Craig interpolation

In mathematical logic, Craig's interpolation theorem is a result about the relationship between different logical theories. Roughly stated, the theorem says that if a formula φ implies a formula ψ, and the two have at least one atomic variable symbol in common, then there is a formula ρ, called an interpolant, such that every nonlogical symbol in ρ occurs both in φ and ψ, φ implies ρ, and ρ implies ψ. The theorem was first proved for first-order logic by William Craig in 1957. Variants of the theorem hold for other logics, such as propositional logic. A stronger form of Craig's interpolation theorem for first-order logic was proved by Roger Lyndon in 1959;^[1]^[2] the overall result is sometimes called the Craig–Lyndon theorem.

Example

In propositional logic, let

\varphi =\lnot (P\land Q)\to (\lnot R\land Q)

\psi =(S\to P)\lor (S\to \lnot R)

.

Then $\varphi$ tautologically implies $\psi$ . This can be verified by writing $\varphi$ in conjunctive normal form:

\varphi \equiv (P\lor \lnot R)\land Q

.

Thus, if $\varphi$ holds, then $P\lor \lnot R$ holds. In turn, $P\lor \lnot R$ tautologically implies $\psi$ . Because the two propositional variables occurring in $P\lor \lnot R$ occur in both $\varphi$ and $\psi$ , this means that $P\lor \lnot R$ is an interpolant for the implication $\varphi \to \psi$ .

Lyndon's interpolation theorem

Suppose that S and T are two first-order theories. As notation, let S ∪ T denote the smallest theory including both S and T; the signature of S ∪ T is the smallest one containing the signatures of S and T. Also let S ∩ T be the intersection of the languages of the two theories; the signature of S ∩ T is the intersection of the signatures of the two languages.

Lyndon's theorem says that if S ∪ T is unsatisfiable, then there is an interpolating sentence ρ in the language of S ∩ T that is true in all models of S and false in all models of T. Moreover, ρ has the stronger property that every relation symbol that has a positive occurrence in ρ has a positive occurrence in some formula of S and a negative occurrence in some formula of T, and every relation symbol with a negative occurrence in ρ has a negative occurrence in some formula of S and a positive occurrence in some formula of T.

Proof of Craig's interpolation theorem

We present here a constructive proof of the Craig interpolation theorem for propositional logic.^[3] Formally, the theorem states:

If ⊨φ → ψ then there is a ρ (the interpolant) such that ⊨φ → ρ and ⊨ρ → ψ, where atoms(ρ) ⊆ atoms(φ) ∩ atoms(ψ). Here atoms(φ) is the set of propositional variables occurring in φ, and ⊨ is the semantic entailment relation for propositional logic.

Proof. Assume ⊨φ → ψ. The proof proceeds by induction on the number of propositional variables occurring in φ that do not occur in ψ, denoted |atoms(φ) − atoms(ψ)|.

Base case |atoms(φ) − atoms(ψ)| = 0: In this case, φ is suitable. This is because since |atoms(φ) − atoms(ψ)| = 0, we know that atoms(φ) ⊆ atoms(φ) ∩ atoms(ψ). Moreover we have that ⊨φ → φ and ⊨φ → ψ. This suffices to show that φ is a suitable interpolant in this case.

Let’s assume for the inductive step that the result has been shown for all χ where |atoms(χ) − atoms(ψ)| = n. Now assume that |atoms(φ) − atoms(ψ)| = n+1. Pick a q ∈ atoms(φ) but q ∉ atoms(ψ). Now define:

φ' := φ[⊤/q] ∨ φ[⊥/q]

Here φ[⊤/q] is the same as φ with every occurrence of q replaced by ⊤ and φ[⊥/q] similarly replaces q with ⊥. We may observe three things from this definition:

⊨φ' → ψ

(1)

|atoms(φ') − atoms(ψ)| = n

(2)

⊨φ → φ'

(3)

From (1), (2) and the inductive step we have that there is an interpolant ρ such that:

⊨φ' → ρ

(4)

⊨ρ → ψ

(5)

But from (3) and (4) we know that

⊨φ → ρ

(6)

Hence, ρ is a suitable interpolant for φ and ψ.

QED

Since the above proof is constructive, one may extract an algorithm for computing interpolants. Using this algorithm, if n = |atoms(φ') − atoms(ψ)|, then the interpolant ρ has O(EXP(n)) more logical connectives than φ (see Big O Notation for details regarding this assertion). Similar constructive proofs may be provided for the basic modal logic K, intuitionistic logic and μ-calculus, with similar complexity measures.

Craig interpolation can be proved by other methods as well. However, these proofs are generally non-constructive:

model-theoretically, via Robinson's joint consistency theorem: in presence of compactness, negation and conjunction, Robinson's joint consistency theorem and Craig interpolation are equivalent.
proof-theoretically, via a Sequent calculus. If cut elimination is possible and as a result the subformula property holds, then Craig interpolation is provable via induction over the derivations.
algebraically, using amalgamation theorems for the variety of algebras representing the logic.
via translation to other logics enjoying Craig interpolation.

Applications

Craig interpolation has many applications, among them consistency proofs, model checking,^[4] proofs in modular specifications, modular ontologies.

References

^ Lyndon, Roger, An interpolation theorem in the predicate calculus.
^ Troelstra, Anne Sjerp; Schwichtenberg, Helmut (2000), Basic Proof Theory, Cambridge tracts in theoretical computer science, vol. 43 (2nd ed.), Cambridge University Press, p. 141, ISBN 978-0-521-77911-1.
^ Harrison pgs. 426–427
^ Vizel, Y.; Weissenbacher, G.; Malik, S. (2015). "Boolean Satisfiability Solvers and Their Applications in Model Checking". Proceedings of the IEEE. 103 (11). doi:10.1109/JPROC.2015.2455034.

Example

Lyndon's interpolation theorem

Proof of Craig's interpolation theorem

Applications

References

Further reading