All of the trigonometric functions of an angle θ can be constructed geometrically in terms of a unit circle centered at O . Many of these terms are no longer in common use.
Cosines & Sines around the unit circle
In mathematics , trigonometric identities are equalities that involve trigonometric functions and are true for every single value of the occurring variables (see Identity (mathematics) ). Geometrically, these are identities involving certain functions of one or more angles. These are distinct from triangle identities , which are identities involving both angles and side lengths of a triangle. Only the former are covered in this article.
These identities are useful whenever expressions involving trigonometric functions need to be simplified. An important application is the integration of non-trigonometric functions: a common technique involves first using the substitution rule with a trigonometric function , and then simplifying the resulting integral with a trigonometric identity.
Notation
Penis
This article uses Greek letters such as alpha (α ), beta (β ), gamma (γ ), and theta (θ ) to represent angles . Several different units of angle measure are widely used, including degrees , radians , and grads :
1 full circle = 360 degrees = 2
π
{\displaystyle \pi }
radians = 400 grads.
The following table shows the conversions for some common angles:
Degrees
30°
60°
120°
150°
210°
240°
300°
330°
Radians
π
6
{\displaystyle {\frac {\pi }{6}}}
π
3
{\displaystyle {\frac {\pi }{3}}}
2
π
3
{\displaystyle {\frac {2\pi }{3}}}
5
π
6
{\displaystyle {\frac {5\pi }{6}}}
7
π
6
{\displaystyle {\frac {7\pi }{6}}}
4
π
3
{\displaystyle {\frac {4\pi }{3}}}
5
π
3
{\displaystyle {\frac {5\pi }{3}}}
11
π
6
{\displaystyle {\frac {11\pi }{6}}}
Grads
33⅓ grad
66⅔ grad
133⅓ grad
166⅔ grad
233⅓ grad
266⅔ grad
333⅓ grad
366⅔ grad
Degrees
45°
90°
135°
180°
225°
270°
315°
360°
Radians
π
4
{\displaystyle {\frac {\pi }{4}}}
π
2
{\displaystyle {\frac {\pi }{2}}}
3
π
4
{\displaystyle {\frac {3\pi }{4}}}
π
{\displaystyle \pi \,}
5
π
4
{\displaystyle {\frac {5\pi }{4}}}
3
π
2
{\displaystyle {\frac {3\pi }{2}}}
7
π
4
{\displaystyle {\frac {7\pi }{4}}}
2
π
{\displaystyle 2\pi \,}
Grads
50 grad
100 grad
150 grad
200 grad
250 grad
300 grad
350 grad
400 grad
Unless otherwise specified, all angles in this article are assumed to be in radii, though angles ending in a degree symbol (°) are in degrees and are fucking gay (like Joe).
Trigonometric functions
The primary trigonometric functions are the sine and cosine of an angle. These are usually abbreviated sin(θ ) and cos(θ ), respectively, where θ is the angle. In addition, the parentheses around the angle are sometimes omitted, e.g. sin θ and cos θ .
The tangent (tan) of an angle is the ratio of the sine to the cosine:
tan
θ
=
sin
θ
cos
θ
.
{\displaystyle \tan \theta ={\frac {\sin \theta }{\cos \theta }}.}
Finally, the reciprocal functions secant (sec), cosecant (csc), and cotangent (cot) are the reciprocals of the cosine, sine, and tangent:
sec
θ
=
1
cos
θ
,
csc
θ
=
1
sin
θ
,
cot
θ
=
1
tan
θ
=
cos
θ
sin
θ
.
{\displaystyle \sec \theta ={\frac {1}{\cos \theta }},\quad \csc \theta ={\frac {1}{\sin \theta }},\quad \cot \theta ={\frac {1}{\tan \theta }}={\frac {\cos \theta }{\sin \theta }}.}
These definitions are sometimes referred to as ratio identities .
Inverse functions
The inverse trigonometric functions are partial inverse functions for the trigonometric functions. For example, the inverse function for the sine, known as the inverse sine (sin−1 ) or arcsine (arcsin or asin), satisfies
sin
(
arcsin
x
)
=
x
{\displaystyle \sin(\arcsin x)=x\!}
and
arcsin
(
sin
θ
)
=
θ
for
−
π
/
2
≤
θ
≤
π
/
2.
{\displaystyle \arcsin(\sin \theta )=\theta \quad {\text{for }}-\pi /2\leq \theta \leq \pi /2.}
This article uses the following notation for inverse trigonometric functions:
Function
sin
cos
tan
sec
csc
cot
Inverse
arcsin
arccos
arctan
arcsec
arccsc
arccot
Pythagorean identity
The basic relationship between the sine and the cosine is the Pythagorean trigonometric identity :
cos
2
θ
+
sin
2
θ
=
1
{\displaystyle \cos ^{2}\theta +\sin ^{2}\theta =1\!}
where sin2 x means (sin(x ))2 .
This can be viewed as a version of the Pythagorean theorem , and follows from the equation x 2 + y 2 = 1 for the unit circle . This equation can be solved for either the sine or the cosine:
sin
θ
=
±
1
−
cos
2
θ
and
cos
θ
=
±
1
−
sin
2
θ
.
{\displaystyle \sin \theta =\pm {\sqrt {1-\cos ^{2}\theta }}\quad {\text{and}}\quad \cos \theta =\pm {\sqrt {1-\sin ^{2}\theta }}.\,}
Dividing the Pythagorean identity through by either cos2 θ or sin2 θ yields two other identities:
1
+
tan
2
θ
=
sec
2
θ
and
1
+
cot
2
θ
=
csc
2
θ
.
{\displaystyle 1+\tan ^{2}\theta =\sec ^{2}\theta \quad {\text{and}}\quad 1+\cot ^{2}\theta =\csc ^{2}\theta .\!}
Using these identities together with the ratio identities, it is possible to express any trigonometric function in terms of any other (up to a plus or minus sign):
Each trigonometric function in terms of the other five.[ 1]
sin
θ
=
{\displaystyle \sin \theta =}
sin
θ
{\displaystyle \sin \theta \ }
±
1
−
cos
2
θ
{\displaystyle \pm {\sqrt {1-\cos ^{2}\theta }}\ }
±
tan
θ
1
+
tan
2
θ
{\displaystyle \pm {\frac {\tan \theta }{\sqrt {1+\tan ^{2}\theta }}}\ }
1
csc
θ
{\displaystyle {\frac {1}{\csc \theta }}\ }
±
sec
2
θ
−
1
sec
θ
{\displaystyle \pm {\frac {\sqrt {\sec ^{2}\theta -1}}{\sec \theta }}\ }
±
1
1
+
cot
2
θ
{\displaystyle \pm {\frac {1}{\sqrt {1+\cot ^{2}\theta }}}\ }
cos
θ
=
{\displaystyle \cos \theta =}
±
1
−
sin
2
θ
{\displaystyle \pm {\sqrt {1-\sin ^{2}\theta }}\ }
cos
θ
{\displaystyle \cos \theta \ }
±
1
1
+
tan
2
θ
{\displaystyle \pm {\frac {1}{\sqrt {1+\tan ^{2}\theta }}}\ }
±
csc
2
θ
−
1
csc
θ
{\displaystyle \pm {\frac {\sqrt {\csc ^{2}\theta -1}}{\csc \theta }}\ }
1
sec
θ
{\displaystyle {\frac {1}{\sec \theta }}\ }
±
cot
θ
1
+
cot
2
θ
{\displaystyle \pm {\frac {\cot \theta }{\sqrt {1+\cot ^{2}\theta }}}\ }
tan
θ
=
{\displaystyle \tan \theta =}
±
sin
θ
1
−
sin
2
θ
{\displaystyle \pm {\frac {\sin \theta }{\sqrt {1-\sin ^{2}\theta }}}\ }
±
1
−
cos
2
θ
cos
θ
{\displaystyle \pm {\frac {\sqrt {1-\cos ^{2}\theta }}{\cos \theta }}\ }
tan
θ
{\displaystyle \tan \theta \ }
±
1
csc
2
θ
−
1
{\displaystyle \pm {\frac {1}{\sqrt {\csc ^{2}\theta -1}}}\ }
±
sec
2
θ
−
1
{\displaystyle \pm {\sqrt {\sec ^{2}\theta -1}}\ }
1
cot
θ
{\displaystyle {\frac {1}{\cot \theta }}\ }
csc
θ
=
{\displaystyle \csc \theta =}
1
sin
θ
{\displaystyle {\frac {1}{\sin \theta }}\ }
±
1
1
−
cos
2
θ
{\displaystyle \pm {\frac {1}{\sqrt {1-\cos ^{2}\theta }}}\ }
±
1
+
tan
2
θ
tan
θ
{\displaystyle \pm {\frac {\sqrt {1+\tan ^{2}\theta }}{\tan \theta }}\ }
csc
θ
{\displaystyle \csc \theta \ }
±
sec
θ
sec
2
θ
−
1
{\displaystyle \pm {\frac {\sec \theta }{\sqrt {\sec ^{2}\theta -1}}}\ }
±
1
+
cot
2
θ
{\displaystyle \pm {\sqrt {1+\cot ^{2}\theta }}\ }
sec
θ
=
{\displaystyle \sec \theta =}
±
1
1
−
sin
2
θ
{\displaystyle \pm {\frac {1}{\sqrt {1-\sin ^{2}\theta }}}\ }
1
cos
θ
{\displaystyle {\frac {1}{\cos \theta }}\ }
±
1
+
tan
2
θ
{\displaystyle \pm {\sqrt {1+\tan ^{2}\theta }}\ }
±
csc
θ
csc
2
θ
−
1
{\displaystyle \pm {\frac {\csc \theta }{\sqrt {\csc ^{2}\theta -1}}}\ }
sec
θ
{\displaystyle \sec \theta \ }
±
1
+
cot
2
θ
cot
θ
{\displaystyle \pm {\frac {\sqrt {1+\cot ^{2}\theta }}{\cot \theta }}\ }
cot
θ
=
{\displaystyle \cot \theta =}
±
1
−
sin
2
θ
sin
θ
{\displaystyle \pm {\frac {\sqrt {1-\sin ^{2}\theta }}{\sin \theta }}\ }
±
cos
θ
1
−
cos
2
θ
{\displaystyle \pm {\frac {\cos \theta }{\sqrt {1-\cos ^{2}\theta }}}\ }
1
tan
θ
{\displaystyle {\frac {1}{\tan \theta }}\ }
±
csc
2
θ
−
1
{\displaystyle \pm {\sqrt {\csc ^{2}\theta -1}}\ }
±
1
sec
2
θ
−
1
{\displaystyle \pm {\frac {1}{\sqrt {\sec ^{2}\theta -1}}}\ }
cot
θ
{\displaystyle \cot \theta \ }
Historic shorthands
The versine , coversine , haversine , and exsecant were used in navigation. For example the haversine formula was used to calculate the distance between two points on a sphere. They are rarely used today.
Name(s)
Abbreviation(s)
Value [ 2]
versed sine, versine
versin
(
θ
)
{\displaystyle \operatorname {versin} (\theta )}
vers
(
θ
)
{\displaystyle \operatorname {vers} (\theta )}
ver
(
θ
)
{\displaystyle \operatorname {ver} (\theta )}
1
−
cos
(
θ
)
{\displaystyle 1-\cos(\theta )}
versed cosine, vercosine
vercosin
(
θ
)
{\displaystyle \operatorname {vercosin} (\theta )}
1
+
cos
(
θ
)
{\displaystyle 1+\cos(\theta )}
coversed sine, coversine
coversin
(
θ
)
{\displaystyle \operatorname {coversin} (\theta )}
cvs
(
θ
)
{\displaystyle \operatorname {cvs} (\theta )}
1
−
sin
(
θ
)
{\displaystyle 1-\sin(\theta )}
coversed cosine, covercosine
covercosin
(
θ
)
{\displaystyle \operatorname {covercosin} (\theta )}
1
+
sin
(
θ
)
{\displaystyle 1+\sin(\theta )}
haversed sine, haversine
haversin
(
θ
)
{\displaystyle \operatorname {haversin} (\theta )}
1
−
cos
(
θ
)
2
{\displaystyle {\frac {1-\cos(\theta )}{2}}}
haversed cosine, havercosine
havercosin
(
θ
)
{\displaystyle \operatorname {havercosin} (\theta )}
1
+
cos
(
θ
)
2
{\displaystyle {\frac {1+\cos(\theta )}{2}}}
hacoversed sine, hacoversine cohaversine
hacoversin
(
θ
)
{\displaystyle \operatorname {hacoversin} (\theta )}
1
−
sin
(
θ
)
2
{\displaystyle {\frac {1-\sin(\theta )}{2}}}
hacoversed cosine, hacovercosine cohavercosine
hacovercosin
(
θ
)
{\displaystyle \operatorname {hacovercosin} (\theta )}
1
+
sin
(
θ
)
2
{\displaystyle {\frac {1+\sin(\theta )}{2}}}
exterior secant, exsecant
exsec
(
θ
)
{\displaystyle \operatorname {exsec} (\theta )}
sec
(
θ
)
−
1
{\displaystyle \sec(\theta )-1}
exterior cosecant, excosecant
excsc
(
θ
)
{\displaystyle \operatorname {excsc} (\theta )}
csc
(
θ
)
−
1
{\displaystyle \csc(\theta )-1}
chord
crd
(
θ
)
{\displaystyle \operatorname {crd} (\theta )}
2
sin
(
θ
2
)
{\displaystyle 2\sin \left({\frac {\theta }{2}}\right)}
Symmetry, shifts, and periodicity
By examining the unit circle, the following properties of the trigonometric functions can be established.
Symmetry
When the trigonometric functions are reflected from certain angles, the result is often one of the other trigonometric functions. This leads to the following identities:
Reflected in
θ
=
0
{\displaystyle \theta =0}
[ 3]
Reflected in
θ
=
π
/
2
{\displaystyle \theta =\pi /2}
(co-function identities)[ 4]
Reflected in
θ
=
π
{\displaystyle \theta =\pi }
sin
(
−
θ
)
=
−
sin
θ
cos
(
−
θ
)
=
+
cos
θ
tan
(
−
θ
)
=
−
tan
θ
csc
(
−
θ
)
=
−
csc
θ
sec
(
−
θ
)
=
+
sec
θ
cot
(
−
θ
)
=
−
cot
θ
{\displaystyle {\begin{aligned}\sin(-\theta )&=-\sin \theta \\\cos(-\theta )&=+\cos \theta \\\tan(-\theta )&=-\tan \theta \\\csc(-\theta )&=-\csc \theta \\\sec(-\theta )&=+\sec \theta \\\cot(-\theta )&=-\cot \theta \end{aligned}}}
sin
(
π
2
−
θ
)
=
+
cos
θ
cos
(
π
2
−
θ
)
=
+
sin
θ
tan
(
π
2
−
θ
)
=
+
cot
θ
csc
(
π
2
−
θ
)
=
+
sec
θ
sec
(
π
2
−
θ
)
=
+
csc
θ
cot
(
π
2
−
θ
)
=
+
tan
θ
{\displaystyle {\begin{aligned}\sin({\tfrac {\pi }{2}}-\theta )&=+\cos \theta \\\cos({\tfrac {\pi }{2}}-\theta )&=+\sin \theta \\\tan({\tfrac {\pi }{2}}-\theta )&=+\cot \theta \\\csc({\tfrac {\pi }{2}}-\theta )&=+\sec \theta \\\sec({\tfrac {\pi }{2}}-\theta )&=+\csc \theta \\\cot({\tfrac {\pi }{2}}-\theta )&=+\tan \theta \end{aligned}}}
sin
(
π
−
θ
)
=
+
sin
θ
cos
(
π
−
θ
)
=
−
cos
θ
tan
(
π
−
θ
)
=
−
tan
θ
csc
(
π
−
θ
)
=
+
csc
θ
sec
(
π
−
θ
)
=
−
sec
θ
cot
(
π
−
θ
)
=
−
cot
θ
{\displaystyle {\begin{aligned}\sin(\pi -\theta )&=+\sin \theta \\\cos(\pi -\theta )&=-\cos \theta \\\tan(\pi -\theta )&=-\tan \theta \\\csc(\pi -\theta )&=+\csc \theta \\\sec(\pi -\theta )&=-\sec \theta \\\cot(\pi -\theta )&=-\cot \theta \\\end{aligned}}}
Shifts and periodicity
By shifting the function round by certain angles, it is often possible to find different trigonometric functions that express the result more simply. Some examples of this are shown by shifting functions round by π/2, π and 2π radians. Because the periods of these functions are either π or 2π, there are cases where the new function is exactly the same as the old function without the shift.
Shift by π/2
Shift by π Period for tan and cot[ 5]
Shift by 2π Period for sin, cos, csc and sec[ 6]
sin
(
θ
+
π
2
)
=
+
cos
θ
cos
(
θ
+
π
2
)
=
−
sin
θ
tan
(
θ
+
π
2
)
=
−
cot
θ
csc
(
θ
+
π
2
)
=
+
sec
θ
sec
(
θ
+
π
2
)
=
−
csc
θ
cot
(
θ
+
π
2
)
=
−
tan
θ
{\displaystyle {\begin{aligned}\sin(\theta +{\tfrac {\pi }{2}})&=+\cos \theta \\\cos(\theta +{\tfrac {\pi }{2}})&=-\sin \theta \\\tan(\theta +{\tfrac {\pi }{2}})&=-\cot \theta \\\csc(\theta +{\tfrac {\pi }{2}})&=+\sec \theta \\\sec(\theta +{\tfrac {\pi }{2}})&=-\csc \theta \\\cot(\theta +{\tfrac {\pi }{2}})&=-\tan \theta \end{aligned}}}
sin
(
θ
+
π
)
=
−
sin
θ
cos
(
θ
+
π
)
=
−
cos
θ
tan
(
θ
+
π
)
=
+
tan
θ
csc
(
θ
+
π
)
=
−
csc
θ
sec
(
θ
+
π
)
=
−
sec
θ
cot
(
θ
+
π
)
=
+
cot
θ
{\displaystyle {\begin{aligned}\sin(\theta +\pi )&=-\sin \theta \\\cos(\theta +\pi )&=-\cos \theta \\\tan(\theta +\pi )&=+\tan \theta \\\csc(\theta +\pi )&=-\csc \theta \\\sec(\theta +\pi )&=-\sec \theta \\\cot(\theta +\pi )&=+\cot \theta \\\end{aligned}}}
sin
(
θ
+
2
π
)
=
+
sin
θ
cos
(
θ
+
2
π
)
=
+
cos
θ
tan
(
θ
+
2
π
)
=
+
tan
θ
csc
(
θ
+
2
π
)
=
+
csc
θ
sec
(
θ
+
2
π
)
=
+
sec
θ
cot
(
θ
+
2
π
)
=
+
cot
θ
{\displaystyle {\begin{aligned}\sin(\theta +2\pi )&=+\sin \theta \\\cos(\theta +2\pi )&=+\cos \theta \\\tan(\theta +2\pi )&=+\tan \theta \\\csc(\theta +2\pi )&=+\csc \theta \\\sec(\theta +2\pi )&=+\sec \theta \\\cot(\theta +2\pi )&=+\cot \theta \end{aligned}}}
Angle sum and difference identities
These are also known as the addition and subtraction theorems or formulæ .
They were originally established by the 10th century Persian mathematician Abū al-Wafā' Būzjānī .
One method of proving these identities is to apply Euler's formula . The use of the symbols
±
{\displaystyle \pm }
and
∓
{\displaystyle \mp }
is described at Plus-minus sign .
Sine
sin
(
α
±
β
)
=
sin
α
cos
β
±
cos
α
sin
β
{\displaystyle \sin(\alpha \pm \beta )=\sin \alpha \cos \beta \pm \cos \alpha \sin \beta \,}
[ 7] [ 8]
Cosine
cos
(
α
±
β
)
=
cos
α
cos
β
∓
sin
α
sin
β
{\displaystyle \cos(\alpha \pm \beta )=\cos \alpha \cos \beta \mp \sin \alpha \sin \beta \,}
[ 8] [ 9]
Tangent
tan
(
α
±
β
)
=
tan
α
±
tan
β
1
∓
tan
α
tan
β
{\displaystyle \tan(\alpha \pm \beta )={\frac {\tan \alpha \pm \tan \beta }{1\mp \tan \alpha \tan \beta }}}
[ 8] [ 10]
Arcsine
arcsin
α
±
arcsin
β
=
arcsin
(
α
1
−
β
2
±
β
1
−
α
2
)
{\displaystyle \arcsin \alpha \pm \arcsin \beta =\arcsin(\alpha {\sqrt {1-\beta ^{2}}}\pm \beta {\sqrt {1-\alpha ^{2}}})}
[ 11]
Arccosine
arccos
α
±
arccos
β
=
arccos
(
α
β
∓
(
1
−
α
2
)
(
1
−
β
2
)
)
{\displaystyle \arccos \alpha \pm \arccos \beta =\arccos(\alpha \beta \mp {\sqrt {(1-\alpha ^{2})(1-\beta ^{2})}})}
[ 12]
Arctangent
arctan
α
±
arctan
β
=
arctan
(
α
±
β
1
∓
α
β
)
{\displaystyle \arctan \alpha \pm \arctan \beta =\arctan \left({\frac {\alpha \pm \beta }{1\mp \alpha \beta }}\right)}
[ 13]
The sum and difference formulæ for sine and cosine can be written in matrix form, thus:
[
cos
α
−
sin
α
sin
α
cos
α
]
[
cos
β
−
sin
β
sin
β
cos
β
]
=
[
cos
(
α
+
β
)
−
sin
(
α
+
β
)
sin
(
α
+
β
)
cos
(
α
+
β
)
]
.
{\displaystyle \left[{\begin{matrix}\cos \alpha &-\sin \alpha \\\sin \alpha &\cos \alpha \end{matrix}}\right]\left[{\begin{matrix}\cos \beta &-\sin \beta \\\sin \beta &\cos \beta \end{matrix}}\right]=\left[{\begin{matrix}\cos(\alpha +\beta )&-\sin(\alpha +\beta )\\\sin(\alpha +\beta )&\cos(\alpha +\beta )\end{matrix}}\right].}
Sines and cosines of sums of infinitely many terms
sin
(
∑
i
=
1
∞
θ
i
)
=
∑
o
d
d
k
≥
1
(
−
1
)
(
k
−
1
)
/
2
∑
A
⊆
{
1
,
2
,
3
,
…
}
|
A
|
=
k
(
∏
i
∈
A
sin
θ
i
∏
i
∉
A
cos
θ
i
)
{\displaystyle \sin \left(\sum _{i=1}^{\infty }\theta _{i}\right)=\sum _{\mathrm {odd} \ k\geq 1}(-1)^{(k-1)/2}\sum _{\begin{smallmatrix}A\subseteq \{\,1,2,3,\dots \,\}\\\left|A\right|=k\end{smallmatrix}}\left(\prod _{i\in A}\sin \theta _{i}\prod _{i\not \in A}\cos \theta _{i}\right)}
cos
(
∑
i
=
1
∞
θ
i
)
=
∑
e
v
e
n
k
≥
0
(
−
1
)
k
/
2
∑
A
⊆
{
1
,
2
,
3
,
…
}
|
A
|
=
k
(
∏
i
∈
A
sin
θ
i
∏
i
∉
A
cos
θ
i
)
{\displaystyle \cos \left(\sum _{i=1}^{\infty }\theta _{i}\right)=\sum _{\mathrm {even} \ k\geq 0}~(-1)^{k/2}~~\sum _{\begin{smallmatrix}A\subseteq \{\,1,2,3,\dots \,\}\\\left|A\right|=k\end{smallmatrix}}\left(\prod _{i\in A}\sin \theta _{i}\prod _{i\not \in A}\cos \theta _{i}\right)}
In these two identities an asymmetry appears that is not seen in the case of sums of finitely many terms: in each product, there are only finitely many sine factors and cofinitely many cosine factors.
If only finitely many of the terms θi are nonzero, then only finitely many of the terms on the right side will be nonzero because sine factors will vanish, and in each term, all but finitely many of the cosine factors will be unity.
Tangents of sums of finitely many terms
Let e k (for k ∈ {0, ..., n }) be the k th-degree elementary symmetric polynomial in the variables:
x
i
=
tan
θ
i
{\displaystyle x_{i}=\tan \theta _{i}\,}
for i ∈ {0, ..., n }, i.e.
e
0
=
1
e
1
=
∑
1
≤
i
≤
n
x
i
=
∑
1
≤
i
≤
n
tan
θ
i
e
2
=
∑
1
≤
i
<
j
≤
n
x
i
x
j
=
∑
1
≤
i
<
j
≤
n
tan
θ
i
tan
θ
j
e
3
=
∑
1
≤
i
<
j
<
k
≤
n
x
i
x
j
x
k
=
∑
1
≤
i
<
j
<
k
≤
n
tan
θ
i
tan
θ
j
tan
θ
k
⋮
⋮
{\displaystyle {\begin{aligned}e_{0}&=1\\[6pt]e_{1}&=\sum _{1\leq i\leq n}x_{i}&&=\sum _{1\leq i\leq n}\tan \theta _{i}\\[6pt]e_{2}&=\sum _{1\leq i<j\leq n}x_{i}x_{j}&&=\sum _{1\leq i<j\leq n}\tan \theta _{i}\tan \theta _{j}\\[6pt]e_{3}&=\sum _{1\leq i<j<k\leq n}x_{i}x_{j}x_{k}&&=\sum _{1\leq i<j<k\leq n}\tan \theta _{i}\tan \theta _{j}\tan \theta _{k}\\&{}\ \ \vdots &&{}\ \ \vdots \end{aligned}}}
Then
tan
(
θ
1
+
⋯
+
θ
n
)
=
e
1
−
e
3
+
e
5
−
⋯
e
0
−
e
2
+
e
4
−
⋯
,
{\displaystyle \tan(\theta _{1}+\cdots +\theta _{n})={\frac {e_{1}-e_{3}+e_{5}-\cdots }{e_{0}-e_{2}+e_{4}-\cdots }},}
the number of terms depending on n .
For example:
tan
(
θ
1
+
θ
2
)
=
e
1
e
0
−
e
2
=
x
1
+
x
2
1
−
x
1
x
2
=
tan
θ
1
+
tan
θ
2
1
−
tan
θ
1
tan
θ
2
,
tan
(
θ
1
+
θ
2
+
θ
3
)
=
e
1
−
e
3
e
0
−
e
2
=
(
x
1
+
x
2
+
x
3
)
−
(
x
1
x
2
x
3
)
1
−
(
x
1
x
2
+
x
1
x
3
+
x
2
x
3
)
,
tan
(
θ
1
+
θ
2
+
θ
3
+
θ
4
)
=
e
1
−
e
3
e
0
−
e
2
+
e
4
=
(
x
1
+
x
2
+
x
3
+
x
4
)
−
(
x
1
x
2
x
3
+
x
1
x
2
x
4
+
x
1
x
3
x
4
+
x
2
x
3
x
4
)
1
−
(
x
1
x
2
+
x
1
x
3
+
x
1
x
4
+
x
2
x
3
+
x
2
x
4
+
x
3
x
4
)
+
(
x
1
x
2
x
3
x
4
)
,
{\displaystyle {\begin{aligned}\tan(\theta _{1}+\theta _{2})&={\frac {e_{1}}{e_{0}-e_{2}}}={\frac {x_{1}+x_{2}}{1\ -\ x_{1}x_{2}}}={\frac {\tan \theta _{1}+\tan \theta _{2}}{1\ -\ \tan \theta _{1}\tan \theta _{2}}},\\\\\tan(\theta _{1}+\theta _{2}+\theta _{3})&={\frac {e_{1}-e_{3}}{e_{0}-e_{2}}}={\frac {(x_{1}+x_{2}+x_{3})\ -\ (x_{1}x_{2}x_{3})}{1\ -\ (x_{1}x_{2}+x_{1}x_{3}+x_{2}x_{3})}},\\\\\tan(\theta _{1}+\theta _{2}+\theta _{3}+\theta _{4})&={\frac {e_{1}-e_{3}}{e_{0}-e_{2}+e_{4}}}\\\\&={\frac {(x_{1}+x_{2}+x_{3}+x_{4})\ -\ (x_{1}x_{2}x_{3}+x_{1}x_{2}x_{4}+x_{1}x_{3}x_{4}+x_{2}x_{3}x_{4})}{1\ -\ (x_{1}x_{2}+x_{1}x_{3}+x_{1}x_{4}+x_{2}x_{3}+x_{2}x_{4}+x_{3}x_{4})\ +\ (x_{1}x_{2}x_{3}x_{4})}},\end{aligned}}}
and so on. The general case can be proved by mathematical induction .
Secants of sums of finitely many terms
sec
(
θ
1
+
⋯
+
θ
n
)
=
sec
θ
1
⋯
sec
θ
n
e
0
−
e
2
+
e
4
−
⋯
{\displaystyle \sec(\theta _{1}+\cdots +\theta _{n})={\frac {\sec \theta _{1}\cdots \sec \theta _{n}}{e_{0}-e_{2}+e_{4}-\cdots }}}
where e k is the k th-degree elementary symmetric polynomial in the n variables x i = tan θ i , i = 1, ..., n , and the number of terms in the denominator depends on n .
For example,
sec
(
α
+
β
+
γ
)
=
sec
α
sec
β
sec
γ
1
−
tan
α
tan
β
−
tan
α
tan
γ
−
tan
β
tan
γ
.
{\displaystyle \sec(\alpha +\beta +\gamma )={\frac {\sec \alpha \sec \beta \sec \gamma }{1-\tan \alpha \tan \beta -\tan \alpha \tan \gamma -\tan \beta \tan \gamma }}.}
Tn is the n th Chebyshev polynomial
cos
n
θ
=
T
n
(
cos
θ
)
{\displaystyle \cos n\theta =T_{n}(\cos \theta )\,}
[ 14]
S n is the n th spread polynomial
sin
2
n
θ
=
S
n
(
sin
2
θ
)
{\displaystyle \sin ^{2}n\theta =S_{n}(\sin ^{2}\theta )\,}
de Moivre's formula ,
i
{\displaystyle i}
is the Imaginary unit
cos
n
θ
+
i
sin
n
θ
=
(
cos
(
θ
)
+
i
sin
(
θ
)
)
n
{\displaystyle \cos n\theta +i\sin n\theta =(\cos(\theta )+i\sin(\theta ))^{n}\,}
[ 15]
1
+
2
cos
(
x
)
+
2
cos
(
2
x
)
+
2
cos
(
3
x
)
+
⋯
+
2
cos
(
n
x
)
=
sin
(
(
n
+
1
2
)
x
)
sin
(
x
/
2
)
.
{\displaystyle 1+2\cos(x)+2\cos(2x)+2\cos(3x)+\cdots +2\cos(nx)={\frac {\sin \left(\left(n+{\frac {1}{2}}\right)x\right)}{\sin(x/2)}}.}
(This function of x is the Dirichlet kernel .)
These can be shown by using either the sum and difference identities or the multiple-angle formulae.
Double-angle formulae[ 16] [ 17]
sin
2
θ
=
2
sin
θ
cos
θ
=
2
tan
θ
1
+
tan
2
θ
{\displaystyle {\begin{aligned}\sin 2\theta &=2\sin \theta \cos \theta \ \\&={\frac {2\tan \theta }{1+\tan ^{2}\theta }}\end{aligned}}}
cos
2
θ
=
cos
2
θ
−
sin
2
θ
=
2
cos
2
θ
−
1
=
1
−
2
sin
2
θ
=
1
−
tan
2
θ
1
+
tan
2
θ
{\displaystyle {\begin{aligned}\cos 2\theta &=\cos ^{2}\theta -\sin ^{2}\theta \\&=2\cos ^{2}\theta -1\\&=1-2\sin ^{2}\theta \\&={\frac {1-\tan ^{2}\theta }{1+\tan ^{2}\theta }}\end{aligned}}}
tan
2
θ
=
2
tan
θ
1
−
tan
2
θ
{\displaystyle \tan 2\theta ={\frac {2\tan \theta }{1-\tan ^{2}\theta }}\,}
cot
2
θ
=
cot
2
θ
−
1
2
cot
θ
{\displaystyle \cot 2\theta ={\frac {\cot ^{2}\theta -1}{2\cot \theta }}\,}
Triple-angle formulae[ 14] [ 18]
sin
3
θ
=
3
sin
θ
−
4
sin
3
θ
{\displaystyle \sin 3\theta =3\sin \theta -4\sin ^{3}\theta \,}
cos
3
θ
=
4
cos
3
θ
−
3
cos
θ
{\displaystyle \cos 3\theta =4\cos ^{3}\theta -3\cos \theta \,}
tan
3
θ
=
3
tan
θ
−
tan
3
θ
1
−
3
tan
2
θ
{\displaystyle \tan 3\theta ={\frac {3\tan \theta -\tan ^{3}\theta }{1-3\tan ^{2}\theta }}}
cot
3
θ
=
3
cot
θ
−
cot
3
θ
1
−
3
cot
2
θ
{\displaystyle \cot 3\theta ={\frac {3\cot \theta -\cot ^{3}\theta }{1-3\cot ^{2}\theta }}}
Half-angle formulae[ 19] [ 20]
sin
θ
2
=
±
1
−
cos
θ
2
{\displaystyle \sin {\frac {\theta }{2}}=\pm \,{\sqrt {\frac {1-\cos \theta }{2}}}}
cos
θ
2
=
±
1
+
cos
θ
2
{\displaystyle \cos {\frac {\theta }{2}}=\pm \,{\sqrt {\frac {1+\cos \theta }{2}}}}
tan
θ
2
=
csc
θ
−
cot
θ
=
±
1
−
cos
θ
1
+
cos
θ
=
sin
θ
1
+
cos
θ
=
1
−
cos
θ
sin
θ
{\displaystyle {\begin{aligned}\tan {\frac {\theta }{2}}&=\csc \theta -\cot \theta \\&=\pm \,{\sqrt {1-\cos \theta \over 1+\cos \theta }}\\&={\frac {\sin \theta }{1+\cos \theta }}\\&={\frac {1-\cos \theta }{\sin \theta }}\end{aligned}}}
cot
θ
2
=
csc
θ
+
cot
θ
=
±
1
+
cos
θ
1
−
cos
θ
=
sin
θ
1
−
cos
θ
=
1
+
cos
θ
sin
θ
{\displaystyle {\begin{aligned}\cot {\frac {\theta }{2}}&=\csc \theta +\cot \theta \\&=\pm \,{\sqrt {1+\cos \theta \over 1-\cos \theta }}\\&={\frac {\sin \theta }{1-\cos \theta }}\\&={\frac {1+\cos \theta }{\sin \theta }}\end{aligned}}}
The fact that the triple-angle formula for sine and cosine only involves powers of a single function allows one to relate the geometric problem of a compass and straightedge construction of angle trisection to the algebraic problem of solving a cubic equation , which allows one to prove that this is in general impossible, by field theory .
A formula for computing the trigonometric identities for the third-angle exists, but it requires finding the zeroes of the cubic equation
x
3
−
3
x
+
d
4
=
0
{\displaystyle x^{3}-{\frac {3x+d}{4}}=0}
, where x is the value of the sine function at some angle and d is the known value of the sine function at the triple angle. However, the discriminant of this equation is negative, so this equation has three real roots (of which only one is the solution within the correct third-circle) but none of these solutions is reducible to a real algebraic expression, as they use intermediate complex numbers under the cube roots , (which may be expressed in terms of real-only functions only if using hyperbolic functions). As a consequence, it is not possible to express the trigonometric values of angles that are not multiples of 3 degrees divided by any power of two, if using a real-only algebraic expression (for example sin(1°)).
See also Casus irreducibilis .
Sine, cosine, and tangent of multiple angles
For specific multiples, these follow from the angle addition formulas, while the general formula was given by 16th century French mathematician Vieta .
sin
n
θ
=
∑
k
=
0
n
(
n
k
)
cos
k
θ
sin
n
−
k
θ
sin
(
1
2
(
n
−
k
)
π
)
{\displaystyle \sin n\theta =\sum _{k=0}^{n}{\binom {n}{k}}\cos ^{k}\theta \,\sin ^{n-k}\theta \,\sin \left({\frac {1}{2}}(n-k)\pi \right)}
cos
n
θ
=
∑
k
=
0
n
(
n
k
)
cos
k
θ
sin
n
−
k
θ
cos
(
1
2
(
n
−
k
)
π
)
{\displaystyle \cos n\theta =\sum _{k=0}^{n}{\binom {n}{k}}\cos ^{k}\theta \,\sin ^{n-k}\theta \,\cos \left({\frac {1}{2}}(n-k)\pi \right)}
tan nθ can be written in terms of tan θ using the recurrence relation:
tan
(
n
+
1
)
θ
=
tan
n
θ
+
tan
θ
1
−
tan
n
θ
tan
θ
.
{\displaystyle \tan \,(n{+}1)\theta ={\frac {\tan n\theta +\tan \theta }{1-\tan n\theta \,\tan \theta }}.}
cot nθ can be written in terms of cot θ using the recurrence relation:
cot
(
n
+
1
)
θ
=
cot
n
θ
cot
θ
−
1
cot
n
θ
+
cot
θ
.
{\displaystyle \cot \,(n{+}1)\theta ={\frac {\cot n\theta \,\cot \theta -1}{\cot n\theta +\cot \theta }}.}
Chebyshev method
The Chebyshev method is a recursive algorithm for finding the n th multiple angle formula knowing the (n − 1)th and (n − 2)th formulae.[ 21]
The cosine for nx can be computed from the cosine of (n − 1) and (n − 2) as follows:
cos
n
x
=
2
⋅
cos
x
⋅
cos
(
n
−
1
)
x
−
cos
(
n
−
2
)
x
{\displaystyle \cos nx=2\cdot \cos x\cdot \cos(n-1)x-\cos(n-2)x\,}
Similarly sin(nx ) can be computed from the sines of (n − 1)x and (n − 2)x
sin
n
x
=
2
⋅
cos
x
⋅
sin
(
n
−
1
)
x
−
sin
(
n
−
2
)
x
{\displaystyle \sin nx=2\cdot \cos x\cdot \sin(n-1)x-\sin(n-2)x\,}
For the tangent, we have:
tan
n
x
=
H
+
K
tan
x
K
−
H
tan
x
{\displaystyle \tan nx={\frac {H+K\tan x}{K-H\tan x}}\,}
where H /K = tan(n − 1)x .
Tangent of an average
tan
(
α
+
β
2
)
=
sin
α
+
sin
β
cos
α
+
cos
β
=
−
cos
α
−
cos
β
sin
α
−
sin
β
{\displaystyle \tan \left({\frac {\alpha +\beta }{2}}\right)={\frac {\sin \alpha +\sin \beta }{\cos \alpha +\cos \beta }}=-\,{\frac {\cos \alpha -\cos \beta }{\sin \alpha -\sin \beta }}}
Setting either α or β to 0 gives the usual tangent half-angle formulæ.
Euler's infinite product
cos
(
θ
2
)
⋅
cos
(
θ
4
)
⋅
cos
(
θ
8
)
⋯
=
∏
n
=
1
∞
cos
(
θ
2
n
)
=
sin
(
θ
)
θ
=
sinc
θ
.
{\displaystyle \cos \left({\theta \over 2}\right)\cdot \cos \left({\theta \over 4}\right)\cdot \cos \left({\theta \over 8}\right)\cdots =\prod _{n=1}^{\infty }\cos \left({\theta \over 2^{n}}\right)={\sin(\theta ) \over \theta }=\operatorname {sinc} \,\theta .}
Obtained by solving the second and third versions of the cosine double-angle formula.
Sine
Cosine
Other
sin
2
θ
=
1
−
cos
2
θ
2
{\displaystyle \sin ^{2}\theta ={\frac {1-\cos 2\theta }{2}}}
cos
2
θ
=
1
+
cos
2
θ
2
{\displaystyle \cos ^{2}\theta ={\frac {1+\cos 2\theta }{2}}}
sin
2
θ
cos
2
θ
=
1
−
cos
4
θ
8
{\displaystyle \sin ^{2}\theta \cos ^{2}\theta ={\frac {1-\cos 4\theta }{8}}}
sin
3
θ
=
3
sin
θ
−
sin
3
θ
4
{\displaystyle \sin ^{3}\theta ={\frac {3\sin \theta -\sin 3\theta }{4}}}
cos
3
θ
=
3
cos
θ
+
cos
3
θ
4
{\displaystyle \cos ^{3}\theta ={\frac {3\cos \theta +\cos 3\theta }{4}}}
sin
3
θ
cos
3
θ
=
3
sin
2
θ
−
sin
6
θ
32
{\displaystyle \sin ^{3}\theta \cos ^{3}\theta ={\frac {3\sin 2\theta -\sin 6\theta }{32}}}
sin
4
θ
=
3
−
4
cos
2
θ
+
cos
4
θ
8
{\displaystyle \sin ^{4}\theta ={\frac {3-4\cos 2\theta +\cos 4\theta }{8}}}
cos
4
θ
=
3
+
4
cos
2
θ
+
cos
4
θ
8
{\displaystyle \cos ^{4}\theta ={\frac {3+4\cos 2\theta +\cos 4\theta }{8}}}
sin
4
θ
cos
4
θ
=
3
−
4
cos
4
θ
+
cos
8
θ
128
{\displaystyle \sin ^{4}\theta \cos ^{4}\theta ={\frac {3-4\cos 4\theta +\cos 8\theta }{128}}}
sin
5
θ
=
10
sin
θ
−
5
sin
3
θ
+
sin
5
θ
16
{\displaystyle \sin ^{5}\theta ={\frac {10\sin \theta -5\sin 3\theta +\sin 5\theta }{16}}}
cos
5
θ
=
10
cos
θ
+
5
cos
3
θ
+
cos
5
θ
16
{\displaystyle \cos ^{5}\theta ={\frac {10\cos \theta +5\cos 3\theta +\cos 5\theta }{16}}}
sin
5
θ
cos
5
θ
=
10
sin
2
θ
−
5
sin
6
θ
+
sin
10
θ
512
{\displaystyle \sin ^{5}\theta \cos ^{5}\theta ={\frac {10\sin 2\theta -5\sin 6\theta +\sin 10\theta }{512}}}
and in general terms of powers of sin θ or cos θ the following is true, and can be deduced using De Moivre's formula , Euler's formula and binomial theorem .
Cosine
Sine
if
n
is odd
{\displaystyle {\text{if }}n{\text{ is odd}}}
cos
n
θ
=
2
2
n
∑
k
=
0
n
−
1
2
(
n
k
)
cos
(
(
n
−
2
k
)
θ
)
{\displaystyle \cos ^{n}\theta ={\frac {2}{2^{n}}}\sum _{k=0}^{\frac {n-1}{2}}{\binom {n}{k}}\cos {((n-2k)\theta )}}
sin
n
θ
=
2
2
n
∑
k
=
0
n
−
1
2
(
−
1
)
(
n
−
1
2
−
k
)
(
n
k
)
sin
(
(
n
−
2
k
)
θ
)
{\displaystyle \sin ^{n}\theta ={\frac {2}{2^{n}}}\sum _{k=0}^{\frac {n-1}{2}}(-1)^{({\frac {n-1}{2}}-k)}{\binom {n}{k}}\sin {((n-2k)\theta )}}
if
n
is even
{\displaystyle {\text{if }}n{\text{ is even}}}
cos
n
θ
=
1
2
n
(
n
n
2
)
+
2
2
n
∑
k
=
0
n
2
−
1
(
n
k
)
cos
(
(
n
−
2
k
)
θ
)
{\displaystyle \cos ^{n}\theta ={\frac {1}{2^{n}}}{\binom {n}{\frac {n}{2}}}+{\frac {2}{2^{n}}}\sum _{k=0}^{{\frac {n}{2}}-1}{\binom {n}{k}}\cos {((n-2k)\theta )}}
sin
n
θ
=
1
2
n
(
n
n
2
)
+
2
2
n
∑
k
=
0
n
2
−
1
(
−
1
)
(
n
2
−
k
)
(
n
k
)
cos
(
(
n
−
2
k
)
θ
)
{\displaystyle \sin ^{n}\theta ={\frac {1}{2^{n}}}{\binom {n}{\frac {n}{2}}}+{\frac {2}{2^{n}}}\sum _{k=0}^{{\frac {n}{2}}-1}(-1)^{({\frac {n}{2}}-k)}{\binom {n}{k}}\cos {((n-2k)\theta )}}
Product-to-sum and sum-to-product identities
The product-to-sum identities or Prosthaphaeresis formulas can be proven by expanding their right-hand sides using the angle addition theorems . See beat (acoustics) for an application of the sum-to-product formulæ.
Product-to-sum[ 22]
cos
θ
cos
φ
=
cos
(
θ
−
φ
)
+
cos
(
θ
+
φ
)
2
{\displaystyle \cos \theta \cos \varphi ={\cos(\theta -\varphi )+\cos(\theta +\varphi ) \over 2}}
sin
θ
sin
φ
=
cos
(
θ
−
φ
)
−
cos
(
θ
+
φ
)
2
{\displaystyle \sin \theta \sin \varphi ={\cos(\theta -\varphi )-\cos(\theta +\varphi ) \over 2}}
sin
θ
cos
φ
=
sin
(
θ
+
φ
)
+
sin
(
θ
−
φ
)
2
{\displaystyle \sin \theta \cos \varphi ={\sin(\theta +\varphi )+\sin(\theta -\varphi ) \over 2}}
cos
θ
sin
φ
=
sin
(
θ
+
φ
)
−
sin
(
θ
−
φ
)
2
{\displaystyle \cos \theta \sin \varphi ={\sin(\theta +\varphi )-\sin(\theta -\varphi ) \over 2}}
Sum-to-product[ 23]
sin
θ
±
sin
φ
=
2
sin
(
θ
±
φ
2
)
cos
(
θ
∓
φ
2
)
{\displaystyle \sin \theta \pm \sin \varphi =2\sin \left({\frac {\theta \pm \varphi }{2}}\right)\cos \left({\frac {\theta \mp \varphi }{2}}\right)}
cos
θ
+
cos
φ
=
2
cos
(
θ
+
φ
2
)
cos
(
θ
−
φ
2
)
{\displaystyle \cos \theta +\cos \varphi =2\cos \left({\frac {\theta +\varphi }{2}}\right)\cos \left({\frac {\theta -\varphi }{2}}\right)}
cos
θ
−
cos
φ
=
−
2
sin
(
θ
+
φ
2
)
sin
(
θ
−
φ
2
)
{\displaystyle \cos \theta -\cos \varphi =-2\sin \left({\theta +\varphi \over 2}\right)\sin \left({\theta -\varphi \over 2}\right)}
If x , y , and z are the three angles of any triangle, or in other words
if
x
+
y
+
z
=
π
=
half circle,
{\displaystyle {\mbox{if }}x+y+z=\pi ={\mbox{half circle,}}\,}
then
tan
(
x
)
+
tan
(
y
)
+
tan
(
z
)
=
tan
(
x
)
tan
(
y
)
tan
(
z
)
.
{\displaystyle {\mbox{then }}\tan(x)+\tan(y)+\tan(z)=\tan(x)\tan(y)\tan(z).\,}
(If any of x , y , z is a right angle, one should take both sides to be ∞. This is neither +∞ nor −∞; for present purposes it makes sense to add just one point at infinity to the real line , that is approached by tan(θ) as tan(θ) either increases through positive values or decreases through negative values. This is a one-point compactification of the real line.)
If
x
+
y
+
z
=
π
=
half circle,
{\displaystyle {\mbox{If }}x+y+z=\pi ={\mbox{half circle,}}\,}
then
sin
(
2
x
)
+
sin
(
2
y
)
+
sin
(
2
z
)
=
4
sin
(
x
)
sin
(
y
)
sin
(
z
)
.
{\displaystyle {\mbox{then }}\sin(2x)+\sin(2y)+\sin(2z)=4\sin(x)\sin(y)\sin(z).\,}
Ptolemy's theorem
If
w
+
x
+
y
+
z
=
π
=
half circle,
{\displaystyle {\mbox{If }}w+x+y+z=\pi ={\mbox{half circle,}}\,}
then
sin
(
w
+
x
)
sin
(
x
+
y
)
=
sin
(
x
+
y
)
sin
(
y
+
z
)
=
sin
(
y
+
z
)
sin
(
z
+
w
)
=
sin
(
z
+
w
)
sin
(
w
+
x
)
=
sin
(
w
)
sin
(
y
)
+
sin
(
x
)
sin
(
z
)
.
{\displaystyle {\begin{aligned}{\mbox{then }}&\sin(w+x)\sin(x+y)\\&{}=\sin(x+y)\sin(y+z)\\&{}=\sin(y+z)\sin(z+w)\\&{}=\sin(z+w)\sin(w+x)=\sin(w)\sin(y)+\sin(x)\sin(z).\end{aligned}}}
(The first three equalities are trivial; the fourth is the substance of this identity.) Essentially this is Ptolemy's theorem adapted to the language of trigonometry.
Linear combinations
For some purposes it is important to know that any linear combination of sine waves of the same period or frequency but different phase shifts is also a sine wave with the same period or frequency, but a different phase shift. In the case of a linear combination of a sine and cosine wave[ 24] (which is just a sine wave with a phase shift of π/2), we have
a
sin
x
+
b
cos
x
=
a
2
+
b
2
⋅
sin
(
x
+
φ
)
{\displaystyle a\sin x+b\cos x={\sqrt {a^{2}+b^{2}}}\cdot \sin(x+\varphi )\,}
where
φ
=
{
arcsin
(
b
a
2
+
b
2
)
if
a
≥
0
,
π
−
arcsin
(
b
a
2
+
b
2
)
if
a
<
0
,
{\displaystyle \varphi ={\begin{cases}\arcsin \left({\frac {b}{\sqrt {a^{2}+b^{2}}}}\right)&{\text{if }}a\geq 0,\\\pi -\arcsin \left({\frac {b}{\sqrt {a^{2}+b^{2}}}}\right)&{\text{if }}a<0,\end{cases}}}
or equivalently
φ
=
arctan
(
b
a
)
+
{
0
if
a
≥
0
,
π
if
a
<
0.
{\displaystyle \varphi =\arctan \left({\frac {b}{a}}\right)+{\begin{cases}0&{\text{if }}a\geq 0,\\\pi &{\text{if }}a<0.\end{cases}}}
More generally, for an arbitrary phase shift, we have
a
sin
x
+
b
sin
(
x
+
α
)
=
c
sin
(
x
+
β
)
{\displaystyle a\sin x+b\sin(x+\alpha )=c\sin(x+\beta )\,}
where
c
=
a
2
+
b
2
−
2
a
b
cos
α
,
{\displaystyle c={\sqrt {a^{2}+b^{2}-2ab\cos \alpha }},\,}
and
β
=
arctan
(
b
sin
α
a
+
b
cos
α
)
+
{
0
if
a
+
b
cos
α
≥
0
,
π
if
a
+
b
cos
α
<
0.
{\displaystyle \beta =\arctan \left({\frac {b\sin \alpha }{a+b\cos \alpha }}\right)+{\begin{cases}0&{\text{if }}a+b\cos \alpha \geq 0,\\\pi &{\text{if }}a+b\cos \alpha <0.\end{cases}}}
Other sums of trigonometric functions
Sum of sines and cosines with arguments in arithmetic progression:
sin
φ
+
sin
(
φ
+
α
)
+
sin
(
φ
+
2
α
)
+
⋯
+
sin
(
φ
+
n
α
)
=
sin
(
(
n
+
1
)
α
2
)
⋅
sin
(
φ
+
n
α
2
)
sin
α
2
.
{\displaystyle \sin {\varphi }+\sin {(\varphi +\alpha )}+\sin {(\varphi +2\alpha )}+\cdots +\sin {(\varphi +n\alpha )}={\frac {\sin {\left({\frac {(n+1)\alpha }{2}}\right)}\cdot \sin {(\varphi +{\frac {n\alpha }{2}})}}{\sin {\frac {\alpha }{2}}}}.}
cos
φ
+
cos
(
φ
+
α
)
+
cos
(
φ
+
2
α
)
+
⋯
+
cos
(
φ
+
n
α
)
=
sin
(
(
n
+
1
)
α
2
)
⋅
cos
(
φ
+
n
α
2
)
sin
α
2
.
{\displaystyle \cos {\varphi }+\cos {(\varphi +\alpha )}+\cos {(\varphi +2\alpha )}+\cdots +\cos {(\varphi +n\alpha )}={\frac {\sin {\left({\frac {(n+1)\alpha }{2}}\right)}\cdot \cos {(\varphi +{\frac {n\alpha }{2}})}}{\sin {\frac {\alpha }{2}}}}.}
For any a and b :
a
cos
(
x
)
+
b
sin
(
x
)
=
a
2
+
b
2
cos
(
x
−
atan2
(
b
,
a
)
)
{\displaystyle a\cos(x)+b\sin(x)={\sqrt {a^{2}+b^{2}}}\cos(x-\operatorname {atan2} \,(b,a))\;}
where atan2 (y , x ) is the generalization of arctan(y /x ) which covers the entire circular range .
tan
(
x
)
+
sec
(
x
)
=
tan
(
x
2
+
π
4
)
.
{\displaystyle \tan(x)+\sec(x)=\tan \left({x \over 2}+{\pi \over 4}\right).}
The above identity is sometimes convenient to know when thinking about the Gudermannian function , which relates the circular and hyperbolic trigonometric functions without resorting to complex numbers .
If x , y , and z are the three angles of any triangle, i.e. if x + y + z = π, then
cot
(
x
)
cot
(
y
)
+
cot
(
y
)
cot
(
z
)
+
cot
(
z
)
cot
(
x
)
=
1.
{\displaystyle \cot(x)\cot(y)+\cot(y)\cot(z)+\cot(z)\cot(x)=1.\,}
If ƒ (x ) is given by the linear fractional transformation
f
(
x
)
=
(
cos
α
)
x
−
sin
α
(
sin
α
)
x
+
cos
α
,
{\displaystyle f(x)={\frac {(\cos \alpha )x-\sin \alpha }{(\sin \alpha )x+\cos \alpha }},}
and similarly
g
(
x
)
=
(
cos
β
)
x
−
sin
β
(
sin
β
)
x
+
cos
β
,
{\displaystyle g(x)={\frac {(\cos \beta )x-\sin \beta }{(\sin \beta )x+\cos \beta }},}
then
f
(
g
(
x
)
)
=
g
(
f
(
x
)
)
=
(
cos
(
α
+
β
)
)
x
−
sin
(
α
+
β
)
(
sin
(
α
+
β
)
)
x
+
cos
(
α
+
β
)
.
{\displaystyle f(g(x))=g(f(x))={\frac {(\cos(\alpha +\beta ))x-\sin(\alpha +\beta )}{(\sin(\alpha +\beta ))x+\cos(\alpha +\beta )}}.}
More tersely stated, if for all α we let ƒ α be what we called ƒ above, then
f
α
∘
f
β
=
f
α
+
β
.
{\displaystyle f_{\alpha }\circ f_{\beta }=f_{\alpha +\beta }.\,}
If x is the slope of a line, then ƒ (x ) is the slope of its rotation through an angle of −α .
Inverse trigonometric functions
arcsin
(
x
)
+
arccos
(
x
)
=
π
/
2
{\displaystyle \arcsin(x)+\arccos(x)=\pi /2\;}
arctan
(
x
)
+
arccot
(
x
)
=
π
/
2.
{\displaystyle \arctan(x)+\operatorname {arccot}(x)=\pi /2.\;}
arctan
(
x
)
+
arctan
(
1
/
x
)
=
{
π
/
2
,
if
x
>
0
−
π
/
2
,
if
x
<
0
{\displaystyle \arctan(x)+\arctan(1/x)=\left\{{\begin{matrix}\pi /2,&{\mbox{if }}x>0\\-\pi /2,&{\mbox{if }}x<0\end{matrix}}\right.}
Compositions of trig and inverse trig functions
sin
[
arccos
(
x
)
]
=
1
−
x
2
{\displaystyle \sin[\arccos(x)]={\sqrt {1-x^{2}}}\,}
tan
[
arcsin
(
x
)
]
=
x
1
−
x
2
{\displaystyle \tan[\arcsin(x)]={\frac {x}{\sqrt {1-x^{2}}}}}
sin
[
arctan
(
x
)
]
=
x
1
+
x
2
{\displaystyle \sin[\arctan(x)]={\frac {x}{\sqrt {1+x^{2}}}}}
tan
[
arccos
(
x
)
]
=
1
−
x
2
x
{\displaystyle \tan[\arccos(x)]={\frac {\sqrt {1-x^{2}}}{x}}}
cos
[
arctan
(
x
)
]
=
1
1
+
x
2
{\displaystyle \cos[\arctan(x)]={\frac {1}{\sqrt {1+x^{2}}}}}
cot
[
arcsin
(
x
)
]
=
1
−
x
2
x
{\displaystyle \cot[\arcsin(x)]={\frac {\sqrt {1-x^{2}}}{x}}}
cos
[
arcsin
(
x
)
]
=
1
−
x
2
{\displaystyle \cos[\arcsin(x)]={\sqrt {1-x^{2}}}\,}
cot
[
arccos
(
x
)
]
=
x
1
−
x
2
{\displaystyle \cot[\arccos(x)]={\frac {x}{\sqrt {1-x^{2}}}}}
Relation to the complex exponential function
e
i
x
=
cos
(
x
)
+
i
sin
(
x
)
{\displaystyle e^{ix}=\cos(x)+i\sin(x)\,}
[ 25] (Euler's formula ),
e
−
i
x
=
cos
(
−
x
)
+
i
sin
(
−
x
)
=
cos
(
x
)
−
i
sin
(
x
)
{\displaystyle e^{-ix}=\cos(-x)+i\sin(-x)=\cos(x)-i\sin(x)\,}
e
i
π
+
1
=
0
{\displaystyle e^{i\pi }+1=0}
(Euler's identity ),
cos
(
x
)
=
e
i
x
+
e
−
i
x
2
{\displaystyle \cos(x)={\frac {e^{ix}+e^{-ix}}{2}}\;}
[ 26]
sin
(
x
)
=
e
i
x
−
e
−
i
x
2
i
{\displaystyle \sin(x)={\frac {e^{ix}-e^{-ix}}{2i}}\;}
[ 27]
and hence the corollary:
tan
(
x
)
=
e
i
x
−
e
−
i
x
i
(
e
i
x
+
e
−
i
x
)
=
sin
(
x
)
cos
(
x
)
{\displaystyle \tan(x)={\frac {e^{ix}-e^{-ix}}{i({e^{ix}+e^{-ix}})}}\;={\frac {\sin(x)}{\cos(x)}}}
where
i
2
=
−
1
{\displaystyle i^{2}=-1}
.
For applications to special functions , the following infinite product formulae for trigonometric functions are useful:[ 28] [ 29]
Identities without variables
The curious identity
cos
20
∘
⋅
cos
40
∘
⋅
cos
80
∘
=
1
8
{\displaystyle \cos 20^{\circ }\cdot \cos 40^{\circ }\cdot \cos 80^{\circ }={\frac {1}{8}}}
is a special case of an identity that contains one variable:
∏
j
=
0
k
−
1
cos
(
2
j
x
)
=
sin
(
2
k
x
)
2
k
sin
(
x
)
.
{\displaystyle \prod _{j=0}^{k-1}\cos(2^{j}x)={\frac {\sin(2^{k}x)}{2^{k}\sin(x)}}.}
A similar-looking identity is
cos
π
7
cos
2
π
7
cos
3
π
7
=
1
8
,
{\displaystyle \cos {\frac {\pi }{7}}\cos {\frac {2\pi }{7}}\cos {\frac {3\pi }{7}}={\frac {1}{8}},}
and in addition
sin
20
∘
⋅
sin
40
∘
⋅
sin
80
∘
=
3
8
.
{\displaystyle \sin 20^{\circ }\cdot \sin 40^{\circ }\cdot \sin 80^{\circ }={\frac {\sqrt {3}}{8}}.}
Similarly:
tan
50
∘
⋅
tan
60
∘
⋅
tan
70
∘
=
tan
80
∘
.
{\displaystyle \tan 50^{\circ }\cdot \tan 60^{\circ }\cdot \tan 70^{\circ }=\tan 80^{\circ }.}
The following is perhaps not as readily generalized to an identity containing variables (but see explanation below):
cos
24
∘
+
cos
48
∘
+
cos
96
∘
+
cos
168
∘
=
1
2
.
{\displaystyle \cos 24^{\circ }+\cos 48^{\circ }+\cos 96^{\circ }+\cos 168^{\circ }={\frac {1}{2}}.}
Degree measure ceases to be more felicitous than radian measure when we consider this identity with 21 in the denominators:
cos
(
2
π
21
)
+
cos
(
2
⋅
2
π
21
)
+
cos
(
4
⋅
2
π
21
)
{\displaystyle \cos \left({\frac {2\pi }{21}}\right)\,+\,\cos \left(2\cdot {\frac {2\pi }{21}}\right)\,+\,\cos \left(4\cdot {\frac {2\pi }{21}}\right)}
+
cos
(
5
⋅
2
π
21
)
+
cos
(
8
⋅
2
π
21
)
+
cos
(
10
⋅
2
π
21
)
=
1
2
.
{\displaystyle \,+\,\cos \left(5\cdot {\frac {2\pi }{21}}\right)\,+\,\cos \left(8\cdot {\frac {2\pi }{21}}\right)\,+\,\cos \left(10\cdot {\frac {2\pi }{21}}\right)={\frac {1}{2}}.}
The factors 1, 2, 4, 5, 8, 10 may start to make the pattern clear: they are those integers less than 21/2 that are relatively prime to (or have no prime factors in common with) 21. The last several examples are corollaries of a basic fact about the irreducible cyclotomic polynomials : the cosines are the real parts of the zeroes of those polynomials; the sum of the zeroes is the Möbius function evaluated at (in the very last case above) 21; only half of the zeroes are present above. The two identities preceding this last one arise in the same fashion with 21 replaced by 10 and 15, respectively.
Computing π
An efficient way to compute π is based on the following identity without variables, due to Machin :
π
4
=
4
arctan
1
5
−
arctan
1
239
{\displaystyle {\frac {\pi }{4}}=4\arctan {\frac {1}{5}}-\arctan {\frac {1}{239}}}
or, alternatively, by using an identity of Leonhard Euler :
π
4
=
5
arctan
1
7
+
2
arctan
3
79
.
{\displaystyle {\frac {\pi }{4}}=5\arctan {\frac {1}{7}}+2\arctan {\frac {3}{79}}.}
A useful mnemonic for certain values of sines and cosines
For certain simple angles, the sines and cosines take the form
n
/
2
{\displaystyle \scriptstyle {\sqrt {n}}/2}
for 0 ≤ n ≤ 4, which makes them easy to remember.
sin
0
=
sin
0
∘
=
0
/
2
=
cos
90
∘
=
cos
(
π
2
)
sin
(
π
6
)
=
sin
30
∘
=
1
/
2
=
cos
60
∘
=
cos
(
π
3
)
sin
(
π
4
)
=
sin
45
∘
=
2
/
2
=
cos
45
∘
=
cos
(
π
4
)
sin
(
π
3
)
=
sin
60
∘
=
3
/
2
=
cos
30
∘
=
cos
(
π
6
)
sin
(
π
2
)
=
sin
90
∘
=
4
/
2
=
cos
0
∘
=
cos
0
{\displaystyle {\begin{matrix}\sin 0&=&\sin 0^{\circ }&=&{\sqrt {0}}/2&=&\cos 90^{\circ }&=&\cos \left({\frac {\pi }{2}}\right)\\\\\sin \left({\frac {\pi }{6}}\right)&=&\sin 30^{\circ }&=&{\sqrt {1}}/2&=&\cos 60^{\circ }&=&\cos \left({\frac {\pi }{3}}\right)\\\\\sin \left({\frac {\pi }{4}}\right)&=&\sin 45^{\circ }&=&{\sqrt {2}}/2&=&\cos 45^{\circ }&=&\cos \left({\frac {\pi }{4}}\right)\\\\\sin \left({\frac {\pi }{3}}\right)&=&\sin 60^{\circ }&=&{\sqrt {3}}/2&=&\cos 30^{\circ }&=&\cos \left({\frac {\pi }{6}}\right)\\\\\sin \left({\frac {\pi }{2}}\right)&=&\sin 90^{\circ }&=&{\sqrt {4}}/2&=&\cos 0^{\circ }&=&\cos 0\end{matrix}}}
Other interesting values
With the golden ratio φ:
cos
(
π
5
)
=
cos
36
∘
=
5
+
1
4
=
φ
2
{\displaystyle \cos \left({\frac {\pi }{5}}\right)=\cos 36^{\circ }={{\sqrt {5}}+1 \over 4}={\frac {\varphi }{2}}}
sin
(
π
10
)
=
sin
18
∘
=
5
−
1
4
=
φ
−
1
2
=
1
2
φ
{\displaystyle \sin \left({\frac {\pi }{10}}\right)=\sin 18^{\circ }={{\sqrt {5}}-1 \over 4}={\varphi -1 \over 2}={1 \over 2\varphi }}
Also see exact trigonometric constants .
Calculus
In calculus the relations stated below require angles to be measured in radians ; the relations would become more complicated if angles were measured in another unit such as degrees. If the trigonometric functions are defined in terms of geometry, their derivatives can be found by verifying two limits. The first is:
lim
x
→
0
sin
x
x
=
1
,
{\displaystyle \lim _{x\rightarrow 0}{\frac {\sin x}{x}}=1,}
verified using the unit circle and squeeze theorem . It may be tempting to propose to use L'Hôpital's rule to establish this limit. However, if one uses this limit in order to prove that the derivative of the sine is the cosine, and then uses the fact that the derivative of the sine is the cosine in applying L'Hôpital's rule, one is reasoning circularly—a logical fallacy. The second limit is:
lim
x
→
0
1
−
cos
x
x
=
0
,
{\displaystyle \lim _{x\rightarrow 0}{\frac {1-\cos x}{x}}=0,}
verified using the identity tan(x /2) = (1 − cos x )/sin x . Having established these two limits, one can use the limit definition of the derivative and the addition theorems to show that (sin x )′ = cos x and (cos x )′ = −sin x . If the sine and cosine functions are defined by their Taylor series , then the derivatives can be found by differentiating the power series term-by-term.
d
d
x
sin
x
=
cos
x
{\displaystyle {d \over dx}\sin x=\cos x}
The rest of the trigonometric functions can be differentiated using the above identities and the rules of differentiation :[ 30] [ 31] [ 32]
d
d
x
sin
x
=
cos
x
,
d
d
x
arcsin
x
=
1
1
−
x
2
d
d
x
cos
x
=
−
sin
x
,
d
d
x
arccos
x
=
−
1
1
−
x
2
d
d
x
tan
x
=
sec
2
x
,
d
d
x
arctan
x
=
1
1
+
x
2
d
d
x
cot
x
=
−
csc
2
x
,
d
d
x
arccot
x
=
−
1
1
+
x
2
d
d
x
sec
x
=
tan
x
sec
x
,
d
d
x
arcsec
x
=
1
|
x
|
x
2
−
1
d
d
x
csc
x
=
−
csc
x
cot
x
,
d
d
x
arccsc
x
=
−
1
|
x
|
x
2
−
1
{\displaystyle {\begin{aligned}{d \over dx}\sin x&=\cos x,&{d \over dx}\arcsin x&={1 \over {\sqrt {1-x^{2}}}}\\\\{d \over dx}\cos x&=-\sin x,&{d \over dx}\arccos x&={-1 \over {\sqrt {1-x^{2}}}}\\\\{d \over dx}\tan x&=\sec ^{2}x,&{d \over dx}\arctan x&={1 \over 1+x^{2}}\\\\{d \over dx}\cot x&=-\csc ^{2}x,&{d \over dx}\operatorname {arccot} x&={-1 \over 1+x^{2}}\\\\{d \over dx}\sec x&=\tan x\sec x,&{d \over dx}\operatorname {arcsec} x&={1 \over |x|{\sqrt {x^{2}-1}}}\\\\{d \over dx}\csc x&=-\csc x\cot x,&{d \over dx}\operatorname {arccsc} x&={-1 \over |x|{\sqrt {x^{2}-1}}}\end{aligned}}\ }
The integral identities can be found in "list of integrals of trigonometric functions ". Some generic forms are listed below.
∫
d
u
a
2
−
u
2
=
sin
−
1
(
u
a
)
+
C
{\displaystyle \int {\frac {du}{\sqrt {a^{2}-u^{2}}}}=\sin ^{-1}\left({\frac {u}{a}}\right)+C}
∫
d
u
a
2
+
u
2
=
1
a
tan
−
1
(
u
a
)
+
C
{\displaystyle \int {\frac {du}{a^{2}+u^{2}}}={\frac {1}{a}}\tan ^{-1}\left({\frac {u}{a}}\right)+C}
∫
d
u
u
u
2
−
a
2
=
1
a
sec
−
1
|
u
a
|
+
C
{\displaystyle \int {\frac {du}{u{\sqrt {u^{2}-a^{2}}}}}={\frac {1}{a}}\sec ^{-1}\left|{\frac {u}{a}}\right|+C}
Implications
The fact that the differentiation of trigonometric functions (sine and cosine) results in linear combinations of the same two functions is of fundamental importance to many fields of mathematics, including differential equations and Fourier transforms .
Exponential definitions
Function
Inverse function[ 33]
sin
θ
=
e
i
θ
−
e
−
i
θ
2
i
{\displaystyle \sin \theta ={\frac {e^{i\theta }-e^{-i\theta }}{2i}}\,}
arcsin
x
=
−
i
ln
(
i
x
+
1
−
x
2
)
{\displaystyle \arcsin x=-i\ln \left(ix+{\sqrt {1-x^{2}}}\right)\,}
cos
θ
=
e
i
θ
+
e
−
i
θ
2
{\displaystyle \cos \theta ={\frac {e^{i\theta }+e^{-i\theta }}{2}}\,}
arccos
x
=
−
i
ln
(
x
+
x
2
−
1
)
{\displaystyle \arccos x=-i\ln \left(x+{\sqrt {x^{2}-1}}\right)\,}
tan
θ
=
e
i
θ
−
e
−
i
θ
i
(
e
i
θ
+
e
−
i
θ
)
{\displaystyle \tan \theta ={\frac {e^{i\theta }-e^{-i\theta }}{i(e^{i\theta }+e^{-i\theta })}}\,}
arctan
x
=
i
2
ln
(
i
+
x
i
−
x
)
{\displaystyle \arctan x={\frac {i}{2}}\ln \left({\frac {i+x}{i-x}}\right)\,}
csc
θ
=
2
i
e
i
θ
−
e
−
i
θ
{\displaystyle \csc \theta ={\frac {2i}{e^{i\theta }-e^{-i\theta }}}\,}
arccsc
x
=
−
i
ln
(
i
x
+
1
−
1
x
2
)
{\displaystyle \operatorname {arccsc} x=-i\ln \left({\tfrac {i}{x}}+{\sqrt {1-{\tfrac {1}{x^{2}}}}}\right)\,}
sec
θ
=
2
e
i
θ
+
e
−
i
θ
{\displaystyle \sec \theta ={\frac {2}{e^{i\theta }+e^{-i\theta }}}\,}
arcsec
x
=
−
i
ln
(
1
x
+
1
−
i
x
2
)
{\displaystyle \operatorname {arcsec} x=-i\ln \left({\tfrac {1}{x}}+{\sqrt {1-{\tfrac {i}{x^{2}}}}}\right)\,}
cot
θ
=
i
(
e
i
θ
+
e
−
i
θ
)
e
i
θ
−
e
−
i
θ
{\displaystyle \cot \theta ={\frac {i(e^{i\theta }+e^{-i\theta })}{e^{i\theta }-e^{-i\theta }}}\,}
arccot
x
=
i
2
ln
(
x
−
i
x
+
i
)
{\displaystyle \operatorname {arccot} x={\frac {i}{2}}\ln \left({\frac {x-i}{x+i}}\right)\,}
cis
θ
=
e
i
θ
{\displaystyle \operatorname {cis} \,\theta =e^{i\theta }\,}
arccis
x
=
ln
x
i
{\displaystyle \operatorname {arccis} \,x={\frac {\ln x}{i}}\,}
Miscellaneous
Dirichlet kernel
The Dirichlet kernel Dn (x ) is the function occurring on both sides of the next identity:
1
+
2
cos
(
x
)
+
2
cos
(
2
x
)
+
2
cos
(
3
x
)
+
⋯
+
2
cos
(
n
x
)
=
sin
[
(
n
+
1
2
)
x
]
sin
(
x
2
)
.
{\displaystyle 1+2\cos(x)+2\cos(2x)+2\cos(3x)+\cdots +2\cos(nx)={\frac {\sin \left[\left(n+{\frac {1}{2}}\right)x\right\rbrack }{\sin \left({\frac {x}{2}}\right)}}.}
The convolution of any integrable function of period 2π with the Dirichlet kernel coincides with the function's n th-degree Fourier approximation. The same holds for any measure or generalized function .
If we set
t
=
tan
(
x
2
)
,
{\displaystyle t=\tan \left({\frac {x}{2}}\right),}
then[ 34]
sin
(
x
)
=
2
t
1
+
t
2
and
cos
(
x
)
=
1
−
t
2
1
+
t
2
and
e
i
x
=
1
+
i
t
1
−
i
t
{\displaystyle \sin(x)={\frac {2t}{1+t^{2}}}{\text{ and }}\cos(x)={\frac {1-t^{2}}{1+t^{2}}}{\text{ and }}e^{ix}={\frac {1+it}{1-it}}}
where eix = cos(x ) + i sin(x ), sometimes abbreviated to cis(x ).
This substitution of t for tan(x /2), with the consequent replacement of sin(x ) by 2t /(1 + t 2 ) and cos(x ) by (1 − t 2 )/(1 + t 2 ) is useful in calculus for converting rational functions in sin(x ) and cos(x ) to functions of t in order to find their antiderivatives. For more information see tangent half-angle formula .
See also
Notes
^ Abramowitz and Stegun, p. 73, 4.3.45
^ Abramowitz and Stegun, p. 78, 4.3.147
^ Abramowitz and Stegun, p. 72, 4.3.13–15
^ The Elementary Identities
^ Abramowitz and Stegun, p. 72, 4.3.9
^ Abramowitz and Stegun, p. 72, 4.3.7–8
^ Abramowitz and Stegun, p. 72, 4.3.16
^ a b c Weisstein, Eric W. "Trigonometric Addition Formulas" . MathWorld .
^ Abramowitz and Stegun, p. 72, 4.3.17
^ Abramowitz and Stegun, p. 72, 4.3.18
^ Abramowitz and Stegun, p. 80, 4.4.42
^ Abramowitz and Stegun, p. 80, 4.4.43
^ Abramowitz and Stegun, p. 80, 4.4.36
^ a b Weisstein, Eric W. "Multiple-Angle Formulas" . MathWorld .
^ Abramowitz and Stegun, p. 74, 4.3.48
^ Abramowitz and Stegun, p. 72, 4.3.24–26
^ Weisstein, Eric W. "Double-Angle Formulas" . MathWorld .
^ Abramowitz and Stegun, p. 72, 4.3.27–28
^ Abramowitz and Stegun, p. 72, 4.3.20–22
^ Weisstein, Eric W. "Half-Angle Formulas" . MathWorld .
^ Ken Ward's Mathematics Pages, http://www.trans4mind.com/personal_development/mathematics/trigonometry/multipleAnglesRecursiveFormula.htm
^ Abramowitz and Stegun, p. 72, 4.3.31–33
^ Abramowitz and Stegun, p. 72, 4.3.34–39
^ Proof at http://pages.pacificcoast.net/~cazelais/252/lc-trig.pdf
^ Abramowitz and Stegun, p. 74, 4.3.47
^ Abramowitz and Stegun, p. 71, 4.3.2
^ Abramowitz and Stegun, p. 71, 4.3.1
^ Abramowitz and Stegun, p. 75, 4.3.89–90
^ Abramowitz and Stegun, p. 85, 4.5.68–69
^ Abramowitz and Stegun, p. 77, 4.3.105–110
^ Abramowitz and Stegun, p. 82, 4.4.52–57
^ Finney, Ross (2003). Calculus : Graphical, Numerical, Algebraic . Glenview, Illinois: Prentice Hall. pp. 159– 161. ISBN 0-13-063131-0 .
^ Abramowitz and Stegun, p. 80, 4.4.26–31
^ Abramowitz and Stegun, p. 72, 4.3.23
References
External links
Template:Link FA