Jump to content

Zaklopac

From Wikipedia, the free encyclopedia
The printable version is no longer supported and may have rendering errors. Please update your browser bookmarks and please use the default browser print function instead.
Zaklopac
Заклопац (Serbian)[1]
Village
Zaklopac is located in Croatia
Zaklopac
Zaklopac
Coordinates: 44°25′38″N 16°04′46″E / 44.42722°N 16.07944°E / 44.42722; 16.07944
Country Croatia
CountyZadar County
MunicipalityGračac
Area
 • Total
12.2 km2 (4.7 sq mi)
Elevation
679 m (2,228 ft)
Population
 (2021)[3]
 • Total
12
 • Density0.98/km2 (2.5/sq mi)
Time zoneUTC+1 (CET)
 • Summer (DST)UTC+2 (CEST)
Postal code
23445 Srb
Area code+385 (23)

Zaklopac (Serbian Cyrillic: Заклопац)[1] is a village in Croatia.

Population

According to the 2011 census, Zaklopac had 23 inhabitants.[4]

Population[5]
1857 1869 1880 1890 1900 1910 1921 1931 1948 1953 1961 1971 1981 1991 2001 2011
316 356 292 392 530 544 515 533 262 237 176 156 145 76 15 23

Note: From 1890-1948 it include data for the former settlements of Donji Zaklopac and Gornji Zaklopac.

1991 census

According to the 1991 census, settlement of Zaklopac had 76 inhabitants, which were ethnically declared as all Serbs.

Austro-hungarian 1910 census

According to the 1910 census, settlement of Zaklopac had 544 inhabitants in 3 hamlets, which were linguistically and religiously declared as this:

Population by language Croatian or Serbian
Brezovac Suvajski 70
Donji Zaklopac 133
Gornji Zaklopac 341
Total 544 (100%)
Population by religion Eastern Orthodox
Brezovac Suvajski 70
Donji Zaklopac 133
Gornji Zaklopac 341
Total 544 (100%)

Literature

  • [1] Savezni zavod za statistiku i evidenciju FNRJ i SFRJ, popis stanovništva 1948, 1953, 1961, 1971, 1981. i 1991. godine.
  • Book: "Narodnosni i vjerski sastav stanovništva Hrvatske, 1880-1991: po naseljima, author: Jakov Gelo, izdavač: Državni zavod za statistiku Republike Hrvatske, 1998., ISBN 953-6667-07-X, ISBN 978-953-6667-07-9;

References