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This is an old revision of this page, as edited by 118.208.187.115 (talk) at 07:45, 7 May 2021 (The image in #Laying_out_the_message is miscaptioned: new section). The present address (URL) is a permanent link to this revision, which may differ significantly from the current revision.

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Is the mode message split by the reference grid or not?

In the text there is a mention about the mode message that "For a full Aztec code, it is broken into four 10-bit pieces, and those pieces are each divided in half by the reference grid." However, according to the picture on the right, the reference grid begins just outside the mode message. So either the picture or the text is incorrect. --Rustamabd (talk) 16:46, 13 February 2013 (UTC)[reply]

- Fixed the image. --Rustamabd (talk) 10:39, 14 February 2013 (UTC)[reply]

Is the Reed-Solomon encoding polynomial given in the text correct?

According to the text, the R-S polynomial is (x-1)(x-2)...(x-2^(k-1)). However according to the Russian reference, the polynomial is (x-2)(x-4)...(x-2^k). The latter is also the polynomial used for QR codes. I'm not sure which polynomial is correct. JavautilRandom (talk) 23:28, 10 May 2013 (UTC)[reply]

Seems that (x-2)(x-4)...(x-2^k) is the correct polynomial for Aztec codes. But (x-1)(x-2)...(x-2^(k-1)) is used by QR codes, where did you see otherwise? Bobmath (talk) 00:30, 11 May 2013 (UTC)[reply]
Sorry, I was right about Aztec and wrong about QR. Thanks for double checking and fixing. JavautilRandom (talk) 16:34, 12 May 2013 (UTC)[reply]
Thanks for pointing it out. By the way, did you see the note about the c parameter on the Forney algorithm page? Bobmath (talk) 22:15, 12 May 2013 (UTC)[reply]

The external link "Aztec code specification draft of 2007-01-25" leads to a page which requires a username and password to access. I suggest removal of this link since the page is not freely accessible. Nascentsequitur (talk) 03:46, 18 March 2014 (UTC)[reply]

I removed the link. The link would pass WP:ELNO's no-login requirement because it is about the subject. That said, I don't think the draft spec would be as useful as the actual spec. Glrx (talk) 21:23, 26 March 2014 (UTC)[reply]

Improve reference to notice of dedication of the patent to the public

I which someone could improve my attempt at giving reference to the official notice of dedication of the patent to the public. It is online from the USPTO:

http://patft.uspto.gov/netahtml/PTO/srchnum.htm

enter 5591956 in the query field (that's the patent number), click "search", then "images", then "correction". Fgrieu (talk) 12:49, 4 June 2014 (UTC)[reply]

Dedication page Glrx (talk) 21:52, 4 June 2014 (UTC)[reply]

Aztec code finite field polynomials

In the text there is a table of Aztec code finite field polynomials.

I am familiar with ordinary polynomials where y is a function of x, but these seem to be a different use of the term polynomial.

Could someone explain please what one of these polynomials is about please as it does not look obviously like the ordinary polynomials that I have seen before? — Preceding unsigned comment added by 86.176.30.53 (talk) 15:28, 11 January 2017 (UTC)[reply]

Which one has higher encoding density? Legal usage differences? Any other PRO & CON? --RokerHRO (talk) 20:22, 11 September 2017 (UTC)[reply]

Code in the Encoding/Laying out the message section contains a typo

The Aztec Code in the Encoding/Laying out the message section currently contains a list of URLs and website names, separated with equals signs. Currently, the second URLs contains a typo ("http;//" instead of "http://"). I've created a new code without the typo using Binary Eye on my phone. I've uploaded it here, could somebody replace it for me or explain how to do it? I've never edited a Wikipedia page, much less uploaded to Commons.

Thanks a bunch! --2600:387:F:4712:0:0:0:7 (talk) 14:23, 4 May 2021 (UTC)[reply]

The image in #Laying_out_the_message is miscaptioned

I was confused because it didn't match what the text said about a 6-layer code, so I ended up counting the width and it is actually a 9-layer code. Accordingly, in the caption, "6-layer (41×41) Aztec code" needs to be replaced with "9-layer (53×53) Aztec code".