Sort-merge join: Difference between revisions
Rikvdkooij (talk | contribs) |
m Correct cap in header and/or general fixes. |
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advance(right_subset, right_sorted, right_key, a) |
advance(right_subset, right_sorted, right_key, a) |
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'''return''' output |
'''return''' output |
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'''function''' advance(subset, sorted, key, a) |
'''function''' advance(subset, sorted, key, a) |
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key = sorted[1].a |
key = sorted[1].a |
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private List<int> list; |
private List<int> list; |
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public const int ENDPOS = -1; |
public const int ENDPOS = -1; |
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public int position = 0; |
public int position = 0; |
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public int Position |
public int Position |
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get { return position; } |
get { return position; } |
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} |
} |
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public int Key |
public int Key |
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{ |
{ |
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get { return list[position]; } |
get { return list[position]; } |
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} |
} |
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public bool Advance() |
public bool Advance() |
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{ |
{ |
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if (position == |
if (position ==list.Count - 1 || position== ENDPOS) |
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{ |
{ |
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position = ENDPOS; |
position = ENDPOS; |
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return true; |
return true; |
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} |
} |
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public void Add(int key) |
public void Add(int key) |
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{ |
{ |
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list.Add(key); |
list.Add(key); |
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} |
} |
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public bool IsPastEnd() |
public bool IsPastEnd() |
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{ |
{ |
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return position == ENDPOS; |
return position == ENDPOS; |
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} |
} |
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public void Print() |
public void Print() |
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{ |
{ |
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Console.WriteLine(key); |
Console.WriteLine(key); |
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} |
} |
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public Relation(List<int> list) |
public Relation(List<int> list) |
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{ |
{ |
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this.list = list; |
this.list = list; |
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} |
} |
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public Relation() |
public Relation() |
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{ |
{ |
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} |
} |
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== |
==External links== |
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C# Implementations of Various Join Algorithms [http://www.necessaryandsufficient.net/2010/02/join-algorithms-illustrated/] |
C# Implementations of Various Join Algorithms [http://www.necessaryandsufficient.net/2010/02/join-algorithms-illustrated/] |
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Revision as of 18:09, 30 June 2010
The Sort-Merge Join (also known as Merge-Join) is an example of a join algorithm and is used in the implementation of a relational database management system.
The basic problem of a join algorithm is to find, for each distinct value of the join attribute, the set of tuples in each relation which display that value. The key idea of the Sort-merge algorithm is to first sort the relations by the join attribute, so that interleaved linear scans will encounter these sets at the same time.
In practice, the most expensive part of performing a sort-merge join is arranging for both inputs to the algorithm to be presented in sorted order. This can be achieved via an explicit sort operation (often an external sort), or by taking advantage of a pre-existing ordering in one or both of the join relations. The latter condition can occur because an input to the join might be produced by an index scan of a tree-based index, another merge join, or some other plan operator that happens to produce output sorted on an appropriate key.
Let's say that we have two relations and and . fits in pages memory and fits in pages memory. So, in the worst case Sort-Merge Join will run in I/Os. In the case that and are not ordered the worst case will be (where the last two terms are the cost of ordering both of them first).
Pseudocode
For simplicity, the algorithm is described in the case of an inner join of two relations on a single attribute. Generalization to other join types, more relations and more keys is straightforward.
function sortMerge(relation left, relation right, attribute a) var relation output var list left_sorted := sort(left, a) var list right_sorted := sort(right, a) var left_key var right_key var set left_subset var set right_subset advance(left_subset, left_sorted, left_key, a) advance(right_subset, right_sorted, right_key, a) while not empty(left_subset) and not empty(right_subset) if left_key = right_key add cross product of left_subset and right_subset to output advance(left_subset, left_sorted, left_key, a) advance(right_subset, right_sorted, right_key, a) else if left_key < right_key advance(left_subset, left_sorted, left_key, a) else // left_key > right_key advance(right_subset, right_sorted, right_key, a) return output
function advance(subset, sorted, key, a) key = sorted[1].a subset = emptySet while not empty(sorted) and sorted[1].a = key insert(subset, sorted[1]) remove first element from sorted
Simple C# Implementation
Note that this implementation assumes the join attributes are unique, i.e., there is no need to output multiple tuples for a given value of the key.
public class MergeJoin { // Assume that left and right are already sorted public static Relation Sort(Relation left, Relation right) { Relation output = new Relation(); while (!left.IsPastEnd() && !right.IsPastEnd()) { if (left.Key == right.Key) { output.Add(left.Key); left.Advance(); right.Advance(); } else if (left.Key < right.Key) left.Advance(); else //(left.Key > right.Key) right.Advance(); } return output; } }
public class Relation { private List<int> list; public const int ENDPOS = -1;
public int position = 0; public int Position { get { return position; } }
public int Key { get { return list[position]; } }
public bool Advance() { if (position ==list.Count - 1 || position== ENDPOS) { position = ENDPOS; return false; } position++; return true; }
public void Add(int key) { list.Add(key); }
public bool IsPastEnd() { return position == ENDPOS; }
public void Print() { foreach (int key in list) Console.WriteLine(key); }
public Relation(List<int> list) { this.list = list; }
public Relation() { this.list = new List<int>(); } }
External links
C# Implementations of Various Join Algorithms [1]