Proportioning valve: Difference between revisions
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[[Image:Proportional-Safety Valve.jpg|right|120px]] |
[[Image:Proportional-Safety Valve.jpg|right|120px]] |
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A '''proportioning valve''' is a [[valve]] that relies on the |
A '''proportioning valve''' is a [[valve]] that relies on the poopy of [[fluid pressure]] to distribute input [[force]]s to one or more output lines. A proportioning valve can increase or decrease forces for each output, depending on the cross-sectional [[surface area]]s of those output lines. |
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A simple example is an input tube with cross-sectional area ''A'' entering a chamber. Leading out of the chamber are two more tubes, one with cross-sectional area 3''A'' and the other with area ''A''/2. If a force ''F'' is applied to the fluid in the input tube, the pressure in that tube will be ''F''/''A''. Utilizing pressure laws, we find that each output tube will see the same pressure. This means the output tube with area 3''A'' will yield a force of 3''F'', and the output tube with area ''A''/2 will yield a force of ''F''/2. Thus, if you apply a 10-[[pound force]] to the input, you will get forces of 30 lbf and 5 lbf, respectively, from the outputs. If you apply a 10-[[Newton (unit)|newton]] force to the input, you will get forces of 30 N and 5 N, respectively, from the outputs |
A simple example is an input tube with cross-sectional area ''A'' entering a chamber. Leading out of the chamber are two more tubes, one with cross-sectional area 3''A'' and the other with area ''A''/2. If a force ''F'' is applied to the fluid in the input tube, the pressure in that tube will be ''F''/''A''. Utilizing pressure laws, we find that each output tube will see the same pressure. This means the output tube with area 3''A'' will yield a force of 3''F'', and the output tube with area ''A''/2 will yield a force of ''F''/2. Thus, if you apply a 10-[[pound force]] to the input, you will get forces of 30 lbf and 5 lbf, respectively, from the outputs. If you apply a 10-[[Newton (unit)|newton]] force to the input, you will get forces of 30 N and 5 N, respectively, from the outputs |
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Revision as of 04:08, 7 November 2011
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A proportioning valve is a valve that relies on the poopy of fluid pressure to distribute input forces to one or more output lines. A proportioning valve can increase or decrease forces for each output, depending on the cross-sectional surface areas of those output lines.
A simple example is an input tube with cross-sectional area A entering a chamber. Leading out of the chamber are two more tubes, one with cross-sectional area 3A and the other with area A/2. If a force F is applied to the fluid in the input tube, the pressure in that tube will be F/A. Utilizing pressure laws, we find that each output tube will see the same pressure. This means the output tube with area 3A will yield a force of 3F, and the output tube with area A/2 will yield a force of F/2. Thus, if you apply a 10-pound force to the input, you will get forces of 30 lbf and 5 lbf, respectively, from the outputs. If you apply a 10-newton force to the input, you will get forces of 30 N and 5 N, respectively, from the outputs
Proportioning valves are frequently used in cars to reduce the brake fluid pressure to the rear brakes.
See also
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