small>talk</small>]].[[Special:Contributions/Jayron32|<small>contribs</small>]] 17:45, 4 June 2009 (UTC)
:::::::Ah! "Buy our amazing anti-wrinkle cream - it has a one in five chance of being better than smearing lard on your face." [[User:SteveBaker|SteveBaker]] ([[User talk:SteveBaker|talk]]) 19:51, 4 June 2009 (UTC)
::::::::But lard has the advantage of making you smell like pie crust and biscuits. Who wouldn't want to smell fresh-baked pie crust all day? --[[User:Jayron32|Jayron32]].[[User talk:Jayron32|<small>talk</small>]].[[Special:Contributions/Jayron32|<small>contribs</small>]] 20:44, 4 June 2009 (UTC)
:::: If I did it right, that's a 99.9999999635% significance level. If I did it wrong, it's even higher. This should be a two-tailed T-test (try saying that ten times fast), right? There may be problems with that study, but sample size isn't one of them. — [[User:DanielLC|DanielLC]] 16:48, 5 June 2009 (UTC)
:::::According to the [[Mayo Clinic]], "''Research suggests that some wrinkle creams contain ingredients that may improve wrinkles. But many of these ingredients haven't undergone scientific research to prove this benefit. If you're looking for a face-lift in a bottle, you probably won't find it in over-the-counter (nonprescription) wrinkle creams. But they may slightly improve the appearance of your skin, depending on how long you use the product and the amount and type of the active ingredient in the wrinkle cream.''"[http://www.mayoclinic.com/health/wrinkle-creams/SN00010] [[User:A Quest For Knowledge|A Quest For Knowledge]] ([[User talk:A Quest For Knowledge|talk]]) 17:58, 4 June 2009 (UTC)

::(EC)::There is [[Absorption (skin)]]. If any of the products achieve that the questions become: Do you want the substance that gets absorbed in your system? and Does your body do anything with the absorbed substance in the layers of skin that is beneficial or does the absorbed substance just accumulate or get transported away? There are some things like [[Botox]] which is a [[neurotoxin]] and [[Silicone]] or animal derived [[Collagen]] that can be injected into the skin. Since they work "internally" they get treated as medical/pharmacutical. Nevertheless they have come under criticism because the two questions above didn't come up with consistent answers when asked by different reviewers. The cosmetics industry is trying to stay away form the cost of having to get their products subjected to licensing for pharmaceuticals (see [[Cosmeceutical]]). So they have to come up with things that do not "''affect the structure or function of the human body''". The reputable ones also try to make sure that their products do not contain known toxins or substances that cause harm in the short term (long term use sometimes reveals things that didn't show up in testing.) Probably more driven by their desire to avoid costly product liability suits than anything else. Adding [[Surfactant]]s like [[soap]] to water makes it a more efficient [[detergent]]. It also removes the protective layer of [[lipid]]s [[Stratum corneum|covering the skin]] and knocks ph of the [[acid mantle]] out of whack. To counterbalance that you can apply oils to your skin after washing. Since using pure oils would give you an unpleasant and impractical film of oil on your skin what we use are [[emulsion]]s. (Also see [[Cold cream]]). Since those are prone to [[Rancidification]] and microbial growth you'll not only find emulsifiers and stabilizers but also [[Antioxidant|preservatives]] in those. <small>(Sometimes cleverly marketed as new Vitamin ingredient)</small> In a further step the cosmetics industry then created [[Moisturizer]]s. Splashing water on your face would not have the same effect, rather the opposite actually. It would rinse away some more oils exposing cells to evaporation and upset the hydrostatic balance causing further drying. It works through constricting fine blood vessels in the skin. AFAIK interest in reducing [[Wrinkle (skin)|wrinkles]] has only gained momentum throughout the past 70 years or so. That along with our increasing knowledge of biochemical processes in the human body has led to many theories being put forward and being rebuked in that respect. The focus used to be the moisture contents of the stratum corneum. Now things like [[electrolyte]] balance, [[Radical (chemistry)|Free radicals]], [[Programmed cell death|cell aging]] and nerve stimulation, among others, are under study. Some of those studies are either financed by the cosmetics industry through grants, or done in their labs. Study results from company owned labs are rarely published. (If one of their labs found the holy grail in anti-wrinkle treatment I bet they'd gladly spin off a subsidiary and go through the pharmaceutical trials.;-) Facial products work in the regard that they don't leave greasy marks on your clothes or things you touch, don't spoil fast, smell pleasant and supply lipids to your skin. A [[Thermoregulation|cooling effect]] while the continuous phase of the emulsion evaporates is also well established. [[Product differentiation]] has companies add various ingredients that at best can provide better product performance and at least not cause any harm. You'd have to research each labeled ingredient separately to get an idea. It is very likely though that lots of substances aren't listed or any research studies are under lock and key at the company. [[Special:Contributions/71.236.26.74|71.236.26.74]] ([[User talk:71.236.26.74|talk]]) 00:04, 5 June 2009 (UTC)

== What happens to toxic sewage sludge? ==

About 40 - 60% (depending on whether you are in the EU or USA) of treated sewage sludge (biosolids) is reused as agricultural fertilizer. From what I can see on the article on [[biosolids]], the main reason some biosolids cannot be used as fertilizer is that they have a heavy metal and toxic substance content that is too high. Is this true? If so, what happens to this waste? Is it incinerated, landfilled etc? <span style="font-size: smaller;" class="autosigned">—Preceding [[Wikipedia:Signatures|unsigned]] comment added by [[Special:Contributions/157.203.42.175|157.203.42.175]] ([[User talk:157.203.42.175|talk]]) 13:23, 4 June 2009 (UTC)</span><!-- Template:UnsignedIP --> <!--Autosigned by SineBot-->

:According to this [[Parliament of the United Kingdom|parliamentary]] note [http://www.parliament.uk/documents/upload/postpn282.pdf], in the UK 62% is applied to agricultural land, 19% is incinerated, 11% is being used in land reclamation with the remainder going to [[landfill]] or [[composting]]. It also discusses the use of sludge to generate energy from [[biogas]] through [[anaerobic digestion]]. The report does not mention toxicity as a problem, apart from the issue of Endocrine-Disrupting Chemicals. [[User:Mikenorton|Mikenorton]] ([[User talk:Mikenorton|talk]]) 14:11, 4 June 2009 (UTC)

::[[Sludge]] has some information. [[Special:Contributions/71.236.26.74|71.236.26.74]] ([[User talk:71.236.26.74|talk]]) 04:10, 5 June 2009 (UTC)

== Frozen peas float when cooked ==

When you put frozen peas in a saucepan of cold water they sink to the bottom. When the water is heated up the peas float to the surface. But as ice is lighter than water, and frozen peas must contain some ice, I would expect the opposite to happen, i.e. they would start off floating then sink when heated. What is going on here? [[User:Lonegroover|Lonegroover]] ([[User talk:Lonegroover|talk]]) 14:45, 4 June 2009 (UTC)
:Peas contain lots of stuff besides just water, so maybe enough to overcome the buoyancy from decrease in density of the water being frozen. Do the peas remain the same size, or do they expand when they thaw/heat? Does this happen only if the water gets hot, or can you reproduce it with room-temp water (to exclude nucleated steam giving the lift)? [[User:DMacks|DMacks]] ([[User talk:DMacks|talk]]) 14:53, 4 June 2009 (UTC)

::Don't forget that water is densest at about 4C. My guess (and it really is just speculation) would be the following:

::Water, in a saucepan at about 10 degrees C, combined with peas at about -18C. Peas initially float in cold water before sinking so clearly the water is denser for a short period. Presumably due to the low temperature of the peas? I would assume that the peas rapidly warm due to their high surface area to volume ratio. As such, the water within the peas would be denser than the water in the pan. Peas have other constituent components, but I would suggest the density of the water in the peas outweighs and (lower) density from the solid matter of the pea. The overall density of the pea should approach the point where they are denser than the surrounding water - this shouldn't be too difficult, the water will be getting colder from the peas but also warmer from the heat input.

::I would imagine that the peas remain denser (colder) than the surrounding water for a while - since the source of heat would warm the water first, then the peas When the water boils, the peas could reach a temperature equilibrium with the water (since the water cannot get hotter, regardless of heat input, without turning to steam), or at least become warm enough such that the weighted average of the density of the pea (i.e. the solid matter and water contained within the pea) could overcome the density of the hot/boiling water. <span style="font-size: smaller;" class="autosigned">—Preceding [[Wikipedia:Signatures|unsigned]] comment added by [[Special:Contributions/157.203.42.175|157.203.42.175]] ([[User talk:157.203.42.175|talk]]) 15:07, 4 June 2009 (UTC)</span><!-- Template:UnsignedIP --> <!--Autosigned by SineBot-->

:::The obvious answer is [[thermal expansion]] of the peas. Assume the peas have a density near water, but slightly more dense. This is because they are mostly water, but with some solid materials. As the peas heat, their radius expands by some small amount - but their volume increases according to (radius<sup>3</sup>), so their density will decrease inversely to that. Although water does change its density slightly, it's generally a good assumption that it is an incompressible fluid. Its density should not change significantly between room temperature and near-boiling. (Our article gives about a 5% change, but I don't know if I trust the [http://www.engineeringtoolbox.com/water-density-specific-weight-d_595.html source data]). But, the water inside the peas will also expand - and so the only relevant volume change is the thermal expansion of the solid materials in the pea. [[User:Nimur|Nimur]] ([[User talk:Nimur|talk]]) 14:44, 5 June 2009 (UTC)

== What happens if I drink five-year-old soda? ==

Not fridged, the 12-pack wasn't even opened. Just curious. I think I'll throw it out anyway. [[Special:Contributions/67.243.7.41|67.243.7.41]] ([[User talk:67.243.7.41|talk]]) 15:34, 4 June 2009 (UTC)

: OR having tried it once. It won't be toxic, but it may be unpalatable as the bubbles will be gone and it may be a bit sludgy on the bottom of the can. [[Special:Contributions/65.121.141.34|65.121.141.34]] ([[User talk:65.121.141.34|talk]]) 16:23, 4 June 2009 (UTC)

:This is not medical advice BUT: you might gain super powers. It's a possibility. Consider your future life as Soda Man, and whether or not you are willing to take on that responsibility. --[[Special:Contributions/98.217.14.211|98.217.14.211]] ([[User talk:98.217.14.211|talk]]) 16:55, 4 June 2009 (UTC)

:Throwing it away it probably wise. I doubt there will be anything harmful about it, but it probably won't taste very nice (depending on how it was stored). It is possible the seal has been broken somehow which might have allowed something harmful to get in, so probably not worth the risk. --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 18:38, 4 June 2009 (UTC)

::::Sugar soda may retain its flavor longer than artificially sweetened soda. I once had some old pop sweetened with Nutrasweet and all sweetness was gone. It tasted like unsweetened Coke with pineapple juice added. Heat speeds the breakdown of Nutrasweet. There is always a possibility that over time there could be greater leaching of metal or plastic from the can into the drink. If it is sealed, how would any carbon dioxide escape to make it flat? [[User:Edison|Edison]] ([[User talk:Edison|talk]]) 18:42, 4 June 2009 (UTC)
:::::Major OR here, but I had some cans of orange soda that actually started leaking through the bottom of the cans after eight or nine years. They were unopened and keep in a closet. The soda actually caused corrosion and leaked out. cheers, [[User:10draftsdeep|10draftsdeep]] ([[User talk:10draftsdeep|talk]]) 19:38, 4 June 2009 (UTC)
::::::If its in a can, the soda may have eroded away enough of the can to impart a metallic taste. Don't know if its toxic though. [[User:Livewireo|Livewireo]] ([[User talk:Livewireo|talk]]) 21:22, 4 June 2009 (UTC)
:::::::Most modern cans have a coating of plastic on the inside I do believe. If the (presumably) citric acid in the orange soda and/or the carbonic acid in any soda has gotten through to the metal of the outside of the can, it's likely also dissolved the plastic coating on the way. This would presumably include any phthalate and/or bisphenol components of the coating plastic. Luckily, most plastic compositions are considered trade secrets, and there is intense dispute over the bio-effects of various plastic additives (softeners, etc.) which may or may not be in the plastic anyway (trade secret!) - so we can just dismiss the whole thing as "no definite evidence". [[User:Franamax|Franamax]] ([[User talk:Franamax|talk]]) 23:33, 4 June 2009 (UTC)

::Check this out: [[Benzene in soft drinks]], then check the label of your soda can. It won't kill you (immediately) but it's not healthy either. Also "a soft drink such as a cola has a pH of 2.7-3.0 compared to battery acid which is 1.0". That and the other ingredients, plus the can should make for an interesting environment for many chemical reactions and interesting compounds to form over time. [[Special:Contributions/71.236.26.74|71.236.26.74]] ([[User talk:71.236.26.74|talk]]) 00:26, 5 June 2009 (UTC)
:::Of course, you do realize that a pH of 3.0 is 1% as acidic as a pH of 1.0. Thus, soda has about 1% of the acid concentration of battery acid. Of course, the liquid in your stomach is pH of around 2 or so, which means that the soda is only 10% as acidic as your own gastric juices, or if you prefer, your gastric juices are 10 times as acidic as soda. Welcome to the wonderful world of [[logarithm]]s. --[[User:Jayron32|Jayron32]].[[User talk:Jayron32|<small>talk</small>]].[[Special:Contributions/Jayron32|<small>contribs</small>]] 04:17, 5 June 2009 (UTC)
::::That's one of the reason I put that quote from an ooold paper in quotation marks. Your stomach is however a pretty good example of an environment that has interesting chemical reactions happening. [[Special:Contributions/71.236.26.74|71.236.26.74]] ([[User talk:71.236.26.74|talk]]) 06:00, 5 June 2009 (UTC)
:Note that you generally don't want to drink any non-diet soda with a broken seal that's older than a few days - once it gets exposed to the environment I would expect the bacteria to come in and party on the sugar. A diet soda on the other hand might be fine for a longer period of time. I'm not sure. [[User:Dcoetzee|Dcoetzee]] 06:39, 5 June 2009 (UTC)
::Nope [[Aspartame]] is less stable that sugar and gets broken down after a while. The interesting thing is what reaction products you're going to get. [[Special:Contributions/71.236.26.74|71.236.26.74]] ([[User talk:71.236.26.74|talk]]) 07:28, 5 June 2009 (UTC)

== Capturing a warm bath's heat ==

It's winter in the southern hemisphere and a nice way to heat up is by taking a warm bath. I couldn't help thinking though of all the energy that gets lost when the warm water flows out the drain after a bath. Given that:

* a kilocalorie is the amount of energy it takes to heat a liter of water by 1 degree Celsius
* lets assume my bathtub holds 150 liters of water
* it's about 17 degrees in my apartment, the water after I'm done bathing is 40 degrees Celsius, a 23 degree difference

I asked Google: "(150 * 23) * kilocalories in kilowatt hours" and got "(150 * 23) * kilocalories = 4.00966667 kilowatt hours"

That's 4 kilowatt hours of energy down the drain! That's like a 1000 watt heater staying on for 4 hours. so this makes me ask, does it make sense to keep the water in the bathtub until it has cooled down so that my place will heat up a bit? One concern is evaporation that might cause the humidity to rise and thus the energy is kept as latent heat rather than actual. In that case, is there something simple one can do to prevent evaporation?

[[Special:Contributions/196.210.200.167|196.210.200.167]] ([[User talk:196.210.200.167|talk]]) 16:14, 4 June 2009 (UTC) Eon
:Any added humidity will make you ''[[heat index|feel]]'' warmer, which is just as good, isn't it? --[[User:TotoBaggins|Sean]] 18:25, 4 June 2009 (UTC)

::I'm not sure. The formulas are given in Fahrenheit, but I suspect at 17 degrees a higher humidity might even make you feel colder. Seems counter intuitive though that just leaving the water in the bathtub can make such a huge difference. [[Special:Contributions/196.210.200.167|196.210.200.167]] ([[User talk:196.210.200.167|talk]]) 19:39, 4 June 2009 (UTC) Eon

:A lid on the bath would prevent evaporation. --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 18:36, 4 June 2009 (UTC)

:I don't see why leaving the water in the bath until it's cooled right down wouldn't work. The humidity might be a problem for your bathroom - but you'll certainly have a slightly lower heating bill if you do this. It's not a bad idea actually. [[User:SteveBaker|SteveBaker]] ([[User talk:SteveBaker|talk]]) 19:44, 4 June 2009 (UTC)

:: According to my electric bill, 4kWh is worth almost 35c, though I would imagine that it would not apply the heat evenly throughout your dwelling (unless you have incredible outer wall insulation)[[Special:Contributions/65.121.141.34|65.121.141.34]] ([[User talk:65.121.141.34|talk]]) 19:53, 4 June 2009 (UTC)
:::Don't have the time to google for it, but there is a product that recovers heat from water and air leaving the house through bathroom vents and plumbing. Can't recall what it was called. (I think "this old house" had one in one of their shows)[[Special:Contributions/71.236.26.74|71.236.26.74]] ([[User talk:71.236.26.74|talk]]) 00:31, 5 June 2009 (UTC)o.k. found a couple of pages [http://www.thomasnet.com/about/heat-recovery-systems-37330149.html] [http://www.certifiedmoldstrategies.com/greenbuilding.htm], Matt's comment here [http://www.metaefficient.com/uncategorized/unified-design-theory-applied-bathrooms.html], [http://wiki.aia.org/Wiki%20Pages/Waste-Heat%20Recovery.aspx] <small>Ugh, should have known</small> and we do have a page [[Waste Heat Recovery Unit]] - [[Special:Contributions/71.236.26.74|71.236.26.74]] ([[User talk:71.236.26.74|talk]]) 03:59, 5 June 2009 (UTC)

:::My contingency plan for what to do in the event of a prolonged power failure in winter includes leaving the hot (and a bit of cold) water trickling into bathtubs and sinks, to keep the pipes and drains from freezing and to heat the house from the water heater. This assumes the overflow can remove the water with the drain plugged. A diverter to direct the hot water to the far end of the tub might be useful. One would get tired of a batch mode of filling the tub and then draining it after an hour, repeated 24x per day. Fireplace and kitchen range (hob) or oven could also be used to advantage, but with suitable care for carbon monoxide. [[User:Edison|Edison]] ([[User talk:Edison|talk]]) 04:49, 5 June 2009 (UTC)

== gravitational equations ==

Is/are the equation/equations for gravity at the center of a Black Hole the same as the equation/equations for gravity in unoccupied (empty) space?
--<small>--<font face="rage italic" size="4.5" color="LightSteelBlue"> [[User:taxa|Taxa]]</font> ([[User talk:taxa|talk]])</small> 17:20, 4 June 2009 (UTC)

:At the very centre of a black hole, the [[singularity]], the laws of physics break down (ie. we don't really know what happens), so there are no equations. In an appropriate coordinate system (eg. [[Kruskal–Szekeres coordinates]]) you can use the same equations to describe everywhere except the singularity, though. --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 18:47, 4 June 2009 (UTC)

:The singularity at the very center of a black hole does things to the equations that physics depends on that are essentially the same as dividing by zero on your pocket calculator. There is no meaningful answer. But a billionth of a trillionth of a gnat's eyebrow from the center, the laws of physics should be pretty well-behaved. The equations are exactly the same - but because these are rather extreme circumstances, you have to use the full relativistic forms of these equations, not the 'low speed/low gravity' approximations that we all learned in high school. [[User:SteveBaker|SteveBaker]] ([[User talk:SteveBaker|talk]]) 19:41, 4 June 2009 (UTC)
[[File:Black fly.jpg|right|200px|Eyebrows?]]
::<small>What is the length of a gnat's eyebrow in [[Planck length]]s? Does anyone know? --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 02:08, 5 June 2009 (UTC)</small>
:::<small>Well, the photo at right claims to be 100x magnification. But (...pet hate...) I'm viewing this simultaneously on a 14" monitor and an 81" plasma screen...so it's a bit hard to measure exactly! [[User:SteveBaker|SteveBaker]] ([[User talk:SteveBaker|talk]]) 04:04, 5 June 2009 (UTC)</small>
::::<small>It's a featured picture as well, I'm surprised nobody caught that... --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 12:29, 5 June 2009 (UTC)</small>

== DO GRAVITATIONAL ENERGY OF EARTH REDUCE BY TIME? ==

Earth keeps the moon in it's gravity spending it's energy .From where do earth gain this energy?
If earth do not gain energy,then is it's gravitational energy reducing by time?[[User:Surabhi12|Surabhi12]] ([[User talk:Surabhi12|talk]]) 18:06, 4 June 2009 (UTC)

:The earth does not spend energy in order to keep its moon. [[User:Dauto|Dauto]] ([[User talk:Dauto|talk]]) 18:19, 4 June 2009 (UTC)

::Well, not in classical physics. But in [[general theory of relativity|relativistic physics]], the circling moon will cause [[gravitational waves]], which will carry away some of the potential energy of the Earth-Moon system. The effect is very small, and, at the moment, entirely overshadowed by the tidal transfer of rotational momentum from the Earth to the Moon. See [[Gravitational wave#Power_radiated_by_Orbiting_Bodies]]. --[[User:Stephan Schulz|Stephan Schulz]] ([[User talk:Stephan Schulz|talk]]) 18:26, 4 June 2009 (UTC)

:The moon is falling towards the Earth, but luckily it keeps missing, just like cannonball "C" shown in the picture. It doesn't take any energy for this to happen. See [[orbit]]. --[[User:TotoBaggins|Sean]] 18:31, 4 June 2009 (UTC)
[[File:Newton_Cannon.svg|thumb]]
{{-}}

::And the Earth is falling towards the moon, but luckily the moon keeps moving out of the way ;) [[User:Gandalf61|Gandalf61]] ([[User talk:Gandalf61|talk]]) 12:30, 5 June 2009 (UTC)

:'''Somebody owes me a dollar'''. (I've decided that I'm charging the universe a dollar every time someone confuses a 'force' (gravity in this case) with 'energy' - I plan to earn enough money from this confusion to replenish my poor 401K). The [[force]] and [[energy]] are very different things. When you stick a fridge magnet onto your fridge, the magnet exerts a force on the metal. But so long as the magnet doesn't move - it doesn't take any energy whatever for it to just hang there...magnets don't "run down". It's the same with the moon. The gravity pull between earth and moon is just a force. So long as the two bodies don't get closer or further apart - there is no energy transaction involved. Forces don't "run down" - they just are. If you hang something from the ceiling with a rope - the rope exerts a force...the rope doesn't "run down". Now, if something were to pull the moon further from the earth - that 'something' would have to expend some energy to do it...if the moon (for some reason) were to fall closer to the earth - then it would actually gain energy (kinetic energy initially - then one hell of a lot of heat energy when it kersplatted into the middle of the pacific ocean!). [[User:SteveBaker|SteveBaker]] ([[User talk:SteveBaker|talk]]) 19:35, 4 June 2009 (UTC)
::Would another explanation be that the Earth is neither exerting a force nor expending energy, it is simply warping space-time such that the shortest path for the Moon to travel through the geodesic happens to be a circle? Just asking... [[User:Franamax|Franamax]] ([[User talk:Franamax|talk]]) 20:07, 4 June 2009 (UTC)
:::Now now, don't confuse a good discussion with a simple, elegent and correct answer. No one needs that now! --[[User:Jayron32|Jayron32]].[[User talk:Jayron32|<small>talk</small>]].[[Special:Contributions/Jayron32|<small>contribs</small>]] 20:34, 4 June 2009 (UTC)
:::Yes, but relativity gives people headaches! That, and the concepts Steve is talking about apply to all forces, even ones that can't be easily dismissed as mere geometry. --[[User:Tango|Tango]] ([[User talk:Tango|talk]])
::<small>I'll give you a [[Zimbabwean dollar|dollar]]. Remind me if see you - bring change! --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 02:07, 5 June 2009 (UTC)</small>
:::<small>Oooh! Thank-you! Actually - with the number of people making this error - I'm pretty sure I can still turn a profit at one [[Zimbabwean dollar]] per confused OP. :-) [[User:SteveBaker|SteveBaker]] ([[User talk:SteveBaker|talk]]) 03:58, 5 June 2009 (UTC)</small>
::::<small>Single Zimbabwean dollars are now so rare that, pervesely, they are probably now valuable to collectors. [[User:Spinningspark|<font style="background:#FFF090;color:#00C000">'''Sp<font style="background:#FFF0A0;color:#80C000">in<font style="color:#C08000">ni</font></font><font style="color:#C00000">ng</font></font><font style="color:#2820F0">Spark'''</font>]] 13:48, 5 June 2009 (UTC)</small>
::::<small>and another piece of trivia (I can't leave this one alone) is according to [[:File:ZWDvUSDchart.png|this]] the $US is now worth more than a [[mole (unit)|mole]] of the original $ZW. That must be a first for a currency. [[User:Spinningspark|<font style="background:#FFF090;color:#00C000">'''Sp<font style="background:#FFF0A0;color:#80C000">in<font style="color:#C08000">ni</font></font><font style="color:#C00000">ng</font></font><font style="color:#2820F0">Spark'''</font>]] 14:17, 5 June 2009 (UTC)</small>

== problem of race ==


Imagine:
A car travels 10km in an hour
A bus travels 20km in an hour
both have a race
Car is ahead of bus at point A.
By the time bus moves to the point A,car must have move little ahead say to point b.
By the time bus moves to the point b,car must have move little ahead again say to point c.
By the time bus moves to the point c,car must have move little ahead say to point d.
This continues .........
Thus car has to become the winner.
'''IS THIS POSSIBLE?''' <small><span class="autosigned">—Preceding [[Wikipedia:Signatures|unsigned]] comment added by [[User:Surabhi12|Surabhi12]] ([[User talk:Surabhi12|talk]] • [[Special:Contributions/Surabhi12|contribs]]) 18:30, 4 June 2009 (UTC)</span></small><!-- Template:Unsigned --> <!--Autosigned by SineBot-->

:See [[Zeno's paradoxes]]. Short answer - it takes an infinite number of steps for the bus to overtake the car but because each of those steps takes sufficiently less time than the one before the total amount of time required to overtake is finite. See [[convergent series]] for the maths behind that. --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 18:35, 4 June 2009 (UTC)

:: Another way to look at this is that suppose the car starts off with a lead of (say) 10km. We know that using 'sensible' math, that the bus will travel at a distance D in time T=D/20 hours and the car at time T=(D-10)/10 hours. When the bus overtakes the car, they are at the same distance at the same time - so we can solve the simultaneous equations and calculate T as 1 hour. The bus catches the car after 1 hour - then zooms right past it. No problem, no controversy, no paradox.

:: But the crazy Zeno's paradox way says: The time it takes the bus to reach A is 1/2 hour. By that time, the car has travelled 5km to point B. 15 minutes later, the bus reaches B and the car has gone on another 2.5km to C. 7.5 minutes later, the bus reaches C...so Zeno tells us where the bus and the car are after 30+15+7.5+3.75+1.875+... minutes. Mathematically, that infinite series adds up to 59.999... minutes. And the distance that the car and bus have travelled in that time is 19.999...km from the start. Well, that's all very interesting and exciting - but by refusing to every allow the 'victim' of the paradox to just go ahead and ask where the vehicles are after a longer amount of time, he arbitarily forces us to look only at times before the two vehicles actually meet. If you limit your calculations to only times before the vehicles meet - you're obviously never going to find the time when they do actually meet. It's not a paradox - it's a dumb way of stopping the person from answering a ridiculously simple question!

:: But why doe Xeno insist on calculating all of these intermediate positions and stubbornly refuse to calculate where they are after exactly one hour? Because he's some stupid philosopher trying to make a name for himself by inventing a "paradox". This is why philosophers are a waste of quarks. We have a perfectly simple, completely understood problem with a VERY simple, non-paradoxical conclusion...but NO...the dumb-as-a-bag-of-hammers philosopher has to insist on never calculating the answer but instead answering an infinite series of questions that we don't need to know the answer to.

:: It's really no different to me saying "What is 2+2?" - but instead of just going ahead and counting it out on your fingers, I arbitarily insist that you first calculate a totally unrelated sum: 1+0.5+0.25+0.125+... which (if you try to do it the hard way) will take you an infinite amount of time - and thereby cunningly prevent you from calculating 2+2. Why the heck would you ever want to do it like that? It's obviously a stupid and unnecessary way to answer my question. So - please treat anything any philosopher says much as you would a comedian. Amusing, possibly mildly entertaining - but in no way relating to reality. [[User:SteveBaker|SteveBaker]] ([[User talk:SteveBaker|talk]]) 19:22, 4 June 2009 (UTC)

::: Well that and your number series will only equal 2 when you are done. [[Special:Contributions/65.121.141.34|65.121.141.34]] ([[User talk:65.121.141.34|talk]]) 19:49, 4 June 2009 (UTC)
:::::I disagree - I think it is instructive to consider the "paradox" and realize that it is solved by convergence. The obvious logical solution allows the student to intuitively grasp the otherwise abstract idea that adding an infinite number of elements can still lead to a finite solution. This does have practical consequences in the study of advanced science and physics - it's an effective way to consider the parity between discrete and continuous number representations, or quantized vs. continuous physical models. [[User:Nimur|Nimur]] ([[User talk:Nimur|talk]]) 23:19, 4 June 2009 (UTC)
:::Perhaps the solution is to tell the philosopher you think he's wrong and ask him to write out the whole series just to be sure... [[User:Franamax|Franamax]] ([[User talk:Franamax|talk]]) 20:10, 4 June 2009 (UTC)
:::It is a little unfair to say philosophers are a waste of quarks in reference to ancient Greek philosophers. I agree modern ones are a waste of quarks, but in ancient times "philosophy" was a far broader subject since other things didn't exist yet. It included mathematics and what would now fall under science (but I'm not willing to call what they did science, since it didn't follow the scientific method). It easy for us now to laugh at them not understanding these simple concepts, but they are only simple to us because someone else has explained them to us. The ancient Greeks (and philosophers for quite a while after them) had some very odd ideas about infinity (as do most people today who don't have formal training in mathematics). The reason Zeno's problem seemed paradoxical to them was because they didn't think it was possible to do an infinite number of things (the idea that they got easier and easier so the total amount of resources required remained finite wasn't known to them). You may find [[Supertask]] interesting. --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 02:03, 5 June 2009 (UTC)
:::: I am reminded of a quote attributed to Johannes Keppler, though it may be apocryphal. I will paraphrase. Basically, Keppler was lecturing on the organization of the solar system, and one of his students asked something like: "Weren't people 100 years ago rather stupid, I mean, they thought the earth was the center of the Universe, and that everything revolved around us. Doesn't that that make those people rather unintelligent." To which Keppler replied something like "If they were right, and the sun DID revolve around the Earth, would the sky look any different?" which makes the point that its easy given the sum of all human knowledge of today to riducule the past thinkers as somehow stupider than us; but we have the benefit of the incremental progress we have made towards understanding the universe, a process they themselves were a part of. One could just as easily have commented that Newton was an idiot for not taking into account relativistice effects of near-light-speed travel, or that proponents of [[phlogiston]] theory were stupid when they thought heat was a substance. 100 years from now people will think we are stupid because some "scientific fact" we are certain is right turns out to be inaccurate in some way. Xeno's ideas look stupid because he didn't have the 2000 years of mathematical thought already spelled out when he devised his paradoxes. However, the basic concept that infinity is a special idea that DOES need its own set of rules to deal with was a unheardof idea at Xeno's time. The fact that anyone was thinking about the infinite several hundreds of years B.C. is pretty prescient if you ask me. --[[User:Jayron32|Jayron32]].[[User talk:Jayron32|<small>talk</small>]].[[Special:Contributions/Jayron32|<small>contribs</small>]] 02:52, 5 June 2009 (UTC)
:::I'd just like to point out that [[0.999...|59.999...=60]]. You could have just said the infinite series just adds up to an hour. Also, this paradox was formulated before infinite series (it isn't just what you get when you add all the values together), so you could only get something below 60, but arbitrarily close to it. — [[User:DanielLC|DanielLC]] 16:16, 5 June 2009 (UTC)
::::That's true - but it doesn't get Zeno off the hook. If we ask when does the hare/Achilles/bus pass the tortoise/car? Or better still we can be REALLY clear and ask: "When is Achilles ten feet ahead of the tortoise?" Then Zeno is arguing that they '''just''' meet at T=59.999...=60 - but he's not letting you find out whether the hare ever PASSES the tortoise. So this rather wonderful mathematical result doesn't help us out much! [[User:SteveBaker|SteveBaker]] ([[User talk:SteveBaker|talk]]) 02:59, 6 June 2009 (UTC)

== Labour and multiple births ==

Given that Twins, and higher number births, are individuals, do mothers ever experience a sort of delayed labor, in which the second child is born at a vastly different time or even date then their sibling? For example, Paul and John are twins, Paul is born first, and John is born 2 days later, after the mother reentered labor.--[[User:Honeymane|<font color="red" face="Old English Text MT, Papyrus">Honeymane</font>]]<sub>[[User_talk:Honeymane|<font face="Klingon, QuigleyWiggly">Heghlu meH QaQ jajvam</font>]]</sub> 19:31, 4 June 2009 (UTC)

:When someone finds a good source on the range, with some statistics, please add the data to the [[Multiple birth]] and [[Twin]] articles, which should discuss this, but currently lack any data (or even a mention). [[User:Tempshill|Tempshill]] ([[User talk:Tempshill|talk]]) 19:53, 4 June 2009 (UTC)
::If anyone wants to ask at the [[WP:Library]] for the fulltexts, here are two sources: "Management of Delayed-Interval Delivery in Multiple Gestations", S. Cristinelli ''et al.'', ''Fetal Diagnosis & Therapy'', Jul/Aug 2005, Vol. 20, Issue 4, pp.285-290. (AN 18247478) [http://web.ebscohost.com/ehost/detail?vid=1&hid=7&sid=491c959d-0678-443b-9fc1-967fbe5b23b1%40SRCSM2&bdata=JnNpdGU9ZWhvc3QtbGl2ZQ%3d%3d#db=aph&AN=18247478] and "Delayed delivery of multiple gestations: Maternal and neonatal outcomes", M. Kalchbrenner ''et al.'', ''American Journal of Obstetrics & Gynecology'', 179(5), pp1145-1149, Nov. 1998. [http://pt.wkhealth.com/pt/re/ajog/abstract.00000447-199811000-00009.htm;jsessionid=KyqczLMTpWV2G2T1CGDXQCLnWCSYcDnyb3lYf2QJhT0S5LS3MRHx!-1260103914!181195628!8091!-1]. According to the abstracts: in 6 cases studied, the delivery interval is 2:93 (median 7) days; the literature (148 cases from 1979-2001) supports 2:153 (median 31) days; and for 7 cases studied, a difference of 32.6 days. I'm rather startled at some of these numbers for delay in delivery, obviously some of the first-borns were very premature. However the absolute numbers indicate that this amount of delay is very rare. As for minor delays (<2 days), I didn't find much. I've fired off a query to my sister. [[User:Franamax|Franamax]] ([[User talk:Franamax|talk]]) 20:39, 4 June 2009 (UTC)
::Oohh, jackpot! "Twin-to-twin delivery time interval:...", W. Stein ''et al.'', ''Acta Obstetricia et Gynecologica'', 2008; 87: 346�353. [http://web.ebscohost.com/ehost/pdf?vid=1&hid=104&sid=9f8d9888-77e4-4fe2-97d8-2ddb2cb46e8f%40sessionmgr107] 4,110 "normal" deliveries, mean interval = 13.5 min (SD 17.1); 75.8% within 15 min, 16.4% within 16-30 min, 4.3% within 31-45 min, 1.7% within 46-60 min, 1.8% > 60 min. Now those are statistics! :) If anyone wants to try writing this up, I have some of the fulltexts and we can put up one of those "Refdesk significantly improved an article" thingies! [[User:Franamax|Franamax]] ([[User talk:Franamax|talk]]) 21:05, 4 June 2009 (UTC)
:::Those statistics with a median of several days are meaningless - the sample has clearly been chosen to be made up of cases with a large delay (since that is what they were studying). The rest of their results may well be interesting, but the length of the delays isn't since they were specially chosen. (The medians are probably only given in order to describe the sample chosen, not to imply anything about delayed births.) --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 01:54, 5 June 2009 (UTC)
:::Franamax, this is outstanding! I added a new "Delivery interval" section to [[Twin]], let me know what you think. The section needs the discussion of the extremely long intervals and could use discussion (beyond the stats) of the very unusual situation where labor begins and then ends, and then a month later begins again. Thanks! [[User:Tempshill|Tempshill]] ([[User talk:Tempshill|talk]]) 05:47, 5 June 2009 (UTC)
::::Looks good, I'll work a little more on those anomalous cases where labour ceases and the delay runs to several days. I also had found [http://books.google.ca/books?id=VKdiFB6IwgoC&pg=PA666&lpg=PA666&dq=delayed+delivery+multiple+gestation&source=bl&ots=8qlnMDjrIu&sig=0sHLH4dFfmAosaREitbJ9yrm3Co&hl=en&ei=iDEoStz4L8-EmQfVvqCFCA&sa=X&oi=book_result&ct=result&resnum=4#PPA666,M1 this] in Google Books (''Multiple Pregnancy'', Blickstein, Keith & Keith), which gets right into the details. Another successful RefDesk collaboration! :) [[User:Franamax|Franamax]] ([[User talk:Franamax|talk]]) 07:10, 5 June 2009 (UTC)
:::::Thanks guys!--[[User:Honeymane|<font color="red" face="Old English Text MT, Papyrus">Honeymane</font>]]<sub>[[User_talk:Honeymane|<font face="Klingon, QuigleyWiggly">Heghlu meH QaQ jajvam</font>]]</sub> 00:58, 6 June 2009 (UTC)

== helium balloon ==

If one were to take a balloon that was made of a material that could stretch an infinite amount while maintaining its structure, and filled it with enough helium for it to rise quickly, would it make it into space (assuming temperature also does not effect the structure of the helium compartment)? It is going far slower then the speed needed for orbit, but helium does escape from our atmosphere.[[Special:Contributions/65.121.141.34|65.121.141.34]] ([[User talk:65.121.141.34|talk]]) 19:58, 4 June 2009 (UTC)

:If we're going to invent materials which cannot possibly exist, why not just cast a magic spell on the balloon and teleport it to space? But seriously, the ballon would rise to a point where its density matched that of the atmosphere. For your theoretical infinitely strecthy balloon, since the volume could be infinitely large, the density could be infinitely small, which means the balloon would keep drifting up. I just have a hard time picturing a helium balloon being infinitely stretchy. --[[User:Jayron32|Jayron32]].[[User talk:Jayron32|<small>talk</small>]].[[Special:Contributions/Jayron32|<small>contribs</small>]] 20:41, 4 June 2009 (UTC)

:As I understand the way you've stated the material, the answer is maybe space, and maybe escape. It's important to remember that [[escape velocity]] is relevant only to a specific impulse of thrust. Anything that continues thrusting as it rises need not reach escape velocity ''as defined at the surface'' in order to reach escape velocity. Anyway, the balloon matches the pressure of the atmosphere and will continue to rise (and expand) until it reaches an altitude where its density is the also same as the surrounding atmosphere. This may well be higher than 100 km, which is the usual qualification for reaching "space". This further may be high enough for the solar wind to thrust it away from Earth, thus maybe escaping. In the absence of solar wind, though (and possibly in spite of it), the balloon reaches stable equilibrium -- were it to rise, it would be more dense than the surrounding atmosphere and thus sink. Were it to sink, it would be less dense and thus rise. Since it's still in the atmosphere and its movements dictated by the atmosphere, I wouldn't characterize this as an orbit and I wouldn't expect the balloon to be in free fall. &mdash; [[User talk:Lomn|Lomn]] 20:50, 4 June 2009 (UTC)
::I was going to mention how the balloon material would have a density greater than that of helium, thus we could calculate the weight of the balloon at Earth surface and add in the weight of helium it encloses and make a definite calculation of the equilibrium point where the overall density of the balloon-helium system was equal to that of the atmosphere. But of course, since it's infinitely stretchy, we can fill the balloon with all the helium on Earth ''before'' we release it, so yes, the average density approaches that of helium alone. Without some constraints, this really can't be calculated... [[User:Franamax|Franamax]] ([[User talk:Franamax|talk]]) 22:23, 4 June 2009 (UTC)

:::And below a critical density, the atmosphere will behave sufficiently like a vacuum or a sparse plasma. Once the balloon is in the ionosphere or thermosphere, buoyancy will be an insignificant force, and thermal interactions will become insignificant (although, a balloon of near-infinite volume might have sufficient number of thermal collisions to break down our cold plasma assumptions...) [[User:Nimur|Nimur]] ([[User talk:Nimur|talk]]) 23:24, 4 June 2009 (UTC)

:::You didn't give us enough information to answer your question. Tell us what's the mass of the ballon, what's the mass of the helium inside and what is the tension on the baloon's rubber, and than we may be able to give you a reasonable answer. [[User:Dauto|Dauto]] ([[User talk:Dauto|talk]]) 00:59, 5 June 2009 (UTC)
:The atmosphere has no end, so I guess the simplest answer is that it will continue to rise and expand until interactions with the rest of the solar system become more significant than interactions with the Earth (which basically means it has escaped the Earth). At some point, either bouyancy would cease to be significant or you would reach a point where the atmosphere gives way to the [[Interplanetary medium]], which I believe is mostly (ionised) hydrogen, so is less dense than helium at equal pressure (to the extent that pressure is well defined in such circumstances). However, your assumptions are clearly impossible, so the only entirely accurate answer is "anything could happen". (See [[Vacuous truth]].) --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 01:46, 5 June 2009 (UTC)
::Actually, the atmosphere has an ill-defined end; it gets infinitessimally thinner as you keep going out from the earth. This does NOT mean that it has no end; to assume it never ends is to make the same error that is made in [[Xeno's paradox]]es. (See discussion elsewhere at the ref desk on this). Eventually, the matter density of the atmosphere fades to match the average matter density of the rest of the so-called "empty space" of the rest of the solar system. At that point, we can say that the atmosphere has ended, since it has become indistinguishable from space. That line can be clearly drawn around the earth, so there is no point in saying it "never" ends. The atmosphere is a physical example of a convergent infinite series, and the operative part here is "convergent". The limit where the diminishing atmosphere converges with the rest of space we can say the atmosphere ends. --[[User:Jayron32|Jayron32]].[[User talk:Jayron32|<small>talk</small>]].[[Special:Contributions/Jayron32|<small>contribs</small>]] 03:06, 5 June 2009 (UTC)
:::By "has no end" I meant it never becomes a true vacuum, which is what would be required for this idealised balloon to stop rising and float on top of the atmosphere. I talked about the atmosphere giving way to the interplanetary medium, so I think it is quite clear that I understand what is going on... --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 03:10, 5 June 2009 (UTC)
::::Well, lets call it a misunderstanding over the use of imprecise language. It would be easy to assume that, when you say it "has no end" that the it continues on forever. It doesn't really, its just that you have to define what you mean by "end". --[[User:Jayron32|Jayron32]].[[User talk:Jayron32|<small>talk</small>]].[[Special:Contributions/Jayron32|<small>contribs</small>]] 03:32, 5 June 2009 (UTC)

== Falling for infinitly long. ==

Since I was learning about terminal velocity I was wondering that would it be physically possible for an object to have a terminal velocity greater than ''c''. If it were a point object such that A was very small, falling through an low density fluid with a low drag coefficient, and a great enough mass. If this were possible (albeit physically it would take a long time to attain it; imagine it falling through an infintly long tube), would that mean that as v--> c, the mass would go to zero. Such that its K(e) would never exceed E=mc<sup>2</sup>. Or would the mass remain the same given that E<sup>2</sup>=(mc<sup>2</sup>)<sup>2</sup>+(pc)<sup>2</sup>. Using the second equation E could increase without bound?
I would imagine a vacuum would have a drag coefficient of zero, this would make terminal velocity infinite, although a perfect vaccum is impossible. <span style="font-size: smaller;" class="autosigned">—Preceding [[Wikipedia:Signatures|unsigned]] comment added by [[Special:Contributions/24.171.145.63|24.171.145.63]] ([[User talk:24.171.145.63|talk]]) 21:16, 4 June 2009 (UTC)</span><!-- Template:UnsignedIP --> <!--Autosigned by SineBot-->
:The short answer is "no". I think we have an article, [[relativistic addition of velocities]] or some such? If not, it should redirect somewhere.
:Things are a bit more complicated if you consider the large-scale geometry of the universe -- see [[observable universe]]. One way of expressing the edge of the observable universe is that it's where galaxies are moving away from us faster than ''c''. --[[User:Trovatore|Trovatore]] ([[User talk:Trovatore|talk]]) 21:20, 4 June 2009 (UTC)
::[[Velocity_addition_formula#Special_Theory_of_Relativity]]. --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 01:38, 5 June 2009 (UTC)
:Why would the mass go to zero? [[Rest mass]] is always the same, irrespective of velocity. [[Relativistic mass]] ''increases'' as velocity increases. The total energy of a moving object is the sum of the rest energy, mc<sup>2</sup> (where m is the rest mass), and the kinetic energy (for small velocities that's mv<sup>2</sup>/2, for velocities near the speed of light you need to use relativity). The rest energy is constant, the kinetic energy increases with velocity (and increases without bound, even though the velocity is bounded above by the speed of light). --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 01:38, 5 June 2009 (UTC)

== A structural designation ==

When listing or describing archictectural structures what does HEW (insert number here) mean e.g. HEW 365, which is for the Gasworks Railway Tunnel around Kings Cross in London? [[User:Simply south|Simply south]] ([[User talk:Simply south|talk]]) 22:20, 4 June 2009 (UTC)
:I think it is the Panel for Historical Engineering Works designation; and think said panel is part of or connected with the [[Institution of Civil Engineers]]. See, for instance, the introduction to [http://books.google.co.uk/books?id=4TA262F55asC&printsec=frontcover&source=gbs_summary_r&cad=0#PPA1,M1 London and the Thames Valley], by Denis Smith, Institution of Civil Engineers (Great Britain), and then note that the book lists HEW numbers against each structure described. --[[User:Tagishsimon|Tagishsimon]] [[User_talk:Tagishsimon|(talk)]] 22:33, 4 June 2009 (UTC)
::See also [http://www.ice.org.uk/knowledge/specialist_history_board.asp ICE overview of PHEW] and a [http://www.ice.org.uk/knowledge/specialist_community_history_PHEW.asp PHEW database] with a crappy user interface --[[User:Tagishsimon|Tagishsimon]] [[User_talk:Tagishsimon|(talk)]] 22:36, 4 June 2009 (UTC)
:::Thank you for that. [[User:Simply south|Simply south]] ([[User talk:Simply south|talk]]) 23:17, 4 June 2009 (UTC)

== Understand weak interaction and beta decay ==

I tried long to understand how a force could result in β decay.

As for my knowledge I usually think of a force as a vectors (or a vector field if we speak of fields): electric force between 2 charges as 2 vectors with the same direction, the same for gravitational force, and I think I could do the same for strong force.
But when I read of weak force and its role in β decay, first I see only feynman diagrams, which I understand, but I cannot fit them with my idea of vectors. Second I see only one particle interacts with this force, when for all of the other forces there are at least 2 particles, or a field and a particle.

I conclude saying that I think I understand the basic mechanism of β<sup>-</sup> decay. So, said in really raw words: a neutron emits (on its own or there is a reason?) a W<sup>-</sup> boson, which "extracts" one unit of negative electric charge from the neutron, and the neutron is transformed in a proton. Then the W<sup>-</sup> boson decays in an electron and an electron antineutrino.

Could someone help me and clean my doubts?

[[User:ColOfAbRiX|ColOfAbRiX]] ([[User talk:ColOfAbRiX|talk]]) 23:56, 4 June 2009 (UTC)

:You said you see only one particle interacting in the beta decay, but when you gave us an example of beta decay you mentioned a neutron, a proton, a W-, an electron and an anti-neutrino. I count five different particles. Even if we exclude the W which plays the role of the "force" here, you still have four interacting particles. Forget about vectors, they won't help you here. You should think of "forces" as interactions between different fields ()The vertices of the Feynman diagrams. [[User:Dauto|Dauto]] ([[User talk:Dauto|talk]]) 01:19, 5 June 2009 (UTC)

= June 5 =
== Distribution of stellar classes ==

According to the table in [[Stellar classification#Harvard spectral classification|Harvard spectral classification]], stars of spectral class M comprise over ~76% of all [[main sequence]] stars while Sun-like stars in spectral class G comprise ~7.6% of all main sequence stars. This suggests to me that class M stars outnumber class G stars by a ratio of 10:1. My own OR suggests that is roughly true within 20 light years of the Sun, but is that ratio maintained throughout the [[Milky Way]] galaxy? Presumably similar ratios can be calculated for other spectral classes as well - I am particularly interested if some parts of the Galaxy are lacking in stars a particular spectral class. [[User:Astronaut|Astronaut]] ([[User talk:Astronaut|talk]]) 00:10, 5 June 2009 (UTC)
:I think the ratio is maintained on a large scale (presumably universally, although I'm not sure how much evidence there is to support that). I'm not sure about the distribution of different spectral classes throughout the galaxy, but there are certainly differences in the [[metallicity]] of stars in different areas (that article explains it fully). --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 01:32, 5 June 2009 (UTC)

::I saw the [[metallicity]] article, but I'm not convinced there is a strong link between metallicity and spectral class, and anyway I'm really only interested in stars in the Milky Way disc. The kind of thing I'm trying to find out is if, for example, we observed that the population density of O and B class stars in the [[spiral arms]] was typically double that in the regions between the spiral arms, could we assume the same was true of the population density of G, K and M class stars, even though we cannot observe them directly? In other words, can I use the distribution of bright stars that can be observed at great distances, to reliably infer the existance of a much larger population of dim stars at these great distances? [[User:Astronaut|Astronaut]] ([[User talk:Astronaut|talk]]) 04:39, 5 June 2009 (UTC)

:::I don't think you can do that because the O class stars are [[Main sequence#Lifetime|short lived]] (less than 10 million years) and won't have enough time to move very far from the star nursery where they are born, while smaller stars can live much longer and will have a more uniforme spacial distribution. [[User:Dauto|Dauto]] ([[User talk:Dauto|talk]]) 06:43, 5 June 2009 (UTC)

:One factor in variation of star population is related to the size of the galactic body they are in. [[Globular cluster]]s are known to lose stars through a process analogous to (and actually called by some) [[globular cluster#N-body simulations|"evaporation"]]. The lighter stars in the cluster are the most "volatile" since they will gain the highest velocities in energy exchange interactions with other stars. Globular clusters thus tend to have a relative poverty of K and M-type stars since these will be the first to achieve escape velocities. [[User:Spinningspark|<font style="background:#FFF090;color:#00C000">'''Sp<font style="background:#FFF0A0;color:#80C000">in<font style="color:#C08000">ni</font></font><font style="color:#C00000">ng</font></font><font style="color:#2820F0">Spark'''</font>]] 13:08, 5 June 2009 (UTC)

:Two important keywords for this type of question are the [[initial mass function]] (IMF) and the star formation history, and it's the latter that chiefly determines the current distribution of stellar types in a given stellar population. Starting from the IMF, an assumption about the star formation history and using stellar evolution models, one can try to model the stellar populations in various environments of the Milky Way, but also in other galaxies. Obviously, while in the Milky Way one can make a tally of individual stars, in other galaxies one only has a limited amount of information, like the colours of galaxies or integrated spectra. What a population of stars in a given area looks like at a given point in time thus depends on both the IMF and the star formation history. From modelling this sort of information one can then try to reconstruct these two factors. I'm far from being an expert in this, but my impression is that the IMF is fairly universal. There are indeed different versions that have been tried and which vary in particular at the low mass end, i.e. at late spectral types, but that controversy seems to be due more to our ignorance rather than variation in different environments. The star formation history is much more variable. Early-type stars, O and B, say, are very short-lived and can only exist in environments where stars are currently being formed. If you switch off star formation (e.g. by removing cold gas) these stars will disappear very quickly and you'll be left with a population that is dominated by late-type stars, main-sequence stars dominating by number, and red giants dominating the light output. The neighbourhood of the sun is in the disk of the Milky Way which is still forming stars, hence we might expect some early-type stars (typically forming [[OB association]]s). The bulge forms much less stars and is therefore dominated by later-type stars. The extreme cases would be "red and dead" [[elliptical galaxy|elliptical galaxies]]. --[[User:Wrongfilter|Wrongfilter]] ([[User talk:Wrongfilter|talk]]) 16:24, 5 June 2009 (UTC)

== Q about lovebirds ==

Is it true that it's impossible to keep one [[lovebird]] as a pet? Is it also true that if you have two lovebirds and one of them dies, then the other one will become depressed, stop eating and die soon after? Thanks. --[[Special:Contributions/84.67.12.110|84.67.12.110]] ([[User talk:84.67.12.110|talk]]) 00:13, 5 June 2009 (UTC)

:I've looked around and read a bunch of likely pages - and I can't find anyone that says this is true. However, it's clear that they are extremely active, intelligent, social birds and might get depressed because they don't have anything to keep them amused when their mate dies. I suspect that the myth of one bird dying and it's mate dying "of a broken heart" soon after has it's roots in the fact that if you buy two birds of the same age on the same day - keep them in the same cage and feed them the same food - then the odds are pretty good that whatever kills one of them will soon kill the other...especially if it's a bit depressed because it's bored. This would seem a lot like death from a broken heart - but in all likelyhood it's probably just that whatever killed the first one also kills the second. As for keeping just one of them - according to most of the sites I've read, it'll do OK PROVIDING you give it tons and tons of attention and keep it busy and interested in life. Having two of them relieves you of some of this huge commitment in that (to some extent) they'll keep each other amused when you aren't around. [[User:SteveBaker|SteveBaker]] ([[User talk:SteveBaker|talk]]) 03:50, 5 June 2009 (UTC)

::[http://diamond.boisestate.edu/gas/mikado/webopera/mk211.html This song] recounts a field observation of catabythismus incidental to amorous dysfunction by Petroica macrocephala, the Miromiro or New Zealand Tit, a bird of the Petroicidae (Australasian robin) family colloquially known as a tom-tit. [[User:Cuddlyable3|Cuddlyable3]] ([[User talk:Cuddlyable3|talk]]) 08:39, 5 June 2009 (UTC)

== largest possible Black Hole ==

Is there a radius at which the density of a Black Hole is so low that it is no longer a Black Hole?
--[[Special:Contributions/71.100.6.71|71.100.6.71]] ([[User talk:71.100.6.71|talk]]) 02:50, 5 June 2009 (UTC)

:No. You are correct that the density of a black hole (ie. the average density within the event horizon as viewed from a distance) decreases as the black hole grows, but there is no minimum density required to remain a black hole. --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 03:15, 5 June 2009 (UTC)

== zinc cloride ==

why zinc cloride is not weighed while it is still hot? <span style="font-size: smaller;" class="autosigned">—Preceding [[Wikipedia:Signatures|unsigned]] comment added by [[Special:Contributions/115.134.149.71|115.134.149.71]] ([[User talk:115.134.149.71|talk]]) 03:51, 5 June 2009 (UTC)</span><!-- Template:UnsignedIP --> <!--Autosigned by SineBot-->

:Nothing should be weighed while its temperature is different from the ambient temperature. If the substance it hotter than the air it will generate [[convection current]]s which can easily disrupt a sensitive balance and give an inaccurate reading. If you are going to weigh something, let it cool to room temperature so that such convection currents do not screw with the balance. Of course, you already knew all of this, because you paid attention when your chemistry teacher explained all of this to you. Right? --[[User:Jayron32|Jayron32]].[[User talk:Jayron32|<small>talk</small>]].[[Special:Contributions/Jayron32|<small>contribs</small>]] 04:02, 5 June 2009 (UTC)

== Lame flight data recorders ==

The flight data recorders presently in use on jumbo jets send out a beacon signal detectable to a reported one mile, but the planes may crash in ocean depths of up to 4 miles, such as the recent Air France jet crash. Would the acoustic beacon power have to increase as the square or the cube to be detectable at 4 times the present distance, so there would be a great likelihood of recovery? This could mean 16 times the radiated acoustic signal or 64 times, respectively. News articles also say the batteries will fail after 30 days of beeping. Why couldn't the flight data recorder have a transponder which sends out a very powerful signal only when a powerful search ship probe signal triggers it, meaning it could still be found long after the crash? [[User:Edison|Edison]] ([[User talk:Edison|talk]]) 05:26, 5 June 2009 (UTC)
:I think the deal with FDRs is that they are built to an old standard, and the standard has never been updated, because having ''one standard'' is preferable in most cases than having 100 different types of FDRs. If they are all identical, then one always knows what to look for. Actually, the better standard would seem to instead broadcast the information via a digital data stream over a satelite system. The problem is that the FDR is attached to the plane. If the flight data information were stored outside the plane, it would greatly reduce the need to recover the box. The black box could still exist as a backup. Of course, the technology exists to do exactly that; the problem would be retrofitting the worlds airplane fleet and relevent ground locations with the system, it would be a daunting task. But the technology certainly exists to devise a better system. --[[User:Jayron32|Jayron32]].[[User talk:Jayron32|<small>talk</small>]].[[Special:Contributions/Jayron32|<small>contribs</small>]] 05:33, 5 June 2009 (UTC)
::I don't know how much data they record, but surely it's enough to make every plane in the air constantly streaming it over expensive satellite bandwidth impractical. --[[User:TotoBaggins|Sean]] 14:11, 5 June 2009 (UTC)
:::Also, couldn't bad weather (like the recent Air France crash occurred in) interrupt the signal? [[User:TastyCakes|TastyCakes]] ([[User talk:TastyCakes|talk]]) 14:25, 5 June 2009 (UTC)

:In an simple isotropic medium it would generally be distance squared, but there is a correction for scattering so it is really more like <math>P \varpropto {e^{-r \over \lambda} \over r^2}</math>, where &lambda; is about 1 km in the ocean. Which means that at 4 km you get about 1/300th the power as at 1 km. A further effect is the diffraction around the [[sofar channel]] in the ocean, which makes it nearly impossible for deep accoustic signals to ever reach the surface anyway, so even with a more powerful transmitter you'd still have to dangle a deep hydrophone to hear it. [[User:Dragons flight|Dragons flight]] ([[User talk:Dragons flight|talk]]) 16:44, 5 June 2009 (UTC)

::Transmitting 4 ''miles'' would require more like 2000 times the power as transmitting 1 mile, given the formula above. [[User:Dragons flight|Dragons flight]] ([[User talk:Dragons flight|talk]]) 17:04, 5 June 2009 (UTC)

:The [[USNS Mary Sears (T-AGS-65)|''Mary Sears'']] was unable to locate the black boxes from [[Adam Air Flight 574]] using hull mounted sonar. After returning to port and equiping a [http://www.janes.com/articles/Janes-Underwater-Security-Systems-and-Technology/Towed-Pinger-Locator-30-TPL-30-United-States.html Towed Pinger Locator] she detected both at a depth of 1700m. According to ''Jane's'' a TPL can detect the signal from a max depth of 20,000 ft.&mdash;[[User:EricR|eric]] 19:31, 5 June 2009 (UTC)
::According to the Adam Air [http://www.scribd.com/doc/2486889/Aircraft-Accident-Report-AdamAir-PKKKW accident report] they were found at 2000 and 1900 meters, and the ''Mary Sears'' was required to pass within 500m of a beacon to locate them.&mdash;[[User:EricR|eric]] 20:08, 5 June 2009 (UTC)

== Radiocarbon and DNA evidence on Voynich Manuscript ==

Has the [[Voynich Manuscript]] been subjected to radiometric dating to determine the age of its materials, or to DNA testing to determine the region of their origin? [[User:NeonMerlin|<span style="background:#000;color:red;border:#0f0 solid;border-width:1px 0">Neon</span>]][[User talk:NeonMerlin|<span style="background:#0f0;color:#000;border:red solid;border-width:1px 0">Merlin</span>]] 05:41, 5 June 2009 (UTC)
:According to [http://www.yale.edu/tnj/content/feb09/pods.html this Yale journal] (scroll down to "Shelf Life"), dated February 2009, "two outside specialists are analyzing the pigments in its ink and carbon dating a tiny sample of its vellum." I haven't come across any reports of their findings, though. [[User:Deor|Deor]] ([[User talk:Deor|talk]]) 15:02, 5 June 2009 (UTC)
::<small>Is it a coincidence that this question came [http://xkcd.com/593/ today]? [[User:Jørgen|Jørgen]] ([[User talk:Jørgen|talk]]) 17:02, 5 June 2009 (UTC)</small>
:::<small>My guess is that Merlin's inquiry was sparked after reading Mr. Munroe's comic this morning, and not by chance. 17:07, 5 June 2009 (UTC)</small>

== Electrical power usage of computer ==

Hi, in this green age I guess it's relevant to ask this question. I've always been told to leave my computer on all the time, as repeated on/off switching could not only damage the switch, it causes electrical spikes which could damage the motherboard(?) over time. However, now my latest concern is that leaving it on consumes at least 600W per hour (that is the size of the power supply unit with the fan). Is this true? When the computer goes into power saving mode (turn off monitor and hard disk) - how much less does it use? Would it use even less if I tell the computer to hibernate during times of no usage? [[User:Sandman30s|Sandman30s]] ([[User talk:Sandman30s|talk]]) 09:24, 5 June 2009 (UTC)

:While there is certainly some increased wear and tear from turning it on and off, I don't think it is much to worry about. If you're just stepping away for 10 minutes it probably isn't worth turning it off, but if it is going to be several hours it would be good to. It's difficult to say how much power it uses at different times, it varies from computer to computer, but the 600W figure would be a maximum (plus whatever your monitor uses and any other equipment that has its own mains plug), it won't use that all the time. You can get a power meter that goes inbetween the plug and the mains socket that will tell you exactly what it is using, I think most high street electrical stores will have them. Hibernation is actually the same as turning it off completely, the only difference is that it saves its current state to the hard drive so it can load back to the same point when it turn it back on. It will probably still use some power when switched off unless you unplug it or switch it off at the mains (see [[Wall wart]]). Leaving it on standby will use a significant amount of power. --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 12:37, 5 June 2009 (UTC)
::Thanks, I think I'll do some tests with a power meter. [[User:Sandman30s|Sandman30s]] ([[User talk:Sandman30s|talk]]) 13:27, 5 June 2009 (UTC)

:::Also, note that in the winter, if you heat your house with electrical heating, you can just leave your computer on as all "wasted" energy contributes to heating your house anyway. (and conversely, if you use AC in the summer, you waste "double" the energy by leaving the computer on (I'd think?)) [[User:Jørgen|Jørgen]] ([[User talk:Jørgen|talk]]) 13:54, 5 June 2009 (UTC)
::::Both of your estimates are accurate - in data centers, it is estimated that total electric bills are equal to 2 times the power consumption of the electronics - this is a very common rule of thumb for estimating costs. This means that for each watt of useful electronics, an extra watt is necessary for air conditioners. It's hard to grasp this heating/air-conditioning concept intuitively - you "know" your computer is warm, but it's not that big... If you have the chance to visit a server-room, get permission to walk BEHIND one of the rack cabinets - behind a rack of 40 high-performance systems - you'll be blasted by the hot-air fan output which might reach a hundred kilowatts - it's like a furnace! [[User:Nimur|Nimur]] ([[User talk:Nimur|talk]]) 14:53, 5 June 2009 (UTC)

:::::Thanks for the info! This should mean that environmentally friendly data centers should be placed in the basements of large offices / residential buildings in cold areas, so that the excess heat can be used to heat the building. I think I've read some articles on large data processing centers being located in places where hydro power is prevalent, or where there is a river available for cooling, both of which would be fine, but I think that placing them in cold areas - pumping cold air in (in some controlled process, of course) to cool the components and using the excess heat for heating - would be an even better approach? Now, I know the logistics of this might be hard, but I'm sort of surprised that no fringe-targeted "environmentally friendly cluster" has marketed this yet. (Oh, and sorry for hijacking the question) [[User:Jørgen|Jørgen]] ([[User talk:Jørgen|talk]]) 15:08, 5 June 2009 (UTC)

::::::The use of cold, outside air as a source of cooling for data centers is already an accepted solution in some areas. Care must be taken that outside air does not introduce fine particulates that might damage equipment, and the temperature and humidity of incoming air must be tuned; these challenges and concerns have delayed the adoption of so-called ''[[Economizer#HVAC|air-side economizer]]s'' or ''[[outside air economizer]]s''. Nevertheless, some more recent studies (by Intel and some electrical utilities; linked from our articles) have allayed fears over these risks. Here's an article about a Canadian firm that gets about 65% of their data center cooling from outside air: [http://searchdatacenter.techtarget.com/news/article/0,289142,sid80_gci1246084,00.html]. [[User:TenOfAllTrades|TenOfAllTrades]]([[User_talk:TenOfAllTrades|talk]]) 16:51, 5 June 2009 (UTC)

:::::::Thanks! Good to see that good ideas are put to use. [[User:Jørgen|Jørgen]] ([[User talk:Jørgen|talk]]) 17:00, 5 June 2009 (UTC)

:::::::In [http://www.computerworld.com/action/article.do?command=printArticleBasic&articleId=9049898 this interview with an IT manager working at the South Pole], he says that at their old data center somebody had just cut a hole in the wall to cool everything inside. [[User:Tempshill|Tempshill]] ([[User talk:Tempshill|talk]]) 17:33, 5 June 2009 (UTC)

== Satellite photos of London from today (5th June 2009) ==


Hi,
Hi,


What is the difference between an auxotroph and a fastidious organism? It seems to me the second one would have more requirements than the first one, but the limit between the two definitions is rather unclear to me.
Is there any way of getting these? I realise live satellite feeds probably aren't available but what about ''very quickly'' archived pictures? --<font color="grey">[[User:Rixxin|Rixxin]] ([[User talk:Rixxin|talk]])</font> 11:26, 5 June 2009 (UTC)

:Photos from weather satellites, maybe. What kind of resolution are you looking for? --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 13:28, 5 June 2009 (UTC)
::Honestly? This is sure gonna sound lame. I was interested to see if there was a big 'ol dark cloud over [[The Palace of Westminster]] today, 'cos it sure felt like there should be!--<font color="grey">[[User:Rixxin|Rixxin]] ([[User talk:Rixxin|talk]])</font> 16:43, 5 June 2009 (UTC)
:::Well, there was a big dark cloud over the whole of England, pretty much... See [http://www.metoffice.gov.uk/weather/uk/se/se_latest_vissat.html here] for visible light satellite images of London and the South East of England over today (one per hour). I can't find a close up of Westminster, but the weather was pretty consistent so it doesn't really matter. --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 18:51, 5 June 2009 (UTC)

:The day will undoubtedly come when we will be able to view any part of the earth in real time, and zoom in on places of interest. Wars could be watched as they took place. Imagine what it would have been like to watch the D-Day invasion in real time.. – GlowWorm. <span style="font-size: smaller;" class="autosigned">—Preceding [[Wikipedia:Signatures|unsigned]] comment added by [[Special:Contributions/98.21.107.157|98.21.107.157]] ([[User talk:98.21.107.157|talk]]) 18:44, 5 June 2009 (UTC)</span><!-- Template:UnsignedIP --> <!--Autosigned by SineBot-->

::::Actually, you could have watched it in real-time, [http://www.archives.gov/northeast/boston/exhibits/homefront/images/3.07-d-day.jpg with the right equipment]. --[[Special:Contributions/98.217.14.211|98.217.14.211]] ([[User talk:98.217.14.211|talk]]) 19:57, 5 June 2009 (UTC)
::It's very unlikely that such a thing would ever happen, however such a nice idea it may be. Think about it. If satellite pictures of battles were freely available on the internet as the battles were taking place, they would be available to both sides and would present serious problems (and of course, advantages) to both sides. --[[User:KageTora|KageTora - (영호 (影虎))]] ([[User talk:KageTora|talk]]) 19:11, 5 June 2009 (UTC)

::You would need millions of satellites, and much more bandwith the entire Internet has today.. --[[Special:Contributions/131.188.3.20|131.188.3.20]] ([[User talk:131.188.3.20|talk]]) 22:34, 5 June 2009 (UTC)
:::Half a century ago it would have sounded ridiculous that everyone was walking around with their own personal mobile phone. You could not build enough transmitters, and where would all the bandwidth come from? Technology will continue to improve apace and if you cannot think of a fundamental theoretical reason to stop such things happening, then they probably will if people want them to. [[User:Spinningspark|<font style="background:#FFF090;color:#00C000">'''Sp<font style="background:#FFF0A0;color:#80C000">in<font style="color:#C08000">ni</font></font><font style="color:#C00000">ng</font></font><font style="color:#2820F0">Spark'''</font>]] 00:04, 6 June 2009 (UTC)

::::Indeed. If you are willing to wait 50 years, almost anything is possible unless it is explicitly impossible (and maybe even then!). I believe three satellites in geostationary orbit with cameras with amazing resolution could cover most of the Earth, all it needs is for someone to invent the cameras and that could easy happen in the next 50 years. --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 00:08, 6 June 2009 (UTC)

:::::It's not the satellites or the cameras - providing whole-earth, realtime coverage (as we've discussed recently) requires insane amounts of hardware - but it's not disallowed by the laws of physics. HOWEVER - what is disallowed is the bandwidth you need to get all of that data back down to earth. 500 million square kilometers - 500 trillion square meters. 50 quadrillion pixels. About 500 quadrillion bits with lossy data compression. For a 'realtime' update - you need to send that between maybe 10 and 60 times a second. So 5 quintillion bits per second. That's a truly outrageous amount of data - it would fill a million hard disk drives every second. It's more data than is available on the whole of the internet...every second. This is not merely an engineering difficulty - it's a serious "fundamental laws of physics" kind of a problem. If we had a million satellites - all with tight-beam laser links to the ground so they didn't interfere with each other - then it would be pretty much impossible - but to do it with three satellites! That's just impossible. [[User:SteveBaker|SteveBaker]] ([[User talk:SteveBaker|talk]]) 02:52, 6 June 2009 (UTC)
::::::a) What law of physics are you suggesting is being violated? b) you're making the same mistake you made last time - there is no need to transmit all the data, just the data that someone wants to receive and c) you are making meaningless comparisons - what do hard drives have to do with anything? No-one is asking you to store the data. Really, Steve, you should know better than to cavalierly claim something is physically impossible. --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 12:29, 6 June 2009 (UTC)

:::::Nanotechnology could be a way to do it. Millions of tiny satellites could be put into orbit. Each satellite would consist of a group of molecules forming a camera and a radio transmitter having a broad beam, Each satellite would be solar powered, with a rechargeable battery for nights. Each camera would be aimed at a certain place on the earth and thus would need only a narrow transmitting bandwidth. The camera would be kept in its earth-aim by viewing certain stars and automatically making aim correction using solar power. The viewer on earth would select the radio frequency of the satellite aimed at the part of the world he is interested in. He would do this by selecting a square on a grid map on his monitor. He could enlarge the picture received, or combine the adjacent pictures of several satellites to cover a larger area. The satellites would not have to be in geocentric orbits, thus preventing overcrowding of that orbit, and permitting good near-polar coverage by using polar orbits with some satellites. Automatic switching would transfer reception from satellite to satellite to maintain the selected view of the earth as the satellites move. Automatic viewing-angle correction would also take place to provide an overhead view or angle view. The satellites could be manufactured cheaply by the millions in a nanofactory. They would be so small and light that they could be put into orbit and replaced at low cost. – GlowWorm.

::::::Steve is being a bit negative here. Updates 60 times a second are not necessary for ''still'' pictures to be considered real-time, that's only necessary if you want video. One a minute might do, which would take three or four orders of magnitude off Steve's figures. Even if the aggregate data rate really is ~10<sup>18</sup> b/s, each individual user does not want ''all'' of that at the same time on one channel, nor is each individual satellite supplying all of that on one channel. This is what networks are for, they are composed of many channels. As for the number of hard drives required to store the data, well you only need them for the data you want to store, you don't have to store any of it if you don't want to. [[User:Spinningspark|<font style="background:#FFF090;color:#00C000">'''Sp<font style="background:#FFF0A0;color:#80C000">in<font style="color:#C08000">ni</font></font><font style="color:#C00000">ng</font></font><font style="color:#2820F0">Spark'''</font>]] 12:27, 6 June 2009 (UTC)

== Is it really true that Planes which cruise at high altitude get hit by lightning? ==

Hi All,

I just keep wondering if the latest French Aeroplane's accident is really due to lightning. As I understand, at the hights of over 28k feet, there are no rainbearing clouds, in fact (again within my limited knowledge)these clouds are much below. As such there shouldn't be lightning too. Am I correct in my understanding? Would appreciate if people could enlighten me on the same.

Warm Regards,
Rainlover_9 [[User:Rainlover 9|Rainlover 9]] ([[User talk:Rainlover 9|talk]]) 14:22, 5 June 2009 (UTC)

:See [[upper-atmospheric lightning]]. [[User:Gandalf61|Gandalf61]] ([[User talk:Gandalf61|talk]]) 14:26, 5 June 2009 (UTC)

::Planes DO get hit by lightning - but not "Upper Atmospheric Lightning)!! Upper-atmospheric lightning is WAY above where a plane flies. A plane will fly at about 35,000 feet - only about 10 km above the ground. The phenomena referenced in [[upper-atmospheric lightning]] are more appropriately called "Transient Luminous Events" because they are neither lightning, nor do they take place in the "atmosphere" (largely being above the stratosphere and in the lower boundary layers of the ionosphere). There is no way even a military aircraft would fly at those altitudes (80 or 100 km above the ground). Airplanes can and do get hit by [[troposphere|tropospheric]] lightning when they fly close to or through a storm - and some [[cumulonimbus clouds]] might have storm tops as high as 60,000 feet above ground. It is ''this type of lightning'' - typically a cloud-to-cloud strike - that results in the occasional airplane strike. [[User:Nimur|Nimur]] ([[User talk:Nimur|talk]]) 14:59, 5 June 2009 (UTC)

::: I have seen a photo of lightning striking up from a cloud as well, so that could be a possibility. Also, an airplane flying along might build up its own static charge, and may become a lightning target by itself, similar to how lightning will go from cloud to cloud. [[Special:Contributions/65.121.141.34|65.121.141.34]] ([[User talk:65.121.141.34|talk]]) 15:03, 5 June 2009 (UTC)

== Is 2 + 2 = 4 in other universes ==

Hello, while wandering about on the Internet I came across this interesting question on Yahoo Answers:

"Is 2 + 2 = 4 in other universes?
Assuming that parallel universes exist, would their mathematics be the same as ours? I.e. could there be a universe in which, for example, 2 + 2 = 5?"

People may be interested in the answers posted:
http://au.answers.yahoo.com/question/index;_ylt=AvNVaIojr7pEw1Bn_IyyzxoJ5wt.;_ylv=3?qid=20090603213159AAKkQK1

Since the theory of multiple universes was derived using the maths that we understand, then it follows that the maths on parallel universes MUST be the same. Otherwise, it would make the theory inconsistent. That's my guess, I was just wondering what others might think about this.

[[Special:Contributions/203.206.250.131|203.206.250.131]] ([[User talk:203.206.250.131|talk]]) 14:29, 5 June 2009 (UTC)

Unless they use different numbers, then it's probaly going to be the same. If you have 2 things and add 2 more it's going to be 4 everytime. --[[User:Abce2|<font face="Fantasy" color="#36F">Abce2</font>]]|<small>[[User Talk:Abce2|<font face="Verdana" color="#09A">''Access''</font>]][[Special:Contributions/Abce2|<font face="Papyrus" color="#FA1">''Denied''</font>]]</small> 14:31, 5 June 2009 (UTC)

Actually I would disagree and say there definitely could be universes where 2+2=5 or even 2=3. The whole idea behind a theorectical multiverse is there are an infinite number of universes in which the laws of physics, logic and math can be different. Time could run backwards, accelerate, or not exist at all. Keep in mind math has never been proven to be (maybe once we get a [[grand unification theory]] it will be)the basis of reality but simply a representation which we've created. But either way, even with a G.U.T. this would only prove math is immutable in OUR universe, others could be entirely different. [[User:TheFutureAwaits|TheFutureAwaits]] ([[User talk:TheFutureAwaits|talk]]) 14:56, 5 June 2009 (UTC)

:A better way to phrase this question is, "Suppose a hypothetical universe existed where 2+2 != 4. What would be the consequences?" I do not think there are any verifiable consequences of such a statement, so it is a non-scientific question. I think I'll leave my response at that, and we can just wait for SteveBaker to show up and remind everyone that needless philosophizing is wasting quarks... [[User:Nimur|Nimur]] ([[User talk:Nimur|talk]]) 15:03, 5 June 2009 (UTC)<br />

:(ec)Personally i think maths evolved from what you see. If you have two balls and someone else gives you two more balls, you find out that you have four balls. This process is called addition. So, maybe, just maybe, there might be a universe where if you have two balls already and i give you two more, another one automatically materializes and you get 5. This is a physical law in the universe that whenever you give two more balls, an additional one should materialize. In this particular universe, i am inclined to believe that 2+2 will indeed be 5, and hence all our mathematics breaks down. So, if there can be universes with different physical laws, this might well be possible, so i think it cannot be said with certainty that 2+2 is always 4. It can just as well be any other number, though it is hard to visualize in this example how it can be a fraction(''half'' a ball? ''pi'' times a ball?) I am assuming decimal systems used in all universes. [[User:Rkr1991|Rkr1991]] ([[User talk:Rkr1991|talk]]) 15:09, 5 June 2009 (UTC)

:It depends on your definitions of 2, +, = and 4. If you define them the same way as we define them, which is not dependant on the universe, then you'll get the same answers. However, life in other universes may well define them differently if different definitions are useful for them. Mathematics and universes are separate things linked by models. We model parts of the universe on mathematical things. To use Rkr1991's example, balls are well modelled in our universe by natural numbers, they might not be well modelled by natural numbers in other universes. That doesn't mean natural numbers are any different, just that they wouldn't be used. There are all kinds of possible number systems in mathematics but we generally only use the ones which are useful for describing our universe. --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 15:20, 5 June 2009 (UTC)<br />

::I disagree with Tango. Even if you define 2, +, = and 4 exactly the same way in our system, the problem posed in my example remains unresolved. As i said earlier, i think maths was derived from what we observe, not hard solid facts. Maths and our universe cannot be separated, and it cannot exist independently. So if we see 2 balls and 2 balls make 5 balls in a universe, then i think our maths indeed breaks down there. [[User:Rkr1991|Rkr1991]] ([[User talk:Rkr1991|talk]]) 15:38, 5 June 2009 (UTC)

:::I agree with Tango. If we see 2 balls and 2 balls make 5 balls, we will reasonably deduce that our definitions of 2, +, = and 4 are no longer useful, and we will redefine one of them. But unless we do that, if instead we keep 2 defined (as is most common) as the set <nowiki>{{}, {{}}}</nowiki> and + through [[Peano axioms#Arithmetic|Peano arithmetic]], 2 + 2 cannot suddenly become 5. It's not like mathematics defines 2 + 2 as "the number of physical objects in the collection resulting from putting two physical objects together with two other physical objects". Correspondence with that physical result is of course the reason for our definitions (that's why Peano chose the axioms he did, etc), but it ''is'' not the definition. —<small>[[User:Jao|JAO]] • [[User talk:Jao|T]] • [[Special:Contributions/Jao|C]]</small> 15:54, 5 June 2009 (UTC)

:::Our definitions of arithmetic are axiomatic, not empirical. Observations don't come into it other than to determine whether those definitions are useful. --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 16:29, 5 June 2009 (UTC)

:(e/c) Math was originally derived from experimentation, but this is no longer the case. A mathematical theory is made by a group of axioms and is supposed to be interesting. People will find parallels between the mathematical theory and the universe, and use that to make scientific theories. You could have a universe where the strength of gravity is not inversely proportional to the square of the distance, but that just means gravity will be modeled with different mathematics. All that being said, there could be universes where it's possible to build a [[hypercomputation|hypercomputer]], and it would be possible to do more sophisticated math. It's not that they'd get different theorems for the same theory (2+2=4 would still be true), it's that they'd be able to use [[axiom schema]]s that we cannot. For example, they might be able to find out if every even number above four is the sum of two odd primes by checking every case, something physically impossible in our universe. — [[User:DanielLC|DanielLC]] 16:03, 5 June 2009 (UTC)

:I would like to point out that there are things that appear axiomatic that are in fact dependent on unstated assumptions. Euclid teaches, and people agreed for quite some time, that the interior angles of a triangle ''always'' add up to 180º. That's been a basic theorem of geometry for hundreds of years, and is as easy to demonstrate as 2+2=4. Of course, unstated is that only works if you are talking about a triangle on a 2-D plane—if you are sketching the triangle on a 3-D surface, it isn't true at all. A triangle on a sphere can have interior angles that add up to more than 180º. There's an unstated limiting factor in Euclidean geometry—that it only applies to 2-D surfaces—that becomes clear if you actually start, say, drawing large triangles on the ground (and you happen to live on a sphere).
:I don't know enough about number theory to say whether there could be something analogous with arithmetic, but it's worth considering. --[[Special:Contributions/98.217.14.211|98.217.14.211]] ([[User talk:98.217.14.211|talk]]) 17:21, 5 June 2009 (UTC)


Thank you [[Special:Contributions/212.195.231.13|212.195.231.13]] ([[User talk:212.195.231.13|talk]]) 23:17, 27 December 2024 (UTC)
::No good mathematician would leave those assumptions unstated, at least in formal work. Everything in mathematics is based on assumptions. Results are always of the form "A implies B" never simply "B". One of the key things that is drilled into any mathematics student, however, is to always state your assumptions. --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 18:01, 5 June 2009 (UTC)
:I'm not 100% sure, but it seems to me that an auxotroph is a specific type of a fastidious organism. [[Special:Contributions/2601:646:8082:BA0:9052:E6AF:23C7:7CAF|2601:646:8082:BA0:9052:E6AF:23C7:7CAF]] ([[User talk:2601:646:8082:BA0:9052:E6AF:23C7:7CAF|talk]]) 03:02, 28 December 2024 (UTC)
:Symbiosis aside, it would seem that most auxotrophs would be fastidious organisms, but there could be many more fastidious organisms that aren't auxotrophs. Auxotrophs specifically can't produce organic compounds on their own. There are a LOT of organisms that rely on the availability of non-organic nutrients, such as specific elements/minerals. For instance, vertebrates require access to calcium. Calcium is an element; our inability to produce it does not make us auxotrophs.
:But perhaps symbiosis would allow an organism to be an auxotroph without being a fastidious organism? For instance, mammals tend to have bacteria in our guts that can digest nutrients that our bodies can't on their own. Perhaps some of those bacteria also assemble certain nutrients that our bodies can't? -- [[User:Avocado|Avocado]] ([[User talk:Avocado|talk]]) 14:27, 28 December 2024 (UTC)


= December 28 =
::If 2+2 *always* equalled 5, then the alternate universe's laws of mathematics would likely look a lot like ours (though perhaps a bit more cumbersome). However, consider a universe in which 2+2 sometimes was 4, sometimes 3, sometimes 5, etc. In a sense, we live in such a universe now. The math we use to deal with this is statistics. Two random variables, when added together, can give you different answers each time you observe them. [[User:Wikiant|Wikiant]] ([[User talk:Wikiant|talk]]) 18:06, 5 June 2009 (UTC)


== Paper with wrong enantiomer in a figure ==
:::In which case they wouldn't model items as numbers but rather as random variables. Mathematics includes all kinds of tools, you need to use the right one for the right job. Just because one tool isn't right for a particular job doesn't mean that it is wrong mathematically. --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 18:10, 5 June 2009 (UTC)


In the following reference:
::I would like to leap to the defence of Euclid on this one. Euclid realised perfectly well that the angles in a triangle summing to 180º was not axiomatic but was dependant on the [[parallel postulate]] and clearly states this as a postulate in his ''Elements'' (postulate 5). It was later mathematicians who through the centuries refused to believe that the parallel postulate could not somehow be proved from other basic postulates. It was only finally admitted that Euclid was right when Einstein discovered that the universe was not, in fact, Euclidean and that other geometries were possible in the real world as well as in the minds of mathematicians. [[User:Spinningspark|<font style="background:#FFF090;color:#00C000">'''Sp<font style="background:#FFF0A0;color:#80C000">in<font style="color:#C08000">ni</font></font><font style="color:#C00000">ng</font></font><font style="color:#2820F0">Spark'''</font>]] 23:06, 5 June 2009 (UTC)
:{{cite journal |last1=Quack |first1=Martin |last2=Seyfang |first2=Georg |last3=Wichmann |first3=Gunther |title=Perspectives on parity violation in chiral molecules: theory, spectroscopic experiment and biomolecular homochirality |journal=Chemical Science |date=2022 |volume=13 |issue=36 |pages=10598–10643 |doi=10.1039/d2sc01323a |pmid=36320700}}
:::Einstein '''used''' [[non-Euclidean geometry]], he didn't invent it. The geometry Einstein used was mostly constructed by [[Bernhard Riemann]], I believe, although several people had done work on the subject before him. Non-Euclidean geometry was known to be relevant to the real world before Einstein came on the scene - we live on the surface of a sphere, which in non-Euclidean. It doesn't matter anyway, you don't need a real world application to prove that the parallel postulate is independent of the preceding four. --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 12:08, 6 June 2009 (UTC)
it is stated in the caption of Fig.&nbsp;8 that ''S''–[[bromochlorofluoromethane]] is predicted to be lower in energy due to [[parity violation]], but in the figure the wrong enantiomer is shown on this side. Which enantiomer is more stable, according to the original sources for this data? –[[User:LaundryPizza03|<b style="color:#77b">Laundry</b><b style="color:#fb0">Pizza</b><b style="color:#b00">03</b>]] ([[User talk:LaundryPizza03|<span style="color:#0d0">d</span>]][[Special:Contribs/LaundryPizza03|<span style="color:#0bf">c̄</span>]]) 08:18, 28 December 2024 (UTC)
:Are we really debating this? If I have two apples on a table, and place two more apples on the same table, I now have four apples on the table. If I lived in a universe where an extra apple materialized merely because I placed two groups of two next to each other, such a universe would violate the principle of causality so as to be entirely unexplainable at any level. Seriously, why is this even being debated to this level? --[[User:Jayron32|Jayron32]].[[User talk:Jayron32|<small>talk</small>]].[[Special:Contributions/Jayron32|<small>contribs</small>]] 19:00, 5 June 2009 (UTC)


== Where can I find data on the circulation and citation rates of these journals? ==
::Your example only violates causality if it is true that 2+2=4. So, your argument boils down to the circular "2+2 must equal 4 because if it didn't, 2+2 wouldn't equal 4." For a possible counter-example, consider this universe wherein subatomic particles and anti-particles spontaneously emerge. This could be interpreted to suggest that 0+0=2. [[User:Wikiant|Wikiant]] ([[User talk:Wikiant|talk]]) 21:05, 5 June 2009 (UTC)


Hello everyone, To write an article about a scientist, you need to know, where can I find data on circulation and citation rates of journals from [https://pubmed.ncbi.nlm.nih.gov/?term=%22Trump%20D%22%5BAuthor%5D this list]? [[User:Vyacheslav84|Vyacheslav84]] ([[User talk:Vyacheslav84|talk]]) 09:58, 28 December 2024 (UTC)
::Why should another universe obey our universe's laws of causality? It isn't difficult to imagine a universe with two timelike dimensions, which would have very different principles of causality. (I think I read a paper once about such a universe and the conclusion was that complex life almost certainly couldn't evolve in it, but that's not important.) --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 21:15, 5 June 2009 (UTC)


== So-called “Hydrogen water” ==
:This reminds me of David Deutsch's concept of "cantgotu" environments in [[The Fabric of Reality]], but I can't remember what if anything he said about the idea of 2+2 not equaling 4. He deals with this general kind of idea, though. [[Special:Contributions/213.122.1.200|213.122.1.200]] ([[User talk:213.122.1.200|talk]]) 22:01, 5 June 2009 (UTC)


I saw an ad promoting a device which presumable splits water into
:: No, no, no. You can't use things popping into existance or whatever to envisage a scenario when 2+2 doesn't equal 4. In our universe, 0.9 times the speed of light plus 0.9 times the speed of light equals 1.8 times the speed of light (yes, it really does). However, if you're '''travelling''' at 0.9 times the speed of light relative to me and you toss a ball out in front of you at 0.9 times the speed of light, it won't be moving at 1.8 times the speed of light relative to me - it'll be more like 0.99. That's not because 0.9+0.9 doesn't equal 1.8 - it's because the arithmetic operator '+' doesn't apply to speeds as we humans always thought it did. This really shouldn't be a surprise, the '+' operator doesn't apply to a while lot of things!
hydrogen and oxygen and infuses water with extra hydrogen, to
:: So if two subatomic particles pop out of nowhere, that doesn't prove that 0+0=2 - it proves that the total number of particles in some volume of space is not a constant - so addition is (again) not an appropriate operation to apply to them.
a claimed surplus of perhaps 5 ppm, which doesn’t seem like much. I found a review article which looked at several dozen related studies that found benefits:https://pmc.ncbi.nlm.nih.gov/articles/PMC10816294/ .
:: The point is that things like '+', '2', '=' and '4' are symbols that stand for concepts that have definitions that humans have applied to them. Our definition says that 2+2=4 - not because that necessarily represents something "real" but because that's what we've defined those symbols to mean.
:: Suppose I were to define the symbol '#' to mean "''the sum of two numbers - except when there is a full moon, when it's the product of two numbers''" - then 2#2=4 happens to be a true statement...but 3#3=6 isn't '''''always''''' true and 7#9=5 is '''''never''''' true. There isn't any deep inner meaning in what I just said - it's just words and definitions. There is probably no physical property of our universe for which the '#' operator is applicable - but my definition is still a perfectly reasonable one and 2#2=4 no matter what. Perhaps in another universe, placing apples on tables follows the '#' operator - but the '+' operator is kinda useless and considered weird to the people who live there, (who are constantly checking their almanacs to see when the next full moon will be!)
:: So this universe does whatever it does - the other universe does whatever it does - and whether our definitions for the symbols '2', '+', '=' and '4' are applicable to apples placed on tables in that other universe (or to the way speeds are combined) is a matter that we can't answer. But our definitions still apply - you can't invalidate something that's axiomatic in the system of mathematics you choose to use.
:: Hence, the answer is a clear "yes" - 2+2=4 everywhere - because we happen to have defined it that way. [[User:SteveBaker|SteveBaker]] ([[User talk:SteveBaker|talk]]) 22:27, 5 June 2009 (UTC)


I’ve noticed that carbon dioxide or chlorine (chloramine?) dissolved in water work their way out pretty easily, so I wonder if dissolved hydrogen could similarly exit hydrogen enriched water and be burped or farted out, rather than entering the blood stream and having health benefits. is it more than the latest snake oil? [[User:Edison|Edison]] ([[User talk:Edison|talk]]) 23:01, 28 December 2024 (UTC)
:I'm going to expand upon what's been said above, because hopefully it'll sort out some confusion. Back off a bit - say we're in a parallel universe which doesn't have the same laws of math. First let's start with a quantity. Names are arbitrary, so let's call it "'''@'''". That's going to be boring by itself, so we'll make another quantity, and we'll call it "'''!'''". Independent quantities by themselves aren't interesting, so let's add an [[Operation (mathematics)|operation]]: "'''%'''". How does this operation behave? It might be nice to have an identity, that is, if we 'percent' a quantity with the identity, we get the other number back. It's arbitrary which one we choose, as they are the same, so let's pick ''''@''''. So we have ''''@ % @'''' => ''''@'''' and ''''! % @'''' => ''''!''''. Okay, but now what about ''''! % !''''? Well, we could say that ''''! % !'''' => ''''@'''', or even ''''! % !'''' => ''''!'''', but we can also introduce a new symbol, so let's do that and call it ''''&''''. So ''''&'''' is defined as ''''! % !''''. Now what is ''''& % !''''? Keeping it open ended we define it to be ''''$''''. And ''''$ % !'''' => ''''#''''. Now, let's figure out what ''''& % &'''' is. Since ''''&'''' is the same as ''''! % !''''; we see that ''''& % &'''' is ''''(! % !) % (! % !)''''. If we say that order in which we 'percent' doesn't matter ([[associative property]]), we can rewrite that as ''''((! % !) % !) % !'''', or ''''(& % !) % !'''' or ''''$ % !'''', which we defined earlier as ''''#''''. As long as ''''! % !'''' => ''''&'''', ''''& % !'''' => ''''$'''', ''''$ % !'''' => ''''#'''', and the ''''%'''' operation has the associative property, ''''& % &'''' => ''''#''''. Hopefully you can see where I'm going with this; the names I gave them were arbitrary. I could have easily have said 0 instead of @, 1 for !, 2/&, 3/$, 4/# and +/%, and you have your situation. If we have defined 1+1=2, 2+1=3, 3+1=4, and addition as associative, then 2+2=4. If 2+2=5, then either 3+1=5, 1+1≠2, or addition is not associative. We certainly could call 3+1, '5' if we wanted, but it would behave exactly the same way 4 does now. It would be the equivalent of writing 'IV' instead of '4' - the name changes, but the properties stay the same. Conversely, with addition being non-associative, why call it "addition"? Associativity is part of what defines addition - if you change that, you have something else.
:Yes, the dissolved hydrogen will exit the water just as quickly (even faster, because of its low [[molecular mass]] and complete lack of [[polarity]] or capability for [[ionic dissociation]]), and even if it does enter the bloodstream, it will likewise get back out in short order before it can actually do anything (which, BTW, is why [[deep-sea diver]]s use it in their breathing mixes -- because it gets out of the bloodstream so much faster and therefore doesn't [[Decompression sickness|build up and form bubbles like nitrogen does]]) -- so, I don't think it will do much! [[Special:Contributions/2601:646:8082:BA0:209E:CE95:DB32:DD64|2601:646:8082:BA0:209E:CE95:DB32:DD64]] ([[User talk:2601:646:8082:BA0:209E:CE95:DB32:DD64|talk]]) 01:50, 29 December 2024 (UTC)
::It's conceivable it might take out the chloramine, I guess. I don't think there's very much of it, but it tastes awful, which is why I add a tiny bit of vitamin C when I drink tap water. It seems to take very little. Of course it's hard to tell whether it's just being masked by the taste of the vitamin C. --[[User:Trovatore|Trovatore]] ([[User talk:Trovatore|talk]]) 02:12, 29 December 2024 (UTC)
:If you just want to split water into hydrogen and oxygen all you need is [[Electrolysis|a battery and two bits of wire]]. You don't say where you saw this ad but if it was on a socia media site forget it. [[User:Shantavira|Shantavira]]|[[User talk:Shantavira|<sup>feed me</sup>]] 11:47, 29 December 2024 (UTC)


= December 29 =
:"Non-standard" arithmetic are used all the time, however. That case earlier, where ''''!%!''''=>''''@'''' (er, 1+1=0)? That's [[modulo arithmetic|modulo 2 arithmetic]]. We also have the case where ''''!%!''''=>''''!'''', except we call that multiplication, and we substitute 1 for @ and 0 for ! instead of vice-versa. We also frequently encounter physical situations where 2+2≠4. Take, for example, adding two liters of water to two liters of sand. 2+2≠4 in that case. Mix 2 cups vinegar to 2 cups baking soda, and the result takes up much more than 4 cups. Physical reality doesn't have to match with abstract mathematical constructs - however, instead of redefining 2+2=3 because the sand and water don't measure 4 liters afterward, or saying that 2+2=8 because of the carbon dioxide gas evolved with baking soda and water, we leave mathematics as a "pure" ideal, with 2+2=4, and realize normal addition doesn't apply to those situations. Likewise, the fact that interior angles of a triangle don't add up to 180 on the surface of the earth didn't invalidate Euclidean geometry - it still exists theoretically, we just realize that when doing surveying, we need to use a [[non-Euclidean geometry]]. -- [[Special:Contributions/128.104.112.106|128.104.112.106]] ([[User talk:128.104.112.106|talk]]) 01:28, 6 June 2009 (UTC)


== Potential energy vs. kinetic energy. Why not also "[[potential velocity]]" vs. "[[kinetic velocity]]"? E.g. in the following case: ==
:Physicist [[Max Tegmark]] has proposed a [[Mathematical universe hypothesis]] which proposes that every mathematical structure exists physically in some universe. But from a mathematical point of view, it seems to go a bit overboard (ask in the math RD for more explanation). Note, [[non-standard arithmetic]] (in mathematical logic) means something different than what 128.104.112.106 seems to think. [[Special:Contributions/207.241.239.70|207.241.239.70]] ([[User talk:207.241.239.70|talk]]) 03:41, 6 June 2009 (UTC)
::I believe the anon put "non-standard" in quotes in order to clarify that they weren't using it in the technical sense but just in the dictionary sense. --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 12:14, 6 June 2009 (UTC)


In a [[harmonic oscillator]], reaching the highest point involves - both a minimal kinetic energy - along with a maximal potential energy, whereas reaching the lowest point involves - both a maximal kinetic energy - along with a minimal potential energy. Thus the mechanical energy becomes the sum of kinetic energy + potential energy, and ''is a conserved quantity''.
== Peacock and Peahen ==


So I wonder if it's reasonable to define also "potential velocity" vs. "kinetic velocity", and claim that in a harmonic oscillator, reaching the highest point involves - both a ''minimal'' "kinetic velocity" (i.e. involves what we usually call ''a rest'') - along with a ''maximal'' "potential velocity", whereas reaching the lowest point involves - both a ''maximal'' "kinetic velocity" (i.e. involves what we usually call ''the actual velocity'') - along with a ''minimal'' "potential velocity". Thus we can also define "mechanical velocity" as the sum of "kinetic velocity" + "potential velocity", and ''claim that the mechanical velocity is a conserved quantity'' - at least as far as a harmonic oscillator is concerned.
Somebody told me that Peahen gets her eggs fertilized by orally shallowing the semen of the peacock.Is it true? <span style="font-size: smaller;" class="autosigned">—Preceding [[Wikipedia:Signatures|unsigned]] comment added by [[Special:Contributions/202.70.74.155|202.70.74.155]] ([[User talk:202.70.74.155|talk]]) 15:32, 5 June 2009 (UTC)</span><!-- Template:UnsignedIP --> <!--Autosigned by SineBot-->
:No. --[[User:Stephan Schulz|Stephan Schulz]] ([[User talk:Stephan Schulz|talk]]) 16:11, 5 June 2009 (UTC)
::Fowlatio? [[User:Edison|Edison]] ([[User talk:Edison|talk]]) 01:59, 6 June 2009 (UTC)


Reasonable?
== Egg protein ==


Note that I could also ask an analogous question - as to the concept of "potential momentum", but this term is already used in the theory of [[hidden momentum]] for another meaning, so for the time being I'm focusing on velocity.
Since eating raw eggs is not better than eating cooked eggs, what way should i cook them so that minimum protein is lost in the process of coooking (i.e. boil, fry etc.)? <span style="font-size: smaller;" class="autosigned">—Preceding [[Wikipedia:Signatures|unsigned]] comment added by [[Special:Contributions/116.71.42.218|116.71.42.218]] ([[User talk:116.71.42.218|talk]]) 18:00, 5 June 2009 (UTC)</span><!-- Template:UnsignedIP --> <!--Autosigned by SineBot-->
:This is a confusing question! If raw is not better than cooked, then why are you concerned about loss during cooking? As for outright loss during cooking, everything is still there except for maybe some small amounts that get stuck to the pan or leached out into the grease or other cooking medium, so something like hard-boiled would keep everything still in there. [[User:DMacks|DMacks]] ([[User talk:DMacks|talk]]) 18:04, 5 June 2009 (UTC)
::The only protein loss during cooking would be the little bits that brown along where the egg meets the pan (see [[Maillard reaction]]). These are likely so small as to be insignificant, so you would be safe frying the eggs. As far as I am concerned, hard boiled eggs serve little purpose except perhaps to make [[deviled eggs]] or [[egg salad]]. I find them pretty bland and unpalatable. But if your concern is making sure you get every molecule of protein out that was there originally, taste be damned, then go with the hard-boiled method. --[[User:Jayron32|Jayron32]].[[User talk:Jayron32|<small>talk</small>]].[[Special:Contributions/Jayron32|<small>contribs</small>]] 18:28, 5 June 2009 (UTC)


[[User:HOTmag|HOTmag]] ([[User talk:HOTmag|talk]]) 12:26, 29 December 2024 (UTC)
:Cooking will [[denaturation (biochemistry)|denature]] protein, but you will not lose the protein (specifically the amino acids). -- [[User:Kainaw|<font color='#ff0000'>k</font><font color='#cc0033'>a</font><font color='#990066'>i</font><font color='#660099'>n</font><font color='#3300cc'>a</font><font color='#0000ff'>w</font>]][[User talk:Kainaw|&trade;]] 18:33, 5 June 2009 (UTC)
: 'kinetic velocity' is just 'velocity'. 'potential velocity' has no meaning. [[User:Andy Dingley|Andy Dingley]] ([[User talk:Andy Dingley|talk]]) 13:56, 29 December 2024 (UTC)
::Per my suggestion, the ratio between distance and time is not called "velocity" but rather "kinetic velocity".
::Further, per my suggestion, if you don't indicate whether the "velocity" you're talking about is a "kinetic velocity" or a "potential velocity" or a "mechanical velocity", the very concept of "velocity" alone has no meaning!
::On the other hand, "potential velocity" is defined as the difference between the "mechanical velocity" and the "kinetic velocity"! Just as, this is the case if we replace "velocity" by "energy". For more details, see the example above, about the harmonic oscillator. [[User:HOTmag|HOTmag]] ([[User talk:HOTmag|talk]]) 15:14, 29 December 2024 (UTC)
:::You could define the ''potential velocity'' of a body at a particular height as the velocity it would hit the ground at if dropped from that height. But the sum of the potential and kinetic velocities would not be conserved; rather <math>v_{\mathrm{tot}} = \sqrt{v_{p}^{2} + v_{k}^{2}}</math> would be constant. [[User:Catslash|catslash]] ([[User talk:Catslash|talk]]) 18:54, 29 December 2024 (UTC)
::::Thank you. [[User:HOTmag|HOTmag]] ([[User talk:HOTmag|talk]]) 20:07, 29 December 2024 (UTC)
::: 'Potential velocity' has no meaning. You seem to be arguing that in a system where energy is conserved, but is transforming between kinetic and potential energy, (You might also want to compare this to [[conservation of momentum]].) then you can express that instead through a new conservation law based on velocity. But this doesn't work. There's no relation between velocity and potential energy.
::: In a harmonic oscillator, the potential energy is typically coming from some central restoring force with a relationship to ''position'', nothing at all to do with velocity. Where some axiomatic external rule (such as [[Hooke's Law]] applying, because the system is a mass on a spring) ''happens'' to relate the position and velocity through a suitable relation, then the system will then ([[Necessity and sufficiency|and only then]]) behave as a harmonic oscillator. But a different system (swap the spring for a [[dashpot]]) doesn't have this, thus won't oscillate. [[User:Andy Dingley|Andy Dingley]] ([[User talk:Andy Dingley|talk]]) 00:00, 30 December 2024 (UTC)
::::Let me quote a sentence from my original post: {{tq|Thus we can also...claim that the mechanical velocity is a conserved quantity - '''at least as far as a harmonic oscillator is concerned'''.}}
::::What's wrong in this quotation? [[User:HOTmag|HOTmag]] ([[User talk:HOTmag|talk]]) 07:52, 30 December 2024 (UTC)
:::::It is true, not only for harmonic oscillators, provided that you define {{math|1='''v'''<sub>pot</sub>&nbsp;=&nbsp;−&nbsp;'''v'''<sub>kin</sub>}}. &nbsp;--[[User talk:Lambiam#top|Lambiam]] 09:07, 30 December 2024 (UTC)
::::* You have defined some arbitrary values for new 'velocities', where their ''only'' definition is that they then demonstrate some new conservation law. Which is really the conservation of energy, but you're refusing to use that term for some reason.
::::: As Catslash pointed out, the conserved quantity here is proportional to the square of velocity, so your conservation equation has to include that. It's simply wrong that any linear function of velocity would be conserved here. Not merely we can't prove that, but we can prove (the sum of the squares diverges from the sum) that it's actually contradicted. For any definition of 'another velocity' which is a linear function of velocity.
::::: Lambiam's definition isn't a conservation law, it's merely a [[mathematical identity]]. The sum of any value and its [[additive inverse]] is always [[additive identity|zero]]. [[User:Andy Dingley|Andy Dingley]] ([[User talk:Andy Dingley|talk]]) 14:04, 30 December 2024 (UTC)
::::::{{small|It is a law of conservation of ''sanity''. Lacking a definition of potential energy, other than by having been informed that kinetic energy + potential energy is a conserved quantity, there is not much better we can do.}} &nbsp;--[[User talk:Lambiam#top|Lambiam]] 11:20, 31 December 2024 (UTC)
::::::: We have a perfectly viable definition of potential energy. For a pendulum it's based on the change in height of the pendulum bob against gravity. For some other oscillators it would involve the work done against a spring. [[User:Andy Dingley|Andy Dingley]] ([[User talk:Andy Dingley|talk]]) 16:33, 31 December 2024 (UTC)
::::::::Oops, I mistyped. I meant to write:
:::::::::"{{small|Lacking a definition of potential velocity, other than by having been informed that kinetic velocity + potential velocity is a conserved quantity, there is not much better we can do.}}"
::::::::&nbsp;--[[User talk:Lambiam#top|Lambiam]] 23:32, 31 December 2024 (UTC)


= December 30 =
To DMacks: I asked a question a couple of weeks back if raw eggs have any advantage over cooked ones and I was told no. And so if I work out and want max protein from the eggs I should hard boil them? I dont care about taste. <span style="font-size: smaller;" class="autosigned">—Preceding [[Wikipedia:Signatures|unsigned]] comment added by [[Special:Contributions/116.71.59.87|116.71.59.87]] ([[User talk:116.71.59.87|talk]]) 19:45, 5 June 2009 (UTC)</span><!-- Template:UnsignedIP --> <!--Autosigned by SineBot-->


== Saltiness comparison ==
:Kainaw already answered the above question, didn't he? [[User:Tempshill|Tempshill]] ([[User talk:Tempshill|talk]]) 22:10, 5 June 2009 (UTC)


Is there some test one might easily perform in a home [[test kitchen]] to compare the [[saltiness]] (due to the concentration of [[Na+|Na<sup>+</sup>]] [[cation]]s) of two liquid preparations, without involving biological [[taste bud]]s? &nbsp;--[[User talk:Lambiam#top|Lambiam]] 09:22, 30 December 2024 (UTC)
== [[exit polls]] ==


:Put two equally sized drops, one of each liquid, on a warm surface, wait for them to evaporate, and compare how much salt residue each leaves? Not very precise or measurable, but significant differences should be noticeable. {The poster formerly known as 87.81.230.195} [[Special:Contributions/94.1.223.204|94.1.223.204]] ([[User talk:94.1.223.204|talk]]) 10:21, 30 December 2024 (UTC)
Has anyone actually got any for the Euro elections? <span style="font-size: smaller;" class="autosigned">—Preceding [[Wikipedia:Signatures|unsigned]] comment added by [[Special:Contributions/86.128.217.5|86.128.217.5]] ([[User talk:86.128.217.5|talk]]) 22:43, 5 June 2009 (UTC)</span><!-- Template:UnsignedIP --> <!--Autosigned by SineBot-->


::The principle is sound, but the residue from one drop won't be measurable using kitchen equipment -- better to put equal amounts of each liquid in two warm pans (use enough liquid to cover the bottom of each pan with a thin layer), wait for them to evaporate and then weigh the residue! Or, if you're not afraid of doing some [[algebra]], you could also try an indirect method -- bring both liquids to a boil, measure the temperature of both, and then use the formula for [[boiling point elevation]] to calculate the saltiness of each! [[Special:Contributions/2601:646:8082:BA0:BD1B:60D8:96CA:C5B0|2601:646:8082:BA0:BD1B:60D8:96CA:C5B0]] ([[User talk:2601:646:8082:BA0:BD1B:60D8:96CA:C5B0|talk]]) 18:22, 30 December 2024 (UTC)
: I'm guessing you're interested in UK results: [[European Parliament election, 2009 (United Kingdom)]] should gradually accumulate that information - our editors usually get results up within minutes of it being announced...for an encyclopedia, we make a better news site than most proper news sites! There seem to be some results and recent polls there - but you'll probably want to hit reload every now and again. On the remote off-chance that it's not the slowly unfolding spectacular train wreck in the UK that you're interested in, there are links for results in the other countries at [[European Parliament election, 2009]]. My brother in law (Tony Goldson) just got elected to the [[Suffolk County Council]] with a landslide result - but no sign of '''that''' result here! [[User:SteveBaker|SteveBaker]] ([[User talk:SteveBaker|talk]]) 02:40, 6 June 2009 (UTC)


:::Presumably the ''liquid preparations'' are not simple saline solutions, but contain other solutes - or else one could simply use a hydrometer. It is unlikely that Lambian is afraid of doing some algebra. [[User:Catslash|catslash]] ([[User talk:Catslash|talk]]) 18:57, 30 December 2024 (UTC)
== work ==
:<s>Assuming the liquid preparations are water-based and don't contain alcohols and/or detergents one can measure their rates of dispersion. Simply add a drop of food dye to each liquid and then time how rapidly droplets of each liquid disperse in distilled water. Materials needed: food dye, eye dropper, distilled water, small clear containers and a timer.</s> [[User:Modocc|Modocc]] ([[User talk:Modocc|talk]]) 21:09, 30 December 2024 (UTC)


:::The [[colligative properties]] of a solution will indicate its molarity, but not identify the solute. ''Liquid preparations'' that might be found in a kitchen are likely to contain both salt and sugar. Electrical conductivity is a property that will be greatly affected by the salt but not the sugar (this does not help in distinguishing Na<sup>+</sup> from K<sup>+</sup> ions though). [[User:Catslash|catslash]] ([[User talk:Catslash|talk]]) 22:23, 30 December 2024 (UTC)
Why would work be defined as a scalar rather than a vector? <span style="font-size: smaller;" class="autosigned">—Preceding [[Wikipedia:Signatures|unsigned]] comment added by [[Special:Contributions/70.52.45.55|70.52.45.55]] ([[User talk:70.52.45.55|talk]]) 23:29, 5 June 2009 (UTC)</span><!-- Template:UnsignedIP --> <!--Autosigned by SineBot-->


:Work done is synonymous with energy. The energy required to do something is equal to the sum of the energies required to do each part, they don't cancel out. --[[User:Tango|Tango]] ([[User talk:Tango|talk]]) 23:39, 5 June 2009 (UTC)
::::That's what I'm thinking too -- use an [[ohmmeter]] to measure the [[electrical conductivity]] of the preparation, and compare to that of solutions with known NaCl concentration (using a [[calibration curve]]-type method). [[Special:Contributions/73.162.165.162|73.162.165.162]] ([[User talk:73.162.165.162|talk]]) 20:18, 31 December 2024 (UTC)


== The (uncommon?) terms "relativistic length", and "relativistic time". ==
: It does seem weird - if your "work done" is pushing a block up an inclined plane or something you kinda feel like it ought to be a vector...but remember that you could be doing work to increase the air pressure in a balloon - what would the direction be in that case? Suppose it was electrical work - charging a battery or something - again, no direction. [[User:SteveBaker|SteveBaker]] ([[User talk:SteveBaker|talk]]) 02:22, 6 June 2009 (UTC)


1. In Wikipedia, the page [[relativistic length contraction]] is automatically redirected to our article [[length contraction]], ''which actually doesn't mention the term "relativistic length" at all''. '''I wonder if there is an accepted term for the concept of relativistic length'''.
:Lets just assume Work to be a vector. Say you're pushing a block of wood up an inclined plane. But the catch us that you're not applying the force along the inclined plane. Say you're applying the force directly horizontally, but the block still moves up. SO now, what would be the direction of your work? Would it be along the inclined plane, where the block actually moves, or horizontally, in the direction where ''you'' actually pushed? If we assign a direction for Work, it results in more confusions, and essentially loss of physical significance as being equivalent to Energy. So, it is best to keep Work as a Scalar. [[User:Rkr1991|Rkr1991]] ([[User talk:Rkr1991|talk]]) 04:26, 6 June 2009 (UTC)


2. A similar qusestion arises, at to the concept of relativistic time: The page [[relativistic time dilation]], is automatically redirected to our article [[time dilation]], which prefers the abbreviated term "time dilation" (59 times) to the term "relativistic time dilation" (8 times only), and ''nowhere'' mentions the term "relativistic time" alone (i.e. without the third word "dilation") - although it does mention the term "proper time" for the shortest time. Further, this article doesn't even mention the term "dilated time" either. It does mention, though, another term: [[coordinate time]], but regardless of time dilation in ''Special'' relativity. '''To sum up, I wonder what's the accepted term used for the dilated time (mainly is Special relativity): Is it "coordinate time"? "Relativistic time"?'''
== Jellyfish as pets. ==


[[User:HOTmag|HOTmag]] ([[User talk:HOTmag|talk]]) 09:32, 30 December 2024 (UTC)
An IP recently asked me if Jellyfish could be kept in a houshold aquarium. I told him/her basically that I didn't know for sure. I offered some in depth, but basic, guidance on how to do it, while reinforcing that I think it is a very bad idea to try. The whole reply can be seen at my talk page. After replying, I realised that while I may not have the answers, someone else might. Basically I have to questions:


:Are you reading these things as "contraction of relativistic length" etc.? It is "relativistic contraction of length" and "relativistic dilation of time". --[[User:Wrongfilter|Wrongfilter]] ([[User talk:Wrongfilter|talk]]) 09:37, 30 December 2024 (UTC)
*Can jellyfish be kept in a household aquarium?
::When I wrote: {{tq|The page [[relativistic time dilation]] is automatically redirected to our article [[time dilation]] which...nowhere mentions the term "relativistic time" alone (i.e. without the third word "dilation")}}, I had already guessed that the term "dilation of relativistic time" (i.e, with the word "dilation" preceding the words "relativistic time") existed nowhere (at least in Wikipedia), and that this redirected page actually meant "relativistic dilation of time". The same is true for the redirected page "relativistic length contraction": I had already gussed it didn't mean "contraction of relativistic length", because (as I had already written): {{tq|the article [[length contraction]]...doesn't mention the term "relativistic length" at all}}.
::Anyway, I'm still waiting for an answer to my original question: Are there accepted terms for the concepts, of relativistic length - as opposed to [[proper length]], and of relativistic time - as opposed to [[proper time]]? [[User:HOTmag|HOTmag]] ([[User talk:HOTmag|talk]]) 10:12, 30 December 2024 (UTC)
:::A term that will be understood in the context of relativistic length contraction is ''relative length'' – that is, length relative to an observer.<sup>[https://books.google.com/books?id=gV6kgxrZjL8C&pg=PA174&dq=%22relative+length%22&hl=en][https://books.google.com/books?id=z925BQAAQBAJ&pg=PA20&dq=%22relative+length%22&hl=en][https://books.google.com/books?id=B5HYBAAAQBAJ&pg=PA195&dq=%22relative+length%22&hl=en]</sup> &nbsp;--[[User talk:Lambiam#top|Lambiam]] 10:55, 31 December 2024 (UTC)


== What did Juan Maldacena say after "Geometry of" in this video? ==
*Was my reply right, wrong, or a little of both?


I was watching this video [[Brian Greene]] and [[Juan Maldacena]] as they explore a wealth of developments connecting black holes, string theory etc, [[Juan Maldacena]] said something right after "'''Geometry of'''" Here is the spot: https://www.youtube.com/live/yNNXia9IrZs?si=G7S90UT4C8Bb-OnG&t=4484 What is that? [[User:HarryOrange|HarryOrange]] ([[User talk:HarryOrange|talk]]) 20:46, 30 December 2024 (UTC)
Thanks for any guidance on this.[[User:Drew R. Smith|<big><font color=#900>'''''D'''''</big></font>]]rew [[User talk:Drew R. Smith|<big><font color=#900>'''''S'''''</big></font>mith]] [[Special:Contributions/Drew R. Smith|<small><font color=#ccc>''What I've done''</small>]] 05:58, 6 June 2009 (UTC)
:[[Schwarzschild solution]]. --[[User:Wrongfilter|Wrongfilter]] ([[User talk:Wrongfilter|talk]]) 21:05, 30 December 2024 (UTC)
:Perhaps this [http://www.jellyfishfacts.net/pet-jellyfish.html web site] can help.--[[User:Lenticel|<span style="color: teal; background: white; font-weight: bold">Lenticel</span>]] <sup>([[User talk:Lenticel|<span style="color: green; font-weight: bold">talk</span>]])</sup> 06:13, 6 June 2009 (UTC)
::Thank you, its the [[Juan Maldacena]]'s accent which made me post here. [[User:HarryOrange|HarryOrange]] ([[User talk:HarryOrange|talk]]) 21:18, 30 December 2024 (UTC)


= December 31 =
:I recently was at an event where someone was selling jellyfish kits for several hundred dollars each. I'll offer some observations from what I saw. This doesn't mean that his "kit" was actually a good idea or the optimal solution. He also seemed to be offering only one species of jelly, so these observations may not apply generally.


== Brightest spot of a discharge tube ==
:#The largest tank on display was not huge, perhaps only 80 gallons and held three large jellies and basically nothing else. No scenery, no reefs, no other fish, nada. Maybe this was an open water species and preferred that; I don't know.
:#The smallest tank was perhaps 15 gallons and held one small jelly, and nothing else.
:#The "ground" in his tanks seemed to be made of rounded plastic stones roughly the size of a thumb but somewhat fatter.
:#Most of his tanks were vertically oriented, i.e. they were taller than they were wide. At the largest scale this was perhaps 3:1. All of the tanks were rounded and had no sharp corners on their vertical face.
:#All of his tanks had heavy duty aerators. Noticeably stronger than I have ever seen on aquariums of similar size. These were mostly enclosed, presumably to prevent the jelly from swimming over the air flow.
:#The type of jelly in question had very short tentacles.


[[File:Neon discharge tube.jpg|thumb|Neon is brighter in the middle.]]
:I wasn't interested enough to ask about care and feeding, so I don't know anything about the water quality or nutritional requirements. I did see some sort of food packs though, so presumably they can eat things other than live/recently caught food. Hope this helps. [[User:Dragons flight|Dragons flight]] ([[User talk:Dragons flight|talk]]) 06:47, 6 June 2009 (UTC)
[[File:Xenon discharge tube.jpg|thumb|Xenon is brighter at the edges.]]
::This helps, in that keeping jellies as pets is more common than I thought. On the other hand I have never seen a "kit" that actually keeps its intended inhabitants alive for even a fraction of its lifespan. Goldfish can live up to forty years in the wild, and seldom live more than a few months in "kits".[[User:Drew R. Smith|<big><font color=#900>'''''D'''''</big></font>]]rew [[User talk:Drew R. Smith|<big><font color=#900>'''''S'''''</big></font>mith]] [[Special:Contributions/Drew R. Smith|<small><font color=#ccc>''What I've done''</small>]] 09:21, 6 June 2009 (UTC)
What causes the discharge tubes to have their brightest spots at different positions? [[User:Nucleus hydro elemon|Nucleus hydro elemon]] ([[User talk:Nucleus hydro elemon|talk]]) 13:12, 31 December 2024 (UTC)


: See also the pictures at [[Gas-filled tube #Gases in use]]. --[[User:CiaPan|CiaPan]] ([[User talk:CiaPan|talk]]) 13:26, 31 December 2024 (UTC)
==Physical strength requirements of Formula 1==
{{small|Not sure if this is more suited to the Entertainment or Science section, so please feel free to move it}}


= January 1 =
During today's qualifying for the Turkish GP a commentator stated that 10kg of weight would add 0.3 seconds per lap. Obviously that is quite a lot of time (adding about 21 seconds in a 70 lap race). This has made be wonder about the impact of keeping down a driver's weight and the trade offs that might entail. As an example, according to [http://uk.eurosport.yahoo.com/formula-1/jenson-button.html this page] Jenson button weighs about 68kg, whereas I weigh about 95kg (I shouldn't, but I do!). At 0.3 seconds per 10kg per lap, I would, with the same driving skill, be 0.81 seconds slower per lap, or 56.7 seconds slower for a 70 lap race. So it would seem that, no matter how skillful, somebody weighing 95kg could never be successful in F1. This makes me wonder why successful F1 drivers do not tend to weigh even less. The jockey Willie Carson, seems to have weighed about 49kg, which would give him roughly a 0.6 second per lap advantage, or 42 seconds per race - presumably a woman would have even greater potential weight wise. Obviously skill is the overriding factor, but I cannot see why a woman, or a much lighter male would not be capabale of the same level of skill. So, I wonder if it is about the physical demands of F1. Is it that a degree of strength is required, that would override the weight advantage of a woman or a lighter male? I would have thought that riding a horse required greater strength than driving a Formula 1 car, and that jockeys must have a very good strength to weight ratio, but obviously there are other factors at play here, because Formula 1 is not full of drivers with the stature of jockeys. I would appreciate any thoughts on this. Thanks [[User:Chuny Beetroot|Chuny Beetroot]] ([[User talk:Chuny Beetroot|talk]]) 12:30, 6 June 2009 (UTC)
During today's qualifying for the Turkish GP a commentator stated that 10kg of weight would add 0.3 seconds per lap. Obviously that is quite a lot of time (adding about 21 seconds in a 70 lap race). This has made be wonder about the impact of keeping down a driver's weight and the trade offs that might entail. As an example, according to [http://uk.eurosport.yahoo.com/formula-1/jenson-button.html this page] Jenson button weighs about 68kg, whereas I weigh about 95kg (I shouldn't, but I do!). At 0.3 seconds per 10kg per lap, I would, with the same driving skill, be 0.81 seconds slower per lap, or 56.7 seconds slower for a 70 lap race. So it would seem that, no matter how skillful, somebody weighing 95kg could never be successful in F1. This makes me wonder why successful F1 drivers do not tend to weigh even less. The jockey Willie Carson, seems to have weighed about 49kg, which would give him roughly a 0.6 second per lap advantage, or 42 seconds per race - presumably a woman would have even greater potential weight wise. Obviously skill is the overriding factor, but I cannot see why a woman, or a much lighter male would not be capabale of the same level of skill. So, I wonder if it is about the physical demands of F1. Is it that a degree of strength is required, that would override the weight advantage of a woman or a lighter male? I would have thought that riding a horse required greater strength than driving a Formula 1 car, and that jockeys must have a very good strength to weight ratio, but obviously there are other factors at play here, because Formula 1 is not full of drivers with the stature of jockeys. I would appreciate any thoughts on this. Thanks [[User:Chuny Beetroot|Chuny Beetroot]] ([[User talk:Chuny Beetroot|talk]]) 12:30, 6 June 2009 (UTC)

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December 18

[edit]

Why don't all mast radiators have top hats?

[edit]

Our mast radiator article describes a device called a "top hat" which increases the range for mast radiators that can't be built tall enough.

So, why would you bother building a mast radiator without a top hat? Couldn't you just build it shorter with the top hat, and save steel? Marnanel (talk) 15:00, 18 December 2024 (UTC)[reply]

The main source cited in our article states, "Top loading is less desirable than increased tower height but is useful where towers must be electrically short due to either extremely low carrier frequencies or to aeronautical limitations. Top loading increases the base resistance and lowers the capacitive base reactance, thus reducing the Q and improving the bandwidth of towers less than 90° high."[1] If "reducing the Q" is an undesirable effect, this is a trade-off design issue in which height seems to be favoured if circumstances permit.  --Lambiam 21:41, 18 December 2024 (UTC)[reply]

Name of our solar system

[edit]

Is our star system officially called "Sol", or is that just something that came from science fiction and then became ubiquitous? 146.90.140.99 (talk) 22:06, 18 December 2024 (UTC)[reply]

It's called the Solar System, and its star is called Sol, from Latin via French. Hence terms like "solstice", which means "sun stands still" in its apparent annual "sine wave" shaped path through the sky. ←Baseball Bugs What's up, Doc? carrots23:31, 18 December 2024 (UTC)[reply]
Via French? According to the OED, it came direct from Latin.[2]  --Lambiam 11:45, 19 December 2024 (UTC)}}[reply]
Old French plus Latin.[3]Baseball Bugs What's up, Doc? carrots14:25, 19 December 2024 (UTC)[reply]
Also in Old French, the word meaning "sun" was soleil.  --Lambiam 23:42, 19 December 2024 (UTC)[reply]
Let's say [citation needed] to that claim. The star is indeed called Sol if you're speaking Latin, but in English it's the Sun (or sun). Of course words like "solar" and "solstice" derive from the Latin name, but using "Sol" to mean "the Sun" does seem to be something from science fiction. --142.112.149.206 (talk) 06:04, 19 December 2024 (UTC)[reply]
"Sol" is occasionally used to mean the Sun by astronomers. I feel like it is used in contexts where it is necessary to distinguish our experience with the Sun here on Earth, such as sunsets, from more "sterile" aspects of the Sun one might experience off the Earth. Abductive (reasoning) 08:56, 19 December 2024 (UTC)[reply]
Being an astronomer myself, I don't think I've ever heard anyone use "Sol" outside of a science fiction context. --Wrongfilter (talk) 09:06, 19 December 2024 (UTC)[reply]
Scientific articles that use the term Sol; Development of the HeliosX mission analysis code for advanced ICF space propulsion and Swarming Proxima Centauri: Optical Communication Over Interstellar Distances. These are rather speculative but as I mentioned, the usage is for off-planet situations. Abductive (reasoning) 13:05, 19 December 2024 (UTC)[reply]
Using Sol, Terra and Luna to refer to the Sun, Earth and Moon only happens if you write your entire article in Latin and in science fiction, not in regular science articles. They are capitalised though. Just as people write about a galaxy (one of many) or the Galaxy (the Milky Way Galaxy, that's our galaxy). The Solar System is also capitalised. PiusImpavidus (talk) 10:38, 19 December 2024 (UTC)[reply]
The article says "Sol" is the "personification" of the sun. Google Image the term "old Sol" and you'll see plenty of images of the sun with a face, not just Sci-Fi stuff. And "Luna" is obviously the basis for a number of words not connected with Sci-Fi. Lunar orbit, lunar module, etc. And the term "terra firma" has often been used in everyday usage. ←Baseball Bugs What's up, Doc? carrots11:34, 19 December 2024 (UTC)[reply]
And yet, if you ask 1,000 people "What's that big yellow thing up in the sky called?", you'll get 1,000 "the Sun"s and zero "Sol"s. Yes, in specialised contexts, Sol is used; but that doesn't justify saying our solar system's star "is called Sol" without any qualification, as if that were the normal, default term. It's not. -- Jack of Oz [pleasantries] 12:16, 19 December 2024 (UTC)[reply]
And after you've gotten that response, ask them why it isn't the "Sunner System". And why a sun room attached to a house isn't called a "sunarium". And why those energy-gathering plates on some roofs are not called "sunner panels". ←Baseball Bugs What's up, Doc? carrots14:22, 19 December 2024 (UTC)[reply]
What does that have to do with anything? The question was 'Is our star system officially called "Sol"?' (my emphasis). The answer is it is not. And that does not preclude other terms being derived from Latin sol (or, often enough, from Greek helios), nobody denies that, it is irrelevant to the question. --Wrongfilter (talk) 14:52, 19 December 2024 (UTC)[reply]
The problem is that the OP's question contains false premises. One is the question of what the "official" name is. There is no "official" name. It's the "conventional" name. And the second part, claiming that "Sol" comes from Sci-fi, is demonstrably false. ←Baseball Bugs What's up, Doc? carrots15:05, 19 December 2024 (UTC)[reply]
Then demonstrate (that the usage of "Sol" as a name for the Sun, in English, not its use to derive adjectives, originated outside of SF), with references. The original question does not even include any premises, with maybe the exception of "ubiquitous". --Wrongfilter (talk) 15:18, 19 December 2024 (UTC)[reply]
"Is our star system officially called "Sol" [answer: NO], or is that just something that came from science fiction [answer: NO] and then became ubiquitous? [whatever that means]". And the wording of your own question, just above, does not make sense. ←Baseball Bugs What's up, Doc? carrots15:24, 19 December 2024 (UTC)[reply]
Looking at Newspapers.com (pay site), I'm seeing colloquial references to "old Sol" (meaning the sun) as far back as the 1820s. No hint of sci-fi derivation. ←Baseball Bugs What's up, Doc? carrots15:32, 19 December 2024 (UTC)[reply]
Great! Well done. --Wrongfilter (talk) 15:41, 19 December 2024 (UTC)[reply]
Feel free to box up this section. ←Baseball Bugs What's up, Doc? carrots15:52, 19 December 2024 (UTC)[reply]
The 1933 OED entry for Sol, linked to above, gives several pre-SF uses, the earliest from 1450.  --Lambiam 23:48, 19 December 2024 (UTC)[reply]
Yes, of course, but that's not surprising, is it? 15th century humanists, astrologers and pre-Victorian poets liked to sprinkle their texts with Latin words. But I don't think this is what the question is about. It's a matter of context, but it should be up to OP to clarify that. --Wrongfilter (talk) 08:48, 20 December 2024 (UTC)[reply]
It's not surprising, but the discussion was not whether the use of Sol in English texts is surprising, but whether it originated outside of SF.  --Lambiam 10:52, 20 December 2024 (UTC)[reply]
In my view, the question has a clear scifi bent, and that particular usage ("Where shall we go for our vacation? Alpha Centauri or Sol?") does not originate in the 15th century. The word is much older, of course it is, but the usage is not. In the 15th century people didn't even know that the Sun is just an ordinary star and could do with a particular name to distinguish it from the others. The connotations of sol were vastly different from what they are today and from what is implied in OP's question. Incidentally, the IAU doesn't even define a name [4], although they recommend using capitalised "Sun". Certainly no "Sol" anywhere. --Wrongfilter (talk) 12:04, 20 December 2024 (UTC)[reply]
Does that make it a Sol-ecism? Clarityfiend (talk) 12:19, 19 December 2024 (UTC)[reply]
More like a Sol-ips-ism. Meaning a factory where suns are made. From Sol = sun, and ipso = facto. Thus endeth the entymogology lesson for today. Go in peace to love and serve whomsoever. -- Jack of Oz [pleasantries] 19:37, 19 December 2024 (UTC) [reply]

Mountains

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Why there are no mountains on Earth with a height above 10,000 m? As the death zone is about at 8,000 m, and above 19,000 m, there is an Armstrong limit, where water boils at normal human body temperature, it is good that there are no more mountains higher than 8,000 km than just 14, but if there were hundreds of mountains above 9,000 m, then these were bad to climb. If there were different limits for death zone and Armstrong limit, would then there be possible to have higher mountains? I have just thought that, it is not a homework? --40bus (talk) 22:29, 18 December 2024 (UTC)[reply]

There are mountains elsewhere in the solar system that are over 20km high. Given that some of those are on airless worlds, I don't think the air pressure has any bearing on it. 146.90.140.99 (talk) 22:57, 18 December 2024 (UTC)[reply]
Multiple sources from web searching suggest the theoretical maximum height for mountains on Earth is around 15,000 m – the limiting factor is Isostasy; the higher (therefore more voluminous) a mountain is, the more its weight causes the crust beneath it to sink. The actual heights of mountains are a trade-off between how fast tectonic movements can raise them versus isostatic sinking and how quickly they are eroded, and tectonic movements do not last for ever. See also Orogeny. {The poster formerly known as 87.81.230.195} 94.1.223.204 (talk) 00:25, 19 December 2024 (UTC)[reply]
And erosion goes faster as the mountain gets higher, in particular when it's high enough to support glaciers – one reason why mountains can get higher on an airless world. Now it gets interesting for a mountain high enough to reach into the stratosphere, as it would be too dry to have anything but bare rock. I suppose it would locally raise the tropopause, preventing that. PiusImpavidus (talk) 11:13, 19 December 2024 (UTC)[reply]

December 19

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Does human DNA become weaker with each generation?

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As with photocopying something over and over, the text becomes less clear each time.

Does human DNA become weaker with each generation? HarryOrange (talk) 21:22, 19 December 2024 (UTC)[reply]

Sure, DNA replication is not perfect, although proofreading reduces the error rate to about 1 mistake per 109 nucleotides (see our article on DNA Replication). But that is per generation of cells, not of the whole organisms. Many mutations will be neutral in effect (because much of our DNA is redundant), some will be deleterious, and a few might be advantageous. It is the process of natural selection that hinders the spread of deleterious mutations: sometimes this aspect is called purifying selection. One thus usually expects a stable mutation–selection balance over time rather than that "DNA becomes weaker with each generation". Medical science is reducing the selection pressure against some mutations, which consequently may become more common. One of the problems for asexual organisms is referred to as Muller's ratchet; assuming that reverse mutations are rare, each generation has at least the mutational load of its predecessor. In contrast, in sexual organisms genetic recombination generates the variation that, combined with selection, can repair the situation. Sexual organisms consequently have a lighter genetic load. JMCHutchinson (talk) 22:42, 19 December 2024 (UTC)[reply]
So purifying selection won't work properly in case of Inbreeding ? HarryOrange (talk) 23:16, 19 December 2024 (UTC)[reply]
The larger the degree of inbreeding, the larger the chance that deleterious traits are expressed. But this very expression of traits leading to decreased biological fitness of their bearers is what actually enables purifying selection in the longer term.  --Lambiam 23:36, 19 December 2024 (UTC)[reply]
@Lambiam so DNA repair won't stop these deleterious traits to get expressed? HarryOrange (talk) 14:11, 20 December 2024 (UTC)[reply]
No, this is not an issue of damage to the DNA. The genes involved are faithfully reproduced and passed on from generation to generation.  --Lambiam 15:53, 20 December 2024 (UTC)[reply]
Or stronger e.g. "...we found that genes specifically duplicated in the Greenland shark form a functionally connected network enriched for DNA repair function", and those guys live for centuries and have much more DNA than us. Sean.hoyland (talk) 15:21, 20 December 2024 (UTC)[reply]
@Lambiam If not due to DNA damage, why do babies from inbreeding appear like DNA-damaged species? HarryOrange (talk) 17:29, 20 December 2024 (UTC)[reply]
Inbred offspring of species that normally outcross may show abnormalities because they are more likely than outcrossed offspring to be homozygous for recessive alleles that are deleterious. In individuals that are heterozygous at these loci, the recessive alleles will not be expressed (because the other wild-type dominant allele is sufficient to do their job adequately). See our article on inbreeding depression. JMCHutchinson (talk) 19:26, 20 December 2024 (UTC)[reply]

Larvae going south

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In a novel I've just finished (The Chemistry of Death by Simon Beckett) he writes:

  • [The larvae] leave the body in an orderly fashion, following each other in a neat procession that always heads south. South-east or south-west sometimes, but never north. No-one knows why.

The author has done considerable international research on the science of forensic identification of decayed bodies and I assume his details can be trusted.

I've looked online for any verification of this surprising statement, but found only this, which seems to debunk it.

Is there any truth to this? -- Jack of Oz [pleasantries] 23:38, 19 December 2024 (UTC)[reply]

Can't speak to its truth, but . . .
  • Does Beckett state this in his own auctorial voice (i.e. as an omniscient narrator)? If so, he might be genuinely mistaken.
  • The book was published nearly 20 years ago, what was the accepted wisdom then?
  • What specific species (if any) is the book describing? – your linked Quora discussion refers only to "maggots" (which can be of numerous species and are a kind of larva, but there are many others, including for example Processionary caterpillars).
  • Alternatively, if the statement is made by a character in the book, is that character meant to be infallible, or is he portrayed as less than omniscient, or an 'unreliable narrator'?
Regarding the statement, in the Northern hemisphere the arc of South-east to South-west is predominently where the Sun is found well above the horizon, the North never, so the larvae involved might simply be seeking maximum warmth or light. {The poster formerly known as 87.81.230.195} 94.1.223.204 (talk) 02:18, 20 December 2024 (UTC)[reply]
This appears in the very first paragraph of Chapter I, which starts out:
  • A human body starts to decompose four minutes after death. Once the encapsulation of life, it now undergoes its final metamorphoses. It begins to digest itself. Cells dissolve from the inside out. Tissue turns to liquid, then to gas. No longer animate, the body becomes an immovable feast for other organisms. Bacteria first, then insects. Flies. Eggs are laid, then hatched. The larvae feed on the nutrient-rich broth, and then migrate. They leave the body in an orderly fashion ... (then the quote above completes the paragraph).
It's not until para 2 that he starts talking about any human characters, and not until para 4 that he invokes the first person.
That's as much as I know. But I find it hard to believe he'd just make up a detail and put it in such a prominent place if it could so easily be debunked if it were not true. -- Jack of Oz [pleasantries] 02:39, 20 December 2024 (UTC)[reply]
I wonder how they would measure the migratory path of maggots within a sealed coffin. ←Baseball Bugs What's up, Doc? carrots02:51, 20 December 2024 (UTC)[reply]
The context of the novel is about finding decaying corpses that have been dumped in a forest. No coffins involved. -- Jack of Oz [pleasantries] 06:08, 20 December 2024 (UTC)[reply]
Baseball Bugs, see also body farm research facilities. Alansplodge (talk) 13:44, 20 December 2024 (UTC)[reply]
Could it be that the larvae are setting off in search of another corpse? The prevailing wind in the UK is from the south-west, so by heading into the wind they won't be distracted by the frangrance of the one they've just left. Shantavira|feed me 09:30, 20 December 2024 (UTC)[reply]

If you can, have a look at 'Heinrich, Bernd. “Coordinated Mass Movements of Blow Fly Larvae (Diptera: Calliphoridae).” Northeastern Naturalist, vol. 20, no. 4, 2013, pp. N23–27. JSTOR, http://www.jstor.org/stable/43288173.' Here are some extracts

  • On the fourth day, after a cooling night with dew on the grass, a stream of tens of thousands of larvae exited from beneath the carcass within 1 h after sunrise, and proceeded in a single 1-2-cm-wide column directly toward the rising sun...
  • However, in this case, the larvae left at night, within 1 h after a cloudburst (at 21 :00 hours). But, unlike before, this nocturnal larval exodus in the rain was diffuse; thousands of larvae spread out in virtually all directions over an 8 m2area. Apparently, the sudden moisture had cued and facilitated the mass exodus, but the absence of sun had prevented a unidirectional, en masse movement.
  • However, on the following morning as the sun was starting to illuminate the carcass on the dewy grass, masses of larvae gathered at the east end of the carcass at 07:00 hours. In one half hour later, they started streaming in a column directly (within one degree) toward the rising sun, and the carcass was then nearly vacated.

It goes on. Maggot migration appears to be a bit more complicated than the novel suggests. Sean.hoyland (talk) 09:39, 20 December 2024 (UTC) I suppose you could try to address it from the other direction and look at the technology your average maggot has access to in terms of light detection, heat detection, olfactory systems, orientation in magnetic fields (like many arthropods) etc. They presumably have quite a lot of tools. Sean.hoyland (talk) 10:13, 20 December 2024 (UTC)[reply]

If orderly migrating maggots tend to move towards the sun, they should display a northward tendency in Oztralia.  --Lambiam 10:31, 20 December 2024 (UTC)[reply]
Maybe, but the novel is set in England.
I must say, as soon as I read the quoted para for the first time, my immediate thought was that it might have something to do with the magnetic field of the earth. -- Jack of Oz [pleasantries] 10:42, 20 December 2024 (UTC)[reply]
Prime suspect might be the Bolwig organ, the photoreceptor cluster many fly larvae have. Sean.hoyland (talk) 10:49, 20 December 2024 (UTC)[reply]
Obviously, Jack, you need to create a corpse, place it in a nearby forest, and carefully observe which way the maggots go. For Science! And Literary Criticism! {The poster formerly known as 87.81.230.195} 94.1.223.204 (talk) 21:01, 20 December 2024 (UTC)[reply]

December 20

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Winter solstice and time of sunrise?

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How is it that despite December 21st supposedly being the shortest day of the year, sunrise here happens later and later until December 26 and only on January 05 starts to turn around to occur earlier and earlier. On December 25 it takes place at about 08:44, between December 26 and January 04 it takes place at about 08:45, and on January 05 it takes place again at about 08:44. (Google rounds out the seconds). Is it Google's fault? Is it everywhere the same? Confused in Brussels, Belgium. 178.51.16.158 (talk) 12:06, 20 December 2024 (UTC)[reply]

The pertinent article is Analemma, start with the section Earliest and latest sunrise and sunset. The details are not that simple to understand, but it's basically due to the ellipticity of Earth's orbit and its axial tilt. --Wrongfilter (talk) 12:22, 20 December 2024 (UTC)[reply]
Also note that sunset begins to be later on 22 December so that the time between sunrise and sunset is a few seconds longer than on 21 December (3 seconds longer on 22/12/24 in Brussels according to this). Alansplodge (talk) 13:33, 20 December 2024 (UTC)[reply]
Also see Equation of time#Major components. The obliquity of the ecliptic (that is, the Earth's axial tilt) is the main component and hardest to understand. But the idea is that the time when the Sun is exactly south (that is, the true noon) moves some minutes back and forth throughout the year and it moves quite rapidly to later times in late December. PiusImpavidus (talk) 19:05, 20 December 2024 (UTC)[reply]
By the way is there a chart somewhere of the date of earliest/latest sunrise/sunset by latitude? —Tamfang (talk) 21:45, 29 December 2024 (UTC)[reply]
Discussed at Wikipedia:Reference desk/Archives/Science/2024 August 9#Total daytime per latitude. 2A02:C7C:F33B:4100:909B:C596:FD17:F530 (talk) 13:42, 30 December 2024 (UTC)[reply]

Three unit questions

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  1. Why territorial waters are defined by nautical miles instead of kilometers?
  2. Why GDP is usually measured in US dollars rather than euros? Euro would be better because it is not tied into any country.
  3. Are there any laws in United States that are defined by metric units?

--40bus (talk) 23:30, 20 December 2024 (UTC)[reply]

  1. There were nautical miles in use before there were kilometers.
  2. There were US dollars in use before there were Euros.
  3. Yes.
The questions all reduce to Why can't millions of people make a change of historically widely accepted units that continue to serve their purpose, and convert to different units that would have no substantive difference, because someone has an opinion. Philvoids (talk) 00:52, 21 December 2024 (UTC)[reply]
Do any people use metric units in marine and air navigation like "The ship is 10 kilometers from the port", "The plane is 10 kilometers from the destination? And is there any European country with metric flight levels? --40bus (talk) 07:22, 21 December 2024 (UTC)[reply]
Inland shipping (rivers, canals and lakes) in Europe (except the UK) is fully metric. Ships going for example TilburyDuisburg may have to switch units along the way. Gliders and ultralight aircraft in Europe often use metric instruments and airport dimensions are also metric (including runway length). Countries are free to define their territorial waters in whatever way they deem fit, so with nautical miles having no legal status in a fully metric country, they may define their territorial waters as extending 22224 metres. PiusImpavidus (talk) 11:23, 21 December 2024 (UTC)[reply]
Our nautical mile article says: "In 1929 the international nautical mile was defined by the First International Extraordinary Hydrographic Conference in Monaco as exactly 1,852 metres (which is 6,076.12 ft). The United States did not adopt the international nautical mile until 1954. Britain adopted it in 1970..."
As the US customary units are actually defined in terms that relate them to metric units, any US law based on measurements is technically defined by metric units.--User:Khajidha (talk) (contributions) 01:55, 21 December 2024 (UTC)[reply]
The US dollar has been the world's dominant reserve currency for about 75 years. As for the metric system in the US, it is standard in scientific, medical, electronics, auto manufacturing and other highly technical industries. By law, all packaged foods and beverages have metric quantities as well as customary quantities. See Metrication in the United States. Cullen328 (talk) 02:28, 21 December 2024 (UTC)[reply]

The Wikipaedia article on the Nautical Mile talks about how the term originated, it was originally defined in terms of latitude not as a number of meters 114.75.48.128 (talk) 10:03, 24 December 2024 (UTC)[reply]

The euro is tied to multiple specific countries is it not? If you use euros you're just changing from one "dependency" to a "dependency" on the eurozone countries. A statement of the problem or problems intended to be addressed would be useful. Currency values are interconvertible in any case. Economics does sometimes use the "international dollar" for certain things, which is intended to adjust for differences in purchasing power between countries and over time. But since it's not an actual "real" currency it's not something one can easily "visualize" in their heads, which is likely why it's not used more. --Slowking Man (talk) 05:41, 26 December 2024 (UTC) Eurostat, the official source of European Union data, uses euros, not dollars, to measure the economy. See [[5]]?DOR (ex-HK) (talk) 01:27, 1 January 2025 (UTC)[reply]

Eurostat, the official source of European Union data, uses euros, not dollars, to measure the economy. See [[6]]?DOR (ex-HK) (talk) 01:27, 1 January 2025 (UTC)[reply]

The user doubled-down on the response. ←Baseball Bugs What's up, Doc? carrots01:32, 1 January 2025 (UTC)[reply]

December 24

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Unknown species of insect

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Am I correct in inferring that this guy is an oriental beetle? I was off-put by the green head at first, but the antennae seem to match. JayCubby 03:00, 24 December 2024 (UTC)[reply]

(reference: https://www.genesdigest.com/macro/image.php?imageid=168&apage=0&ipage=1)

It looks like one of the invasive Japanese beetles that happens to like my blackberries in the summer. Modocc (talk) 13:11, 24 December 2024 (UTC)[reply]
I would say not necessarily a Japanese beetle, but almost certainly one of the other Scarab beetles, though with 35,000 species that doesn't help a lot. Looking at the infobox illustration in that article, 16. & 17., "Anisoplia segetum" looks very similar, but evidently we either don't have an article or (if our Anisoplia article is a complete list) it's been renamed. {The poster formerly known as 87.81.230.195} 94.1.223.204 (talk) 14:18, 24 December 2024 (UTC)[reply]
Yes, it's not the Japanese beetle for this beetle appears to lack its white-dotted fringe although its condition is deteriorated. Its shape is also more or less more slender; and not as round. Modocc (talk) 15:02, 24 December 2024 (UTC)[reply]
Perhaps it is the shining leaf chafer Strigoderma pimalis. Shown here. Modocc (talk) 16:09, 24 December 2024 (UTC)[reply]
That looks like easily the best match I've seen so far, and likely correct. {The poster formerly known as 87.81.230.195} 94.1.223.204 (talk) 17:09, 24 December 2024 (UTC)[reply]

December 25

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Mass of oscillating neutrino

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From the conservation of energy and momentum it follows that a particle that is not subject to external forces must have constancy of mass.

If I am right, this means that the mass of the neutrino cannot change during the neutrino oscillation, although its flavoring may. Is this written down somewhere? Thank you. Hevesli (talk) 19:24, 25 December 2024 (UTC)[reply]

Any (flavored) neutrino that is really observed is a superposition of two or three mass eigenstates. This is actually the cause of neutrino oscillations. So, the answer to your question is complicated. Ruslik_Zero 19:40, 25 December 2024 (UTC)[reply]
Important note: particle physicists today generally only ever use "mass" to mean "invariant mass" and never anything else: [7]. Like the term says, invariant mass is well, invariant, it never changes ever, no matter what "external forces" may or may not be involved. Being proper particle-icans and following the standard practice in the field, then, the three neutrino masses are constant values. ..."Wait, three?" Yeah sure, turns out neutrinos come in three "flavors" but each flavor is a mixture of the three possible mass "states". As mentioned, due to Quantum Weirdness we aren't able to get these different states "alone by themselves" to measure each by itself, so we only know the differences of the squares of the masses. Yeah welcome to quantum mechanics.
Richard Feynman: "Quantum mechanics describes nature as absurd from the point of view of common sense. And yet it fully agrees with experiment. So I hope you can accept nature as She is  – absurd." --Slowking Man (talk) 06:06, 26 December 2024 (UTC)[reply]
The equation uses invariant mass m0 which is constant if E and p are constant. The traveling neutrino has a varying mass mixture of different flavors with different masses. If a mixture of different masses changes, you would expect the resulting mass to change with it. But somehow this does not happen as the neutrino mass mixture changes. These mixture changes cannot be any changes. The changes must be such that the resulting mass of the traveling neutrino remains constant. My question is whether this is described somewhere. Hevesli (talk) 11:16, 26 December 2024 (UTC)[reply]
I freely confess I'm uncertain exactly what's being "asked for" or "gotten at" here. Have you looked at the neutrino oscillation article? From it: That is, the three neutrino states that interact with the charged leptons in weak interactions are each a different superposition of the three (propagating) neutrino states of definite mass. Neutrinos are emitted and absorbed in weak processes in flavor eigenstates[a] but travel as mass eigenstates.[18]
What is it that we're "doing" with the energy–momentum relation here? For the neutrino, we don't have a single value of "mass" to plug in for , because we can't "see" the individual mass eigenstates, only some linear combination of them. What you want for describing neutrino interactions is quantum field theory, which is special relativity + QM. (Remember, relativity is a "classical" theory, which presumes everything always has single well-defined values of everything. Which isn't true in quantum-world.) --Slowking Man (talk) 18:41, 26 December 2024 (UTC)[reply]
Not all potential evolutions of a linear combination of unequal values produce constant results. Constancy can only be guaranteed by a constraint on the evolutions. Does the fact that this constraint is satisfied in the case of neutrino oscillation follow from the mathematical formulation of the Standard Model, or does this formulation allow evolutions of the mass mixture for which the combination is not constant? If the unequal values are unknown, I have no idea of how such a constraint might be formulated. I think the OP is asking whether this constraint is described somewhere.  --Lambiam 00:51, 27 December 2024 (UTC)[reply]


December 27

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Low-intensity exercise

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If you exercise at a low intensity for an extended period of time, does the runner's high still occur if you do it for long enough? Or does it only occur above a certain threshold intensity of exercise? 2601:646:8082:BA0:CDFF:17F5:371:402F (talk) 20:13, 27 December 2024 (UTC)[reply]

Hows about you try it and report back? :) ←Baseball Bugs What's up, Doc? carrots21:31, 27 December 2024 (UTC)[reply]
I wanted to try it just today, but I had to exchange the under-desk elliptical trainer I got for Christmas for a different model with more inclined treadles because with the one I got, my knees would hit the desk at the top of every cycle. Anyway, I was hoping someone else tried it first (preferably as part of a formal scientific study) so I would know if I could control whether I got a runner's high from exercise or not? 2601:646:8082:BA0:9052:E6AF:23C7:7CAF (talk) 03:09, 28 December 2024 (UTC)[reply]

Also, sorry for adding to my own question, but here's a related one: is it known whether the length of a person's dopamine receptor D4 (which is inversely correlated with its sensitivity) influences whether said person gets a runner's high from exercise (and especially from low-intensity exercise)? 2601:646:8082:BA0:9052:E6AF:23C7:7CAF (talk) 03:14, 28 December 2024 (UTC)[reply]

Hi,

What is the difference between an auxotroph and a fastidious organism? It seems to me the second one would have more requirements than the first one, but the limit between the two definitions is rather unclear to me.

Thank you 212.195.231.13 (talk) 23:17, 27 December 2024 (UTC)[reply]

I'm not 100% sure, but it seems to me that an auxotroph is a specific type of a fastidious organism. 2601:646:8082:BA0:9052:E6AF:23C7:7CAF (talk) 03:02, 28 December 2024 (UTC)[reply]
Symbiosis aside, it would seem that most auxotrophs would be fastidious organisms, but there could be many more fastidious organisms that aren't auxotrophs. Auxotrophs specifically can't produce organic compounds on their own. There are a LOT of organisms that rely on the availability of non-organic nutrients, such as specific elements/minerals. For instance, vertebrates require access to calcium. Calcium is an element; our inability to produce it does not make us auxotrophs.
But perhaps symbiosis would allow an organism to be an auxotroph without being a fastidious organism? For instance, mammals tend to have bacteria in our guts that can digest nutrients that our bodies can't on their own. Perhaps some of those bacteria also assemble certain nutrients that our bodies can't? -- Avocado (talk) 14:27, 28 December 2024 (UTC)[reply]

December 28

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Paper with wrong enantiomer in a figure

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In the following reference:

Quack, Martin; Seyfang, Georg; Wichmann, Gunther (2022). "Perspectives on parity violation in chiral molecules: theory, spectroscopic experiment and biomolecular homochirality". Chemical Science. 13 (36): 10598–10643. doi:10.1039/d2sc01323a. PMID 36320700.

it is stated in the caption of Fig. 8 that Sbromochlorofluoromethane is predicted to be lower in energy due to parity violation, but in the figure the wrong enantiomer is shown on this side. Which enantiomer is more stable, according to the original sources for this data? –LaundryPizza03 (d) 08:18, 28 December 2024 (UTC)[reply]

Where can I find data on the circulation and citation rates of these journals?

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Hello everyone, To write an article about a scientist, you need to know, where can I find data on circulation and citation rates of journals from this list? Vyacheslav84 (talk) 09:58, 28 December 2024 (UTC)[reply]

So-called “Hydrogen water”

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I saw an ad promoting a device which presumable splits water into hydrogen and oxygen and infuses water with extra hydrogen, to a claimed surplus of perhaps 5 ppm, which doesn’t seem like much. I found a review article which looked at several dozen related studies that found benefits:https://pmc.ncbi.nlm.nih.gov/articles/PMC10816294/ .

I’ve noticed that carbon dioxide or chlorine (chloramine?) dissolved in water work their way out pretty easily, so I wonder if dissolved hydrogen could similarly exit hydrogen enriched water and be burped or farted out, rather than entering the blood stream and having health benefits. is it more than the latest snake oil? Edison (talk) 23:01, 28 December 2024 (UTC)[reply]

Yes, the dissolved hydrogen will exit the water just as quickly (even faster, because of its low molecular mass and complete lack of polarity or capability for ionic dissociation), and even if it does enter the bloodstream, it will likewise get back out in short order before it can actually do anything (which, BTW, is why deep-sea divers use it in their breathing mixes -- because it gets out of the bloodstream so much faster and therefore doesn't build up and form bubbles like nitrogen does) -- so, I don't think it will do much! 2601:646:8082:BA0:209E:CE95:DB32:DD64 (talk) 01:50, 29 December 2024 (UTC)[reply]
It's conceivable it might take out the chloramine, I guess. I don't think there's very much of it, but it tastes awful, which is why I add a tiny bit of vitamin C when I drink tap water. It seems to take very little. Of course it's hard to tell whether it's just being masked by the taste of the vitamin C. --Trovatore (talk) 02:12, 29 December 2024 (UTC)[reply]
If you just want to split water into hydrogen and oxygen all you need is a battery and two bits of wire. You don't say where you saw this ad but if it was on a socia media site forget it. Shantavira|feed me 11:47, 29 December 2024 (UTC)[reply]

December 29

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Potential energy vs. kinetic energy. Why not also "potential velocity" vs. "kinetic velocity"? E.g. in the following case:

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In a harmonic oscillator, reaching the highest point involves - both a minimal kinetic energy - along with a maximal potential energy, whereas reaching the lowest point involves - both a maximal kinetic energy - along with a minimal potential energy. Thus the mechanical energy becomes the sum of kinetic energy + potential energy, and is a conserved quantity.

So I wonder if it's reasonable to define also "potential velocity" vs. "kinetic velocity", and claim that in a harmonic oscillator, reaching the highest point involves - both a minimal "kinetic velocity" (i.e. involves what we usually call a rest) - along with a maximal "potential velocity", whereas reaching the lowest point involves - both a maximal "kinetic velocity" (i.e. involves what we usually call the actual velocity) - along with a minimal "potential velocity". Thus we can also define "mechanical velocity" as the sum of "kinetic velocity" + "potential velocity", and claim that the mechanical velocity is a conserved quantity - at least as far as a harmonic oscillator is concerned.

Reasonable?

Note that I could also ask an analogous question - as to the concept of "potential momentum", but this term is already used in the theory of hidden momentum for another meaning, so for the time being I'm focusing on velocity.

HOTmag (talk) 12:26, 29 December 2024 (UTC)[reply]

'kinetic velocity' is just 'velocity'. 'potential velocity' has no meaning. Andy Dingley (talk) 13:56, 29 December 2024 (UTC)[reply]
Per my suggestion, the ratio between distance and time is not called "velocity" but rather "kinetic velocity".
Further, per my suggestion, if you don't indicate whether the "velocity" you're talking about is a "kinetic velocity" or a "potential velocity" or a "mechanical velocity", the very concept of "velocity" alone has no meaning!
On the other hand, "potential velocity" is defined as the difference between the "mechanical velocity" and the "kinetic velocity"! Just as, this is the case if we replace "velocity" by "energy". For more details, see the example above, about the harmonic oscillator. HOTmag (talk) 15:14, 29 December 2024 (UTC)[reply]
You could define the potential velocity of a body at a particular height as the velocity it would hit the ground at if dropped from that height. But the sum of the potential and kinetic velocities would not be conserved; rather would be constant. catslash (talk) 18:54, 29 December 2024 (UTC)[reply]
Thank you. HOTmag (talk) 20:07, 29 December 2024 (UTC)[reply]
'Potential velocity' has no meaning. You seem to be arguing that in a system where energy is conserved, but is transforming between kinetic and potential energy, (You might also want to compare this to conservation of momentum.) then you can express that instead through a new conservation law based on velocity. But this doesn't work. There's no relation between velocity and potential energy.
In a harmonic oscillator, the potential energy is typically coming from some central restoring force with a relationship to position, nothing at all to do with velocity. Where some axiomatic external rule (such as Hooke's Law applying, because the system is a mass on a spring) happens to relate the position and velocity through a suitable relation, then the system will then (and only then) behave as a harmonic oscillator. But a different system (swap the spring for a dashpot) doesn't have this, thus won't oscillate. Andy Dingley (talk) 00:00, 30 December 2024 (UTC)[reply]
Let me quote a sentence from my original post: Thus we can also...claim that the mechanical velocity is a conserved quantity - at least as far as a harmonic oscillator is concerned.
What's wrong in this quotation? HOTmag (talk) 07:52, 30 December 2024 (UTC)[reply]
It is true, not only for harmonic oscillators, provided that you define vpot = − vkin.  --Lambiam 09:07, 30 December 2024 (UTC)[reply]
  • You have defined some arbitrary values for new 'velocities', where their only definition is that they then demonstrate some new conservation law. Which is really the conservation of energy, but you're refusing to use that term for some reason.
As Catslash pointed out, the conserved quantity here is proportional to the square of velocity, so your conservation equation has to include that. It's simply wrong that any linear function of velocity would be conserved here. Not merely we can't prove that, but we can prove (the sum of the squares diverges from the sum) that it's actually contradicted. For any definition of 'another velocity' which is a linear function of velocity.
Lambiam's definition isn't a conservation law, it's merely a mathematical identity. The sum of any value and its additive inverse is always zero. Andy Dingley (talk) 14:04, 30 December 2024 (UTC)[reply]
It is a law of conservation of sanity. Lacking a definition of potential energy, other than by having been informed that kinetic energy + potential energy is a conserved quantity, there is not much better we can do.  --Lambiam 11:20, 31 December 2024 (UTC)[reply]
We have a perfectly viable definition of potential energy. For a pendulum it's based on the change in height of the pendulum bob against gravity. For some other oscillators it would involve the work done against a spring. Andy Dingley (talk) 16:33, 31 December 2024 (UTC)[reply]
Oops, I mistyped. I meant to write:
"Lacking a definition of potential velocity, other than by having been informed that kinetic velocity + potential velocity is a conserved quantity, there is not much better we can do."
 --Lambiam 23:32, 31 December 2024 (UTC)[reply]

December 30

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Saltiness comparison

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Is there some test one might easily perform in a home test kitchen to compare the saltiness (due to the concentration of Na+ cations) of two liquid preparations, without involving biological taste buds?  --Lambiam 09:22, 30 December 2024 (UTC)[reply]

Put two equally sized drops, one of each liquid, on a warm surface, wait for them to evaporate, and compare how much salt residue each leaves? Not very precise or measurable, but significant differences should be noticeable. {The poster formerly known as 87.81.230.195} 94.1.223.204 (talk) 10:21, 30 December 2024 (UTC)[reply]
The principle is sound, but the residue from one drop won't be measurable using kitchen equipment -- better to put equal amounts of each liquid in two warm pans (use enough liquid to cover the bottom of each pan with a thin layer), wait for them to evaporate and then weigh the residue! Or, if you're not afraid of doing some algebra, you could also try an indirect method -- bring both liquids to a boil, measure the temperature of both, and then use the formula for boiling point elevation to calculate the saltiness of each! 2601:646:8082:BA0:BD1B:60D8:96CA:C5B0 (talk) 18:22, 30 December 2024 (UTC)[reply]
Presumably the liquid preparations are not simple saline solutions, but contain other solutes - or else one could simply use a hydrometer. It is unlikely that Lambian is afraid of doing some algebra. catslash (talk) 18:57, 30 December 2024 (UTC)[reply]
Assuming the liquid preparations are water-based and don't contain alcohols and/or detergents one can measure their rates of dispersion. Simply add a drop of food dye to each liquid and then time how rapidly droplets of each liquid disperse in distilled water. Materials needed: food dye, eye dropper, distilled water, small clear containers and a timer. Modocc (talk) 21:09, 30 December 2024 (UTC)[reply]
The colligative properties of a solution will indicate its molarity, but not identify the solute. Liquid preparations that might be found in a kitchen are likely to contain both salt and sugar. Electrical conductivity is a property that will be greatly affected by the salt but not the sugar (this does not help in distinguishing Na+ from K+ ions though). catslash (talk) 22:23, 30 December 2024 (UTC)[reply]
That's what I'm thinking too -- use an ohmmeter to measure the electrical conductivity of the preparation, and compare to that of solutions with known NaCl concentration (using a calibration curve-type method). 73.162.165.162 (talk) 20:18, 31 December 2024 (UTC)[reply]

The (uncommon?) terms "relativistic length", and "relativistic time".

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1. In Wikipedia, the page relativistic length contraction is automatically redirected to our article length contraction, which actually doesn't mention the term "relativistic length" at all. I wonder if there is an accepted term for the concept of relativistic length.

2. A similar qusestion arises, at to the concept of relativistic time: The page relativistic time dilation, is automatically redirected to our article time dilation, which prefers the abbreviated term "time dilation" (59 times) to the term "relativistic time dilation" (8 times only), and nowhere mentions the term "relativistic time" alone (i.e. without the third word "dilation") - although it does mention the term "proper time" for the shortest time. Further, this article doesn't even mention the term "dilated time" either. It does mention, though, another term: coordinate time, but regardless of time dilation in Special relativity. To sum up, I wonder what's the accepted term used for the dilated time (mainly is Special relativity): Is it "coordinate time"? "Relativistic time"?

HOTmag (talk) 09:32, 30 December 2024 (UTC)[reply]

Are you reading these things as "contraction of relativistic length" etc.? It is "relativistic contraction of length" and "relativistic dilation of time". --Wrongfilter (talk) 09:37, 30 December 2024 (UTC)[reply]
When I wrote: The page relativistic time dilation is automatically redirected to our article time dilation which...nowhere mentions the term "relativistic time" alone (i.e. without the third word "dilation"), I had already guessed that the term "dilation of relativistic time" (i.e, with the word "dilation" preceding the words "relativistic time") existed nowhere (at least in Wikipedia), and that this redirected page actually meant "relativistic dilation of time". The same is true for the redirected page "relativistic length contraction": I had already gussed it didn't mean "contraction of relativistic length", because (as I had already written): the article length contraction...doesn't mention the term "relativistic length" at all.
Anyway, I'm still waiting for an answer to my original question: Are there accepted terms for the concepts, of relativistic length - as opposed to proper length, and of relativistic time - as opposed to proper time? HOTmag (talk) 10:12, 30 December 2024 (UTC)[reply]
A term that will be understood in the context of relativistic length contraction is relative length – that is, length relative to an observer.[8][9][10]  --Lambiam 10:55, 31 December 2024 (UTC)[reply]

What did Juan Maldacena say after "Geometry of" in this video?

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I was watching this video Brian Greene and Juan Maldacena as they explore a wealth of developments connecting black holes, string theory etc, Juan Maldacena said something right after "Geometry of" Here is the spot: https://www.youtube.com/live/yNNXia9IrZs?si=G7S90UT4C8Bb-OnG&t=4484 What is that? HarryOrange (talk) 20:46, 30 December 2024 (UTC)[reply]

Schwarzschild solution. --Wrongfilter (talk) 21:05, 30 December 2024 (UTC)[reply]
Thank you, its the Juan Maldacena's accent which made me post here. HarryOrange (talk) 21:18, 30 December 2024 (UTC)[reply]

December 31

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Brightest spot of a discharge tube

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Neon is brighter in the middle.
Xenon is brighter at the edges.

What causes the discharge tubes to have their brightest spots at different positions? Nucleus hydro elemon (talk) 13:12, 31 December 2024 (UTC)[reply]

See also the pictures at Gas-filled tube #Gases in use. --CiaPan (talk) 13:26, 31 December 2024 (UTC)[reply]

January 1

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