Talk:Separation logic

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$\ast$ and $-\!\!\ast$

Stating " $-\!\!\ast$ is the right adjoint of $\ast$ " is useless without first giving any notion of what $\ast$ and $-\!\!\ast$ are meant to represent. Clconway (talk) 18:04, 9 March 2010 (UTC)[reply]

It's even more useless considering there are at least 10 different mathematical meanings of adjoint and it's not clear which is intended. Clconway (talk) 18:08, 9 March 2010 (UTC)[reply]

The previous two comments are outdated, but their author refuses to accept their removal. Apparently on Wikipedia you are not allowed to edit what someone else wrote. Rgrig (talk) 13:20, 3 January 2012 (UTC)[reply]

Hi, there. I am said author. I stipulate that my year-and-a-half-old comments are outdated. ~~Not sure what you mean by my "refus[ing] to accept their removal" since this is the first I've heard of it; maybe there's a bot running to prevent non-self edits on Talk pages.~~ As far as I know, WP practice is to leave outdated comments in place as an archive of the discussion. Clconway (talk) 23:49, 3 January 2012 (UTC)[reply]

I see now that you're talking about an edit from last March I had forgotten about completely. Yes, I reverted your attempt to remove my comments. See WP:TPOC: "You should not edit or delete the comments of other editors without their permission."

Again, I freely admit my earlier comments are no longer applicable to the article. Thanks for working to improve Wikipedia. Clconway (talk) 23:56, 3 January 2012 (UTC)[reply]

∗ {\displaystyle \ast } and − ∗ {\displaystyle -\!\!\ast }

$\ast$ and $-\!\!\ast$