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${\mathrm {d} \over \mathrm {d} x}\int _{0}^{x}t^{3}\,\mathrm {d} t=f(x){\mathrm {d} x \over \mathrm {d} x}-f(0){\mathrm {d} 0 \over \mathrm {0} }=x^{3}.$

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This is not a Love Song

$1=2$ [1]

Revision as of 17:36, 26 July 2007 view source 24.172.113.130 (talk) →Super ← Previous edit		Revision as of 17:36, 26 July 2007 view source Joco3000 (talk \| contribs) 4 edits →Super Next edit →
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	<math>1 = 2</math>		<math>1 = 2</math>
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