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This is an old revision of this page, as edited by 203.214.51.192 (talk) at 21:29, 4 August 2006 (Dispute with Femto). The present address (URL) is a permanent link to this revision, which may differ significantly from the current revision.

Exellent sweep work and getting that formula in order. Cheers. --Piewalker 21:49, 25 Apr 2005 (UTC)

Dispute with AbsolutDan

I found this message on my Talk page: "Please stop. If you continue to use Wikipedia for advertising, as you did in Cohen's kappa, you will be blocked from editing. A link to the edit I have reverted can be found here: link. If you believe this edit should not have been reverted, please contact me. --AbsolutDan (talk) 12:49, 4 August 2006 (UTC)" Can someone provide an opinion on the suitability of the link to Cohen's Kappa Example: http://www.6sigma101.com/glossary/cohen_kappa.htm#1 What is wrong with this example? In what way is this advertizing? —The preceding unsigned comment was added by 203.214.51.192 (talkcontribs) .

The formula looks fine at that link. Advertising or not, the 2x2 tables are helpful. It's the correct formula. Leaving that page, to be honest I don't feel an overwhelming, compulsory, capitalistic urge to buy anything. In fact, after visiting that page I want to buy less stuff and use the formula to gauge interrater agreement between other people who also went there and want to buy less. Piewalker 15:10, 4 August 2006 (UTC)[reply]

Thanks, Piewalker. Do you support re-adding the link?

Sure. We can always remove it later if the forces of good or evil collectively decide this one hyperlink sucks. Piewalker 16:00, 4 August 2006 (UTC)[reply]
That's opposite of how it works, the inclusion of links has to be justified, not their removal. You need to explain first, what makes the link a unique resource to the encyclopedic content that isn't already in the article or could be easily included? Femto 18:04, 4 August 2006 (UTC)[reply]
I guess you're right, Femto. Even though I already justified inclusion of the link with my first post in sentence 2, 3, and 4, I suppose it's not necessarily a "unique" resource. One could get this data from many places. I still think 2x2 tables are excellent examples that are easily modifiable for adaptation to the article (so it's not plagiarism). Thanks for volunteering yourself to do that, "Male, European, and already paranoid about giving away this much information." Holler if you need help. Cheerio. Piewalker 18:42, 4 August 2006 (UTC)[reply]
I'm not volunteering, 203.214.51.192 should. Instead of keeping to re-include contentious external links, add truly free internal content to Wikipedia. Femto 18:54, 4 August 2006 (UTC)[reply]

Dispute with Femto

So that you can remove it at your whim? It is very clear that Wikipedia is about spam wars by self-confessed vigilante like you and AbsolutDan, and not about supporting genuine contributions. As you know yourself you violate Wikipedia rules by removing content supported by another editor who has proven that the advertising point made by AbsolutDan is simply not true. As you can see from this discussion records the other external link here never had to be justified (I am not suggesting to remove it though). This is a clear example of your selective, vindictive approach. You made it "contentious" and totally ignored its content. What is "truly free internal content"? How is http://www.6sigma101.com/glossary/cohen_kappa.htm#1 not free? Is it because you cannot see it in Opera?