Talk:Reinhardt domain: Difference between revisions
Content deleted Content added
→Example in 1 dimensional case: Agree for general Reinhardt domains, but what does logarithmically complex mean? |
|||
| Line 5: | Line 5: | ||
What do you think? That is actually the first time I study Reinhardt domain, so I don't want to do any change myself for the moment. |
What do you think? That is actually the first time I study Reinhardt domain, so I don't want to do any change myself for the moment. |
||
[[User:Bongilles|Bongilles]] ([[User talk:Bongilles|talk]]) 22:15, 30 January 2013 (UTC) |
[[User:Bongilles|Bongilles]] ([[User talk:Bongilles|talk]]) 22:15, 30 January 2013 (UTC) |
||
:I basically thought the same thing. Based on the definition presented here, the Reinhardt domain appears to be up to n open annuluses containing the zn. This could include a disc if one of the zn is the origin. It might be useful to mention annuluses (annuli?) in the article, if this interpretaion is correct (I've first encountered Reinhardt domains just now by reading this article). It may be that to be "logarithmically convex" a 1d Reinhardt domain must be a disk, which would make the article correct (I don't know what logarithmically convex means).--[[User:Wikimedes|Wikimedes]] ([[User talk:Wikimedes|talk]]) 19:56, 8 August 2014 (UTC) |
|||
Revision as of 19:56, 8 August 2014
Example in 1 dimensional case
It seems to me that the following sentence is not exact: "Note that in one complex variable, a logarithmically convex Reinhardt domain is simply a disc." I think it should be anulus instead of disc. But if we add the condition of containing the origin then it has to be a disc. What do you think? That is actually the first time I study Reinhardt domain, so I don't want to do any change myself for the moment. Bongilles (talk) 22:15, 30 January 2013 (UTC)
- I basically thought the same thing. Based on the definition presented here, the Reinhardt domain appears to be up to n open annuluses containing the zn. This could include a disc if one of the zn is the origin. It might be useful to mention annuluses (annuli?) in the article, if this interpretaion is correct (I've first encountered Reinhardt domains just now by reading this article). It may be that to be "logarithmically convex" a 1d Reinhardt domain must be a disk, which would make the article correct (I don't know what logarithmically convex means).--Wikimedes (talk) 19:56, 8 August 2014 (UTC)