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'<!-- The IAU uses the COMMONWEALTH ENGLISH spelling of "neighbourhood". Please do not change. --> "'''Clearing the neighbourhood''' around its orbit" is a criterion for a [[celestial body]] to be considered a [[planet]] in the [[Solar System]]. PLuto is a planet. End of story.This was one of the three criteria adopted by the [[International Astronomical Union]] (IAU) in its 2006 [[IAU definition of planet|definition of planet]].<ref name="IAU definition">{{cite news| url=http://www.iau.org/public_press/news/detail/iau0603/| title=IAU 2006 General Assembly: Result of the IAU Resolution votes| date=24 August 2006| accessdate = 2009-10-23| publisher=IAU}}</ref> In 2015, a proposal was made to utilise the criterion in extending the definition to [[exoplanet]]s.<ref name="Margot 2015" /> In the end stages of [[Nebular hypothesis|planet formation]], a [[planet]] (as so defined) will have "cleared the neighbourhood" of its own orbital zone, meaning it has become gravitationally dominant, and there are no other bodies of comparable size other than its [[natural satellite|satellites]] or those otherwise under its gravitational influence. A large body that meets the other criteria for a planet but has not cleared its neighbourhood is classified as a [[dwarf planet]]. This includes [[Pluto]], which is constrained in its orbit by the gravity of [[Neptune]] and shares its orbital neighbourhood with [[Kuiper belt]] objects. The IAU's definition does not attach specific numbers or equations to this term, but all the planets have cleared their neighbourhoods to a much greater extent (by [[Order of magnitude|orders of magnitude]]) than any dwarf planet, or any candidate for dwarf planet. The phrase may be derived from a paper presented to the general assembly of the IAU in 2000 by [[Alan Stern]] and [[Harold F. Levison]]. The authors used several similar phrases as they developed a theoretical basis for determining if an object orbiting a [[star]] is likely to "clear its neighboring region" of [[planetesimal]]s, based on the object's [[mass]] and its [[orbital period]].<ref name="Stern 2002">{{cite journal | last=Stern | first=S. Alan |author2=Levison, Harold F. | year=2002 | title=Regarding the criteria for planethood and proposed planetary classification schemes | url=http://www.boulder.swri.edu/~hal/PDF/planet_def.pdf | format=[[PDF]] | journal=Highlights of Astronomy| volume=12 | pages=205–213, as presented at the XXIVth General Assembly of the IAU–2000 [Manchester, UK, 7–18 August 2000]|bibcode = 2002HiA....12..205S }}</ref> [[Steven Soter]] prefers to use the term "dynamical dominance"<ref name="Soter 2006"/> and [[Jean-Luc Margot]] notes that such language "seems less prone to misinterpretation".<ref name="Margot 2015" /> Clearly distinguishing "planets" from "dwarf planets" and other [[minor planet]]s had become necessary because the IAU had adopted different rules for naming newly discovered major and minor planets, without establishing a basis for telling them apart. The naming process for [[Eris (dwarf planet)|Eris]] stalled after the announcement of its discovery in 2005, pending clarification of this first step. ==Criteria== The phrase refers to an orbiting body (a planet or [[protoplanet]]) "sweeping out" its [[Planetary orbit|orbital]] region over time, by [[gravitation]]ally interacting with smaller [[Astronomical objects|bodies]] nearby. Over many orbital cycles, a large body will tend to cause small bodies either to [[Accretion (astrophysics)|accrete]] with it, or to be disturbed to another orbit, or to be captured either as a [[satellite]] or into a [[orbital resonance|resonant orbit]]. As a consequence it does not then share its orbital region with other bodies of significant size, except for its own satellites, or other bodies governed by its own gravitational influence. This latter restriction excludes objects whose orbits may cross but that will never collide with each other due to [[orbital resonance]], such as [[Jupiter]] and [[Jupiter trojan|its trojans]], [[Earth]] and [[3753 Cruithne]], or [[Neptune]] and the [[plutinos]].<ref name="Stern 2002"/> As to the extent of orbit clearing required, [[Jean-Luc Margot]] emphasises "a planet can never completely clear its orbital zone, because gravitational and radiative forces continually perturb the orbits of asteroids and comets into planet-crossing orbits" and states that the IAU did not intend the impossible standard of impeccable orbit clearing.<ref name="Margot 2015" /> ===Stern–Levison's ''Λ''=== In their paper, [[Alan Stern|Stern]] and [[Harold F. Levison|Levison]] sought an algorithm to determine which "''planetary bodies control the region surrounding them''".<ref name="Stern 2002"/> They defined ''Λ'' ([[lambda]]), a measure of a body's ability to scatter smaller masses out of its orbital region over a period of time equal to the age of the Universe ([[Hubble time]]). Λ is a dimensionless number defined as :<math>\Lambda = \frac{m^2}{a^\frac{3}{2}}\,k</math> where ''m'' is the mass of the body, ''a'' is the body's semi-major axis, and ''k'' is a function of the orbital elements of the small body being scattered and the degree to which it must be scattered. In the domain of the solar planetary disc, there is little variation in the average values of ''k'' for small bodies at a particular distance from the Sun.<ref name="Soter 2006">{{cite journal| title= What is a Planet?| first=Steven| last=Soter| date=2006-08-16| doi= 10.1086/508861| journal= The Astronomical Journal| volume=132| issue= 6| pages= 2513–2519| arxiv=astro-ph/0608359|bibcode = 2006AJ....132.2513S }}</ref> If Λ > 1, then the body will likely clear out the small bodies in its orbital zone. Stern and Levison used this discriminant to separate the [[hydrostatic equilibrium#Planetary geology|gravitionally rounded]], Sun-orbiting bodies into ''überplanets'', which are "''dynamically important enough to have cleared its neighboring planetesimals''", and ''unterplanets''. The überplanets are the eight most massive solar orbiters (i.e. the IAU planets), and the unterplanets are the rest (i.e. the IAU dwarf planets). ===Soter's ''µ''=== [[Steven Soter]] proposed an observationally based measure ''µ'' ([[mu (letter)|mu]]), which he called the "''planetary discriminant''", to separate bodies orbiting stars into planets and non-planets.<ref name="Soter 2006"/> Per Soter, two bodies are defined to share an ''orbital zone'' if their orbits cross a common radial distance from the primary, and their non-resonant periods differ by less than an order of magnitude. The order-of-magnitude similarity in period requirement excludes comets from the calculation, but the combined mass of the comets turns out to be negligible compared to the other small Solar System bodies, so their inclusion would have little impact on the results. µ is then calculated by dividing the mass of the candidate body by the total mass of the other objects that share its orbital zone. It is a measure of the actual degree of cleanliness of the orbital zone. Soter proposed that if µ > 100, then the candidate body be regarded as a planet. ===Margot's Π=== Astronomer [[Jean-Luc Margot]] has proposed a discriminant, [[Pi (letter)|Π]], that can categorise a body based only on its own mass, its semi-major axis, and its star's mass.<ref name="Margot 2015">{{cite journal| title= A Quantitative Criterion for Defining Planets| first=Jean-Luc| last=Margot| date=2015-10-15| doi= 10.1088/0004-6256/150/6/185| journal= The Astronomical Journal| volume=150| issue=6| pages=185| arxiv=1507.06300v4 |url= http://arxiv.org/pdf/1507.06300v4.pdf}}</ref> Like Stern–Levison's Λ, Π is a measure of the ability of the body to clear its orbit, but unlike Λ, it is solely based on theory and does not use empirical data from the Solar System. Π is based on properties that are feasibly determinable even for exoplanetary bodies, unlike Soter's µ, which requires an accurate census of the orbital zone. :<math>\Pi = \frac{m}{M^\frac{5}{2}a^\frac{9}{8}}\,k</math> where ''m'' is the mass of the candidate body in [[Earth mass]]es, ''a'' is its semi-major axis in [[astronomical unit|AU]], ''M'' is the mass of the parent star in [[solar mass]]es, and ''k'' is a constant. Π depends on the extent of clearing desired and the time required to do so. Margot selected an extent of <math>2\sqrt{3}</math> times the [[Hill sphere|Hill radius]] and a time limit of the parent star's lifetime on the [[main sequence]] (which is a function of the mass of the star). Then, in the mentioned units and a main-sequence lifetime of 10 billion years, k = 807.<ref group=lower-alpha>This expression for ''k'' can be derived by following Margot's paper as follows: The time required for a body of mass ''m'' in orbit around a body of mass ''M'' with an orbital period ''P'' is:<br> <math>t_{clear} = P \frac{\delta x^2}{D_x ^2}</math><br> With <math>\delta x \simeq \frac{C}{a} \left(\frac{m}{3M}\right)^\frac{1}{3}, D_x \simeq \frac{10}{a} \frac{m}{M}, P = 2 \pi \sqrt{\frac{a^3}{GM}},</math> and ''C'' the number of Hill radii to be cleared.<br><br> This gives<br><br> <math>t_{clear} = 2 \pi \sqrt{\frac{a^3}{GM}} \frac{C^2}{a^2} \left(\frac{m}{3M}\right)^\frac{2}{3} \frac{a^2 M^2}{100 m^2} = \frac{2 \pi}{100 \sqrt{G}} \frac{C^2}{3^\frac{2}{3}} a^\frac{3}{2} M^\frac{5}{6} m^{-\frac{4}{3}}</math><br><br> requiring that the clearing time ''t_clear'' to be less than a characteristic timescale ''t_*'' gives:<br><br> <math>t_* \ge t_{clear} = 2 \pi \sqrt{\frac{a^3}{GM}} \frac{C^2}{a^2} \left(\frac{m}{3M}\right)^\frac{2}{3} \frac{a^2 M^2}{100 m^2} = \frac{2 \pi}{100 \sqrt{G}} \frac{C^2}{3^\frac{2}{3}} a^\frac{3}{2} M^\frac{5}{6} m^{-\frac{4}{3}}</math><br><br> this means that a body with a mass ''m'' can clear its orbit within the designated timescale if it satisfies<br><br> <math>m \ge {\left[ \frac{2 \pi}{100 \sqrt{G}} \frac{C^2}{3^\frac{2}{3} t_*} a^\frac{3}{2} M^\frac{5}{6} \right]}^\frac{3}{4} = { {\left(\frac{2 \pi}{100 \sqrt{G}}\right)}^\frac{3}{4} \frac{C^\frac{3}{2}}{\sqrt{3} {t_*}^\frac{3}{4}} a^\frac{9}{8} M^\frac{5}{8} }</math><br><br> This can be rewritten as follows<br><br> <math>\frac{m}{m_{Earth}} \ge { {\left(\frac{2 \pi}{100 \sqrt{G}}\right)}^\frac{3}{4} \frac{C^\frac{3}{2}}{\sqrt{3} {t_*}^\frac{3}{4}} {\left(\frac{a}{a_{Earth}}\right)}^\frac{9}{8} {\left(\frac{M}{M_{Sun}}\right)}^\frac{5}{8} \frac{a_{Earth}^\frac{9}{8} M_{Sun}^\frac{5}{8}}{m_{Earth}}}</math><br><br> so that the variables can be changed to use solar masses, Earth masses, and distances in AU by<br><br> <math> \frac{M}{M_{Sun}} \to \bar M , \frac{m}{m_{Earth}} \to \bar m ,</math> and <math> \frac{a}{a_{Earth}} \to \bar a </math><br><br> Then, equating ''t_*'' to be the main-sequence lifetime of the star ''t_MS'', the above expression can be rewritten using<br><br> <math> t_* \simeq t_{MS} \propto {\left(\frac{M}{M_{Sun}}\right)}^{-\frac{5}{2}}t_{Sun} ,</math><br><br> with ''t_Sun'' the main-sequence lifetime of the Sun, and making a similar change in variables to time in years<br><br> <math> \frac{t_{Sun}}{P_{Earth}} \to \bar t_{Sun} .</math><br><br> This then gives<br><br> <math>\bar m \ge {\left(\frac{2 \pi}{100 \sqrt{G}}\right)}^\frac{3}{4} \frac{C^\frac{3}{2}}{\sqrt{3} {\bar t_{Sun}}^\frac{3}{4}} \bar a^\frac{9}{8} \bar M^\frac{5}{2} \frac{a_{Earth}^\frac{9}{8} M_{Sun}^\frac{5}{8}}{m_{Earth} P_{Earth}^\frac{3}{4}}</math><br><br> Then, the orbital-clearing parameter is the mass of the body divided by the minimum mass required to clear its orbit (which is the right-hand side of the above expression) and leaving out the bars for simplicity gives the expression for Π as given in this article:<br><br> <math>\Pi = \frac{m}{m_{clear}} = \frac{m}{a^\frac{9}{8} M^\frac{5}{2}} {\left(\frac{100 \sqrt{G}}{2 \pi}\right)}^\frac{3}{4} \frac{\sqrt{3} {t_{Sun}}^\frac{3}{4}}{C^\frac{3}{2}} \frac{m_{Earth} P_{Earth}^\frac{3}{4}}{a_{Earth}^\frac{9}{8} M_{Sun}^\frac{5}{8}} .</math><br><br> which means that<br><br> <math> k = {\left(\frac{100 \sqrt{G}}{2 \pi}\right)}^\frac{3}{4} \frac{\sqrt{3} {t_{Sun}}^\frac{3}{4}}{C^\frac{3}{2}} m_{Earth} P_{Earth}^\frac{3}{4} a_{Earth}^{-\frac{9}{8}} M_{Sun}^{-\frac{5}{8}} </math><br><br> Earth's orbital period can then be used to remove ''a_Earth'' and ''P_Earth'' from the expression:<br><br> <math> P_{Earth} = 2 \pi \sqrt{\frac{{a_{Earth}}^3}{M_{Sun}G}} , </math><br><br> which gives<br><br> <math> k = {\left(\frac{100 \cancel{\sqrt{G}}}{\cancel{2 \pi}}\right)}^\frac{3}{4} \frac{\sqrt{3} {t_{Sun}}^\frac{3}{4}}{C^\frac{3}{2}} m_{Earth} {\left(\cancel{2 \pi} \sqrt{\frac{\cancel{{a_{Earth}}^3}}{M_{Sun}\cancel{G}}}\right)}^\frac{3}{4} \cancel{a_{Earth}^{-\frac{9}{8}}} M_{Sun}^{-\frac{5}{8}} ,</math><br><br> so that this becomes<br><br> <math>k = \sqrt{3} C^{-\frac{3}{2}} (100 t_{Sun})^\frac{3}{4} \frac{m_{Earth}}{M_{Sun}}</math><br><br> Plugging in the numbers gives ''k'' = 807.</ref> The body is a planet if Π > 1. The minimum mass necessary to clear the given orbit is given when Π = 1. Π is based on a calculation of the number of orbits required for the candidate body to impart enough energy to a small body in a nearby orbit such that the smaller body is cleared out of the desired orbital extent. This is unlike Λ, which uses an average of the clearing times required for a sample of asteroids in the [[asteroid belt]], and is thus biased to that region of the Solar System. Π's use of the main-sequence lifetime means that the body will eventually clear an orbit around the star; Λ's use of a [[Hubble time]] means that the star might disrupt its planetary system (e.g. by going nova) before the object is actually able to clear its orbit. The formula for Π assumes a circular orbit. Its adaptation to elliptical orbits is left for future work, but Margot expects it to be the same as that of a circular orbit to within an order of magnitude. ==Numerical values== Below is a list of planets and dwarf planets ranked by Margot's planetary discriminant Π, in decreasing order.<ref name="Margot 2015"/> For all eight planets defined by the IAU, Π is orders of magnitude greater than 1, whereas for all dwarf planets, Π is orders of magnitude less than 1. Also listed are Stern–Levison's Λ and Soter's µ; again, the planets are orders of magnitude greater than 1 for Λ and 100 for µ, and the dwarf planets are orders of magnitude less than 1 for Λ and 100 for µ. Also shown are the distances where Π = 1 and Λ = 1 (where the body would change from being a planet to being a dwarf planet). {| class="sortable wikitable" |- ! Rank ! Name ! Margot's planetary<br>discriminant Π ! Soter's planetary<br>discriminant µ ! Stern–Levison<br>parameter Λ</sub> <br> {{efn|These values are based on a value of ''k'' estimated for Ceres and the asteroids belt: ''k'' equals 1.53{{E-sp|5}} AU^1.5/{{Earth mass}}², where [[Astronomical Unit|AU]] is the astronomical unit and [[Earth mass|{{Earth mass}}]] is the mass of Earth. Accordingly, Λ is dimensionless.}} ! Mass (kg) ! Type of object ! Π = 1<br>distance ([[Astronomical unit|AU]]) ! Λ = 1<br>distance ([[Astronomical unit|AU]]) |- |1||Pluto Yeah Boyz||align=right| {{sort|400000000|4.0{{E-sp|4}}}} ||align=right| {{sort|0625000|6.25{{E-sp|5}}}} ||align=right|{{sort|1300000000|1.30{{E-sp|9}}}}|| align="right" |deez Nuts|| 5th planet ||align=right| {{nts|64000}} ||align=right| {{nts|6220000}} |- |2|| [[Saturn]] ||align=right| {{sort|061000000|6.1{{E-sp|3}}}} ||align=right| {{sort|0190000|1.9{{E-sp|5}}}} ||align=right|{{sort|0046800000|4.68{{E-sp|7}}}}||align=right| {{sort|0568460000|5.6846{{E-sp|26}}}} || 6th planet ||align=right| {{nts|22000}} ||align=right| {{nts|1250000}} |- |3|| [[Venus]] ||align=right| {{sort|009500000|9.5{{E-sp|2}}}} ||align=right| {{sort|1350000|1.35{{E-sp|6}}}} ||align=right|{{sort|0000166000|1.66{{E-sp|5}}}}||align=right| {{sort|0004868500|4.8685{{E-sp|24}}}} || 2nd planet ||align=right| {{nts|320}} ||align=right| {{nts|2180}} |- |4|| [[Earth]] ||align=right| {{sort|008100000|8.1{{E-sp|2}}}} ||align=right| {{sort|1700000|1.7{{E-sp|6}}}} ||align=right|{{sort|0000153000|1.53{{E-sp|5}}}}||align=right|{{sort|0005973600|5.9736{{E-sp|24}}}} || 3rd planet ||align=right| {{nts|380}} ||align=right| {{nts|2870}} |- |5|| [[Uranus]] ||align=right| {{sort|004200000|4.2{{E-sp|2}}}} ||align=right| {{sort|0029000|2.9{{E-sp|4}}}} ||align=right|{{sort|0000384000|3.84{{E-sp|5}}}}||align=right| {{sort|0086832000|8.6832{{E-sp|25}}}} || 7th planet ||align=right| {{nts|4100}} ||align=right| {{nts|102000}} |- |6|| [[Neptune]] ||align=right| {{sort|003000000|3.0{{E-sp|2}}}} ||align=right| {{sort|0024000|2.4{{E-sp|4}}}} ||align=right|{{sort|0000273000|2.73{{E-sp|5}}}}||align=right| {{sort|0102430000|1.0243{{E-sp|26}}}} || 8th planet ||align=right| {{nts|4800}} ||align=right| {{nts|127000}} |- |7|| [[Mercury (planet)|Mercury]] ||align=right| {{sort|001300000|1.3{{E-sp|2}}}} ||align=right| {{sort|0091000|9.1{{E-sp|4}}}} ||align=right|{{sort|0000001950|1.95{{E-sp|3}}}}||align=right| {{sort|0000330220|3.3022{{E-sp|23}}}} || 1st planet ||align=right| {{nts|29}} ||align=right| {{nts|60}} |- |8|| [[Mars]] ||align=right| {{sort|000540000|5.4{{E-sp|1}}}} ||align=right| {{sort|0180000|1.8{{E-sp|5}}}} ||align=right|{{sort|0000000942|9.42{{E-sp|2}}}}||align=right| {{sort|0000641850|6.4185{{E-sp|23}}}} || 4th planet ||align=right| {{nts|53}} ||align=right| {{nts|146}} |- |9|| [[Ceres (dwarf planet)|Ceres]] ||align=right| {{sort|000000400|4.0{{E-sp|&minus;2}}}} ||align=right| {{sort|0000000.33|0.33}} ||align=right|{{sort|0000000000.000832|8.32{{E-sp|&minus;4}}}}||align=right| {{sort|0000000943|9.43{{E-sp|20}}}} || dwarf planet ||align=right| {{nts|0.16}} ||align=right| {{nts|0.0245}} |- |10||Jupiter||align=right| {{sort|000000280|2.8{{E-sp|&minus;2}}}} ||align=right| {{sort|0000000.077|0.077}} ||align=right|{{sort|0000000000.00295|2.95{{E-sp|&minus;3}}}}||align=right| {{sort|0000012900|1.29{{E-sp|22}}}} || dwarf planet ||align=right| {{nts|1.7}} ||align=right| {{nts|0.812}} |- |11|| [[Eris (dwarf planet)|Eris]] ||align=right| {{sort|000000200|2.0{{E-sp|&minus;2}}}} ||align=right| {{sort|0000000.10|0.10}} ||align=right|{{sort|0000000000.00215|2.15{{E-sp|&minus;3}}}}||align=right| {{sort|0000016700|1.67{{E-sp|22}}}} || dwarf planet ||align=right| {{nts|2.1}} ||align=right| {{nts|1.13}} |- |12|| [[Haumea]] ||align=right| {{sort|000000079|7.8{{E-sp|&minus;3}}}} ||align=right| {{sort|0000000.02|0.02<ref name=est/>}} ||align=right|{{sort|0000000000.000241|2.41{{E-sp|&minus;4}}}}||align=right| {{sort|0000004000|4.0{{E-sp|21}}}}|| dwarf planet ||align=right| {{nts|0.58}} ||align=right| {{nts|0.168}} |- |13|| [[Makemake]] ||align=right| {{sort|000000074|7.3{{E-sp|&minus;3}}}} ||align=right| {{sort|0000000.02|0.02<ref name=est>Calculated using the estimate for the mass of the Kuiper belt found in [http://adsabs.harvard.edu/abs/2007MNRAS.tmp...24I Iorio, 2007] of 0.033 Earth masses</ref>}} ||align=right|{{sort|0000000000.000222|2.22{{E-sp|&minus;4}}}}||align=right| {{sort|0000004000|~4{{E-sp|21}}}} || dwarf planet ||align=right| {{nts|0.58}} ||align=right| {{nts|0.168}} |- ! colspan=9 style="font-size: 0.8em; font-weight: normal; text-align: center; padding: 4px;" |<!-- note --> Note: 1 [[light-year]] ≈ {{nts|63241}} [[Astronomical unit|AU]] |} ==Disagreement== [[Image:TheKuiperBelt 75AU All.svg|right|thumb|400px|Orbits of celestial bodies in the Kuiper belt with approximate distances and inclination. Objects marked with red are in orbital resonances with Neptune, with Pluto (the largest red circle) located in the "spike" of plutinos at the 2:3 resonance]] Stern, currently leading [[NASA]]'s ''[[New Horizons]]'' mission to Pluto, disagrees with the reclassification of Pluto on the basis of its inability to clear a neighbourhood. One of his arguments is that the IAU's wording is vague, and that—like Pluto—[[Earth]], [[Mars]], Jupiter and Neptune have not cleared their orbital neighbourhoods either. Earth co-orbits with 10,000 [[near-Earth asteroid]]s (NEAs), and Jupiter has [[Jupiter trojan|100,000 trojans]] in its orbital path. "If Neptune had cleared its zone, Pluto wouldn't be there", he has said.<ref>{{cite web| url=http://news.bbc.co.uk/2/hi/science/nature/5283956.stm| title=Pluto vote 'hijacked' in revolt| publisher=BBC News| date=25 August 2006| accessdate = 2006-09-03| first=Paul| last= Rincon}}</ref> However, Stern himself co-developed one of the measurable discriminants: [[Clearing the neighbourhood#Stern–Levison's Λ|Stern and Levison's ''Λ'']]. In that context he stated, "we define an ''überplanet'' as a planetary body in orbit about a star that is dynamically important enough to have cleared its neighboring planetesimals ..." and a few paragraphs later, "From a dynamical standpoint, our solar system clearly contains 8 überplanets"—including Earth, Mars, Jupiter, and Neptune.<ref name="Stern 2002"/> Although he proposed this to define dynamical subcategories of planets, he still rejects it for defining what a planet essentially is, advocating the use of intrinsic attributes<ref name="Stern Interview">{{cite new| url=http://www.space.com/12710-pluto-defender-alan-stern-dwarf-planet-interview.html| title=Pluto's Planet Title Defender: Q & A With Planetary Scientist Alan Stern| date=24 August 2011| accessdate = 2016-03-08| publisher=Space.com}}</ref> over dynamical relationships. ==See also== *[[List of Solar System objects]] *[[List of gravitationally rounded objects of the Solar System]] *[[List of Solar System objects by size]] *[[List of notable asteroids]] *[[Mesoplanet]] ==Notes== {{notelist}} ==References== {{Reflist}} ==External links== * [[Ottawa Citizen]]: [http://www.canada.com/ottawacitizen/news/story.html?id=a9591aed-f19f-4ac3-a324-1f8bb46d9379&p=2 The case against Pluto] (P. Surdas Mohit) Thursday, August 24, 2006 {{Solar System}} [[Category:Planetary science]] [[Category:Planets]] [[Category:Definition of planet]] [[Category:Pluto's planethood]] [[Category:Dynamics of the Solar System]] [[Category:Celestial mechanics]] [[Category:Astronomical controversies]]'