Talk:Summed-area table: Difference between revisions
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The formula seems to be incorrect, the sum I(C)+I(A)-I(B)-I(D) calculates rectangle NOT including A, that is x0<(!)<=x1 and y0<=y<(!)y1.--[[Special:Contributions/46.223.253.194|46.223.253.194]] ([[User talk:46.223.253.194|talk]]) 12:08, 26 January 2014 (UTC) |
The formula seems to be incorrect, the sum I(C)+I(A)-I(B)-I(D) calculates rectangle NOT including A, that is x0<(!)<=x1 and y0<=y<(!)y1.--[[Special:Contributions/46.223.253.194|46.223.253.194]] ([[User talk:46.223.253.194|talk]]) 12:08, 26 January 2014 (UTC) |
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Actually, the sum I(C)+I(A)-I(B)-I(D) calculates rectangle not including A, B and D edges, that is x0 < x and y0 < y. I tested that one in my c++ project. <span style="font-size: smaller;" class="autosigned">— Preceding [[Wikipedia:Signatures|unsigned]] comment added by [[Special:Contributions/188.124.228.2|188.124.228.2]] ([[User talk:188.124.228.2|talk]]) 06:48, 11 April 2014 (UTC)</span><!-- Template:Unsigned IP --> <!--Autosigned by SineBot--> |
Actually, the sum I(C)+I(A)-I(B)-I(D) calculates rectangle not including (A, B) and (A, D) edges, that is x0 < x and y0 < y. I tested that one in my c++ project. <span style="font-size: smaller;" class="autosigned">— Preceding [[Wikipedia:Signatures|unsigned]] comment added by [[Special:Contributions/188.124.228.2|188.124.228.2]] ([[User talk:188.124.228.2|talk]]) 06:48, 11 April 2014 (UTC)</span><!-- Template:Unsigned IP --> <!--Autosigned by SineBot--> |
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Revision as of 06:52, 11 April 2014
This article needs a lot of clearing up. Although the formulas are correct its notation is unclear for people who don't know the Viola/Jones paper. What is A, B, C, D? A sum, area or a point? What is the function A(x)? What is i(x,y)? What is the one argumented function I(X) opposed to I(x, y)? All these are essential points missing. --85.177.99.146 (talk) 13:41, 26 January 2013 (UTC)
The formula seems to be incorrect, the sum I(C)+I(A)-I(B)-I(D) calculates rectangle NOT including A, that is x0<(!)<=x1 and y0<=y<(!)y1.--46.223.253.194 (talk) 12:08, 26 January 2014 (UTC)
Actually, the sum I(C)+I(A)-I(B)-I(D) calculates rectangle not including (A, B) and (A, D) edges, that is x0 < x and y0 < y. I tested that one in my c++ project. — Preceding unsigned comment added by 188.124.228.2 (talk) 06:48, 11 April 2014 (UTC)