1884 United States presidential election in Indiana
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| Elections in Indiana |
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The 1884 United States presidential election in Indiana took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for president and vice president.
Indiana voted for the Democratic nominee, Grover Cleveland over the Republican nominee, James G. Blaine. Cleveland won the state by a narrow margin of 1.31%.
Results
| 1884 United States presidential election in Indiana[1] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Democratic | Grover Cleveland of New York | Thomas Andrews Hendricks of Indiana | 245,005 | 49.46% | 15 | 100.00% | ||
| Republican | James Gillespie Blaine of Maine | John Alexander Logan of Illinois | 238,489 | 48.15% | 0 | 0.00% | ||
| Greenback | Benjamin Franklin Butler of Massachusetts | Absolom Madden West of Mississippi | 8,810 | 1.78% | 0 | 0.00% | ||
| Prohibition | John Pierce St. John of Kansas | William Daniel of Maryland | 3,028 | 0.61% | 0 | 0.00% | ||
| Total | 495,332 | 100.00% | 15 | 100.00% | ||||
References
- ^ "1884 Presidential General Election Results - Indiana". U.S. Election Atlas. Retrieved 23 December 2013.
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