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Young's inequality

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In mathematics, the standard form of Young's inequality states that if a and b are nonnegative real numbers and p and q are positive real numbers such that 1/p + 1/q = 1 then we have

Equality holds if and only if ap = bq. Young's inequality is a special case of the inequality of weighted arithmetic and geometric means. It is named for William Henry Young.

An elementary case of Young's inequality is the inequality with exponent 2,

which also gives rise to the so-called Young's inequality with ε (valid for any ε > 0),

Generalization using Legendre transforms

If f is a convex function and its Legendre transform is denoted by g, then

This follows immediately from the definition of the Legendre transform. This inequality also holds — in the form a ·bf(a) + g(b) — if f is a convex function taking a vector argument (Arnold 1989, §14).

Examples

  • The Legendre transform of f(a) = ap/p is g(b) = bq/q with q such that 1/p + 1/q = 1, and thus the standard Young inequality mentioned above is a special case.
  • The Legendre transform of f(a) = ea – 1 is g(b) = 1 – b + b ln b, hence ab ≤ eab + b ln b for all non-negative a and b. This estimate is useful in large deviations theory under exponential moment conditions, because b ln b appears in the definition of relative entropy, which it the rate function in Sanov's theorem.

An inequality for Lp norms

In real analysis, the following is also called Young's inequality:

Suppose f is in Lp and g is in Lq and

with 1 ≤ p, q ,r ≤ ∞ and 1/p+1/q>1. Then

Here the star denotes convolution, Lp is Lebesgue space, and

denotes the usual Lp norm. This can be proved by use of the Hölder inequality.

Use

Young's inequality is used in the proof of Hölder's inequality. It is also used widely to estimate the norm of nonlinear terms in PDE theory, since it allows one to estimate a product of two terms by a sum of the same terms raised to a power and scaled.

Proof of the standard form

The proof is trivial if a = 0 or b = 0. Therefore, assume a, b > 0.

If ap = bq, then by the rules for exponentiation and the assumption 1/p + 1/q = 1,

and we have equality in Young's inequality.

Assume in addition apbq for the remaing part of the proof. By the functional equation of the natural logarithm,

Note that the natural logarithm is strictly increasing, because its first derivative is positive for every positive number, hence ln ap ≠ ln bq. Its inverse is the exponential function f(x) = exp(x), which is strictly convex, since its second derivative is positive for every real number. Therefore the exponential function satisfies the defining property of strictly convex functions: for every t in the open interval (0,1) and all real numbers x and y with x ≠ y,

Applying this strict inequality for t = 1/p, 1 – t = 1/q, x = ln ap and y = ln bq gives

which completes the proof.

Proof of the elementary case

Young's inequality with exponent 2 is the special case p = q = 2. However, it has a more elementary proof, just observe that

add 2ab to every side and devide by 2.

Young's inequality with ε follows by applying Young's inequality with exponent 2 to

References

  • Arnold, V. I. (1989), Mathematical Methods of Classical Mechanics (second ed.), Springer, ISBN 978-0-387-96890-2.