Jump to content

Talk:Chudnovsky algorithm

Page contents not supported in other languages.
From Wikipedia, the free encyclopedia

This is an old revision of this page, as edited by MFH (talk | contribs) at 17:50, 14 March 2018 (Usage: Rougly 15 digits per k ?). The present address (URL) is a permanent link to this revision, which may differ significantly from the current revision.

WikiProject iconMathematics Stub‑class Low‑priority
WikiProject iconThis article is within the scope of WikiProject Mathematics, a collaborative effort to improve the coverage of mathematics on Wikipedia. If you would like to participate, please visit the project page, where you can join the discussion and see a list of open tasks.
StubThis article has been rated as Stub-class on Wikipedia's content assessment scale.
LowThis article has been rated as Low-priority on the project's priority scale.

Plagiarism

The materials which I saw in this footnote are first wrong and also stolen from another web site. Sunos 6 (talk | contribs) 05:15, 9 April 2008 (UTC)[reply]

Usage

How can the reader use this algorithm - from what point he can certainly know the n-th digit after the decimal dot is correct? 79.179.42.44 (talk) 21:16, 16 February 2012 (UTC)[reply]

The error will be approximately equal to the next term, so by estimating very roughly the size of the next term, you know up to where the approximation is correct. The factor (6k)!/(3k)!k!^3 grows by a factor 693, 982, 1147, 1252 for the first 5 terms, and ~ 1500 for the next 20 terms. This is to be divided by 262537412640768000, which yields a ratio of ~ 1.5e14 between subsequent terms. If this is not wrong, it should yield roughly 14 more digits at each step. — MFH:Talk 17:50, 14 March 2018 (UTC)[reply]

multiple of e ?

The link between 640320 and e^(pi sqrt 163) is given, but is there a simple explanation for 13591409 x 2e-7 = 2.7182818 ~ e? — MFH:Talk 17:32, 14 March 2018 (UTC)[reply]