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P = (a + b + c + d + e + f + g + h + i) + e
P = (a + b + c + d + e + f + g + h + i) + e


But (a + b + c + d + e + f + g + h + i) is just the sum of the numbers 1 to 9 in some order, i.e. 45
But (a + ... + i) is just the sum of all the numbers 1 to 9 in some order, i.e. 45


So P = 45 + e
So P = 45 + e

Revision as of 17:31, 30 August 2017

Sujiko is a logic-based, combinatorial number-placement puzzle created by Jai Gomer of Kobayaashi Studios.[1]

A completed Sujiko puzzle.

The puzzle takes place on a 3x3 grid with four circled number clues at the centre of each quadrant which indicate the sum of the four numbers in that quadrant. The numbers 1-9 must be placed in the grid, in accordance with the circled clues, to complete the puzzle.

Sujiko is featured in UK newspapers including The Times, The Telegraph, and The Sun.[2]

Sujiko properties

File:Sujiko cells 2.jpg
Yellow equals middle plus 45

The puzzle has a mathematical property, often ignored by puzzle setters, that can sometimes make supposedly-difficult examples somewhat trivial, as follows:

The sum of two diagonally-opposite CORNER numbers and the two TOTALS on the OTHER diagonal (e.g. the yellow numbers in the second image) is always equal to the MIDDLE number, plus 45.

In letters:
(a + i) + (T2 + T3) [= P, say]
= (c + g) + (T1 + T4) [ = Q, say]
= e + 45

E.g. from the completed Sujiko Puzzle shown,
(4 + 9) + (18 + 15) = 46
(8 + 6) + (17 + 15) = 46
And 1 + 45 = 46

Proof, for P:

T2 = b + c + e + f
T3 = d + e + g + h

So P = (a + i) + (T2 + T3) can be rewritten as
P = (a + i) + (b + c + e + f) + (d + e + g + h)
Or, rearranging,
P = (a + b + c + d + e + f + g + h + i) + e

But (a + ... + i) is just the sum of all the numbers 1 to 9 in some order, i.e. 45

So P = 45 + e

Q is trivially obvious, by symmetry (or can be similarly proved from first principles).

References

  1. ^ "Sujiko". Puzzler. Retrieved 2016-07-22.
  2. ^ "Kobayaashi". www.sujiko.co.uk. Retrieved 2016-07-22.