Talk:Normal operator: Difference between revisions

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Does " $N^{2}$ normal" implies "N normal"? I think I heard that the answer is affirmative when N is assumed to be, say, paranormal or something. I want to know the precise statement (so we can put in the article). -- Taku (talk) 23:52, 11 February 2009 (UTC)[reply]

don't know. nice to have someone interested in operator theory around. Mct mht (talk) 03:18, 12 February 2009 (UTC)[reply]

In full generality it's false, otherwise any nilpotent operator would be normal. Besides, I think any statement involving paranormal operators should appear in the article about paranormal operators rather than this one. Gamesou (talk) 11:07, 3 April 2009 (UTC)[reply]

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	:don't know. nice to have someone interested in operator theory around. [[User:Mct mht\|Mct mht]] ([[User talk:Mct mht\|talk]]) 03:18, 12 February 2009 (UTC)		:don't know. nice to have someone interested in operator theory around. [[User:Mct mht\|Mct mht]] ([[User talk:Mct mht\|talk]]) 03:18, 12 February 2009 (UTC)

			In full generality it's false, otherwise any nilpotent operator would be normal. Besides, I think any statement involving paranormal operators should appear in the article about paranormal operators rather than this one. [[User:Gamesou\|Gamesou]] ([[User talk:Gamesou\|talk]]) 11:07, 3 April 2009 (UTC)