Talk:Pentagram

Tetragram?

From http://www.ebay.com/itm/181468439544

"There is a Tetragram surrounded by inscriptions on one side and a pentagram on the other."

Both sides look like pentagrams to me... 82.42.161.70 (talk) 10:09, 24 July 2014 (UTC)

The lister simply didn't know what they were looking at. Notice the necklace inscription actually reads tetragrammaton, something completely different. — Huntster (t @ c) 11:03, 24 July 2014 (UTC)

Tetra-gram is a compound word as it is the penta-gram. Penta refers to the number 5 in Greek, tetra refers to the number 4 and gram refers to the word line in both cases. Obviously a star shape can't me shaped with 4 lines ...W5ry3 (talk) 22:45, 24 November 2016 (UTC)

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Does adjusting the formatting of a table require citing sources???

A table in this article looked like this:

$\sin {\frac {\pi }{10}}=\sin 18^{\circ }={\frac {{\sqrt {5}}-1}{4}}={\frac {\varphi -1}{2}}={\frac {1}{2\varphi }}$

$\cos {\frac {\pi }{10}}=\cos 18^{\circ }={\frac {\sqrt {2(5+{\sqrt {5}})}}{4}}$

$\tan {\frac {\pi }{10}}=\tan 18^{\circ }={\frac {\sqrt {5(5-2{\sqrt {5}})}}{5}}$

$\cot {\frac {\pi }{10}}=\cot 18^{\circ }={\sqrt {5+2{\sqrt {5}}}}$

$\sin {\frac {\pi }{5}}=\sin 36^{\circ }={\frac {\sqrt {2(5-{\sqrt {5}})}}{4}}$

$\cos {\frac {\pi }{5}}=\cos 36^{\circ }={\frac {{\sqrt {5}}+1}{4}}={\frac {\varphi }{2}}$

$\tan {\frac {\pi }{5}}=\tan 36^{\circ }={\sqrt {5-2{\sqrt {5}}}}$

$\cot {\frac {\pi }{5}}=\cot 36^{\circ }={\frac {\sqrt {5(5+2{\sqrt {5}})}}{5}}$

I changed it so that it looked like this:

${\begin{aligned}\sin {\frac {\pi }{10}}&=\sin 18^{\circ }={\frac {{\sqrt {5}}-1}{4}}={\frac {\varphi -1}{2}}={\frac {1}{2\varphi }}\\[5pt]\cos {\frac {\pi }{10}}&=\cos 18^{\circ }={\frac {\sqrt {2(5+{\sqrt {5}})}}{4}}\\[5pt]\tan {\frac {\pi }{10}}&=\tan 18^{\circ }={\frac {\sqrt {5(5-2{\sqrt {5}})}}{5}}\\[5pt]\cot {\frac {\pi }{10}}&=\cot 18^{\circ }={\sqrt {5+2{\sqrt {5}}}}\\[5pt]\sin {\frac {\pi }{5}}&=\sin 36^{\circ }={\frac {\sqrt {2(5-{\sqrt {5}})}}{4}}\\[5pt]\cos {\frac {\pi }{5}}&=\cos 36^{\circ }={\frac {{\sqrt {5}}+1}{4}}={\frac {\varphi }{2}}\\[5pt]\tan {\frac {\pi }{5}}&=\tan 36^{\circ }={\sqrt {5-2{\sqrt {5}}}}\\[5pt]\cot {\frac {\pi }{5}}&=\cot 36^{\circ }={\frac {\sqrt {5(5+2{\sqrt {5}})}}{5}}\end{aligned}}$

This did not alter the information in the table but made the formatting neater. Notice that the leftmost the column of "equals" signs is now vertically aligned and there's a bit more space between lines.

But User:Epinoia reverted it with this summary:

you might be right, but you will have to cite sources to support a change like this

Is there any sort of source that could be cited for something like this? Michael Hardy (talk) 23:54, 5 January 2019 (UTC)

My apologies if I misread your edit - it appeared as if you were changing the math, not just the formatting - if I am mistaken please re-instate your edit - cheers - Epinoia (talk) 01:47, 6 January 2019 (UTC)

Done. — Cheers, Steelpillow (Talk) 10:33, 6 January 2019 (UTC)